MS Access SQL - How to pull last 13 months data from the first of the first month?
I tried the below code to pull last 13 months of data. But it is not pulling from the 1st of the month. How can I modify it to pull data from the first day of the month?
For e.g. If I am running it today (11/13/18), I want data from 11/1/17 to today.
SELECT * FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, DATE());
sql ms-access ms-access-2016
edited Nov 13 '18 at 17:23
Gordon Linoff
767k35300402
asked Nov 13 '18 at 17:23
SKaySKay
51
add a comment |
I tried the below code to pull last 13 months of data. But it is not pulling from the 1st of the month. How can I modify it to pull data from the first day of the month?
For e.g. If I am running it today (11/13/18), I want data from 11/1/17 to today.
SELECT * FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, DATE());
sql ms-access ms-access-2016
edited Nov 13 '18 at 17:23
Gordon Linoff
767k35300402
asked Nov 13 '18 at 17:23
SKaySKay
51
add a comment |
I tried the below code to pull last 13 months of data. But it is not pulling from the 1st of the month. How can I modify it to pull data from the first day of the month?
For e.g. If I am running it today (11/13/18), I want data from 11/1/17 to today.
SELECT * FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, DATE());
sql ms-access ms-access-2016
edited Nov 13 '18 at 17:23
Gordon Linoff
767k35300402
asked Nov 13 '18 at 17:23
SKaySKay
51
I tried the below code to pull last 13 months of data. But it is not pulling from the 1st of the month. How can I modify it to pull data from the first day of the month?
For e.g. If I am running it today (11/13/18), I want data from 11/1/17 to today.
SELECT * FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, DATE());
sql ms-access ms-access-2016
sql ms-access ms-access-2016
edited Nov 13 '18 at 17:23
Gordon Linoff
767k35300402
asked Nov 13 '18 at 17:23
SKaySKay
51
edited Nov 13 '18 at 17:23
Gordon Linoff
767k35300402
asked Nov 13 '18 at 17:23
SKaySKay
51
edited Nov 13 '18 at 17:23
Gordon Linoff
767k35300402
edited Nov 13 '18 at 17:23
Gordon Linoff
767k35300402
edited Nov 13 '18 at 17:23
Gordon Linoff
767k35300402
767k35300402
asked Nov 13 '18 at 17:23
SKaySKay
51
asked Nov 13 '18 at 17:23
SKaySKay
51
asked Nov 13 '18 at 17:23
SKaySKay
51
51
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
You need to change the day to 1 as
SELECT *
FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("d", -(DAY(Date())-1),DATEADD("m", -13, DATE());
Or by using DATESERIAL() function which return a DATE from parts as
SELECT *
FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, DATESERIAL(YEAR(Date()), MONTH(DATE()), 1))
It will get the YEAR part from the date which is 2018 in your case, then get the MONTH part which is 11 and 1 which is the day and concatenate them to return a DATE as 2018-11-1
answered Nov 13 '18 at 17:35
SamiSami
8,72331241
Great job, now you made an exact copy...
– forpas
Nov 13 '18 at 17:51
Oh yeah that's what you think
– Sami
Nov 13 '18 at 17:52
Of course it is
– forpas
Nov 13 '18 at 17:53
Thank you @Sami. I used Dateseriel function.
– SKay
Nov 13 '18 at 22:30
add a comment |
This:
SELECT * FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, Dateserial(year(date()), month(date()),1));
uses
Dateserial(year(date()), month(date()),1)
which gives you the 1st of the current month
so you subtract from this the 13 months.
answered Nov 13 '18 at 17:40
forpasforpas
11k3423
Thank you @forpas, it worked!
– SKay
Nov 13 '18 at 22:28
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
You need to change the day to 1 as
SELECT *
FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("d", -(DAY(Date())-1),DATEADD("m", -13, DATE());
Or by using DATESERIAL() function which return a DATE from parts as
SELECT *
FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, DATESERIAL(YEAR(Date()), MONTH(DATE()), 1))
It will get the YEAR part from the date which is 2018 in your case, then get the MONTH part which is 11 and 1 which is the day and concatenate them to return a DATE as 2018-11-1
answered Nov 13 '18 at 17:35
SamiSami
8,72331241
Great job, now you made an exact copy...
– forpas
Nov 13 '18 at 17:51
Oh yeah that's what you think
– Sami
Nov 13 '18 at 17:52
Of course it is
– forpas
Nov 13 '18 at 17:53
Thank you @Sami. I used Dateseriel function.
– SKay
Nov 13 '18 at 22:30
add a comment |
You need to change the day to 1 as
SELECT *
FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("d", -(DAY(Date())-1),DATEADD("m", -13, DATE());
Or by using DATESERIAL() function which return a DATE from parts as
SELECT *
FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, DATESERIAL(YEAR(Date()), MONTH(DATE()), 1))
It will get the YEAR part from the date which is 2018 in your case, then get the MONTH part which is 11 and 1 which is the day and concatenate them to return a DATE as 2018-11-1
answered Nov 13 '18 at 17:35
SamiSami
8,72331241
Great job, now you made an exact copy...
– forpas
Nov 13 '18 at 17:51
Oh yeah that's what you think
– Sami
Nov 13 '18 at 17:52
Of course it is
– forpas
Nov 13 '18 at 17:53
Thank you @Sami. I used Dateseriel function.
– SKay
Nov 13 '18 at 22:30
add a comment |
You need to change the day to 1 as
SELECT *
FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("d", -(DAY(Date())-1),DATEADD("m", -13, DATE());
Or by using DATESERIAL() function which return a DATE from parts as
SELECT *
FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, DATESERIAL(YEAR(Date()), MONTH(DATE()), 1))
It will get the YEAR part from the date which is 2018 in your case, then get the MONTH part which is 11 and 1 which is the day and concatenate them to return a DATE as 2018-11-1
answered Nov 13 '18 at 17:35
SamiSami
8,72331241
You need to change the day to 1 as
SELECT *
FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("d", -(DAY(Date())-1),DATEADD("m", -13, DATE());
Or by using DATESERIAL() function which return a DATE from parts as
SELECT *
FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, DATESERIAL(YEAR(Date()), MONTH(DATE()), 1))
It will get the YEAR part from the date which is 2018 in your case, then get the MONTH part which is 11 and 1 which is the day and concatenate them to return a DATE as 2018-11-1
answered Nov 13 '18 at 17:35
SamiSami
8,72331241
edited Nov 13 '18 at 17:49
answered Nov 13 '18 at 17:35
SamiSami
8,72331241
answered Nov 13 '18 at 17:35
SamiSami
8,72331241
answered Nov 13 '18 at 17:35
SamiSami
8,72331241
8,72331241
Great job, now you made an exact copy...
– forpas
Nov 13 '18 at 17:51
Oh yeah that's what you think
– Sami
Nov 13 '18 at 17:52
Of course it is
– forpas
Nov 13 '18 at 17:53
Thank you @Sami. I used Dateseriel function.
– SKay
Nov 13 '18 at 22:30
add a comment |
Great job, now you made an exact copy...
– forpas
Nov 13 '18 at 17:51
Oh yeah that's what you think
– Sami
Nov 13 '18 at 17:52
Of course it is
– forpas
Nov 13 '18 at 17:53
Thank you @Sami. I used Dateseriel function.
– SKay
Nov 13 '18 at 22:30
Great job, now you made an exact copy...
– forpas
Nov 13 '18 at 17:51
Great job, now you made an exact copy...
– forpas
Nov 13 '18 at 17:51
Oh yeah that's what you think
– Sami
Nov 13 '18 at 17:52
Oh yeah that's what you think
– Sami
Nov 13 '18 at 17:52
Of course it is
– forpas
Nov 13 '18 at 17:53
Of course it is
– forpas
Nov 13 '18 at 17:53
Thank you @Sami. I used Dateseriel function.
– SKay
Nov 13 '18 at 22:30
Thank you @Sami. I used Dateseriel function.
– SKay
Nov 13 '18 at 22:30
add a comment |
This:
SELECT * FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, Dateserial(year(date()), month(date()),1));
uses
Dateserial(year(date()), month(date()),1)
which gives you the 1st of the current month
so you subtract from this the 13 months.
answered Nov 13 '18 at 17:40
forpasforpas
11k3423
Thank you @forpas, it worked!
– SKay
Nov 13 '18 at 22:28
add a comment |
This:
SELECT * FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, Dateserial(year(date()), month(date()),1));
uses
Dateserial(year(date()), month(date()),1)
which gives you the 1st of the current month
so you subtract from this the 13 months.
answered Nov 13 '18 at 17:40
forpasforpas
11k3423
Thank you @forpas, it worked!
– SKay
Nov 13 '18 at 22:28
add a comment |
This:
SELECT * FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, Dateserial(year(date()), month(date()),1));
uses
Dateserial(year(date()), month(date()),1)
which gives you the 1st of the current month
so you subtract from this the 13 months.
answered Nov 13 '18 at 17:40
forpasforpas
11k3423
This:
SELECT * FROM MyTable T
WHERE T.[Date Joined] >= DATEADD("m", -13, Dateserial(year(date()), month(date()),1));
uses
Dateserial(year(date()), month(date()),1)
which gives you the 1st of the current month
so you subtract from this the 13 months.
answered Nov 13 '18 at 17:40
forpasforpas
11k3423
answered Nov 13 '18 at 17:40
forpasforpas
11k3423
answered Nov 13 '18 at 17:40
forpasforpas
11k3423
answered Nov 13 '18 at 17:40
forpasforpas
11k3423
11k3423
Thank you @forpas, it worked!
– SKay
Nov 13 '18 at 22:28
add a comment |
Thank you @forpas, it worked!
– SKay
Nov 13 '18 at 22:28
Thank you @forpas, it worked!
– SKay
Nov 13 '18 at 22:28
Thank you @forpas, it worked!
– SKay
Nov 13 '18 at 22:28
add a comment |
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