JavaScript How to run variables in if and for?

I want to use FOR loop instead, please.

let int1, int1, int3;//... (int4 to int999)
let op1, op;//... (op2 to op999)
if(int1 < 200) 
 op1 = int1;

else 
 op1 = '';

if(int2 < 200) {... (same IF statement for int2 to int999)

Instead, I want this.

for(i = 1; i < 5; i++) 
 let int = [int1, int2, int3, int4];
 let op = [op1, op2, op3, op4];
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = '';
 

alert(op1 + op2 + op3 + op4);

But that doesn't work somebody help.

edited Nov 14 '18 at 21:59

asked Nov 14 '18 at 21:20

Liquidice Slayer

Let input be an array let input = [input1, input2, ...];

– Jonas Wilms
Nov 14 '18 at 21:22

Any time you find yourself using variables with sequential names like that, you almost always should be using an array instead.

– Barmar
Nov 14 '18 at 21:24

I updated the code but it still doesn't work.

– Liquidice Slayer
Nov 14 '18 at 21:55

add a comment |

I want to use FOR loop instead, please.

let int1, int1, int3;//... (int4 to int999)
let op1, op;//... (op2 to op999)
if(int1 < 200) 
 op1 = int1;

else 
 op1 = '';

if(int2 < 200) {... (same IF statement for int2 to int999)

Instead, I want this.

for(i = 1; i < 5; i++) 
 let int = [int1, int2, int3, int4];
 let op = [op1, op2, op3, op4];
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = '';
 

alert(op1 + op2 + op3 + op4);

But that doesn't work somebody help.

edited Nov 14 '18 at 21:59

asked Nov 14 '18 at 21:20

Liquidice Slayer

Let input be an array let input = [input1, input2, ...];

– Jonas Wilms
Nov 14 '18 at 21:22

Any time you find yourself using variables with sequential names like that, you almost always should be using an array instead.

– Barmar
Nov 14 '18 at 21:24

I updated the code but it still doesn't work.

– Liquidice Slayer
Nov 14 '18 at 21:55

add a comment |

I want to use FOR loop instead, please.

let int1, int1, int3;//... (int4 to int999)
let op1, op;//... (op2 to op999)
if(int1 < 200) 
 op1 = int1;

else 
 op1 = '';

if(int2 < 200) {... (same IF statement for int2 to int999)

Instead, I want this.

for(i = 1; i < 5; i++) 
 let int = [int1, int2, int3, int4];
 let op = [op1, op2, op3, op4];
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = '';
 

alert(op1 + op2 + op3 + op4);

But that doesn't work somebody help.

edited Nov 14 '18 at 21:59

asked Nov 14 '18 at 21:20

Liquidice Slayer

I want to use FOR loop instead, please.

let int1, int1, int3;//... (int4 to int999)
let op1, op;//... (op2 to op999)
if(int1 < 200) 
 op1 = int1;

else 
 op1 = '';

if(int2 < 200) {... (same IF statement for int2 to int999)

Instead, I want this.

for(i = 1; i < 5; i++) 
 let int = [int1, int2, int3, int4];
 let op = [op1, op2, op3, op4];
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = '';
 

alert(op1 + op2 + op3 + op4);

But that doesn't work somebody help.

javascript for-loop if-statement

edited Nov 14 '18 at 21:59

asked Nov 14 '18 at 21:20

Liquidice Slayer

edited Nov 14 '18 at 21:59

asked Nov 14 '18 at 21:20

Liquidice Slayer

edited Nov 14 '18 at 21:59

asked Nov 14 '18 at 21:20

Liquidice Slayer

asked Nov 14 '18 at 21:20

Liquidice Slayer

asked Nov 14 '18 at 21:20

Liquidice Slayer

Let input be an array let input = [input1, input2, ...];

– Jonas Wilms
Nov 14 '18 at 21:22

Any time you find yourself using variables with sequential names like that, you almost always should be using an array instead.

– Barmar
Nov 14 '18 at 21:24

I updated the code but it still doesn't work.

– Liquidice Slayer
Nov 14 '18 at 21:55

add a comment |

Let input be an array let input = [input1, input2, ...];

– Jonas Wilms
Nov 14 '18 at 21:22

Any time you find yourself using variables with sequential names like that, you almost always should be using an array instead.

– Barmar
Nov 14 '18 at 21:24

I updated the code but it still doesn't work.

– Liquidice Slayer
Nov 14 '18 at 21:55

Let input be an array let input = [input1, input2, ...];

– Jonas Wilms
Nov 14 '18 at 21:22

Any time you find yourself using variables with sequential names like that, you almost always should be using an array instead.

– Barmar
Nov 14 '18 at 21:24

I updated the code but it still doesn't work.

– Liquidice Slayer
Nov 14 '18 at 21:55

add a comment |

2 Answers
2

active

oldest

votes

Your code should be as follows with an example:

let int = [1, 2, 3, 4];
let op = [999, 999, 999, 999];

for(i = 0; i < 4; i++) 
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = '';
 

alert(op[0] + op[1] + op[2] + op[3]);

Out:

Or in your kind of "symbolic form":

let int = [int1, int2, int3, int4];
let op = [op1, op2, op3, op4];

for(i = 0; i < 4; i++) 
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = 0;
 

alert(op[0] + op[1] + op[2] + op[3]);

edited Nov 15 '18 at 0:40

answered Nov 14 '18 at 23:31

Geeocode

2,4001921

close but op1 isn't being added because its undefined somehow

– Liquidice Slayer
Nov 15 '18 at 0:11

@LiquidiceSlayer to solve on the mystery you have to provide me the actual values of op1 to op4 and int1 to int4 and I answer the rests. Because as you can see with a real example data it works.

– Geeocode
Nov 15 '18 at 0:18

op1-4 can be whatever you want(input: 3, 4, 2, 5 but output 425)

– Liquidice Slayer
Nov 15 '18 at 0:25

if int1-5 is 12345, the code outputs 2345 (op5 is in for some reason while op1 is left out)

– Liquidice Slayer
Nov 15 '18 at 0:28

The problem is solved if int[i] is replaced with int[i-1]. However, that doesn't seem elegant.

– Liquidice Slayer
Nov 15 '18 at 0:32

|
show 4 more comments

Instead of a set of variables, You should use an array instead.
Then, Your code would look something like this:

let input = [input1, input2 ... input999];
let output = ;
for(let i = 0; i < input.length; i++)
 if(input[i]) 
 output[i] = input[i];
 else 
 alert("error")
 
)

edited Nov 15 '18 at 11:31

answered Nov 14 '18 at 21:43

Mateusz

263

I'm only allowed if while and for.

– Liquidice Slayer
Nov 14 '18 at 21:58

Here, updated with simple for loop

– Mateusz
Nov 14 '18 at 22:08

it doesn't work, it says int is undefined.

– Liquidice Slayer
Nov 14 '18 at 23:37

Int doesn't get transfered to op.

– Liquidice Slayer
Nov 15 '18 at 0:01

Have you filled the input array with actual data ?

– Mateusz
Nov 15 '18 at 11:33

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

Your code should be as follows with an example:

let int = [1, 2, 3, 4];
let op = [999, 999, 999, 999];

for(i = 0; i < 4; i++) 
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = '';
 

alert(op[0] + op[1] + op[2] + op[3]);

Out:

Or in your kind of "symbolic form":

let int = [int1, int2, int3, int4];
let op = [op1, op2, op3, op4];

for(i = 0; i < 4; i++) 
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = 0;
 

alert(op[0] + op[1] + op[2] + op[3]);

edited Nov 15 '18 at 0:40

answered Nov 14 '18 at 23:31

Geeocode

2,4001921

close but op1 isn't being added because its undefined somehow

– Liquidice Slayer
Nov 15 '18 at 0:11

@LiquidiceSlayer to solve on the mystery you have to provide me the actual values of op1 to op4 and int1 to int4 and I answer the rests. Because as you can see with a real example data it works.

– Geeocode
Nov 15 '18 at 0:18

op1-4 can be whatever you want(input: 3, 4, 2, 5 but output 425)

– Liquidice Slayer
Nov 15 '18 at 0:25

if int1-5 is 12345, the code outputs 2345 (op5 is in for some reason while op1 is left out)

– Liquidice Slayer
Nov 15 '18 at 0:28

The problem is solved if int[i] is replaced with int[i-1]. However, that doesn't seem elegant.

– Liquidice Slayer
Nov 15 '18 at 0:32

|
show 4 more comments

Your code should be as follows with an example:

let int = [1, 2, 3, 4];
let op = [999, 999, 999, 999];

for(i = 0; i < 4; i++) 
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = '';
 

alert(op[0] + op[1] + op[2] + op[3]);

Out:

Or in your kind of "symbolic form":

let int = [int1, int2, int3, int4];
let op = [op1, op2, op3, op4];

for(i = 0; i < 4; i++) 
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = 0;
 

alert(op[0] + op[1] + op[2] + op[3]);

edited Nov 15 '18 at 0:40

answered Nov 14 '18 at 23:31

Geeocode

2,4001921

close but op1 isn't being added because its undefined somehow

– Liquidice Slayer
Nov 15 '18 at 0:11

@LiquidiceSlayer to solve on the mystery you have to provide me the actual values of op1 to op4 and int1 to int4 and I answer the rests. Because as you can see with a real example data it works.

– Geeocode
Nov 15 '18 at 0:18

op1-4 can be whatever you want(input: 3, 4, 2, 5 but output 425)

– Liquidice Slayer
Nov 15 '18 at 0:25

if int1-5 is 12345, the code outputs 2345 (op5 is in for some reason while op1 is left out)

– Liquidice Slayer
Nov 15 '18 at 0:28

The problem is solved if int[i] is replaced with int[i-1]. However, that doesn't seem elegant.

– Liquidice Slayer
Nov 15 '18 at 0:32

|
show 4 more comments

Your code should be as follows with an example:

let int = [1, 2, 3, 4];
let op = [999, 999, 999, 999];

for(i = 0; i < 4; i++) 
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = '';
 

alert(op[0] + op[1] + op[2] + op[3]);

Out:

Or in your kind of "symbolic form":

let int = [int1, int2, int3, int4];
let op = [op1, op2, op3, op4];

for(i = 0; i < 4; i++) 
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = 0;
 

alert(op[0] + op[1] + op[2] + op[3]);

edited Nov 15 '18 at 0:40

answered Nov 14 '18 at 23:31

Geeocode

2,4001921

Your code should be as follows with an example:

let int = [1, 2, 3, 4];
let op = [999, 999, 999, 999];

for(i = 0; i < 4; i++) 
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = '';
 

alert(op[0] + op[1] + op[2] + op[3]);

Out:

Or in your kind of "symbolic form":

let int = [int1, int2, int3, int4];
let op = [op1, op2, op3, op4];

for(i = 0; i < 4; i++) 
 if(int[i] < 200) 
 op[i] = int[i];
 
 else 
 op[i] = 0;
 

alert(op[0] + op[1] + op[2] + op[3]);

edited Nov 15 '18 at 0:40

answered Nov 14 '18 at 23:31

Geeocode

2,4001921

edited Nov 15 '18 at 0:40

answered Nov 14 '18 at 23:31

Geeocode

2,4001921

answered Nov 14 '18 at 23:31

Geeocode

2,4001921

answered Nov 14 '18 at 23:31

Geeocode

2,4001921

close but op1 isn't being added because its undefined somehow

– Liquidice Slayer
Nov 15 '18 at 0:11

@LiquidiceSlayer to solve on the mystery you have to provide me the actual values of op1 to op4 and int1 to int4 and I answer the rests. Because as you can see with a real example data it works.

– Geeocode
Nov 15 '18 at 0:18

op1-4 can be whatever you want(input: 3, 4, 2, 5 but output 425)

– Liquidice Slayer
Nov 15 '18 at 0:25

if int1-5 is 12345, the code outputs 2345 (op5 is in for some reason while op1 is left out)

– Liquidice Slayer
Nov 15 '18 at 0:28

The problem is solved if int[i] is replaced with int[i-1]. However, that doesn't seem elegant.

– Liquidice Slayer
Nov 15 '18 at 0:32

|
show 4 more comments

close but op1 isn't being added because its undefined somehow

– Liquidice Slayer
Nov 15 '18 at 0:11

@LiquidiceSlayer to solve on the mystery you have to provide me the actual values of op1 to op4 and int1 to int4 and I answer the rests. Because as you can see with a real example data it works.

– Geeocode
Nov 15 '18 at 0:18

op1-4 can be whatever you want(input: 3, 4, 2, 5 but output 425)

– Liquidice Slayer
Nov 15 '18 at 0:25

if int1-5 is 12345, the code outputs 2345 (op5 is in for some reason while op1 is left out)

– Liquidice Slayer
Nov 15 '18 at 0:28

The problem is solved if int[i] is replaced with int[i-1]. However, that doesn't seem elegant.

– Liquidice Slayer
Nov 15 '18 at 0:32

close but op1 isn't being added because its undefined somehow

– Liquidice Slayer
Nov 15 '18 at 0:11

@LiquidiceSlayer to solve on the mystery you have to provide me the actual values of op1 to op4 and int1 to int4 and I answer the rests. Because as you can see with a real example data it works.

– Geeocode
Nov 15 '18 at 0:18

op1-4 can be whatever you want(input: 3, 4, 2, 5 but output 425)

– Liquidice Slayer
Nov 15 '18 at 0:25

if int1-5 is 12345, the code outputs 2345 (op5 is in for some reason while op1 is left out)

– Liquidice Slayer
Nov 15 '18 at 0:28

The problem is solved if int[i] is replaced with int[i-1]. However, that doesn't seem elegant.

– Liquidice Slayer
Nov 15 '18 at 0:32

|
show 4 more comments

Instead of a set of variables, You should use an array instead.
Then, Your code would look something like this:

let input = [input1, input2 ... input999];
let output = ;
for(let i = 0; i < input.length; i++)
 if(input[i]) 
 output[i] = input[i];
 else 
 alert("error")
 
)

edited Nov 15 '18 at 11:31

answered Nov 14 '18 at 21:43

Mateusz

263

I'm only allowed if while and for.

– Liquidice Slayer
Nov 14 '18 at 21:58

Here, updated with simple for loop

– Mateusz
Nov 14 '18 at 22:08

it doesn't work, it says int is undefined.

– Liquidice Slayer
Nov 14 '18 at 23:37

Int doesn't get transfered to op.

– Liquidice Slayer
Nov 15 '18 at 0:01

Have you filled the input array with actual data ?

– Mateusz
Nov 15 '18 at 11:33

add a comment |

Instead of a set of variables, You should use an array instead.
Then, Your code would look something like this:

let input = [input1, input2 ... input999];
let output = ;
for(let i = 0; i < input.length; i++)
 if(input[i]) 
 output[i] = input[i];
 else 
 alert("error")
 
)

edited Nov 15 '18 at 11:31

answered Nov 14 '18 at 21:43

Mateusz

263

I'm only allowed if while and for.

– Liquidice Slayer
Nov 14 '18 at 21:58

Here, updated with simple for loop

– Mateusz
Nov 14 '18 at 22:08

it doesn't work, it says int is undefined.

– Liquidice Slayer
Nov 14 '18 at 23:37

Int doesn't get transfered to op.

– Liquidice Slayer
Nov 15 '18 at 0:01

Have you filled the input array with actual data ?

– Mateusz
Nov 15 '18 at 11:33

add a comment |

Instead of a set of variables, You should use an array instead.
Then, Your code would look something like this:

let input = [input1, input2 ... input999];
let output = ;
for(let i = 0; i < input.length; i++)
 if(input[i]) 
 output[i] = input[i];
 else 
 alert("error")
 
)

edited Nov 15 '18 at 11:31

answered Nov 14 '18 at 21:43

Mateusz

263

Instead of a set of variables, You should use an array instead.
Then, Your code would look something like this:

let input = [input1, input2 ... input999];
let output = ;
for(let i = 0; i < input.length; i++)
 if(input[i]) 
 output[i] = input[i];
 else 
 alert("error")
 
)

edited Nov 15 '18 at 11:31

answered Nov 14 '18 at 21:43

Mateusz

263

edited Nov 15 '18 at 11:31

answered Nov 14 '18 at 21:43

Mateusz

263

answered Nov 14 '18 at 21:43

Mateusz

263

answered Nov 14 '18 at 21:43

Mateusz

263

I'm only allowed if while and for.

– Liquidice Slayer
Nov 14 '18 at 21:58

Here, updated with simple for loop

– Mateusz
Nov 14 '18 at 22:08

it doesn't work, it says int is undefined.

– Liquidice Slayer
Nov 14 '18 at 23:37

Int doesn't get transfered to op.

– Liquidice Slayer
Nov 15 '18 at 0:01

Have you filled the input array with actual data ?

– Mateusz
Nov 15 '18 at 11:33

add a comment |

I'm only allowed if while and for.

– Liquidice Slayer
Nov 14 '18 at 21:58

Here, updated with simple for loop

– Mateusz
Nov 14 '18 at 22:08

it doesn't work, it says int is undefined.

– Liquidice Slayer
Nov 14 '18 at 23:37

Int doesn't get transfered to op.

– Liquidice Slayer
Nov 15 '18 at 0:01

Have you filled the input array with actual data ?

– Mateusz
Nov 15 '18 at 11:33

I'm only allowed if while and for.

– Liquidice Slayer
Nov 14 '18 at 21:58

Here, updated with simple for loop

– Mateusz
Nov 14 '18 at 22:08

it doesn't work, it says int is undefined.

– Liquidice Slayer
Nov 14 '18 at 23:37

Int doesn't get transfered to op.

– Liquidice Slayer
Nov 15 '18 at 0:01

Have you filled the input array with actual data ?

– Mateusz
Nov 15 '18 at 11:33

add a comment |

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