Odtnhj

There are 8 input arguments in my function unstable_L(T1,T2,z1,z2,z3,z0h,z0m,U).

I would like to create this function with 5 required inouts and 3 optional inputs in which the optional value will be my default values that I have set if the user do not fill in. How can I make it? Is there any mistake in my coding?

nargin = 8;
if nargin > 8
 disp (" the function unstable_L_new has only maximum of 8 input paramaters")

else
% Fill in unset optional values.
switch nargin
 case 5
 if isempty(z0h)
 z0h = 0.005;

 elseif isempty(z0m)
 z0m = 0.005;

 elseif isempty(U)
 U = 2.0;

 end

 case 6
 if isempty(z0m)
 z0m = 0.005;

 elseif isempty(U)
 U = 2.0;

 end

 case 7
 if isempty(U)
 U = 2.0;
 end
end
end

The way I understand your problem is that your last three arguments z0h, z0m and U are optional.

The way you can make this work is by checking if they exist

function unstable_L(T1,T2,z1,z2,z3,z0h,z0m,U)

 if (~exist('z0h', 'var'))
 z0h = 1;
 end

 if (~exist('z0m', 'var'))
 z0m = 0.005;
 end

 if (~exist('U', 'var'))
 U = 2.0;
 end

 % rest of function