SQL PIVOT table with MIN() and on Multiple columns










0















Here is the table structure



ID TypeX TypeXDesc XDate TypeCodeY
040001 3669 Unspecified Cat 2005-08-08 1
040001 3669 Unspecified Cat 2006-08-29 2
040001 37515 Tear Film 2005-08-08 1
040001 37999 Disor 2004-07-22 1


Transform above table INTO below USING PIVOT



ID TypeX_1 TypeXDesc_1 XDate_1 TypeCodeY_1 TypeX_2 TypeXDesc_2 XDate_2 TypeCodeY_2 TypeX_3 TypeXDesc_3 XDate_3 TypeCodeY_3
040001 3669 Unspecified Cat 2005-08-08 1 37515 Tear Film 2005-08-08 1 37999 Disor 2004-07-22 1


Look at the same TypeX code but XDate is different and we need to get Min(XDate) so first row is qualified not the second row.










share|improve this question






















  • Any comments please, minor clue would get me going..

    – user1810575
    Nov 15 '18 at 18:28











  • Quit trying to use the PIVOT operator and use aggregated case expressions.

    – Jason A. Long
    Nov 15 '18 at 18:30











  • I started off with aggregated case expressions but its long time to run the query and some one suggested me to use PIVOT. Also there are 20 columns TypeX_1,2,3...20, it was getting expensive using aggregated case exp

    – user1810575
    Nov 15 '18 at 18:41











  • The PIVOT syntax isn't going to be any better. In fact the aggregated CASE will normally out perform the PIVOT.

    – Jason A. Long
    Nov 15 '18 at 18:45















0















Here is the table structure



ID TypeX TypeXDesc XDate TypeCodeY
040001 3669 Unspecified Cat 2005-08-08 1
040001 3669 Unspecified Cat 2006-08-29 2
040001 37515 Tear Film 2005-08-08 1
040001 37999 Disor 2004-07-22 1


Transform above table INTO below USING PIVOT



ID TypeX_1 TypeXDesc_1 XDate_1 TypeCodeY_1 TypeX_2 TypeXDesc_2 XDate_2 TypeCodeY_2 TypeX_3 TypeXDesc_3 XDate_3 TypeCodeY_3
040001 3669 Unspecified Cat 2005-08-08 1 37515 Tear Film 2005-08-08 1 37999 Disor 2004-07-22 1


Look at the same TypeX code but XDate is different and we need to get Min(XDate) so first row is qualified not the second row.










share|improve this question






















  • Any comments please, minor clue would get me going..

    – user1810575
    Nov 15 '18 at 18:28











  • Quit trying to use the PIVOT operator and use aggregated case expressions.

    – Jason A. Long
    Nov 15 '18 at 18:30











  • I started off with aggregated case expressions but its long time to run the query and some one suggested me to use PIVOT. Also there are 20 columns TypeX_1,2,3...20, it was getting expensive using aggregated case exp

    – user1810575
    Nov 15 '18 at 18:41











  • The PIVOT syntax isn't going to be any better. In fact the aggregated CASE will normally out perform the PIVOT.

    – Jason A. Long
    Nov 15 '18 at 18:45













0












0








0








Here is the table structure



ID TypeX TypeXDesc XDate TypeCodeY
040001 3669 Unspecified Cat 2005-08-08 1
040001 3669 Unspecified Cat 2006-08-29 2
040001 37515 Tear Film 2005-08-08 1
040001 37999 Disor 2004-07-22 1


Transform above table INTO below USING PIVOT



ID TypeX_1 TypeXDesc_1 XDate_1 TypeCodeY_1 TypeX_2 TypeXDesc_2 XDate_2 TypeCodeY_2 TypeX_3 TypeXDesc_3 XDate_3 TypeCodeY_3
040001 3669 Unspecified Cat 2005-08-08 1 37515 Tear Film 2005-08-08 1 37999 Disor 2004-07-22 1


Look at the same TypeX code but XDate is different and we need to get Min(XDate) so first row is qualified not the second row.










share|improve this question














Here is the table structure



ID TypeX TypeXDesc XDate TypeCodeY
040001 3669 Unspecified Cat 2005-08-08 1
040001 3669 Unspecified Cat 2006-08-29 2
040001 37515 Tear Film 2005-08-08 1
040001 37999 Disor 2004-07-22 1


Transform above table INTO below USING PIVOT



ID TypeX_1 TypeXDesc_1 XDate_1 TypeCodeY_1 TypeX_2 TypeXDesc_2 XDate_2 TypeCodeY_2 TypeX_3 TypeXDesc_3 XDate_3 TypeCodeY_3
040001 3669 Unspecified Cat 2005-08-08 1 37515 Tear Film 2005-08-08 1 37999 Disor 2004-07-22 1


Look at the same TypeX code but XDate is different and we need to get Min(XDate) so first row is qualified not the second row.







sql sql-server sql-server-2008-r2






share|improve this question













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asked Nov 15 '18 at 17:17









user1810575user1810575

30511638




30511638












  • Any comments please, minor clue would get me going..

    – user1810575
    Nov 15 '18 at 18:28











  • Quit trying to use the PIVOT operator and use aggregated case expressions.

    – Jason A. Long
    Nov 15 '18 at 18:30











  • I started off with aggregated case expressions but its long time to run the query and some one suggested me to use PIVOT. Also there are 20 columns TypeX_1,2,3...20, it was getting expensive using aggregated case exp

    – user1810575
    Nov 15 '18 at 18:41











  • The PIVOT syntax isn't going to be any better. In fact the aggregated CASE will normally out perform the PIVOT.

    – Jason A. Long
    Nov 15 '18 at 18:45

















  • Any comments please, minor clue would get me going..

    – user1810575
    Nov 15 '18 at 18:28











  • Quit trying to use the PIVOT operator and use aggregated case expressions.

    – Jason A. Long
    Nov 15 '18 at 18:30











  • I started off with aggregated case expressions but its long time to run the query and some one suggested me to use PIVOT. Also there are 20 columns TypeX_1,2,3...20, it was getting expensive using aggregated case exp

    – user1810575
    Nov 15 '18 at 18:41











  • The PIVOT syntax isn't going to be any better. In fact the aggregated CASE will normally out perform the PIVOT.

    – Jason A. Long
    Nov 15 '18 at 18:45
















Any comments please, minor clue would get me going..

– user1810575
Nov 15 '18 at 18:28





Any comments please, minor clue would get me going..

– user1810575
Nov 15 '18 at 18:28













Quit trying to use the PIVOT operator and use aggregated case expressions.

– Jason A. Long
Nov 15 '18 at 18:30





Quit trying to use the PIVOT operator and use aggregated case expressions.

– Jason A. Long
Nov 15 '18 at 18:30













I started off with aggregated case expressions but its long time to run the query and some one suggested me to use PIVOT. Also there are 20 columns TypeX_1,2,3...20, it was getting expensive using aggregated case exp

– user1810575
Nov 15 '18 at 18:41





I started off with aggregated case expressions but its long time to run the query and some one suggested me to use PIVOT. Also there are 20 columns TypeX_1,2,3...20, it was getting expensive using aggregated case exp

– user1810575
Nov 15 '18 at 18:41













The PIVOT syntax isn't going to be any better. In fact the aggregated CASE will normally out perform the PIVOT.

– Jason A. Long
Nov 15 '18 at 18:45





The PIVOT syntax isn't going to be any better. In fact the aggregated CASE will normally out perform the PIVOT.

– Jason A. Long
Nov 15 '18 at 18:45












1 Answer
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You can accomplish this using conditional aggregation. In this case, you can enumerate the rows with within typex/id groups using row_number(). You can enumerate the groups with with typex/id using dense_rank().



Then, use conditional aggregation:



select t.id,
max(case when grpnum = 1 and seqnum = 1 then typex end) as typex_1,
max(case when grpnum = 1 and seqnum = 1 then TypeXDesc end) as TypeXDesc_1,
max(case when grpnum = 1 and seqnum = 1 then XDate end) as XDate_1,
max(case when grpnum = 1 and seqnum = 1 then TypeCodeY end) as TypeCodeY_1,
max(case when grpnum = 2 and seqnum = 1 then typex end) as typex_12,
max(case when grpnum = 2 and seqnum = 1 then TypeXDesc end) as TypeXDesc_2,
max(case when grpnum = 2 and seqnum = 1 then XDate end) as XDate_2,
max(case when grpnum = 2 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3,
max(case when grpnum = 3 and seqnum = 1 then typex end) as typex_1,
max(case when grpnum = 3 and seqnum = 1 then TypeXDesc end) as TypeXDesc_3,
max(case when grpnum = 3 and seqnum = 1 then XDate end) as XDate_3,
max(case when grpnum = 3 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3
from (select t.*,
row_number() over (partition by id, typex order by xdate as seqnum,
dense_rank() over (partition by id order by typex) as grpnum
from t
) t
group by id;





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    1 Answer
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    1 Answer
    1






    active

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    active

    oldest

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    active

    oldest

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    0














    You can accomplish this using conditional aggregation. In this case, you can enumerate the rows with within typex/id groups using row_number(). You can enumerate the groups with with typex/id using dense_rank().



    Then, use conditional aggregation:



    select t.id,
    max(case when grpnum = 1 and seqnum = 1 then typex end) as typex_1,
    max(case when grpnum = 1 and seqnum = 1 then TypeXDesc end) as TypeXDesc_1,
    max(case when grpnum = 1 and seqnum = 1 then XDate end) as XDate_1,
    max(case when grpnum = 1 and seqnum = 1 then TypeCodeY end) as TypeCodeY_1,
    max(case when grpnum = 2 and seqnum = 1 then typex end) as typex_12,
    max(case when grpnum = 2 and seqnum = 1 then TypeXDesc end) as TypeXDesc_2,
    max(case when grpnum = 2 and seqnum = 1 then XDate end) as XDate_2,
    max(case when grpnum = 2 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3,
    max(case when grpnum = 3 and seqnum = 1 then typex end) as typex_1,
    max(case when grpnum = 3 and seqnum = 1 then TypeXDesc end) as TypeXDesc_3,
    max(case when grpnum = 3 and seqnum = 1 then XDate end) as XDate_3,
    max(case when grpnum = 3 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3
    from (select t.*,
    row_number() over (partition by id, typex order by xdate as seqnum,
    dense_rank() over (partition by id order by typex) as grpnum
    from t
    ) t
    group by id;





    share|improve this answer



























      0














      You can accomplish this using conditional aggregation. In this case, you can enumerate the rows with within typex/id groups using row_number(). You can enumerate the groups with with typex/id using dense_rank().



      Then, use conditional aggregation:



      select t.id,
      max(case when grpnum = 1 and seqnum = 1 then typex end) as typex_1,
      max(case when grpnum = 1 and seqnum = 1 then TypeXDesc end) as TypeXDesc_1,
      max(case when grpnum = 1 and seqnum = 1 then XDate end) as XDate_1,
      max(case when grpnum = 1 and seqnum = 1 then TypeCodeY end) as TypeCodeY_1,
      max(case when grpnum = 2 and seqnum = 1 then typex end) as typex_12,
      max(case when grpnum = 2 and seqnum = 1 then TypeXDesc end) as TypeXDesc_2,
      max(case when grpnum = 2 and seqnum = 1 then XDate end) as XDate_2,
      max(case when grpnum = 2 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3,
      max(case when grpnum = 3 and seqnum = 1 then typex end) as typex_1,
      max(case when grpnum = 3 and seqnum = 1 then TypeXDesc end) as TypeXDesc_3,
      max(case when grpnum = 3 and seqnum = 1 then XDate end) as XDate_3,
      max(case when grpnum = 3 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3
      from (select t.*,
      row_number() over (partition by id, typex order by xdate as seqnum,
      dense_rank() over (partition by id order by typex) as grpnum
      from t
      ) t
      group by id;





      share|improve this answer

























        0












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        0







        You can accomplish this using conditional aggregation. In this case, you can enumerate the rows with within typex/id groups using row_number(). You can enumerate the groups with with typex/id using dense_rank().



        Then, use conditional aggregation:



        select t.id,
        max(case when grpnum = 1 and seqnum = 1 then typex end) as typex_1,
        max(case when grpnum = 1 and seqnum = 1 then TypeXDesc end) as TypeXDesc_1,
        max(case when grpnum = 1 and seqnum = 1 then XDate end) as XDate_1,
        max(case when grpnum = 1 and seqnum = 1 then TypeCodeY end) as TypeCodeY_1,
        max(case when grpnum = 2 and seqnum = 1 then typex end) as typex_12,
        max(case when grpnum = 2 and seqnum = 1 then TypeXDesc end) as TypeXDesc_2,
        max(case when grpnum = 2 and seqnum = 1 then XDate end) as XDate_2,
        max(case when grpnum = 2 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3,
        max(case when grpnum = 3 and seqnum = 1 then typex end) as typex_1,
        max(case when grpnum = 3 and seqnum = 1 then TypeXDesc end) as TypeXDesc_3,
        max(case when grpnum = 3 and seqnum = 1 then XDate end) as XDate_3,
        max(case when grpnum = 3 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3
        from (select t.*,
        row_number() over (partition by id, typex order by xdate as seqnum,
        dense_rank() over (partition by id order by typex) as grpnum
        from t
        ) t
        group by id;





        share|improve this answer













        You can accomplish this using conditional aggregation. In this case, you can enumerate the rows with within typex/id groups using row_number(). You can enumerate the groups with with typex/id using dense_rank().



        Then, use conditional aggregation:



        select t.id,
        max(case when grpnum = 1 and seqnum = 1 then typex end) as typex_1,
        max(case when grpnum = 1 and seqnum = 1 then TypeXDesc end) as TypeXDesc_1,
        max(case when grpnum = 1 and seqnum = 1 then XDate end) as XDate_1,
        max(case when grpnum = 1 and seqnum = 1 then TypeCodeY end) as TypeCodeY_1,
        max(case when grpnum = 2 and seqnum = 1 then typex end) as typex_12,
        max(case when grpnum = 2 and seqnum = 1 then TypeXDesc end) as TypeXDesc_2,
        max(case when grpnum = 2 and seqnum = 1 then XDate end) as XDate_2,
        max(case when grpnum = 2 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3,
        max(case when grpnum = 3 and seqnum = 1 then typex end) as typex_1,
        max(case when grpnum = 3 and seqnum = 1 then TypeXDesc end) as TypeXDesc_3,
        max(case when grpnum = 3 and seqnum = 1 then XDate end) as XDate_3,
        max(case when grpnum = 3 and seqnum = 1 then TypeCodeY end) as TypeCodeY_3
        from (select t.*,
        row_number() over (partition by id, typex order by xdate as seqnum,
        dense_rank() over (partition by id order by typex) as grpnum
        from t
        ) t
        group by id;






        share|improve this answer












        share|improve this answer



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        answered Nov 15 '18 at 20:19









        Gordon LinoffGordon Linoff

        790k35314418




        790k35314418





























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