SAS data format to int format
I have a date column in date format i.e. 05MAY1985. I would like a column with just the year, but in an int format as opposed to a date format.
So I have extracted just the year from the date by:
year = date;
FORMAT year YEAR4.;
Is there a way to get this year as an int? I have tried int(year) but that converts the year into the number of days since 1960.
sas
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I have a date column in date format i.e. 05MAY1985. I would like a column with just the year, but in an int format as opposed to a date format.
So I have extracted just the year from the date by:
year = date;
FORMAT year YEAR4.;
Is there a way to get this year as an int? I have tried int(year) but that converts the year into the number of days since 1960.
sas
add a comment |
I have a date column in date format i.e. 05MAY1985. I would like a column with just the year, but in an int format as opposed to a date format.
So I have extracted just the year from the date by:
year = date;
FORMAT year YEAR4.;
Is there a way to get this year as an int? I have tried int(year) but that converts the year into the number of days since 1960.
sas
I have a date column in date format i.e. 05MAY1985. I would like a column with just the year, but in an int format as opposed to a date format.
So I have extracted just the year from the date by:
year = date;
FORMAT year YEAR4.;
Is there a way to get this year as an int? I have tried int(year) but that converts the year into the number of days since 1960.
sas
sas
asked Nov 14 '18 at 14:03
Will.S89Will.S89
857
857
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1 Answer
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Applying a format does not change the underlying value, just the way it is displayed. Try using the year
function - e.g. year = year(date);
.
This worked! Thank you!
– Will.S89
Nov 14 '18 at 14:35
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Applying a format does not change the underlying value, just the way it is displayed. Try using the year
function - e.g. year = year(date);
.
This worked! Thank you!
– Will.S89
Nov 14 '18 at 14:35
add a comment |
Applying a format does not change the underlying value, just the way it is displayed. Try using the year
function - e.g. year = year(date);
.
This worked! Thank you!
– Will.S89
Nov 14 '18 at 14:35
add a comment |
Applying a format does not change the underlying value, just the way it is displayed. Try using the year
function - e.g. year = year(date);
.
Applying a format does not change the underlying value, just the way it is displayed. Try using the year
function - e.g. year = year(date);
.
answered Nov 14 '18 at 14:08
user667489user667489
7,97721227
7,97721227
This worked! Thank you!
– Will.S89
Nov 14 '18 at 14:35
add a comment |
This worked! Thank you!
– Will.S89
Nov 14 '18 at 14:35
This worked! Thank you!
– Will.S89
Nov 14 '18 at 14:35
This worked! Thank you!
– Will.S89
Nov 14 '18 at 14:35
add a comment |
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