Short name of the file path on Windows is not correctly returned









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I want to get short file path from a given Windows path.
For this reason I use the following JAVA code (with JNA library):



 char result = new char[65535];
Kernel32.INSTANCE.GetShortPathName(file.toString(), result, result.length);
System.out.println(Native.toString(result));


The above code works fine. However, in some cases the returned value is empty string. For example, using the following existing path on Windows yeilds an empty value:



C:UserssomeuserDownloadsGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmdsMlll



The returned value of Kernel32.INSTANCE.GetShortPathName is 0, which according to javadoc is




If the function fails for any other reason, the return value is zero. To get extended error information, call GetLastError.




Calling GetLastError returns 3.



Now, using the following command:



dir /x


I'm able to see that the file actually has an alredy generated short name (GFL4AH~1).



What I've missed?










share|improve this question



























    up vote
    0
    down vote

    favorite












    I want to get short file path from a given Windows path.
    For this reason I use the following JAVA code (with JNA library):



     char result = new char[65535];
    Kernel32.INSTANCE.GetShortPathName(file.toString(), result, result.length);
    System.out.println(Native.toString(result));


    The above code works fine. However, in some cases the returned value is empty string. For example, using the following existing path on Windows yeilds an empty value:



    C:UserssomeuserDownloadsGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmdsMlll



    The returned value of Kernel32.INSTANCE.GetShortPathName is 0, which according to javadoc is




    If the function fails for any other reason, the return value is zero. To get extended error information, call GetLastError.




    Calling GetLastError returns 3.



    Now, using the following command:



    dir /x


    I'm able to see that the file actually has an alredy generated short name (GFL4AH~1).



    What I've missed?










    share|improve this question

























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I want to get short file path from a given Windows path.
      For this reason I use the following JAVA code (with JNA library):



       char result = new char[65535];
      Kernel32.INSTANCE.GetShortPathName(file.toString(), result, result.length);
      System.out.println(Native.toString(result));


      The above code works fine. However, in some cases the returned value is empty string. For example, using the following existing path on Windows yeilds an empty value:



      C:UserssomeuserDownloadsGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmdsMlll



      The returned value of Kernel32.INSTANCE.GetShortPathName is 0, which according to javadoc is




      If the function fails for any other reason, the return value is zero. To get extended error information, call GetLastError.




      Calling GetLastError returns 3.



      Now, using the following command:



      dir /x


      I'm able to see that the file actually has an alredy generated short name (GFL4AH~1).



      What I've missed?










      share|improve this question















      I want to get short file path from a given Windows path.
      For this reason I use the following JAVA code (with JNA library):



       char result = new char[65535];
      Kernel32.INSTANCE.GetShortPathName(file.toString(), result, result.length);
      System.out.println(Native.toString(result));


      The above code works fine. However, in some cases the returned value is empty string. For example, using the following existing path on Windows yeilds an empty value:



      C:UserssomeuserDownloadsGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmGfl4AHIHf6SVMPMT9hjitNZOSXVofG1A9VJrv66YerqDfW8TW73O3VUb1wYYnOOB2l9CvSmTjfPLUvIwwvkddiL3sj7XNB1gqGGrUnmotsG4V3WR50SV1JAkXe2M0MpR4VDoYAUt5WgLpdLqoIdRlH4bd7OcZ3j0GOs90FGuZpZpjhEZBobNz1CwK50jJWYCwAHNmaYOYrC3JnOl6xtX4phNJmdsMlll



      The returned value of Kernel32.INSTANCE.GetShortPathName is 0, which according to javadoc is




      If the function fails for any other reason, the return value is zero. To get extended error information, call GetLastError.




      Calling GetLastError returns 3.



      Now, using the following command:



      dir /x


      I'm able to see that the file actually has an alredy generated short name (GFL4AH~1).



      What I've missed?







      java windows filesystems jna






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      edited Nov 11 at 16:46

























      asked Nov 11 at 16:13









      user4881671

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          I found the solution:



           int returnCode = Kernel32.INSTANCE.GetShortPathName("\\?\" + file.toString(), result, result.length);


          From MS docs:




          To specify an extended-length path, use the "?" prefix. For example, "?D:very long path".







          share|improve this answer




















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            up vote
            0
            down vote













            I found the solution:



             int returnCode = Kernel32.INSTANCE.GetShortPathName("\\?\" + file.toString(), result, result.length);


            From MS docs:




            To specify an extended-length path, use the "?" prefix. For example, "?D:very long path".







            share|improve this answer
























              up vote
              0
              down vote













              I found the solution:



               int returnCode = Kernel32.INSTANCE.GetShortPathName("\\?\" + file.toString(), result, result.length);


              From MS docs:




              To specify an extended-length path, use the "?" prefix. For example, "?D:very long path".







              share|improve this answer






















                up vote
                0
                down vote










                up vote
                0
                down vote









                I found the solution:



                 int returnCode = Kernel32.INSTANCE.GetShortPathName("\\?\" + file.toString(), result, result.length);


                From MS docs:




                To specify an extended-length path, use the "?" prefix. For example, "?D:very long path".







                share|improve this answer












                I found the solution:



                 int returnCode = Kernel32.INSTANCE.GetShortPathName("\\?\" + file.toString(), result, result.length);


                From MS docs:




                To specify an extended-length path, use the "?" prefix. For example, "?D:very long path".








                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 12 at 8:14









                user4881671

                407




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