Display output with awk without brackets










0















I want my output to display in a certain way.



I have the code beneath but i want to display the dates without the on both sides:



icat -o 2048 someimage.E01 171 | grep /etc | awk 'print $1 "t" $7 " t" $4 $5 ' 

167.22.123.17 /home/me/file1 [13/Sep/2014:12:52:16-0400]
167.22.123.17 /home/me/file2 [13/Sep/2014:12:53:44-0400]


I want it to be displayed like:



167.22.123.17 /home/me/file1 [13/Sep/2014:12:52:16-0400]
167.22.123.17 /home/me/file2 [13/Sep/2014:12:53:44-0400]


I looked around on the internet but i can't find a solution that works. Some assistance would be great!










share|improve this question



















  • 3





    Your current and desired outputs are the same. I'm guessing that's just a copy-and-paste mistake.

    – IMSoP
    Nov 14 '18 at 10:14






  • 1





    Try adding sub(/[/, "", $4); sub(/]/, "", $5); after { if your Field 4 contains [ and Field 5 contains ]. To remove all [ or ]s, use gsub(//, "", $4) and gsub(//, "", $5).

    – Wiktor Stribiżew
    Nov 14 '18 at 10:18












  • can you present the output of icat

    – kvantour
    Nov 14 '18 at 13:45















0















I want my output to display in a certain way.



I have the code beneath but i want to display the dates without the on both sides:



icat -o 2048 someimage.E01 171 | grep /etc | awk 'print $1 "t" $7 " t" $4 $5 ' 

167.22.123.17 /home/me/file1 [13/Sep/2014:12:52:16-0400]
167.22.123.17 /home/me/file2 [13/Sep/2014:12:53:44-0400]


I want it to be displayed like:



167.22.123.17 /home/me/file1 [13/Sep/2014:12:52:16-0400]
167.22.123.17 /home/me/file2 [13/Sep/2014:12:53:44-0400]


I looked around on the internet but i can't find a solution that works. Some assistance would be great!










share|improve this question



















  • 3





    Your current and desired outputs are the same. I'm guessing that's just a copy-and-paste mistake.

    – IMSoP
    Nov 14 '18 at 10:14






  • 1





    Try adding sub(/[/, "", $4); sub(/]/, "", $5); after { if your Field 4 contains [ and Field 5 contains ]. To remove all [ or ]s, use gsub(//, "", $4) and gsub(//, "", $5).

    – Wiktor Stribiżew
    Nov 14 '18 at 10:18












  • can you present the output of icat

    – kvantour
    Nov 14 '18 at 13:45













0












0








0








I want my output to display in a certain way.



I have the code beneath but i want to display the dates without the on both sides:



icat -o 2048 someimage.E01 171 | grep /etc | awk 'print $1 "t" $7 " t" $4 $5 ' 

167.22.123.17 /home/me/file1 [13/Sep/2014:12:52:16-0400]
167.22.123.17 /home/me/file2 [13/Sep/2014:12:53:44-0400]


I want it to be displayed like:



167.22.123.17 /home/me/file1 [13/Sep/2014:12:52:16-0400]
167.22.123.17 /home/me/file2 [13/Sep/2014:12:53:44-0400]


I looked around on the internet but i can't find a solution that works. Some assistance would be great!










share|improve this question
















I want my output to display in a certain way.



I have the code beneath but i want to display the dates without the on both sides:



icat -o 2048 someimage.E01 171 | grep /etc | awk 'print $1 "t" $7 " t" $4 $5 ' 

167.22.123.17 /home/me/file1 [13/Sep/2014:12:52:16-0400]
167.22.123.17 /home/me/file2 [13/Sep/2014:12:53:44-0400]


I want it to be displayed like:



167.22.123.17 /home/me/file1 [13/Sep/2014:12:52:16-0400]
167.22.123.17 /home/me/file2 [13/Sep/2014:12:53:44-0400]


I looked around on the internet but i can't find a solution that works. Some assistance would be great!







awk






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share|improve this question













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edited Nov 14 '18 at 10:26









RavinderSingh13

27.8k41638




27.8k41638










asked Nov 14 '18 at 10:13









user2492483user2492483

83




83







  • 3





    Your current and desired outputs are the same. I'm guessing that's just a copy-and-paste mistake.

    – IMSoP
    Nov 14 '18 at 10:14






  • 1





    Try adding sub(/[/, "", $4); sub(/]/, "", $5); after { if your Field 4 contains [ and Field 5 contains ]. To remove all [ or ]s, use gsub(//, "", $4) and gsub(//, "", $5).

    – Wiktor Stribiżew
    Nov 14 '18 at 10:18












  • can you present the output of icat

    – kvantour
    Nov 14 '18 at 13:45












  • 3





    Your current and desired outputs are the same. I'm guessing that's just a copy-and-paste mistake.

    – IMSoP
    Nov 14 '18 at 10:14






  • 1





    Try adding sub(/[/, "", $4); sub(/]/, "", $5); after { if your Field 4 contains [ and Field 5 contains ]. To remove all [ or ]s, use gsub(//, "", $4) and gsub(//, "", $5).

    – Wiktor Stribiżew
    Nov 14 '18 at 10:18












  • can you present the output of icat

    – kvantour
    Nov 14 '18 at 13:45







3




3





Your current and desired outputs are the same. I'm guessing that's just a copy-and-paste mistake.

– IMSoP
Nov 14 '18 at 10:14





Your current and desired outputs are the same. I'm guessing that's just a copy-and-paste mistake.

– IMSoP
Nov 14 '18 at 10:14




1




1





Try adding sub(/[/, "", $4); sub(/]/, "", $5); after { if your Field 4 contains [ and Field 5 contains ]. To remove all [ or ]s, use gsub(//, "", $4) and gsub(//, "", $5).

– Wiktor Stribiżew
Nov 14 '18 at 10:18






Try adding sub(/[/, "", $4); sub(/]/, "", $5); after { if your Field 4 contains [ and Field 5 contains ]. To remove all [ or ]s, use gsub(//, "", $4) and gsub(//, "", $5).

– Wiktor Stribiżew
Nov 14 '18 at 10:18














can you present the output of icat

– kvantour
Nov 14 '18 at 13:45





can you present the output of icat

– kvantour
Nov 14 '18 at 13:45












2 Answers
2






active

oldest

votes


















0














This might work:



icat -o 2048 someimage.E01 171 | awk -v OFS="t" '//etc/print $1,$7, substr($4,2) substr($5,1,length($5)-1) ' 


And this could also work:



icat -o 2048 someimage.E01 171 | awk 'BEGINFS="[[:blank:]]+";OFS="t"//etc/print $1,$7,$4 $5 ' 





share|improve this answer






























    0














    Could you please try the following. I am using --re-interval since I am having old awk you could remove it in case you have a new version of awk.



    awk --re-interval '
    match($0,/[[0-9]+/[a-zA-Z]3/[0-9]4:[0-9]2:[0-9]2:[0-9]2-[0-9]4]/)
    print substr($0,1,RSTART-1),substr($0,RSTART+1,RLENGTH-2),substr($0,RSTART+RLENGTH+1)
    next

    1
    ' Input_file





    share|improve this answer
























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      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

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      active

      oldest

      votes









      0














      This might work:



      icat -o 2048 someimage.E01 171 | awk -v OFS="t" '//etc/print $1,$7, substr($4,2) substr($5,1,length($5)-1) ' 


      And this could also work:



      icat -o 2048 someimage.E01 171 | awk 'BEGINFS="[[:blank:]]+";OFS="t"//etc/print $1,$7,$4 $5 ' 





      share|improve this answer



























        0














        This might work:



        icat -o 2048 someimage.E01 171 | awk -v OFS="t" '//etc/print $1,$7, substr($4,2) substr($5,1,length($5)-1) ' 


        And this could also work:



        icat -o 2048 someimage.E01 171 | awk 'BEGINFS="[[:blank:]]+";OFS="t"//etc/print $1,$7,$4 $5 ' 





        share|improve this answer

























          0












          0








          0







          This might work:



          icat -o 2048 someimage.E01 171 | awk -v OFS="t" '//etc/print $1,$7, substr($4,2) substr($5,1,length($5)-1) ' 


          And this could also work:



          icat -o 2048 someimage.E01 171 | awk 'BEGINFS="[[:blank:]]+";OFS="t"//etc/print $1,$7,$4 $5 ' 





          share|improve this answer













          This might work:



          icat -o 2048 someimage.E01 171 | awk -v OFS="t" '//etc/print $1,$7, substr($4,2) substr($5,1,length($5)-1) ' 


          And this could also work:



          icat -o 2048 someimage.E01 171 | awk 'BEGINFS="[[:blank:]]+";OFS="t"//etc/print $1,$7,$4 $5 ' 






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 14 '18 at 13:47









          kvantourkvantour

          8,74831330




          8,74831330























              0














              Could you please try the following. I am using --re-interval since I am having old awk you could remove it in case you have a new version of awk.



              awk --re-interval '
              match($0,/[[0-9]+/[a-zA-Z]3/[0-9]4:[0-9]2:[0-9]2:[0-9]2-[0-9]4]/)
              print substr($0,1,RSTART-1),substr($0,RSTART+1,RLENGTH-2),substr($0,RSTART+RLENGTH+1)
              next

              1
              ' Input_file





              share|improve this answer





























                0














                Could you please try the following. I am using --re-interval since I am having old awk you could remove it in case you have a new version of awk.



                awk --re-interval '
                match($0,/[[0-9]+/[a-zA-Z]3/[0-9]4:[0-9]2:[0-9]2:[0-9]2-[0-9]4]/)
                print substr($0,1,RSTART-1),substr($0,RSTART+1,RLENGTH-2),substr($0,RSTART+RLENGTH+1)
                next

                1
                ' Input_file





                share|improve this answer



























                  0












                  0








                  0







                  Could you please try the following. I am using --re-interval since I am having old awk you could remove it in case you have a new version of awk.



                  awk --re-interval '
                  match($0,/[[0-9]+/[a-zA-Z]3/[0-9]4:[0-9]2:[0-9]2:[0-9]2-[0-9]4]/)
                  print substr($0,1,RSTART-1),substr($0,RSTART+1,RLENGTH-2),substr($0,RSTART+RLENGTH+1)
                  next

                  1
                  ' Input_file





                  share|improve this answer















                  Could you please try the following. I am using --re-interval since I am having old awk you could remove it in case you have a new version of awk.



                  awk --re-interval '
                  match($0,/[[0-9]+/[a-zA-Z]3/[0-9]4:[0-9]2:[0-9]2:[0-9]2-[0-9]4]/)
                  print substr($0,1,RSTART-1),substr($0,RSTART+1,RLENGTH-2),substr($0,RSTART+RLENGTH+1)
                  next

                  1
                  ' Input_file






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 14 '18 at 15:35









                  kvantour

                  8,74831330




                  8,74831330










                  answered Nov 14 '18 at 10:31









                  RavinderSingh13RavinderSingh13

                  27.8k41638




                  27.8k41638



























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