Changing label display in bokeh according to the text input
I have a text input in my bokeh application as follows:
textbox=TextInput(value="DIAAAAC35TQSDA8", title="Enter deal_id:")
textbox.on_change("value", text_handler)
I use the text handler function to generate a new chart using:
source.data = dict(x=x_data, y=y_data)
This works perfectly fine. However, i also have a label in my original chart.
p.add_layout(Arrow(x_start=x_old, y_start=y_old, x_end=x_old, y_end=y_old, `end=VeeHead(fill_color="red", size=25)))
How do I make the x_old, y_old values change depending on the new textInput?
python bokeh
edited Nov 13 '18 at 20:30
James Z
11.1k71935
asked Nov 13 '18 at 17:09
A.DSA.DS
759
add a comment |
I have a text input in my bokeh application as follows:
textbox=TextInput(value="DIAAAAC35TQSDA8", title="Enter deal_id:")
textbox.on_change("value", text_handler)
I use the text handler function to generate a new chart using:
source.data = dict(x=x_data, y=y_data)
This works perfectly fine. However, i also have a label in my original chart.
p.add_layout(Arrow(x_start=x_old, y_start=y_old, x_end=x_old, y_end=y_old, `end=VeeHead(fill_color="red", size=25)))
How do I make the x_old, y_old values change depending on the new textInput?
python bokeh
edited Nov 13 '18 at 20:30
James Z
11.1k71935
asked Nov 13 '18 at 17:09
A.DSA.DS
759
add a comment |
I have a text input in my bokeh application as follows:
textbox=TextInput(value="DIAAAAC35TQSDA8", title="Enter deal_id:")
textbox.on_change("value", text_handler)
I use the text handler function to generate a new chart using:
source.data = dict(x=x_data, y=y_data)
This works perfectly fine. However, i also have a label in my original chart.
p.add_layout(Arrow(x_start=x_old, y_start=y_old, x_end=x_old, y_end=y_old, `end=VeeHead(fill_color="red", size=25)))
How do I make the x_old, y_old values change depending on the new textInput?
python bokeh
edited Nov 13 '18 at 20:30
James Z
11.1k71935
asked Nov 13 '18 at 17:09
A.DSA.DS
759
I have a text input in my bokeh application as follows:
textbox=TextInput(value="DIAAAAC35TQSDA8", title="Enter deal_id:")
textbox.on_change("value", text_handler)
I use the text handler function to generate a new chart using:
source.data = dict(x=x_data, y=y_data)
This works perfectly fine. However, i also have a label in my original chart.
p.add_layout(Arrow(x_start=x_old, y_start=y_old, x_end=x_old, y_end=y_old, `end=VeeHead(fill_color="red", size=25)))
How do I make the x_old, y_old values change depending on the new textInput?
python bokeh
python bokeh
edited Nov 13 '18 at 20:30
James Z
11.1k71935
asked Nov 13 '18 at 17:09
A.DSA.DS
759
edited Nov 13 '18 at 20:30
James Z
11.1k71935
asked Nov 13 '18 at 17:09
A.DSA.DS
759
edited Nov 13 '18 at 20:30
James Z
11.1k71935
edited Nov 13 '18 at 20:30
James Z
11.1k71935
edited Nov 13 '18 at 20:30
James Z
11.1k71935
11.1k71935
asked Nov 13 '18 at 17:09
A.DSA.DS
759
asked Nov 13 '18 at 17:09
A.DSA.DS
759
asked Nov 13 '18 at 17:09
A.DSA.DS
759
759
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Try making a labelset and adding it to your plot.
label = LabelSet(x='x',y='y',text='labels in ColumnDataSource', source=source)
p.add_layout(labels)
Then update it in your texthandler function by feeding it the new ColumnDataSource as source, assuming you handle your callback by updating a ColumnDataSource.
answered Nov 14 '18 at 8:56
PalliePallie
3107
I used another label and different formats. But basically adding another source using ColumnDataSource worked. Thanks!
– A.DS
Nov 14 '18 at 14:16
add a comment |
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1 Answer
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active
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try making a labelset and adding it to your plot.
label = LabelSet(x='x',y='y',text='labels in ColumnDataSource', source=source)
p.add_layout(labels)
Then update it in your texthandler function by feeding it the new ColumnDataSource as source, assuming you handle your callback by updating a ColumnDataSource.
answered Nov 14 '18 at 8:56
PalliePallie
3107
I used another label and different formats. But basically adding another source using ColumnDataSource worked. Thanks!
– A.DS
Nov 14 '18 at 14:16
add a comment |
Try making a labelset and adding it to your plot.
label = LabelSet(x='x',y='y',text='labels in ColumnDataSource', source=source)
p.add_layout(labels)
Then update it in your texthandler function by feeding it the new ColumnDataSource as source, assuming you handle your callback by updating a ColumnDataSource.
answered Nov 14 '18 at 8:56
PalliePallie
3107
I used another label and different formats. But basically adding another source using ColumnDataSource worked. Thanks!
– A.DS
Nov 14 '18 at 14:16
add a comment |
Try making a labelset and adding it to your plot.
label = LabelSet(x='x',y='y',text='labels in ColumnDataSource', source=source)
p.add_layout(labels)
Then update it in your texthandler function by feeding it the new ColumnDataSource as source, assuming you handle your callback by updating a ColumnDataSource.
answered Nov 14 '18 at 8:56
PalliePallie
3107
Try making a labelset and adding it to your plot.
label = LabelSet(x='x',y='y',text='labels in ColumnDataSource', source=source)
p.add_layout(labels)
Then update it in your texthandler function by feeding it the new ColumnDataSource as source, assuming you handle your callback by updating a ColumnDataSource.
answered Nov 14 '18 at 8:56
PalliePallie
3107
answered Nov 14 '18 at 8:56
PalliePallie
3107
answered Nov 14 '18 at 8:56
PalliePallie
3107
answered Nov 14 '18 at 8:56
PalliePallie
3107
3107
I used another label and different formats. But basically adding another source using ColumnDataSource worked. Thanks!
– A.DS
Nov 14 '18 at 14:16
add a comment |
I used another label and different formats. But basically adding another source using ColumnDataSource worked. Thanks!
– A.DS
Nov 14 '18 at 14:16
I used another label and different formats. But basically adding another source using ColumnDataSource worked. Thanks!
– A.DS
Nov 14 '18 at 14:16
I used another label and different formats. But basically adding another source using ColumnDataSource worked. Thanks!
– A.DS
Nov 14 '18 at 14:16
add a comment |
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