Bulk rename files from csv files r
I am struggling to find a clear answer to by problem.
I have a dataframe that has a file path and a filename.
data.frame': 6 obs. of 2 variables: $ Path : Factor w/ 97 levels "J:\GBD2017\China\Splitweekly\281_2010_10.pdf",..: 1 2 3 4 5 6 $ Filename: Factor w/ 97 levels "1000095452.pdf",..: 97 1 2 3 4 5
I want to rename each filepath J:\GBD2017\China\Splitweekly\281_2010_10.pdf so the last xx_xx_xx.pdf is replaced with the value in the filename column.
eg J:\GBD2017\China\Splitweekly\281_2010_10.pdf would become J:\GBD2017\China\Splitweekly\1000095452.pdf.
I am going to have hundreds of files so any method needs to be efficient.
Dput:
structure(list(Path = structure(1:6, .Label = c("J:\GBD2017\China \Splitweekly\281_2010_10.pdf",
`"J:\GBD2017\China\Splitweekly\282_2010_11.pdf", "J:\GBD2017\China \Splitweekly\283_2010_12.pdf"), class = "factor"), Filename = `structure(c(97L, 1L, 2L, 3L, L, 5L), .Label = c("1000095452.pdf","1000095453.pdf", "1000095454.pdf"), class = "factor")), .Names = c("Path", "Filename"), row.names = c(NA, 6L), class = "data.frame")
r file bulk renaming
asked Nov 14 '18 at 14:02
BohnstonBohnston
278
add a comment |
I am struggling to find a clear answer to by problem.
I have a dataframe that has a file path and a filename.
data.frame': 6 obs. of 2 variables: $ Path : Factor w/ 97 levels "J:\GBD2017\China\Splitweekly\281_2010_10.pdf",..: 1 2 3 4 5 6 $ Filename: Factor w/ 97 levels "1000095452.pdf",..: 97 1 2 3 4 5
I want to rename each filepath J:\GBD2017\China\Splitweekly\281_2010_10.pdf so the last xx_xx_xx.pdf is replaced with the value in the filename column.
eg J:\GBD2017\China\Splitweekly\281_2010_10.pdf would become J:\GBD2017\China\Splitweekly\1000095452.pdf.
I am going to have hundreds of files so any method needs to be efficient.
Dput:
structure(list(Path = structure(1:6, .Label = c("J:\GBD2017\China \Splitweekly\281_2010_10.pdf",
`"J:\GBD2017\China\Splitweekly\282_2010_11.pdf", "J:\GBD2017\China \Splitweekly\283_2010_12.pdf"), class = "factor"), Filename = `structure(c(97L, 1L, 2L, 3L, L, 5L), .Label = c("1000095452.pdf","1000095453.pdf", "1000095454.pdf"), class = "factor")), .Names = c("Path", "Filename"), row.names = c(NA, 6L), class = "data.frame")
r file bulk renaming
asked Nov 14 '18 at 14:02
BohnstonBohnston
278
?dirname;?basename;?file.path
– hrbrmstr
Nov 14 '18 at 14:08
Im not sure what you are saying
– Bohnston
Nov 14 '18 at 14:12
I'm suggesting you read the documentation for those three functions as they're all you'll need to accomplish your goal.
– hrbrmstr
Nov 14 '18 at 14:22
add a comment |
I am struggling to find a clear answer to by problem.
I have a dataframe that has a file path and a filename.
data.frame': 6 obs. of 2 variables: $ Path : Factor w/ 97 levels "J:\GBD2017\China\Splitweekly\281_2010_10.pdf",..: 1 2 3 4 5 6 $ Filename: Factor w/ 97 levels "1000095452.pdf",..: 97 1 2 3 4 5
I want to rename each filepath J:\GBD2017\China\Splitweekly\281_2010_10.pdf so the last xx_xx_xx.pdf is replaced with the value in the filename column.
eg J:\GBD2017\China\Splitweekly\281_2010_10.pdf would become J:\GBD2017\China\Splitweekly\1000095452.pdf.
I am going to have hundreds of files so any method needs to be efficient.
Dput:
structure(list(Path = structure(1:6, .Label = c("J:\GBD2017\China \Splitweekly\281_2010_10.pdf",
`"J:\GBD2017\China\Splitweekly\282_2010_11.pdf", "J:\GBD2017\China \Splitweekly\283_2010_12.pdf"), class = "factor"), Filename = `structure(c(97L, 1L, 2L, 3L, L, 5L), .Label = c("1000095452.pdf","1000095453.pdf", "1000095454.pdf"), class = "factor")), .Names = c("Path", "Filename"), row.names = c(NA, 6L), class = "data.frame")
r file bulk renaming
asked Nov 14 '18 at 14:02
BohnstonBohnston
278
I am struggling to find a clear answer to by problem.
I have a dataframe that has a file path and a filename.
data.frame': 6 obs. of 2 variables: $ Path : Factor w/ 97 levels "J:\GBD2017\China\Splitweekly\281_2010_10.pdf",..: 1 2 3 4 5 6 $ Filename: Factor w/ 97 levels "1000095452.pdf",..: 97 1 2 3 4 5
I want to rename each filepath J:\GBD2017\China\Splitweekly\281_2010_10.pdf so the last xx_xx_xx.pdf is replaced with the value in the filename column.
eg J:\GBD2017\China\Splitweekly\281_2010_10.pdf would become J:\GBD2017\China\Splitweekly\1000095452.pdf.
I am going to have hundreds of files so any method needs to be efficient.
Dput:
structure(list(Path = structure(1:6, .Label = c("J:\GBD2017\China \Splitweekly\281_2010_10.pdf",
`"J:\GBD2017\China\Splitweekly\282_2010_11.pdf", "J:\GBD2017\China \Splitweekly\283_2010_12.pdf"), class = "factor"), Filename = `structure(c(97L, 1L, 2L, 3L, L, 5L), .Label = c("1000095452.pdf","1000095453.pdf", "1000095454.pdf"), class = "factor")), .Names = c("Path", "Filename"), row.names = c(NA, 6L), class = "data.frame")
r file bulk renaming
r file bulk renaming
asked Nov 14 '18 at 14:02
BohnstonBohnston
278
asked Nov 14 '18 at 14:02
BohnstonBohnston
278
asked Nov 14 '18 at 14:02
BohnstonBohnston
278
asked Nov 14 '18 at 14:02
BohnstonBohnston
278
asked Nov 14 '18 at 14:02
BohnstonBohnston
278
278
?dirname;?basename;?file.path
– hrbrmstr
Nov 14 '18 at 14:08
Im not sure what you are saying
– Bohnston
Nov 14 '18 at 14:12
I'm suggesting you read the documentation for those three functions as they're all you'll need to accomplish your goal.
– hrbrmstr
Nov 14 '18 at 14:22
add a comment |
?dirname;?basename;?file.path
– hrbrmstr
Nov 14 '18 at 14:08
Im not sure what you are saying
– Bohnston
Nov 14 '18 at 14:12
I'm suggesting you read the documentation for those three functions as they're all you'll need to accomplish your goal.
– hrbrmstr
Nov 14 '18 at 14:22
?dirname ; ?basename ; ?file.path– hrbrmstr
Nov 14 '18 at 14:08
?dirname ; ?basename ; ?file.path– hrbrmstr
Nov 14 '18 at 14:08
Im not sure what you are saying
– Bohnston
Nov 14 '18 at 14:12
Im not sure what you are saying
– Bohnston
Nov 14 '18 at 14:12
I'm suggesting you read the documentation for those three functions as they're all you'll need to accomplish your goal.
– hrbrmstr
Nov 14 '18 at 14:22
I'm suggesting you read the documentation for those three functions as they're all you'll need to accomplish your goal.
– hrbrmstr
Nov 14 '18 at 14:22
add a comment |
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?dirname;?basename;?file.path– hrbrmstr
Nov 14 '18 at 14:08
Im not sure what you are saying
– Bohnston
Nov 14 '18 at 14:12
I'm suggesting you read the documentation for those three functions as they're all you'll need to accomplish your goal.
– hrbrmstr
Nov 14 '18 at 14:22