How deserialize [JsonExtensionData] Dictionary with casting










0















[JsonExtensionData] allows you to do is to serialize elements of a JSON document which does not have matching properties on the destination object to the dictionary which is decorated with the [JsonExtensionData] attribute.



How to create a dictionary of objects cast into the appropriate type??



For example:



var json = "rn "sampleClass": "name":"Name" , 
"sampleOtherClass": "name":"OtherName" ,rn "X": "Jan"rn";


and



var result =JsonConvert.DeserializeObject<Test>(json);


and



public class Test

public string X get; set;

[JsonExtensionData]
public Dictionary<string, object> Y get; set;



The dictionary should contain such elements:



Dictionary<string, object> students = new Dictionary<string, object>()

"sampleClass", new ClassName Name="MyName" ,
"sampleOtherClass", new SampleOtherClass Name="MyName"
;


Which means that for node sampleClass we want to create object SampleClass and next to add the dictionary Y.



Currently, the value in the DictionaryEntry is a string e.g. name: "Name"



The source:
https://dotnetfiddle.net/mhU6ME



Update:



Now I used the below approach to deserialize, but when I want to have one [JsonExtensionData] Dictionary to deserialize/serialize it brings problems to have two collections.



public class Class1

public string Code get; set;

public string Name get; set;

public bool IsActive get; set;

[JsonExtensionData]
public Dictionary<string, JToken> _JTokenProperty get; set;

public Dictionary<string, PropertiesClass> Properties1 get; set; = new Dictionary<string, PropertiesClass>();










share|improve this question
























  • Why do you have a data-structure storing instances that seem to have nothing in common in a single common map? But anyway: what is your problem exactly? What results do you get?

    – HimBromBeere
    Nov 14 '18 at 9:47












  • The reason is that the rest api returns user-defined objects.

    – PiotrN
    Nov 14 '18 at 9:50











  • Currently, the key and the string as value are created "key", "name: "Name"

    – PiotrN
    Nov 14 '18 at 9:55











  • I think you have to write your custom serializer and within that you hjave to tell Json.net of what type those properties are. I have made a quick search and it seems that here you find a simple example on how this may work. I have not testet this yet. stackoverflow.com/a/40439958/9809950

    – Josef Biehler
    Nov 14 '18 at 9:59











  • Possible duplicate of How to parse not fully corresponding json

    – Adriani6
    Nov 14 '18 at 10:02















0















[JsonExtensionData] allows you to do is to serialize elements of a JSON document which does not have matching properties on the destination object to the dictionary which is decorated with the [JsonExtensionData] attribute.



How to create a dictionary of objects cast into the appropriate type??



For example:



var json = "rn "sampleClass": "name":"Name" , 
"sampleOtherClass": "name":"OtherName" ,rn "X": "Jan"rn";


and



var result =JsonConvert.DeserializeObject<Test>(json);


and



public class Test

public string X get; set;

[JsonExtensionData]
public Dictionary<string, object> Y get; set;



The dictionary should contain such elements:



Dictionary<string, object> students = new Dictionary<string, object>()

"sampleClass", new ClassName Name="MyName" ,
"sampleOtherClass", new SampleOtherClass Name="MyName"
;


Which means that for node sampleClass we want to create object SampleClass and next to add the dictionary Y.



Currently, the value in the DictionaryEntry is a string e.g. name: "Name"



The source:
https://dotnetfiddle.net/mhU6ME



Update:



Now I used the below approach to deserialize, but when I want to have one [JsonExtensionData] Dictionary to deserialize/serialize it brings problems to have two collections.



public class Class1

public string Code get; set;

public string Name get; set;

public bool IsActive get; set;

[JsonExtensionData]
public Dictionary<string, JToken> _JTokenProperty get; set;

public Dictionary<string, PropertiesClass> Properties1 get; set; = new Dictionary<string, PropertiesClass>();










share|improve this question
























  • Why do you have a data-structure storing instances that seem to have nothing in common in a single common map? But anyway: what is your problem exactly? What results do you get?

    – HimBromBeere
    Nov 14 '18 at 9:47












  • The reason is that the rest api returns user-defined objects.

    – PiotrN
    Nov 14 '18 at 9:50











  • Currently, the key and the string as value are created "key", "name: "Name"

    – PiotrN
    Nov 14 '18 at 9:55











  • I think you have to write your custom serializer and within that you hjave to tell Json.net of what type those properties are. I have made a quick search and it seems that here you find a simple example on how this may work. I have not testet this yet. stackoverflow.com/a/40439958/9809950

    – Josef Biehler
    Nov 14 '18 at 9:59











  • Possible duplicate of How to parse not fully corresponding json

    – Adriani6
    Nov 14 '18 at 10:02













0












0








0








[JsonExtensionData] allows you to do is to serialize elements of a JSON document which does not have matching properties on the destination object to the dictionary which is decorated with the [JsonExtensionData] attribute.



How to create a dictionary of objects cast into the appropriate type??



For example:



var json = "rn "sampleClass": "name":"Name" , 
"sampleOtherClass": "name":"OtherName" ,rn "X": "Jan"rn";


and



var result =JsonConvert.DeserializeObject<Test>(json);


and



public class Test

public string X get; set;

[JsonExtensionData]
public Dictionary<string, object> Y get; set;



The dictionary should contain such elements:



Dictionary<string, object> students = new Dictionary<string, object>()

"sampleClass", new ClassName Name="MyName" ,
"sampleOtherClass", new SampleOtherClass Name="MyName"
;


Which means that for node sampleClass we want to create object SampleClass and next to add the dictionary Y.



Currently, the value in the DictionaryEntry is a string e.g. name: "Name"



The source:
https://dotnetfiddle.net/mhU6ME



Update:



Now I used the below approach to deserialize, but when I want to have one [JsonExtensionData] Dictionary to deserialize/serialize it brings problems to have two collections.



public class Class1

public string Code get; set;

public string Name get; set;

public bool IsActive get; set;

[JsonExtensionData]
public Dictionary<string, JToken> _JTokenProperty get; set;

public Dictionary<string, PropertiesClass> Properties1 get; set; = new Dictionary<string, PropertiesClass>();










share|improve this question
















[JsonExtensionData] allows you to do is to serialize elements of a JSON document which does not have matching properties on the destination object to the dictionary which is decorated with the [JsonExtensionData] attribute.



How to create a dictionary of objects cast into the appropriate type??



For example:



var json = "rn "sampleClass": "name":"Name" , 
"sampleOtherClass": "name":"OtherName" ,rn "X": "Jan"rn";


and



var result =JsonConvert.DeserializeObject<Test>(json);


and



public class Test

public string X get; set;

[JsonExtensionData]
public Dictionary<string, object> Y get; set;



The dictionary should contain such elements:



Dictionary<string, object> students = new Dictionary<string, object>()

"sampleClass", new ClassName Name="MyName" ,
"sampleOtherClass", new SampleOtherClass Name="MyName"
;


Which means that for node sampleClass we want to create object SampleClass and next to add the dictionary Y.



Currently, the value in the DictionaryEntry is a string e.g. name: "Name"



The source:
https://dotnetfiddle.net/mhU6ME



Update:



Now I used the below approach to deserialize, but when I want to have one [JsonExtensionData] Dictionary to deserialize/serialize it brings problems to have two collections.



public class Class1

public string Code get; set;

public string Name get; set;

public bool IsActive get; set;

[JsonExtensionData]
public Dictionary<string, JToken> _JTokenProperty get; set;

public Dictionary<string, PropertiesClass> Properties1 get; set; = new Dictionary<string, PropertiesClass>();







c# json.net






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 15 '18 at 10:30







PiotrN

















asked Nov 14 '18 at 9:45









PiotrNPiotrN

11




11












  • Why do you have a data-structure storing instances that seem to have nothing in common in a single common map? But anyway: what is your problem exactly? What results do you get?

    – HimBromBeere
    Nov 14 '18 at 9:47












  • The reason is that the rest api returns user-defined objects.

    – PiotrN
    Nov 14 '18 at 9:50











  • Currently, the key and the string as value are created "key", "name: "Name"

    – PiotrN
    Nov 14 '18 at 9:55











  • I think you have to write your custom serializer and within that you hjave to tell Json.net of what type those properties are. I have made a quick search and it seems that here you find a simple example on how this may work. I have not testet this yet. stackoverflow.com/a/40439958/9809950

    – Josef Biehler
    Nov 14 '18 at 9:59











  • Possible duplicate of How to parse not fully corresponding json

    – Adriani6
    Nov 14 '18 at 10:02

















  • Why do you have a data-structure storing instances that seem to have nothing in common in a single common map? But anyway: what is your problem exactly? What results do you get?

    – HimBromBeere
    Nov 14 '18 at 9:47












  • The reason is that the rest api returns user-defined objects.

    – PiotrN
    Nov 14 '18 at 9:50











  • Currently, the key and the string as value are created "key", "name: "Name"

    – PiotrN
    Nov 14 '18 at 9:55











  • I think you have to write your custom serializer and within that you hjave to tell Json.net of what type those properties are. I have made a quick search and it seems that here you find a simple example on how this may work. I have not testet this yet. stackoverflow.com/a/40439958/9809950

    – Josef Biehler
    Nov 14 '18 at 9:59











  • Possible duplicate of How to parse not fully corresponding json

    – Adriani6
    Nov 14 '18 at 10:02
















Why do you have a data-structure storing instances that seem to have nothing in common in a single common map? But anyway: what is your problem exactly? What results do you get?

– HimBromBeere
Nov 14 '18 at 9:47






Why do you have a data-structure storing instances that seem to have nothing in common in a single common map? But anyway: what is your problem exactly? What results do you get?

– HimBromBeere
Nov 14 '18 at 9:47














The reason is that the rest api returns user-defined objects.

– PiotrN
Nov 14 '18 at 9:50





The reason is that the rest api returns user-defined objects.

– PiotrN
Nov 14 '18 at 9:50













Currently, the key and the string as value are created "key", "name: "Name"

– PiotrN
Nov 14 '18 at 9:55





Currently, the key and the string as value are created "key", "name: "Name"

– PiotrN
Nov 14 '18 at 9:55













I think you have to write your custom serializer and within that you hjave to tell Json.net of what type those properties are. I have made a quick search and it seems that here you find a simple example on how this may work. I have not testet this yet. stackoverflow.com/a/40439958/9809950

– Josef Biehler
Nov 14 '18 at 9:59





I think you have to write your custom serializer and within that you hjave to tell Json.net of what type those properties are. I have made a quick search and it seems that here you find a simple example on how this may work. I have not testet this yet. stackoverflow.com/a/40439958/9809950

– Josef Biehler
Nov 14 '18 at 9:59













Possible duplicate of How to parse not fully corresponding json

– Adriani6
Nov 14 '18 at 10:02





Possible duplicate of How to parse not fully corresponding json

– Adriani6
Nov 14 '18 at 10:02












2 Answers
2






active

oldest

votes


















0














how about if you try the dynamic instance instead of object.



public class Test

public string X get; set;

[JsonExtensionData]
public Dictionary<string, dynamic> Y get; set;






share|improve this answer























  • In my opinion that does not give us possibility to cast.

    – PiotrN
    Nov 14 '18 at 10:16


















0














Json.Net has the ability to (de)serialize objects specifying the actual type of the object.



In the serialization process a property "$type" for storing the Type is added to the resulting JSON. Then in deserialization this property is checked to obtain the actual Type.
Of course it must be a Type which inherits/implements the declared Type in you class.
Since you're using object, you shouldn't have problems.



You can activate this feature by setting the TypeNameHandling property of the JsonSerializerSettings to Auto, which activates this behaviour when the object type is different from the declared type.



https://www.newtonsoft.com/json/help/html/SerializationSettings.htm#TypeNameHandling






share|improve this answer























  • However this is not my restful service that's why it does not return $type and I do not have the option of adding $type

    – PiotrN
    Nov 14 '18 at 11:52






  • 1





    How, then, the program is supposed to decide which is the correct type? If you need to make assumptions based on things such as the name of the property (the key of the dictionary) or the content of the object, I think the only way is to write your own JsonConverter and place your custom logic into the ReadJson method.

    – Matteo Melli
    Nov 14 '18 at 15:05












  • Now I used [OnDeserialized] private void OnDeserialized(StreamingContext context)

    – PiotrN
    Nov 14 '18 at 15:38










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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














how about if you try the dynamic instance instead of object.



public class Test

public string X get; set;

[JsonExtensionData]
public Dictionary<string, dynamic> Y get; set;






share|improve this answer























  • In my opinion that does not give us possibility to cast.

    – PiotrN
    Nov 14 '18 at 10:16















0














how about if you try the dynamic instance instead of object.



public class Test

public string X get; set;

[JsonExtensionData]
public Dictionary<string, dynamic> Y get; set;






share|improve this answer























  • In my opinion that does not give us possibility to cast.

    – PiotrN
    Nov 14 '18 at 10:16













0












0








0







how about if you try the dynamic instance instead of object.



public class Test

public string X get; set;

[JsonExtensionData]
public Dictionary<string, dynamic> Y get; set;






share|improve this answer













how about if you try the dynamic instance instead of object.



public class Test

public string X get; set;

[JsonExtensionData]
public Dictionary<string, dynamic> Y get; set;







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 14 '18 at 10:08









zetawarszetawars

442212




442212












  • In my opinion that does not give us possibility to cast.

    – PiotrN
    Nov 14 '18 at 10:16

















  • In my opinion that does not give us possibility to cast.

    – PiotrN
    Nov 14 '18 at 10:16
















In my opinion that does not give us possibility to cast.

– PiotrN
Nov 14 '18 at 10:16





In my opinion that does not give us possibility to cast.

– PiotrN
Nov 14 '18 at 10:16













0














Json.Net has the ability to (de)serialize objects specifying the actual type of the object.



In the serialization process a property "$type" for storing the Type is added to the resulting JSON. Then in deserialization this property is checked to obtain the actual Type.
Of course it must be a Type which inherits/implements the declared Type in you class.
Since you're using object, you shouldn't have problems.



You can activate this feature by setting the TypeNameHandling property of the JsonSerializerSettings to Auto, which activates this behaviour when the object type is different from the declared type.



https://www.newtonsoft.com/json/help/html/SerializationSettings.htm#TypeNameHandling






share|improve this answer























  • However this is not my restful service that's why it does not return $type and I do not have the option of adding $type

    – PiotrN
    Nov 14 '18 at 11:52






  • 1





    How, then, the program is supposed to decide which is the correct type? If you need to make assumptions based on things such as the name of the property (the key of the dictionary) or the content of the object, I think the only way is to write your own JsonConverter and place your custom logic into the ReadJson method.

    – Matteo Melli
    Nov 14 '18 at 15:05












  • Now I used [OnDeserialized] private void OnDeserialized(StreamingContext context)

    – PiotrN
    Nov 14 '18 at 15:38















0














Json.Net has the ability to (de)serialize objects specifying the actual type of the object.



In the serialization process a property "$type" for storing the Type is added to the resulting JSON. Then in deserialization this property is checked to obtain the actual Type.
Of course it must be a Type which inherits/implements the declared Type in you class.
Since you're using object, you shouldn't have problems.



You can activate this feature by setting the TypeNameHandling property of the JsonSerializerSettings to Auto, which activates this behaviour when the object type is different from the declared type.



https://www.newtonsoft.com/json/help/html/SerializationSettings.htm#TypeNameHandling






share|improve this answer























  • However this is not my restful service that's why it does not return $type and I do not have the option of adding $type

    – PiotrN
    Nov 14 '18 at 11:52






  • 1





    How, then, the program is supposed to decide which is the correct type? If you need to make assumptions based on things such as the name of the property (the key of the dictionary) or the content of the object, I think the only way is to write your own JsonConverter and place your custom logic into the ReadJson method.

    – Matteo Melli
    Nov 14 '18 at 15:05












  • Now I used [OnDeserialized] private void OnDeserialized(StreamingContext context)

    – PiotrN
    Nov 14 '18 at 15:38













0












0








0







Json.Net has the ability to (de)serialize objects specifying the actual type of the object.



In the serialization process a property "$type" for storing the Type is added to the resulting JSON. Then in deserialization this property is checked to obtain the actual Type.
Of course it must be a Type which inherits/implements the declared Type in you class.
Since you're using object, you shouldn't have problems.



You can activate this feature by setting the TypeNameHandling property of the JsonSerializerSettings to Auto, which activates this behaviour when the object type is different from the declared type.



https://www.newtonsoft.com/json/help/html/SerializationSettings.htm#TypeNameHandling






share|improve this answer













Json.Net has the ability to (de)serialize objects specifying the actual type of the object.



In the serialization process a property "$type" for storing the Type is added to the resulting JSON. Then in deserialization this property is checked to obtain the actual Type.
Of course it must be a Type which inherits/implements the declared Type in you class.
Since you're using object, you shouldn't have problems.



You can activate this feature by setting the TypeNameHandling property of the JsonSerializerSettings to Auto, which activates this behaviour when the object type is different from the declared type.



https://www.newtonsoft.com/json/help/html/SerializationSettings.htm#TypeNameHandling







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 14 '18 at 10:24









Matteo MelliMatteo Melli

494




494












  • However this is not my restful service that's why it does not return $type and I do not have the option of adding $type

    – PiotrN
    Nov 14 '18 at 11:52






  • 1





    How, then, the program is supposed to decide which is the correct type? If you need to make assumptions based on things such as the name of the property (the key of the dictionary) or the content of the object, I think the only way is to write your own JsonConverter and place your custom logic into the ReadJson method.

    – Matteo Melli
    Nov 14 '18 at 15:05












  • Now I used [OnDeserialized] private void OnDeserialized(StreamingContext context)

    – PiotrN
    Nov 14 '18 at 15:38

















  • However this is not my restful service that's why it does not return $type and I do not have the option of adding $type

    – PiotrN
    Nov 14 '18 at 11:52






  • 1





    How, then, the program is supposed to decide which is the correct type? If you need to make assumptions based on things such as the name of the property (the key of the dictionary) or the content of the object, I think the only way is to write your own JsonConverter and place your custom logic into the ReadJson method.

    – Matteo Melli
    Nov 14 '18 at 15:05












  • Now I used [OnDeserialized] private void OnDeserialized(StreamingContext context)

    – PiotrN
    Nov 14 '18 at 15:38
















However this is not my restful service that's why it does not return $type and I do not have the option of adding $type

– PiotrN
Nov 14 '18 at 11:52





However this is not my restful service that's why it does not return $type and I do not have the option of adding $type

– PiotrN
Nov 14 '18 at 11:52




1




1





How, then, the program is supposed to decide which is the correct type? If you need to make assumptions based on things such as the name of the property (the key of the dictionary) or the content of the object, I think the only way is to write your own JsonConverter and place your custom logic into the ReadJson method.

– Matteo Melli
Nov 14 '18 at 15:05






How, then, the program is supposed to decide which is the correct type? If you need to make assumptions based on things such as the name of the property (the key of the dictionary) or the content of the object, I think the only way is to write your own JsonConverter and place your custom logic into the ReadJson method.

– Matteo Melli
Nov 14 '18 at 15:05














Now I used [OnDeserialized] private void OnDeserialized(StreamingContext context)

– PiotrN
Nov 14 '18 at 15:38





Now I used [OnDeserialized] private void OnDeserialized(StreamingContext context)

– PiotrN
Nov 14 '18 at 15:38

















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