Can't save Bool in Swift










0















I'm new to Swift (background in C++) and I'm trying to do a very simple thing: save a Bool. It works perfectly if I convert the bool to a string that is either "A" or "B" and then convert back but if I save the bool directly with encode and aDecoder the Bool comes back nil every time. Can't find anything about it on the internet.



As you can see below I simply substitute a string for a Bool and it works.



func boolwontsave(aBool:Bool) -> String 
if aBool
return "A"

return "B"


func encode(with aCoder: NSCoder)

aCoder.encode(name, forKey: PropertyKey.name)
aCoder.encode(number, forKey: PropertyKey.number)
aCoder.encode(boolwontsave(aBool: ispresent), forKey: PropertyKey.present)



required convenience init?(coder aDecoder: NSCoder)

// The name is required. If we cannot decode a name string, the initializer should fail.
guard let name = aDecoder.decodeObject(forKey: PropertyKey.name) as? String else
os_log("Unable to decode the name for a player object.", log: OSLog.default, type: .debug)
return nil


let number = aDecoder.decodeObject(forKey: PropertyKey.number) as? String

guard let localpresent = aDecoder.decodeObject(forKey: PropertyKey.present) as? String else
print("got the nil")
os_log("Unable to decode the ispresent for a player object.", log: OSLog.default, type: .debug)
return nil



// Must call designated initializer.
self.init(name:name, number:number, present: localpresent == "A")




Aren't Bools supposed to save? This seems inelegant.










share|improve this question
























  • What do you mean by saying "save a bool". Also please provide a code where you're trying to retrieve your bool and it return nil.

    – inokey
    Nov 15 '18 at 15:17











  • A bigger question is why you are using NSCoding and NSCoder in Swift. Is there a reason you are not using the Swift Codable features instead?

    – rmaddy
    Nov 15 '18 at 16:26















0















I'm new to Swift (background in C++) and I'm trying to do a very simple thing: save a Bool. It works perfectly if I convert the bool to a string that is either "A" or "B" and then convert back but if I save the bool directly with encode and aDecoder the Bool comes back nil every time. Can't find anything about it on the internet.



As you can see below I simply substitute a string for a Bool and it works.



func boolwontsave(aBool:Bool) -> String 
if aBool
return "A"

return "B"


func encode(with aCoder: NSCoder)

aCoder.encode(name, forKey: PropertyKey.name)
aCoder.encode(number, forKey: PropertyKey.number)
aCoder.encode(boolwontsave(aBool: ispresent), forKey: PropertyKey.present)



required convenience init?(coder aDecoder: NSCoder)

// The name is required. If we cannot decode a name string, the initializer should fail.
guard let name = aDecoder.decodeObject(forKey: PropertyKey.name) as? String else
os_log("Unable to decode the name for a player object.", log: OSLog.default, type: .debug)
return nil


let number = aDecoder.decodeObject(forKey: PropertyKey.number) as? String

guard let localpresent = aDecoder.decodeObject(forKey: PropertyKey.present) as? String else
print("got the nil")
os_log("Unable to decode the ispresent for a player object.", log: OSLog.default, type: .debug)
return nil



// Must call designated initializer.
self.init(name:name, number:number, present: localpresent == "A")




Aren't Bools supposed to save? This seems inelegant.










share|improve this question
























  • What do you mean by saying "save a bool". Also please provide a code where you're trying to retrieve your bool and it return nil.

    – inokey
    Nov 15 '18 at 15:17











  • A bigger question is why you are using NSCoding and NSCoder in Swift. Is there a reason you are not using the Swift Codable features instead?

    – rmaddy
    Nov 15 '18 at 16:26













0












0








0








I'm new to Swift (background in C++) and I'm trying to do a very simple thing: save a Bool. It works perfectly if I convert the bool to a string that is either "A" or "B" and then convert back but if I save the bool directly with encode and aDecoder the Bool comes back nil every time. Can't find anything about it on the internet.



As you can see below I simply substitute a string for a Bool and it works.



func boolwontsave(aBool:Bool) -> String 
if aBool
return "A"

return "B"


func encode(with aCoder: NSCoder)

aCoder.encode(name, forKey: PropertyKey.name)
aCoder.encode(number, forKey: PropertyKey.number)
aCoder.encode(boolwontsave(aBool: ispresent), forKey: PropertyKey.present)



required convenience init?(coder aDecoder: NSCoder)

// The name is required. If we cannot decode a name string, the initializer should fail.
guard let name = aDecoder.decodeObject(forKey: PropertyKey.name) as? String else
os_log("Unable to decode the name for a player object.", log: OSLog.default, type: .debug)
return nil


let number = aDecoder.decodeObject(forKey: PropertyKey.number) as? String

guard let localpresent = aDecoder.decodeObject(forKey: PropertyKey.present) as? String else
print("got the nil")
os_log("Unable to decode the ispresent for a player object.", log: OSLog.default, type: .debug)
return nil



// Must call designated initializer.
self.init(name:name, number:number, present: localpresent == "A")




Aren't Bools supposed to save? This seems inelegant.










share|improve this question
















I'm new to Swift (background in C++) and I'm trying to do a very simple thing: save a Bool. It works perfectly if I convert the bool to a string that is either "A" or "B" and then convert back but if I save the bool directly with encode and aDecoder the Bool comes back nil every time. Can't find anything about it on the internet.



As you can see below I simply substitute a string for a Bool and it works.



func boolwontsave(aBool:Bool) -> String 
if aBool
return "A"

return "B"


func encode(with aCoder: NSCoder)

aCoder.encode(name, forKey: PropertyKey.name)
aCoder.encode(number, forKey: PropertyKey.number)
aCoder.encode(boolwontsave(aBool: ispresent), forKey: PropertyKey.present)



required convenience init?(coder aDecoder: NSCoder)

// The name is required. If we cannot decode a name string, the initializer should fail.
guard let name = aDecoder.decodeObject(forKey: PropertyKey.name) as? String else
os_log("Unable to decode the name for a player object.", log: OSLog.default, type: .debug)
return nil


let number = aDecoder.decodeObject(forKey: PropertyKey.number) as? String

guard let localpresent = aDecoder.decodeObject(forKey: PropertyKey.present) as? String else
print("got the nil")
os_log("Unable to decode the ispresent for a player object.", log: OSLog.default, type: .debug)
return nil



// Must call designated initializer.
self.init(name:name, number:number, present: localpresent == "A")




Aren't Bools supposed to save? This seems inelegant.







swift nscoding






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 16:24









rmaddy

245k27324388




245k27324388










asked Nov 15 '18 at 15:09









Sam HawksworthSam Hawksworth

1




1












  • What do you mean by saying "save a bool". Also please provide a code where you're trying to retrieve your bool and it return nil.

    – inokey
    Nov 15 '18 at 15:17











  • A bigger question is why you are using NSCoding and NSCoder in Swift. Is there a reason you are not using the Swift Codable features instead?

    – rmaddy
    Nov 15 '18 at 16:26

















  • What do you mean by saying "save a bool". Also please provide a code where you're trying to retrieve your bool and it return nil.

    – inokey
    Nov 15 '18 at 15:17











  • A bigger question is why you are using NSCoding and NSCoder in Swift. Is there a reason you are not using the Swift Codable features instead?

    – rmaddy
    Nov 15 '18 at 16:26
















What do you mean by saying "save a bool". Also please provide a code where you're trying to retrieve your bool and it return nil.

– inokey
Nov 15 '18 at 15:17





What do you mean by saying "save a bool". Also please provide a code where you're trying to retrieve your bool and it return nil.

– inokey
Nov 15 '18 at 15:17













A bigger question is why you are using NSCoding and NSCoder in Swift. Is there a reason you are not using the Swift Codable features instead?

– rmaddy
Nov 15 '18 at 16:26





A bigger question is why you are using NSCoding and NSCoder in Swift. Is there a reason you are not using the Swift Codable features instead?

– rmaddy
Nov 15 '18 at 16:26












2 Answers
2






active

oldest

votes


















1














It's very easy to save a Bool if you are using the proper API.



In terms of NSCoding a Bool is not an object, there is a decodeBool(forKey method.



required convenience init?(coder aDecoder: NSCoder) 

// The name is required. If we cannot decode a name string, the initializer should fail.
guard let name = aDecoder.decodeObject(forKey: PropertyKey.name) as? String else
os_log("Unable to decode the name for a player object.", log: OSLog.default, type: .debug)
return nil


let number = aDecoder.decodeObject(forKey: PropertyKey.number) as? String
let localpresent = aDecoder.decodeBool(forKey: PropertyKey.present)

// Must call designated initializer.
self.init(name:name, number:number, present: localpresent)



func encode(with aCoder: NSCoder)
aCoder.encode(name, forKey: PropertyKey.name)
aCoder.encode(number, forKey: PropertyKey.number)
aCoder.encode(ispresent, forKey: PropertyKey.present)



In Swift 4+ I'd prefer the native Codable protocol over constrained NSCoding.




  • NSCoding requires an class inherited from NSObject.


  • Codable can be used for any struct, class and enum which conforms to the protocol.





share|improve this answer























  • Thanks for all the quick answers. I'll convert to using Codable, which I think will also solve my other challenge around saving nested arrays. Thanks again everyone!

    – Sam Hawksworth
    Nov 15 '18 at 18:45


















0














Use decodeBool(forKey key: String) instead of decodeObject(forKey: String)



DecodeBool decodes and returns a boolean value that was previously encoded with encode(_:forKey:) and associated with the string key.



aCoder.encode(true, forKey: PropertyKey.present)
aCoder.decodeBool(forKey: PropertyKey.present)





share|improve this answer






















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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    It's very easy to save a Bool if you are using the proper API.



    In terms of NSCoding a Bool is not an object, there is a decodeBool(forKey method.



    required convenience init?(coder aDecoder: NSCoder) 

    // The name is required. If we cannot decode a name string, the initializer should fail.
    guard let name = aDecoder.decodeObject(forKey: PropertyKey.name) as? String else
    os_log("Unable to decode the name for a player object.", log: OSLog.default, type: .debug)
    return nil


    let number = aDecoder.decodeObject(forKey: PropertyKey.number) as? String
    let localpresent = aDecoder.decodeBool(forKey: PropertyKey.present)

    // Must call designated initializer.
    self.init(name:name, number:number, present: localpresent)



    func encode(with aCoder: NSCoder)
    aCoder.encode(name, forKey: PropertyKey.name)
    aCoder.encode(number, forKey: PropertyKey.number)
    aCoder.encode(ispresent, forKey: PropertyKey.present)



    In Swift 4+ I'd prefer the native Codable protocol over constrained NSCoding.




    • NSCoding requires an class inherited from NSObject.


    • Codable can be used for any struct, class and enum which conforms to the protocol.





    share|improve this answer























    • Thanks for all the quick answers. I'll convert to using Codable, which I think will also solve my other challenge around saving nested arrays. Thanks again everyone!

      – Sam Hawksworth
      Nov 15 '18 at 18:45















    1














    It's very easy to save a Bool if you are using the proper API.



    In terms of NSCoding a Bool is not an object, there is a decodeBool(forKey method.



    required convenience init?(coder aDecoder: NSCoder) 

    // The name is required. If we cannot decode a name string, the initializer should fail.
    guard let name = aDecoder.decodeObject(forKey: PropertyKey.name) as? String else
    os_log("Unable to decode the name for a player object.", log: OSLog.default, type: .debug)
    return nil


    let number = aDecoder.decodeObject(forKey: PropertyKey.number) as? String
    let localpresent = aDecoder.decodeBool(forKey: PropertyKey.present)

    // Must call designated initializer.
    self.init(name:name, number:number, present: localpresent)



    func encode(with aCoder: NSCoder)
    aCoder.encode(name, forKey: PropertyKey.name)
    aCoder.encode(number, forKey: PropertyKey.number)
    aCoder.encode(ispresent, forKey: PropertyKey.present)



    In Swift 4+ I'd prefer the native Codable protocol over constrained NSCoding.




    • NSCoding requires an class inherited from NSObject.


    • Codable can be used for any struct, class and enum which conforms to the protocol.





    share|improve this answer























    • Thanks for all the quick answers. I'll convert to using Codable, which I think will also solve my other challenge around saving nested arrays. Thanks again everyone!

      – Sam Hawksworth
      Nov 15 '18 at 18:45













    1












    1








    1







    It's very easy to save a Bool if you are using the proper API.



    In terms of NSCoding a Bool is not an object, there is a decodeBool(forKey method.



    required convenience init?(coder aDecoder: NSCoder) 

    // The name is required. If we cannot decode a name string, the initializer should fail.
    guard let name = aDecoder.decodeObject(forKey: PropertyKey.name) as? String else
    os_log("Unable to decode the name for a player object.", log: OSLog.default, type: .debug)
    return nil


    let number = aDecoder.decodeObject(forKey: PropertyKey.number) as? String
    let localpresent = aDecoder.decodeBool(forKey: PropertyKey.present)

    // Must call designated initializer.
    self.init(name:name, number:number, present: localpresent)



    func encode(with aCoder: NSCoder)
    aCoder.encode(name, forKey: PropertyKey.name)
    aCoder.encode(number, forKey: PropertyKey.number)
    aCoder.encode(ispresent, forKey: PropertyKey.present)



    In Swift 4+ I'd prefer the native Codable protocol over constrained NSCoding.




    • NSCoding requires an class inherited from NSObject.


    • Codable can be used for any struct, class and enum which conforms to the protocol.





    share|improve this answer













    It's very easy to save a Bool if you are using the proper API.



    In terms of NSCoding a Bool is not an object, there is a decodeBool(forKey method.



    required convenience init?(coder aDecoder: NSCoder) 

    // The name is required. If we cannot decode a name string, the initializer should fail.
    guard let name = aDecoder.decodeObject(forKey: PropertyKey.name) as? String else
    os_log("Unable to decode the name for a player object.", log: OSLog.default, type: .debug)
    return nil


    let number = aDecoder.decodeObject(forKey: PropertyKey.number) as? String
    let localpresent = aDecoder.decodeBool(forKey: PropertyKey.present)

    // Must call designated initializer.
    self.init(name:name, number:number, present: localpresent)



    func encode(with aCoder: NSCoder)
    aCoder.encode(name, forKey: PropertyKey.name)
    aCoder.encode(number, forKey: PropertyKey.number)
    aCoder.encode(ispresent, forKey: PropertyKey.present)



    In Swift 4+ I'd prefer the native Codable protocol over constrained NSCoding.




    • NSCoding requires an class inherited from NSObject.


    • Codable can be used for any struct, class and enum which conforms to the protocol.






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 15 '18 at 15:29









    vadianvadian

    153k17163189




    153k17163189












    • Thanks for all the quick answers. I'll convert to using Codable, which I think will also solve my other challenge around saving nested arrays. Thanks again everyone!

      – Sam Hawksworth
      Nov 15 '18 at 18:45

















    • Thanks for all the quick answers. I'll convert to using Codable, which I think will also solve my other challenge around saving nested arrays. Thanks again everyone!

      – Sam Hawksworth
      Nov 15 '18 at 18:45
















    Thanks for all the quick answers. I'll convert to using Codable, which I think will also solve my other challenge around saving nested arrays. Thanks again everyone!

    – Sam Hawksworth
    Nov 15 '18 at 18:45





    Thanks for all the quick answers. I'll convert to using Codable, which I think will also solve my other challenge around saving nested arrays. Thanks again everyone!

    – Sam Hawksworth
    Nov 15 '18 at 18:45













    0














    Use decodeBool(forKey key: String) instead of decodeObject(forKey: String)



    DecodeBool decodes and returns a boolean value that was previously encoded with encode(_:forKey:) and associated with the string key.



    aCoder.encode(true, forKey: PropertyKey.present)
    aCoder.decodeBool(forKey: PropertyKey.present)





    share|improve this answer



























      0














      Use decodeBool(forKey key: String) instead of decodeObject(forKey: String)



      DecodeBool decodes and returns a boolean value that was previously encoded with encode(_:forKey:) and associated with the string key.



      aCoder.encode(true, forKey: PropertyKey.present)
      aCoder.decodeBool(forKey: PropertyKey.present)





      share|improve this answer

























        0












        0








        0







        Use decodeBool(forKey key: String) instead of decodeObject(forKey: String)



        DecodeBool decodes and returns a boolean value that was previously encoded with encode(_:forKey:) and associated with the string key.



        aCoder.encode(true, forKey: PropertyKey.present)
        aCoder.decodeBool(forKey: PropertyKey.present)





        share|improve this answer













        Use decodeBool(forKey key: String) instead of decodeObject(forKey: String)



        DecodeBool decodes and returns a boolean value that was previously encoded with encode(_:forKey:) and associated with the string key.



        aCoder.encode(true, forKey: PropertyKey.present)
        aCoder.decodeBool(forKey: PropertyKey.present)






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 15 '18 at 15:30









        Raul MantillaRaul Mantilla

        1295




        1295



























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