Different results with intermediate prints
I have this function
def getDigits (num) :
check = checkNum(num)
#print('num: '+str(num))
if check is False :
strNum = str(num)
numList = map(toInt, strNum)
#print(list(numList))
squareList = map(getSquareOfDigits, numList)
#print(list(squareList))
sumOfSquares = sum(squareList)
print('sumSqr: '+str(sumOfSquares))
getDigits(sumOfSquares)
else :
return check
And the result of it is:
sumSqr: 4
sumSqr: 16
sumSqr: 37
sumSqr: 58
sumSqr: 89
sumSqr: 9
sumSqr: 81
sumSqr: 65
sumSqr: 61
sumSqr: 37
sumSqr: 58
sumSqr: 89
But if I uncomment all the prints, the result is:
[2]
sumSqr: 0
[3]
sumSqr: 0
ok, I know that the list method change the result, but I want to know it there's a way to print the object variables without changing the result, and not using an intermediate variable.
UPDATE
full example here
python python-3.x
add a comment |
I have this function
def getDigits (num) :
check = checkNum(num)
#print('num: '+str(num))
if check is False :
strNum = str(num)
numList = map(toInt, strNum)
#print(list(numList))
squareList = map(getSquareOfDigits, numList)
#print(list(squareList))
sumOfSquares = sum(squareList)
print('sumSqr: '+str(sumOfSquares))
getDigits(sumOfSquares)
else :
return check
And the result of it is:
sumSqr: 4
sumSqr: 16
sumSqr: 37
sumSqr: 58
sumSqr: 89
sumSqr: 9
sumSqr: 81
sumSqr: 65
sumSqr: 61
sumSqr: 37
sumSqr: 58
sumSqr: 89
But if I uncomment all the prints, the result is:
[2]
sumSqr: 0
[3]
sumSqr: 0
ok, I know that the list method change the result, but I want to know it there's a way to print the object variables without changing the result, and not using an intermediate variable.
UPDATE
full example here
python python-3.x
2
Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.
– GlobalTraveler
Nov 17 '18 at 11:42
1
Traveler is talking about this. How would we know, whatcheckNum, toInt, getSquareOfDigitsdo?
– Mr. T
Nov 17 '18 at 13:07
add a comment |
I have this function
def getDigits (num) :
check = checkNum(num)
#print('num: '+str(num))
if check is False :
strNum = str(num)
numList = map(toInt, strNum)
#print(list(numList))
squareList = map(getSquareOfDigits, numList)
#print(list(squareList))
sumOfSquares = sum(squareList)
print('sumSqr: '+str(sumOfSquares))
getDigits(sumOfSquares)
else :
return check
And the result of it is:
sumSqr: 4
sumSqr: 16
sumSqr: 37
sumSqr: 58
sumSqr: 89
sumSqr: 9
sumSqr: 81
sumSqr: 65
sumSqr: 61
sumSqr: 37
sumSqr: 58
sumSqr: 89
But if I uncomment all the prints, the result is:
[2]
sumSqr: 0
[3]
sumSqr: 0
ok, I know that the list method change the result, but I want to know it there's a way to print the object variables without changing the result, and not using an intermediate variable.
UPDATE
full example here
python python-3.x
I have this function
def getDigits (num) :
check = checkNum(num)
#print('num: '+str(num))
if check is False :
strNum = str(num)
numList = map(toInt, strNum)
#print(list(numList))
squareList = map(getSquareOfDigits, numList)
#print(list(squareList))
sumOfSquares = sum(squareList)
print('sumSqr: '+str(sumOfSquares))
getDigits(sumOfSquares)
else :
return check
And the result of it is:
sumSqr: 4
sumSqr: 16
sumSqr: 37
sumSqr: 58
sumSqr: 89
sumSqr: 9
sumSqr: 81
sumSqr: 65
sumSqr: 61
sumSqr: 37
sumSqr: 58
sumSqr: 89
But if I uncomment all the prints, the result is:
[2]
sumSqr: 0
[3]
sumSqr: 0
ok, I know that the list method change the result, but I want to know it there's a way to print the object variables without changing the result, and not using an intermediate variable.
UPDATE
full example here
python python-3.x
python python-3.x
edited Nov 17 '18 at 19:10
asked Nov 15 '18 at 18:05
user10608741
2
Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.
– GlobalTraveler
Nov 17 '18 at 11:42
1
Traveler is talking about this. How would we know, whatcheckNum, toInt, getSquareOfDigitsdo?
– Mr. T
Nov 17 '18 at 13:07
add a comment |
2
Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.
– GlobalTraveler
Nov 17 '18 at 11:42
1
Traveler is talking about this. How would we know, whatcheckNum, toInt, getSquareOfDigitsdo?
– Mr. T
Nov 17 '18 at 13:07
2
2
Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.
– GlobalTraveler
Nov 17 '18 at 11:42
Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.
– GlobalTraveler
Nov 17 '18 at 11:42
1
1
Traveler is talking about this. How would we know, what
checkNum, toInt, getSquareOfDigits do?– Mr. T
Nov 17 '18 at 13:07
Traveler is talking about this. How would we know, what
checkNum, toInt, getSquareOfDigits do?– Mr. T
Nov 17 '18 at 13:07
add a comment |
1 Answer
1
active
oldest
votes
The point is that numList = map(toInt, strNum) makes numList a iterator. After it has been iterated over once, it's exhausted and will no longer contain any values. The line print(list(numList)) does exactly that by iterating over it, creating a list, printing a string representation of that list and then throwing everything away. If the print-line is commented, the iterator returned by map will generate values; with the print in-place, numList is effectively empty.
To prevent this, use numList = list(map(toInt, strNum)); that way, you have a persistent list-object which you can re-use.
answered Nov 17 '18 at 15:16
user2722968user2722968
2,75411637
ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?
– user10608741
Nov 21 '18 at 17:04
1
I honestly dont understand: Not add it to the code?
– user2722968
Nov 21 '18 at 19:21
in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable
– user10608741
Nov 22 '18 at 16:01
As I said above, usenumList = list(map(toInt, strNum))instead of justnumList = map(...). This will causenumListto be a list-object, not an iterator. You can thenprint(numList)without side-effects.
– user2722968
Nov 22 '18 at 16:25
add a comment |
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The point is that numList = map(toInt, strNum) makes numList a iterator. After it has been iterated over once, it's exhausted and will no longer contain any values. The line print(list(numList)) does exactly that by iterating over it, creating a list, printing a string representation of that list and then throwing everything away. If the print-line is commented, the iterator returned by map will generate values; with the print in-place, numList is effectively empty.
To prevent this, use numList = list(map(toInt, strNum)); that way, you have a persistent list-object which you can re-use.
answered Nov 17 '18 at 15:16
user2722968user2722968
2,75411637
ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?
– user10608741
Nov 21 '18 at 17:04
1
I honestly dont understand: Not add it to the code?
– user2722968
Nov 21 '18 at 19:21
in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable
– user10608741
Nov 22 '18 at 16:01
As I said above, usenumList = list(map(toInt, strNum))instead of justnumList = map(...). This will causenumListto be a list-object, not an iterator. You can thenprint(numList)without side-effects.
– user2722968
Nov 22 '18 at 16:25
add a comment |
The point is that numList = map(toInt, strNum) makes numList a iterator. After it has been iterated over once, it's exhausted and will no longer contain any values. The line print(list(numList)) does exactly that by iterating over it, creating a list, printing a string representation of that list and then throwing everything away. If the print-line is commented, the iterator returned by map will generate values; with the print in-place, numList is effectively empty.
To prevent this, use numList = list(map(toInt, strNum)); that way, you have a persistent list-object which you can re-use.
answered Nov 17 '18 at 15:16
user2722968user2722968
2,75411637
ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?
– user10608741
Nov 21 '18 at 17:04
1
I honestly dont understand: Not add it to the code?
– user2722968
Nov 21 '18 at 19:21
in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable
– user10608741
Nov 22 '18 at 16:01
As I said above, usenumList = list(map(toInt, strNum))instead of justnumList = map(...). This will causenumListto be a list-object, not an iterator. You can thenprint(numList)without side-effects.
– user2722968
Nov 22 '18 at 16:25
add a comment |
The point is that numList = map(toInt, strNum) makes numList a iterator. After it has been iterated over once, it's exhausted and will no longer contain any values. The line print(list(numList)) does exactly that by iterating over it, creating a list, printing a string representation of that list and then throwing everything away. If the print-line is commented, the iterator returned by map will generate values; with the print in-place, numList is effectively empty.
To prevent this, use numList = list(map(toInt, strNum)); that way, you have a persistent list-object which you can re-use.
answered Nov 17 '18 at 15:16
user2722968user2722968
2,75411637
The point is that numList = map(toInt, strNum) makes numList a iterator. After it has been iterated over once, it's exhausted and will no longer contain any values. The line print(list(numList)) does exactly that by iterating over it, creating a list, printing a string representation of that list and then throwing everything away. If the print-line is commented, the iterator returned by map will generate values; with the print in-place, numList is effectively empty.
To prevent this, use numList = list(map(toInt, strNum)); that way, you have a persistent list-object which you can re-use.
answered Nov 17 '18 at 15:16
user2722968user2722968
2,75411637
answered Nov 17 '18 at 15:16
user2722968user2722968
2,75411637
answered Nov 17 '18 at 15:16
user2722968user2722968
2,75411637
answered Nov 17 '18 at 15:16
user2722968user2722968
2,75411637
2,75411637
ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?
– user10608741
Nov 21 '18 at 17:04
1
I honestly dont understand: Not add it to the code?
– user2722968
Nov 21 '18 at 19:21
in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable
– user10608741
Nov 22 '18 at 16:01
As I said above, usenumList = list(map(toInt, strNum))instead of justnumList = map(...). This will causenumListto be a list-object, not an iterator. You can thenprint(numList)without side-effects.
– user2722968
Nov 22 '18 at 16:25
add a comment |
ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?
– user10608741
Nov 21 '18 at 17:04
1
I honestly dont understand: Not add it to the code?
– user2722968
Nov 21 '18 at 19:21
in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable
– user10608741
Nov 22 '18 at 16:01
As I said above, usenumList = list(map(toInt, strNum))instead of justnumList = map(...). This will causenumListto be a list-object, not an iterator. You can thenprint(numList)without side-effects.
– user2722968
Nov 22 '18 at 16:25
ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?
– user10608741
Nov 21 '18 at 17:04
ok, good answer. But, what if I want only to see an intermediate result and not add it to my code?
– user10608741
Nov 21 '18 at 17:04
1
1
I honestly dont understand: Not add it to the code?
– user2722968
Nov 21 '18 at 19:21
I honestly dont understand: Not add it to the code?
– user2722968
Nov 21 '18 at 19:21
in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable
– user10608741
Nov 22 '18 at 16:01
in php if I have doubs about what have after some code, I can do a print of the result and see it, without change the code execution, in JS I can do a console log, and so on... I want to do the same in python, see what I have in the middle of the execution without change the variable
– user10608741
Nov 22 '18 at 16:01
As I said above, use
numList = list(map(toInt, strNum)) instead of just numList = map(...). This will cause numList to be a list-object, not an iterator. You can then print(numList) without side-effects.– user2722968
Nov 22 '18 at 16:25
As I said above, use
numList = list(map(toInt, strNum)) instead of just numList = map(...). This will cause numList to be a list-object, not an iterator. You can then print(numList) without side-effects.– user2722968
Nov 22 '18 at 16:25
add a comment |
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2
Can you provide a complete and verifiable example? I suspect something unintended is going on with your return.
– GlobalTraveler
Nov 17 '18 at 11:42
1
Traveler is talking about this. How would we know, what
checkNum, toInt, getSquareOfDigitsdo?– Mr. T
Nov 17 '18 at 13:07