array initializer must be an initializer list or string literal c
0
I am newbie in C. I do not know why I am getting this error and how to fix it?
void FPS_PRINT_ENROLLED()
int checkNum = 0;
int ID = 0;
int num_Enroll = 0;
num_Enroll = Available_ID();
char strNum[3] = 0;
itoa(num_Enroll, strNum);
uint32_t numLen = strlen((char *)strNum);
UART_send_A3("Number of Stored Prints: ", 25);
UART_send_A3(&strNum, numLen);
The error message is: array initializer must be an initializer list or string literal
Please see the attached screenshot of the error message. Also, the c file is attached.
By the way, this is in PSoC Creator 4.1 which uses C language.
code file download link through GoogleDrive
c string literals initializer psoc
edited Nov 14 '18 at 5:33
kenlukas
1,28731317
asked Nov 14 '18 at 3:18
Sulaiman AlsuhaimiSulaiman Alsuhaimi
31
add a comment |
0
I am newbie in C. I do not know why I am getting this error and how to fix it?
void FPS_PRINT_ENROLLED()
int checkNum = 0;
int ID = 0;
int num_Enroll = 0;
num_Enroll = Available_ID();
char strNum[3] = 0;
itoa(num_Enroll, strNum);
uint32_t numLen = strlen((char *)strNum);
UART_send_A3("Number of Stored Prints: ", 25);
UART_send_A3(&strNum, numLen);
The error message is: array initializer must be an initializer list or string literal
Please see the attached screenshot of the error message. Also, the c file is attached.
By the way, this is in PSoC Creator 4.1 which uses C language.
code file download link through GoogleDrive
c string literals initializer psoc
edited Nov 14 '18 at 5:33
kenlukas
1,28731317
asked Nov 14 '18 at 3:18
Sulaiman AlsuhaimiSulaiman Alsuhaimi
31
1
this line:char strNum[3] = 0;is a problem. The variable on the left is an array of chars with three elements. The initializer on the right is a a scalar int. They types do not match. Try putting the initializer in curly braces which will assign 0 to each element, like this:char strNum[3] = 0;
– bruceg
Nov 14 '18 at 3:21
1
@bruceg Such a nice explanation. This should go in as an answer.
– Sandeep
Nov 14 '18 at 3:32
1
Great @bruceg , thanks!
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:35
add a comment |
0
0
0
1
I am newbie in C. I do not know why I am getting this error and how to fix it?
void FPS_PRINT_ENROLLED()
int checkNum = 0;
int ID = 0;
int num_Enroll = 0;
num_Enroll = Available_ID();
char strNum[3] = 0;
itoa(num_Enroll, strNum);
uint32_t numLen = strlen((char *)strNum);
UART_send_A3("Number of Stored Prints: ", 25);
UART_send_A3(&strNum, numLen);
The error message is: array initializer must be an initializer list or string literal
Please see the attached screenshot of the error message. Also, the c file is attached.
By the way, this is in PSoC Creator 4.1 which uses C language.
code file download link through GoogleDrive
c string literals initializer psoc
edited Nov 14 '18 at 5:33
kenlukas
1,28731317
asked Nov 14 '18 at 3:18
Sulaiman AlsuhaimiSulaiman Alsuhaimi
31
I am newbie in C. I do not know why I am getting this error and how to fix it?
void FPS_PRINT_ENROLLED()
int checkNum = 0;
int ID = 0;
int num_Enroll = 0;
num_Enroll = Available_ID();
char strNum[3] = 0;
itoa(num_Enroll, strNum);
uint32_t numLen = strlen((char *)strNum);
UART_send_A3("Number of Stored Prints: ", 25);
UART_send_A3(&strNum, numLen);
The error message is: array initializer must be an initializer list or string literal
Please see the attached screenshot of the error message. Also, the c file is attached.
By the way, this is in PSoC Creator 4.1 which uses C language.
code file download link through GoogleDrive
c string literals initializer psoc
c string literals initializer psoc
edited Nov 14 '18 at 5:33
kenlukas
1,28731317
asked Nov 14 '18 at 3:18
Sulaiman AlsuhaimiSulaiman Alsuhaimi
31
edited Nov 14 '18 at 5:33
kenlukas
1,28731317
asked Nov 14 '18 at 3:18
Sulaiman AlsuhaimiSulaiman Alsuhaimi
31
edited Nov 14 '18 at 5:33
kenlukas
1,28731317
edited Nov 14 '18 at 5:33
kenlukas
1,28731317
edited Nov 14 '18 at 5:33
kenlukas
1,28731317
1,28731317
asked Nov 14 '18 at 3:18
Sulaiman AlsuhaimiSulaiman Alsuhaimi
31
asked Nov 14 '18 at 3:18
Sulaiman AlsuhaimiSulaiman Alsuhaimi
31
asked Nov 14 '18 at 3:18
Sulaiman AlsuhaimiSulaiman Alsuhaimi
31
31
1
this line:char strNum[3] = 0;is a problem. The variable on the left is an array of chars with three elements. The initializer on the right is a a scalar int. They types do not match. Try putting the initializer in curly braces which will assign 0 to each element, like this:char strNum[3] = 0;
– bruceg
Nov 14 '18 at 3:21
1
@bruceg Such a nice explanation. This should go in as an answer.
– Sandeep
Nov 14 '18 at 3:32
1
Great @bruceg , thanks!
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:35
add a comment |
1
this line:char strNum[3] = 0;is a problem. The variable on the left is an array of chars with three elements. The initializer on the right is a a scalar int. They types do not match. Try putting the initializer in curly braces which will assign 0 to each element, like this:char strNum[3] = 0;
– bruceg
Nov 14 '18 at 3:21
1
@bruceg Such a nice explanation. This should go in as an answer.
– Sandeep
Nov 14 '18 at 3:32
1
Great @bruceg , thanks!
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:35
1
1
this line:
char strNum[3] = 0; is a problem. The variable on the left is an array of chars with three elements. The initializer on the right is a a scalar int. They types do not match. Try putting the initializer in curly braces which will assign 0 to each element, like this: char strNum[3] = 0;– bruceg
Nov 14 '18 at 3:21
this line:
char strNum[3] = 0; is a problem. The variable on the left is an array of chars with three elements. The initializer on the right is a a scalar int. They types do not match. Try putting the initializer in curly braces which will assign 0 to each element, like this: char strNum[3] = 0;– bruceg
Nov 14 '18 at 3:21
1
1
@bruceg Such a nice explanation. This should go in as an answer.
– Sandeep
Nov 14 '18 at 3:32
@bruceg Such a nice explanation. This should go in as an answer.
– Sandeep
Nov 14 '18 at 3:32
1
1
Great @bruceg , thanks!
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:35
Great @bruceg , thanks!
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:35
add a comment |
1 Answer
1
active
oldest
votes
0
char strNum[3] = 0;
This line creates a three character string. You then use it as a string with the function strlen and the uart_send.
As a C string it must be terminated with a null character, so you only have two usable characters. It must also be initialised as a string, the compiler is telling you that you haven't done this correctly.
Try something like one of these lines
char strNum[3] = ""; // Empty string
char strNum[3] = "AB"; // Full string
char strNum[3] = "0"; // String holding the character zero
answered Nov 14 '18 at 3:32
lodlod
953612
1
Detail: Although all 3 array elements are initialized to zero, the string is only 1 character:strNum[0].
– chux
Nov 14 '18 at 3:43
Awesome! I changed it to char strNum[3] = "0"; and got it working. Will this affect my code if I keep it like this or you are just explaining to me?
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:30
No, it is a perfectly valid piece of code. Keep in mind that it is a string representation of a number, not a number. You can't increment it or modify it like you would a number. If you have issues with that it would be best to ask another question.
– lod
Nov 14 '18 at 5:43
If your statement “It must also be initialised as a string” is meant to say that an array ofcharmust be initialized with a string literal, then it is incorrect. As the compiler message notes, it may be initialized with an initializer list (enclosed in braces), such as2, 1, 0or'a', 'b', 0.
– Eric Postpischil
Nov 14 '18 at 11:59
char strNum[3] = 0;doesn't create jack, it is not valid C. Hence the compiler error.
– Lundin
Nov 14 '18 at 12:20
add a comment |
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1 Answer
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0
char strNum[3] = 0;
This line creates a three character string. You then use it as a string with the function strlen and the uart_send.
As a C string it must be terminated with a null character, so you only have two usable characters. It must also be initialised as a string, the compiler is telling you that you haven't done this correctly.
Try something like one of these lines
char strNum[3] = ""; // Empty string
char strNum[3] = "AB"; // Full string
char strNum[3] = "0"; // String holding the character zero
answered Nov 14 '18 at 3:32
lodlod
953612
1
Detail: Although all 3 array elements are initialized to zero, the string is only 1 character:strNum[0].
– chux
Nov 14 '18 at 3:43
Awesome! I changed it to char strNum[3] = "0"; and got it working. Will this affect my code if I keep it like this or you are just explaining to me?
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:30
No, it is a perfectly valid piece of code. Keep in mind that it is a string representation of a number, not a number. You can't increment it or modify it like you would a number. If you have issues with that it would be best to ask another question.
– lod
Nov 14 '18 at 5:43
If your statement “It must also be initialised as a string” is meant to say that an array ofcharmust be initialized with a string literal, then it is incorrect. As the compiler message notes, it may be initialized with an initializer list (enclosed in braces), such as2, 1, 0or'a', 'b', 0.
– Eric Postpischil
Nov 14 '18 at 11:59
char strNum[3] = 0;doesn't create jack, it is not valid C. Hence the compiler error.
– Lundin
Nov 14 '18 at 12:20
add a comment |
0
char strNum[3] = 0;
This line creates a three character string. You then use it as a string with the function strlen and the uart_send.
As a C string it must be terminated with a null character, so you only have two usable characters. It must also be initialised as a string, the compiler is telling you that you haven't done this correctly.
Try something like one of these lines
char strNum[3] = ""; // Empty string
char strNum[3] = "AB"; // Full string
char strNum[3] = "0"; // String holding the character zero
answered Nov 14 '18 at 3:32
lodlod
953612
1
Detail: Although all 3 array elements are initialized to zero, the string is only 1 character:strNum[0].
– chux
Nov 14 '18 at 3:43
Awesome! I changed it to char strNum[3] = "0"; and got it working. Will this affect my code if I keep it like this or you are just explaining to me?
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:30
No, it is a perfectly valid piece of code. Keep in mind that it is a string representation of a number, not a number. You can't increment it or modify it like you would a number. If you have issues with that it would be best to ask another question.
– lod
Nov 14 '18 at 5:43
If your statement “It must also be initialised as a string” is meant to say that an array ofcharmust be initialized with a string literal, then it is incorrect. As the compiler message notes, it may be initialized with an initializer list (enclosed in braces), such as2, 1, 0or'a', 'b', 0.
– Eric Postpischil
Nov 14 '18 at 11:59
char strNum[3] = 0;doesn't create jack, it is not valid C. Hence the compiler error.
– Lundin
Nov 14 '18 at 12:20
add a comment |
0
0
0
char strNum[3] = 0;
This line creates a three character string. You then use it as a string with the function strlen and the uart_send.
As a C string it must be terminated with a null character, so you only have two usable characters. It must also be initialised as a string, the compiler is telling you that you haven't done this correctly.
Try something like one of these lines
char strNum[3] = ""; // Empty string
char strNum[3] = "AB"; // Full string
char strNum[3] = "0"; // String holding the character zero
answered Nov 14 '18 at 3:32
lodlod
953612
char strNum[3] = 0;
This line creates a three character string. You then use it as a string with the function strlen and the uart_send.
As a C string it must be terminated with a null character, so you only have two usable characters. It must also be initialised as a string, the compiler is telling you that you haven't done this correctly.
Try something like one of these lines
char strNum[3] = ""; // Empty string
char strNum[3] = "AB"; // Full string
char strNum[3] = "0"; // String holding the character zero
answered Nov 14 '18 at 3:32
lodlod
953612
answered Nov 14 '18 at 3:32
lodlod
953612
answered Nov 14 '18 at 3:32
lodlod
953612
answered Nov 14 '18 at 3:32
lodlod
953612
953612
1
Detail: Although all 3 array elements are initialized to zero, the string is only 1 character:strNum[0].
– chux
Nov 14 '18 at 3:43
Awesome! I changed it to char strNum[3] = "0"; and got it working. Will this affect my code if I keep it like this or you are just explaining to me?
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:30
No, it is a perfectly valid piece of code. Keep in mind that it is a string representation of a number, not a number. You can't increment it or modify it like you would a number. If you have issues with that it would be best to ask another question.
– lod
Nov 14 '18 at 5:43
If your statement “It must also be initialised as a string” is meant to say that an array ofcharmust be initialized with a string literal, then it is incorrect. As the compiler message notes, it may be initialized with an initializer list (enclosed in braces), such as2, 1, 0or'a', 'b', 0.
– Eric Postpischil
Nov 14 '18 at 11:59
char strNum[3] = 0;doesn't create jack, it is not valid C. Hence the compiler error.
– Lundin
Nov 14 '18 at 12:20
add a comment |
1
Detail: Although all 3 array elements are initialized to zero, the string is only 1 character:strNum[0].
– chux
Nov 14 '18 at 3:43
Awesome! I changed it to char strNum[3] = "0"; and got it working. Will this affect my code if I keep it like this or you are just explaining to me?
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:30
No, it is a perfectly valid piece of code. Keep in mind that it is a string representation of a number, not a number. You can't increment it or modify it like you would a number. If you have issues with that it would be best to ask another question.
– lod
Nov 14 '18 at 5:43
If your statement “It must also be initialised as a string” is meant to say that an array ofcharmust be initialized with a string literal, then it is incorrect. As the compiler message notes, it may be initialized with an initializer list (enclosed in braces), such as2, 1, 0or'a', 'b', 0.
– Eric Postpischil
Nov 14 '18 at 11:59
char strNum[3] = 0;doesn't create jack, it is not valid C. Hence the compiler error.
– Lundin
Nov 14 '18 at 12:20
1
1
Detail: Although all 3 array elements are initialized to zero, the string is only 1 character:
strNum[0].– chux
Nov 14 '18 at 3:43
Detail: Although all 3 array elements are initialized to zero, the string is only 1 character:
strNum[0].– chux
Nov 14 '18 at 3:43
Awesome! I changed it to char strNum[3] = "0"; and got it working. Will this affect my code if I keep it like this or you are just explaining to me?
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:30
Awesome! I changed it to char strNum[3] = "0"; and got it working. Will this affect my code if I keep it like this or you are just explaining to me?
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:30
No, it is a perfectly valid piece of code. Keep in mind that it is a string representation of a number, not a number. You can't increment it or modify it like you would a number. If you have issues with that it would be best to ask another question.
– lod
Nov 14 '18 at 5:43
No, it is a perfectly valid piece of code. Keep in mind that it is a string representation of a number, not a number. You can't increment it or modify it like you would a number. If you have issues with that it would be best to ask another question.
– lod
Nov 14 '18 at 5:43
If your statement “It must also be initialised as a string” is meant to say that an array of
char must be initialized with a string literal, then it is incorrect. As the compiler message notes, it may be initialized with an initializer list (enclosed in braces), such as 2, 1, 0 or 'a', 'b', 0 .– Eric Postpischil
Nov 14 '18 at 11:59
If your statement “It must also be initialised as a string” is meant to say that an array of
char must be initialized with a string literal, then it is incorrect. As the compiler message notes, it may be initialized with an initializer list (enclosed in braces), such as 2, 1, 0 or 'a', 'b', 0 .– Eric Postpischil
Nov 14 '18 at 11:59
char strNum[3] = 0; doesn't create jack, it is not valid C. Hence the compiler error.– Lundin
Nov 14 '18 at 12:20
char strNum[3] = 0; doesn't create jack, it is not valid C. Hence the compiler error.– Lundin
Nov 14 '18 at 12:20
add a comment |
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1
this line:
char strNum[3] = 0;is a problem. The variable on the left is an array of chars with three elements. The initializer on the right is a a scalar int. They types do not match. Try putting the initializer in curly braces which will assign 0 to each element, like this:char strNum[3] = 0;– bruceg
Nov 14 '18 at 3:21
1
@bruceg Such a nice explanation. This should go in as an answer.
– Sandeep
Nov 14 '18 at 3:32
1
Great @bruceg , thanks!
– Sulaiman Alsuhaimi
Nov 14 '18 at 5:35