if statements give me several warnings what do they mean?
-1
fkelly6 = matrix(data = NA, nrow = 252, 3)
for(i in 1:252)
fkelly6[i,] = matrix(c(ftmp6[i,],1-sum(ftmp6[i,])),1,3)
if(fkelly6[i,]>= 15)
fkelly6[i,]<-15
I want check if all the f are >= 15 and in case substitute them with 15.
the code works but it gives me several warnings that say: "In if (fkelly6[i, ] >= 15) { ... :
the condition has length > 1 and only the first element will be used"
what do them mean?
thanks
r if-statement
asked Nov 13 '18 at 8:04
Tommaso DellolmoTommaso Dellolmo
75
add a comment |
-1
fkelly6 = matrix(data = NA, nrow = 252, 3)
for(i in 1:252)
fkelly6[i,] = matrix(c(ftmp6[i,],1-sum(ftmp6[i,])),1,3)
if(fkelly6[i,]>= 15)
fkelly6[i,]<-15
I want check if all the f are >= 15 and in case substitute them with 15.
the code works but it gives me several warnings that say: "In if (fkelly6[i, ] >= 15) { ... :
the condition has length > 1 and only the first element will be used"
what do them mean?
thanks
r if-statement
asked Nov 13 '18 at 8:04
Tommaso DellolmoTommaso Dellolmo
75
the error is because in your if you have a vector of length 3 (in this case) and it's compared to a scalar (15), so the condition as length > 1. Basically you have something like c(10, 15, 10) > 15, the if can't work this way.
– RLave
Nov 13 '18 at 8:10
so I have to create a vector of length 3 and fill it up with 15?
– Tommaso Dellolmo
Nov 13 '18 at 8:10
add a comment |
-1
-1
-1
fkelly6 = matrix(data = NA, nrow = 252, 3)
for(i in 1:252)
fkelly6[i,] = matrix(c(ftmp6[i,],1-sum(ftmp6[i,])),1,3)
if(fkelly6[i,]>= 15)
fkelly6[i,]<-15
I want check if all the f are >= 15 and in case substitute them with 15.
the code works but it gives me several warnings that say: "In if (fkelly6[i, ] >= 15) { ... :
the condition has length > 1 and only the first element will be used"
what do them mean?
thanks
r if-statement
asked Nov 13 '18 at 8:04
Tommaso DellolmoTommaso Dellolmo
75
fkelly6 = matrix(data = NA, nrow = 252, 3)
for(i in 1:252)
fkelly6[i,] = matrix(c(ftmp6[i,],1-sum(ftmp6[i,])),1,3)
if(fkelly6[i,]>= 15)
fkelly6[i,]<-15
I want check if all the f are >= 15 and in case substitute them with 15.
the code works but it gives me several warnings that say: "In if (fkelly6[i, ] >= 15) { ... :
the condition has length > 1 and only the first element will be used"
what do them mean?
thanks
r if-statement
r if-statement
asked Nov 13 '18 at 8:04
Tommaso DellolmoTommaso Dellolmo
75
asked Nov 13 '18 at 8:04
Tommaso DellolmoTommaso Dellolmo
75
edited Nov 13 '18 at 8:06
Tommaso Dellolmo
asked Nov 13 '18 at 8:04
Tommaso DellolmoTommaso Dellolmo
75
asked Nov 13 '18 at 8:04
Tommaso DellolmoTommaso Dellolmo
75
asked Nov 13 '18 at 8:04
Tommaso DellolmoTommaso Dellolmo
75
75
the error is because in your if you have a vector of length 3 (in this case) and it's compared to a scalar (15), so the condition as length > 1. Basically you have something like c(10, 15, 10) > 15, the if can't work this way.
– RLave
Nov 13 '18 at 8:10
so I have to create a vector of length 3 and fill it up with 15?
– Tommaso Dellolmo
Nov 13 '18 at 8:10
add a comment |
the error is because in your if you have a vector of length 3 (in this case) and it's compared to a scalar (15), so the condition as length > 1. Basically you have something like c(10, 15, 10) > 15, the if can't work this way.
– RLave
Nov 13 '18 at 8:10
so I have to create a vector of length 3 and fill it up with 15?
– Tommaso Dellolmo
Nov 13 '18 at 8:10
the error is because in your if you have a vector of length 3 (in this case) and it's compared to a scalar (15), so the condition as length > 1. Basically you have something like c(10, 15, 10) > 15, the if can't work this way.
– RLave
Nov 13 '18 at 8:10
the error is because in your if you have a vector of length 3 (in this case) and it's compared to a scalar (15), so the condition as length > 1. Basically you have something like c(10, 15, 10) > 15, the if can't work this way.
– RLave
Nov 13 '18 at 8:10
so I have to create a vector of length 3 and fill it up with 15?
– Tommaso Dellolmo
Nov 13 '18 at 8:10
so I have to create a vector of length 3 and fill it up with 15?
– Tommaso Dellolmo
Nov 13 '18 at 8:10
add a comment |
1 Answer
1
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0
This is how you can change some values without a loop:
m <- matrix(1:6, nrow = 2, ncol = 3)
m
# [,1] [,2] [,3]
# [1,] 1 3 5
# [2,] 2 4 6
m[m>=4] <- 0 # every value which is >=4 will be set to zero
m
# [,1] [,2] [,3]
# [1,] 1 3 0
# [2,] 2 0 0
answered Nov 13 '18 at 8:14
RLaveRLave
3,8501922
add a comment |
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1 Answer
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votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
0
This is how you can change some values without a loop:
m <- matrix(1:6, nrow = 2, ncol = 3)
m
# [,1] [,2] [,3]
# [1,] 1 3 5
# [2,] 2 4 6
m[m>=4] <- 0 # every value which is >=4 will be set to zero
m
# [,1] [,2] [,3]
# [1,] 1 3 0
# [2,] 2 0 0
answered Nov 13 '18 at 8:14
RLaveRLave
3,8501922
add a comment |
0
This is how you can change some values without a loop:
m <- matrix(1:6, nrow = 2, ncol = 3)
m
# [,1] [,2] [,3]
# [1,] 1 3 5
# [2,] 2 4 6
m[m>=4] <- 0 # every value which is >=4 will be set to zero
m
# [,1] [,2] [,3]
# [1,] 1 3 0
# [2,] 2 0 0
answered Nov 13 '18 at 8:14
RLaveRLave
3,8501922
add a comment |
0
0
0
This is how you can change some values without a loop:
m <- matrix(1:6, nrow = 2, ncol = 3)
m
# [,1] [,2] [,3]
# [1,] 1 3 5
# [2,] 2 4 6
m[m>=4] <- 0 # every value which is >=4 will be set to zero
m
# [,1] [,2] [,3]
# [1,] 1 3 0
# [2,] 2 0 0
answered Nov 13 '18 at 8:14
RLaveRLave
3,8501922
This is how you can change some values without a loop:
m <- matrix(1:6, nrow = 2, ncol = 3)
m
# [,1] [,2] [,3]
# [1,] 1 3 5
# [2,] 2 4 6
m[m>=4] <- 0 # every value which is >=4 will be set to zero
m
# [,1] [,2] [,3]
# [1,] 1 3 0
# [2,] 2 0 0
answered Nov 13 '18 at 8:14
RLaveRLave
3,8501922
answered Nov 13 '18 at 8:14
RLaveRLave
3,8501922
answered Nov 13 '18 at 8:14
RLaveRLave
3,8501922
answered Nov 13 '18 at 8:14
RLaveRLave
3,8501922
3,8501922
add a comment |
add a comment |
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the error is because in your if you have a vector of length 3 (in this case) and it's compared to a scalar (15), so the condition as length > 1. Basically you have something like c(10, 15, 10) > 15, the if can't work this way.
– RLave
Nov 13 '18 at 8:10
so I have to create a vector of length 3 and fill it up with 15?
– Tommaso Dellolmo
Nov 13 '18 at 8:10