different result with scipy integrate.tplquad









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With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.

This is Matematica code.



Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)] 


I can't see what I am doing wrong with ntegrate.tplquad



f = lambda x,y,z: 1-x 

x1, x2 = 0,2

y1, y2 = lambda x : 0 , lambda x:3-1.5*x

z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y

print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0









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  • @kabanus, I will update with the code. But there is is link to wolfram on the first line.
    – LetzerWille
    Oct 8 at 21:29














up vote
1
down vote

favorite












With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.

This is Matematica code.



Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)] 


I can't see what I am doing wrong with ntegrate.tplquad



f = lambda x,y,z: 1-x 

x1, x2 = 0,2

y1, y2 = lambda x : 0 , lambda x:3-1.5*x

z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y

print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0









share|improve this question























  • @kabanus, I will update with the code. But there is is link to wolfram on the first line.
    – LetzerWille
    Oct 8 at 21:29












up vote
1
down vote

favorite









up vote
1
down vote

favorite











With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.

This is Matematica code.



Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)] 


I can't see what I am doing wrong with ntegrate.tplquad



f = lambda x,y,z: 1-x 

x1, x2 = 0,2

y1, y2 = lambda x : 0 , lambda x:3-1.5*x

z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y

print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0









share|improve this question















With Matematica this integral gives me 3. wolfram alpha
With integrate.tplquad I get -3.

This is Matematica code.



Integrate[1-x, (0,2),(0,3-1.5*x),(0,6-3*x -2*y)] 


I can't see what I am doing wrong with ntegrate.tplquad



f = lambda x,y,z: 1-x 

x1, x2 = 0,2

y1, y2 = lambda x : 0 , lambda x:3-1.5*x

z1, z2 = lambda x,y:0, lambda x,y: 6 -3*x -2*y

print(integrate.tplquad(f,x1,x2, y1, y2, z1, z2)[0])
-3.0






python scipy wolfram-mathematica






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edited Oct 8 at 21:34









kabanus

10.9k21237




10.9k21237










asked Oct 8 at 21:16









LetzerWille

3,4032918




3,4032918











  • @kabanus, I will update with the code. But there is is link to wolfram on the first line.
    – LetzerWille
    Oct 8 at 21:29
















  • @kabanus, I will update with the code. But there is is link to wolfram on the first line.
    – LetzerWille
    Oct 8 at 21:29















@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29




@kabanus, I will update with the code. But there is is link to wolfram on the first line.
– LetzerWille
Oct 8 at 21:29












1 Answer
1






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up vote
3
down vote



accepted










Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:



 f = lambda x, y, z: 1 - z





share|improve this answer
















  • 1




    I actually thought it more natural to change the signature rather than the function. Weird how these things are.
    – kabanus
    Oct 8 at 21:34










  • This one is really counter intuitive. Thank you.
    – LetzerWille
    Oct 8 at 21:49










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
3
down vote



accepted










Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:



 f = lambda x, y, z: 1 - z





share|improve this answer
















  • 1




    I actually thought it more natural to change the signature rather than the function. Weird how these things are.
    – kabanus
    Oct 8 at 21:34










  • This one is really counter intuitive. Thank you.
    – LetzerWille
    Oct 8 at 21:49














up vote
3
down vote



accepted










Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:



 f = lambda x, y, z: 1 - z





share|improve this answer
















  • 1




    I actually thought it more natural to change the signature rather than the function. Weird how these things are.
    – kabanus
    Oct 8 at 21:34










  • This one is really counter intuitive. Thank you.
    – LetzerWille
    Oct 8 at 21:49












up vote
3
down vote



accepted







up vote
3
down vote



accepted






Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:



 f = lambda x, y, z: 1 - z





share|improve this answer












Double-check the tplquad docstring; you'll see that the signature of the function f is f(z, y, x). So it looks like your integrand should be:



 f = lambda x, y, z: 1 - z






share|improve this answer












share|improve this answer



share|improve this answer










answered Oct 8 at 21:30









Warren Weckesser

67.3k794129




67.3k794129







  • 1




    I actually thought it more natural to change the signature rather than the function. Weird how these things are.
    – kabanus
    Oct 8 at 21:34










  • This one is really counter intuitive. Thank you.
    – LetzerWille
    Oct 8 at 21:49












  • 1




    I actually thought it more natural to change the signature rather than the function. Weird how these things are.
    – kabanus
    Oct 8 at 21:34










  • This one is really counter intuitive. Thank you.
    – LetzerWille
    Oct 8 at 21:49







1




1




I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34




I actually thought it more natural to change the signature rather than the function. Weird how these things are.
– kabanus
Oct 8 at 21:34












This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49




This one is really counter intuitive. Thank you.
– LetzerWille
Oct 8 at 21:49

















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