Need to store html date input in JS var
1
I need help with JS and html. I need to store <input type = "date" id = "date"> in JS var. If you try to store the date in simple var and try to print it instead of your chosen date you get printed "undefined" :
$("#printDate").click(function()
var dateVar = ($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
If you try to store the date in the dateVar using new Date() you get printed "Invalid date": 
$("#printDate").click(function()
var dateVar = new Date($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
Thank you for any kind of help!
upd: full page code:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
`<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">`</script>
</head>
<body>
<div id="results"></div>
<input type="date" id = "dateInput">
<button id = "printDate">PrintDate</button>
<script>
$("#printDate").click(function()
var dateVar = new Date($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
</script>
</body>
</html>
javascript html
asked Nov 14 '18 at 13:59
KeetchKeetch
255
add a comment |
1
I need help with JS and html. I need to store <input type = "date" id = "date"> in JS var. If you try to store the date in simple var and try to print it instead of your chosen date you get printed "undefined" :
$("#printDate").click(function()
var dateVar = ($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
If you try to store the date in the dateVar using new Date() you get printed "Invalid date":
$("#printDate").click(function()
var dateVar = new Date($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
Thank you for any kind of help!
upd: full page code:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
`<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">`</script>
</head>
<body>
<div id="results"></div>
<input type="date" id = "dateInput">
<button id = "printDate">PrintDate</button>
<script>
$("#printDate").click(function()
var dateVar = new Date($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
</script>
</body>
</html>
javascript html
asked Nov 14 '18 at 13:59
KeetchKeetch
255
2
Can you please paste full snippet of what's not working for you? jsfiddle.net/92w0yjtk it looks perfectly fine
– Sgoldy
Nov 14 '18 at 14:05
add a comment |
1
1
1
I need help with JS and html. I need to store <input type = "date" id = "date"> in JS var. If you try to store the date in simple var and try to print it instead of your chosen date you get printed "undefined" :
$("#printDate").click(function()
var dateVar = ($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
If you try to store the date in the dateVar using new Date() you get printed "Invalid date":
$("#printDate").click(function()
var dateVar = new Date($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
Thank you for any kind of help!
upd: full page code:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
`<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">`</script>
</head>
<body>
<div id="results"></div>
<input type="date" id = "dateInput">
<button id = "printDate">PrintDate</button>
<script>
$("#printDate").click(function()
var dateVar = new Date($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
</script>
</body>
</html>
javascript html
asked Nov 14 '18 at 13:59
KeetchKeetch
255
I need help with JS and html. I need to store <input type = "date" id = "date"> in JS var. If you try to store the date in simple var and try to print it instead of your chosen date you get printed "undefined" :
$("#printDate").click(function()
var dateVar = ($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
If you try to store the date in the dateVar using new Date() you get printed "Invalid date":
$("#printDate").click(function()
var dateVar = new Date($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
Thank you for any kind of help!
upd: full page code:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
`<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">`</script>
</head>
<body>
<div id="results"></div>
<input type="date" id = "dateInput">
<button id = "printDate">PrintDate</button>
<script>
$("#printDate").click(function()
var dateVar = new Date($("#date").val());
$("#results").append("<p>" + dateVar + "</p>")
);
</script>
</body>
</html>
javascript html
javascript html
asked Nov 14 '18 at 13:59
KeetchKeetch
255
asked Nov 14 '18 at 13:59
KeetchKeetch
255
edited Nov 14 '18 at 14:20
Keetch
asked Nov 14 '18 at 13:59
KeetchKeetch
255
asked Nov 14 '18 at 13:59
KeetchKeetch
255
asked Nov 14 '18 at 13:59
KeetchKeetch
255
255
2
Can you please paste full snippet of what's not working for you? jsfiddle.net/92w0yjtk it looks perfectly fine
– Sgoldy
Nov 14 '18 at 14:05
add a comment |
2
Can you please paste full snippet of what's not working for you? jsfiddle.net/92w0yjtk it looks perfectly fine
– Sgoldy
Nov 14 '18 at 14:05
2
2
Can you please paste full snippet of what's not working for you? jsfiddle.net/92w0yjtk it looks perfectly fine
– Sgoldy
Nov 14 '18 at 14:05
Can you please paste full snippet of what's not working for you? jsfiddle.net/92w0yjtk it looks perfectly fine
– Sgoldy
Nov 14 '18 at 14:05
add a comment |
2 Answers
2
active
oldest
votes
3
$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
); <!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">`</script>
</head>
<body>
<div id="results"></div>
<input type="date" id = "dateInput">
<button id = "printDate">PrintDate</button>
</body>
</html>The only problem with your code is you are targetting wrong id i.e $("#date") instead of $("#dateInput")
answered Nov 14 '18 at 14:23
Zainul AbideenZainul Abideen
1,166315
Such a shame :D
– Keetch
Nov 14 '18 at 14:28
@Keetch don't worry this happens. :P
– Zainul Abideen
Nov 14 '18 at 14:29
add a comment |
0
<div id="results"></div>
<input type="date" id="dateInput">
<button id="printDate">PrintDate</button>
<script>
$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
);
</script>
You have a typing error.
answered Nov 14 '18 at 14:26
LucasLucas
1
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
); <!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">`</script>
</head>
<body>
<div id="results"></div>
<input type="date" id = "dateInput">
<button id = "printDate">PrintDate</button>
</body>
</html>The only problem with your code is you are targetting wrong id i.e $("#date") instead of $("#dateInput")
answered Nov 14 '18 at 14:23
Zainul AbideenZainul Abideen
1,166315
Such a shame :D
– Keetch
Nov 14 '18 at 14:28
@Keetch don't worry this happens. :P
– Zainul Abideen
Nov 14 '18 at 14:29
add a comment |
3
$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
); <!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">`</script>
</head>
<body>
<div id="results"></div>
<input type="date" id = "dateInput">
<button id = "printDate">PrintDate</button>
</body>
</html>The only problem with your code is you are targetting wrong id i.e $("#date") instead of $("#dateInput")
answered Nov 14 '18 at 14:23
Zainul AbideenZainul Abideen
1,166315
Such a shame :D
– Keetch
Nov 14 '18 at 14:28
@Keetch don't worry this happens. :P
– Zainul Abideen
Nov 14 '18 at 14:29
add a comment |
3
3
3
$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
); <!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">`</script>
</head>
<body>
<div id="results"></div>
<input type="date" id = "dateInput">
<button id = "printDate">PrintDate</button>
</body>
</html>The only problem with your code is you are targetting wrong id i.e $("#date") instead of $("#dateInput")
answered Nov 14 '18 at 14:23
Zainul AbideenZainul Abideen
1,166315
$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
); <!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">`</script>
</head>
<body>
<div id="results"></div>
<input type="date" id = "dateInput">
<button id = "printDate">PrintDate</button>
</body>
</html>The only problem with your code is you are targetting wrong id i.e $("#date") instead of $("#dateInput")
$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
); <!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">`</script>
</head>
<body>
<div id="results"></div>
<input type="date" id = "dateInput">
<button id = "printDate">PrintDate</button>
</body>
</html>$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
); <!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js">`</script>
</head>
<body>
<div id="results"></div>
<input type="date" id = "dateInput">
<button id = "printDate">PrintDate</button>
</body>
</html>answered Nov 14 '18 at 14:23
Zainul AbideenZainul Abideen
1,166315
answered Nov 14 '18 at 14:23
Zainul AbideenZainul Abideen
1,166315
answered Nov 14 '18 at 14:23
Zainul AbideenZainul Abideen
1,166315
answered Nov 14 '18 at 14:23
Zainul AbideenZainul Abideen
1,166315
1,166315
Such a shame :D
– Keetch
Nov 14 '18 at 14:28
@Keetch don't worry this happens. :P
– Zainul Abideen
Nov 14 '18 at 14:29
add a comment |
Such a shame :D
– Keetch
Nov 14 '18 at 14:28
@Keetch don't worry this happens. :P
– Zainul Abideen
Nov 14 '18 at 14:29
Such a shame :D
– Keetch
Nov 14 '18 at 14:28
Such a shame :D
– Keetch
Nov 14 '18 at 14:28
@Keetch don't worry this happens. :P
– Zainul Abideen
Nov 14 '18 at 14:29
@Keetch don't worry this happens. :P
– Zainul Abideen
Nov 14 '18 at 14:29
add a comment |
0
<div id="results"></div>
<input type="date" id="dateInput">
<button id="printDate">PrintDate</button>
<script>
$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
);
</script>
You have a typing error.
answered Nov 14 '18 at 14:26
LucasLucas
1
add a comment |
0
<div id="results"></div>
<input type="date" id="dateInput">
<button id="printDate">PrintDate</button>
<script>
$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
);
</script>
You have a typing error.
answered Nov 14 '18 at 14:26
LucasLucas
1
add a comment |
0
0
0
<div id="results"></div>
<input type="date" id="dateInput">
<button id="printDate">PrintDate</button>
<script>
$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
);
</script>
You have a typing error.
answered Nov 14 '18 at 14:26
LucasLucas
1
<div id="results"></div>
<input type="date" id="dateInput">
<button id="printDate">PrintDate</button>
<script>
$("#printDate").click(function()
var dateVar = new Date($("#dateInput").val());
$("#results").append("<p>" + dateVar + "</p>")
);
</script>
You have a typing error.
answered Nov 14 '18 at 14:26
LucasLucas
1
answered Nov 14 '18 at 14:26
LucasLucas
1
answered Nov 14 '18 at 14:26
LucasLucas
1
answered Nov 14 '18 at 14:26
LucasLucas
1
1
add a comment |
add a comment |
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2
Can you please paste full snippet of what's not working for you? jsfiddle.net/92w0yjtk it looks perfectly fine
– Sgoldy
Nov 14 '18 at 14:05