How to print single string and not object?
I'm working with a simple reactive form and after entering firstName, lastName and Answer I'm able to print out the values in the console like this:
firstName: "Peter", lastName: "Smith", answer: …
However, I want to print out the value of answer as a simple string and NOT an object.
Expected Result:
firstName:"Peter", lastName:"Smith", answer:'Yes'
Does anyone have any idea how to make this happen?
Here's my code: LIVE DEMO
angular typescript primeng
asked Nov 13 '18 at 22:02
progxprogx
331522
add a comment |
I'm working with a simple reactive form and after entering firstName, lastName and Answer I'm able to print out the values in the console like this:
firstName: "Peter", lastName: "Smith", answer: …
However, I want to print out the value of answer as a simple string and NOT an object.
Expected Result:
firstName:"Peter", lastName:"Smith", answer:'Yes'
Does anyone have any idea how to make this happen?
Here's my code: LIVE DEMO
angular typescript primeng
asked Nov 13 '18 at 22:02
progxprogx
331522
2
You could alwaysconsole.logthis instead:Object.assign(, this.searchform.value, answer: this.searchform.value.answer.label )
– Daniel W Strimpel
Nov 13 '18 at 22:13
You can literally copy that code in your stackblitz as is to see it... stackblitz.com/edit/angular-rvpmjk
– Daniel W Strimpel
Nov 13 '18 at 22:23
@DanielWStrimpel thanks a lot bro!
– progx
Nov 13 '18 at 22:24
JSON.stringify(this.searchform.value); try this or you can directly use Json pipe in html like json
– Nitin Walia
Nov 13 '18 at 22:24
add a comment |
I'm working with a simple reactive form and after entering firstName, lastName and Answer I'm able to print out the values in the console like this:
firstName: "Peter", lastName: "Smith", answer: …
However, I want to print out the value of answer as a simple string and NOT an object.
Expected Result:
firstName:"Peter", lastName:"Smith", answer:'Yes'
Does anyone have any idea how to make this happen?
Here's my code: LIVE DEMO
angular typescript primeng
asked Nov 13 '18 at 22:02
progxprogx
331522
I'm working with a simple reactive form and after entering firstName, lastName and Answer I'm able to print out the values in the console like this:
firstName: "Peter", lastName: "Smith", answer: …
However, I want to print out the value of answer as a simple string and NOT an object.
Expected Result:
firstName:"Peter", lastName:"Smith", answer:'Yes'
Does anyone have any idea how to make this happen?
Here's my code: LIVE DEMO
angular typescript primeng
angular typescript primeng
asked Nov 13 '18 at 22:02
progxprogx
331522
asked Nov 13 '18 at 22:02
progxprogx
331522
asked Nov 13 '18 at 22:02
progxprogx
331522
asked Nov 13 '18 at 22:02
progxprogx
331522
asked Nov 13 '18 at 22:02
progxprogx
331522
331522
2
You could alwaysconsole.logthis instead:Object.assign(, this.searchform.value, answer: this.searchform.value.answer.label )
– Daniel W Strimpel
Nov 13 '18 at 22:13
You can literally copy that code in your stackblitz as is to see it... stackblitz.com/edit/angular-rvpmjk
– Daniel W Strimpel
Nov 13 '18 at 22:23
@DanielWStrimpel thanks a lot bro!
– progx
Nov 13 '18 at 22:24
JSON.stringify(this.searchform.value); try this or you can directly use Json pipe in html like json
– Nitin Walia
Nov 13 '18 at 22:24
add a comment |
2
You could alwaysconsole.logthis instead:Object.assign(, this.searchform.value, answer: this.searchform.value.answer.label )
– Daniel W Strimpel
Nov 13 '18 at 22:13
You can literally copy that code in your stackblitz as is to see it... stackblitz.com/edit/angular-rvpmjk
– Daniel W Strimpel
Nov 13 '18 at 22:23
@DanielWStrimpel thanks a lot bro!
– progx
Nov 13 '18 at 22:24
JSON.stringify(this.searchform.value); try this or you can directly use Json pipe in html like json
– Nitin Walia
Nov 13 '18 at 22:24
2
2
You could always
console.log this instead: Object.assign(, this.searchform.value, answer: this.searchform.value.answer.label )– Daniel W Strimpel
Nov 13 '18 at 22:13
You could always
console.log this instead: Object.assign(, this.searchform.value, answer: this.searchform.value.answer.label )– Daniel W Strimpel
Nov 13 '18 at 22:13
You can literally copy that code in your stackblitz as is to see it... stackblitz.com/edit/angular-rvpmjk
– Daniel W Strimpel
Nov 13 '18 at 22:23
You can literally copy that code in your stackblitz as is to see it... stackblitz.com/edit/angular-rvpmjk
– Daniel W Strimpel
Nov 13 '18 at 22:23
@DanielWStrimpel thanks a lot bro!
– progx
Nov 13 '18 at 22:24
@DanielWStrimpel thanks a lot bro!
– progx
Nov 13 '18 at 22:24
JSON.stringify(this.searchform.value); try this or you can directly use Json pipe in html like json
– Nitin Walia
Nov 13 '18 at 22:24
JSON.stringify(this.searchform.value); try this or you can directly use Json pipe in html like json
– Nitin Walia
Nov 13 '18 at 22:24
add a comment |
3 Answers
3
active
oldest
votes
Remove the optionLabel="label" property from your p-dropdown, and intialise the answers object with a value, and a label:
this.answers = [
label: 'Yes', value: 'Yes' ,
label: 'No', value: 'No' ,
];
This will now print in your expected format.
Here is a fork of the Stackblitz
answered Nov 13 '18 at 23:13
user184994user184994
11.2k11828
Thanks a lot for your input bro!
– progx
Nov 14 '18 at 15:32
add a comment |
How about this?
const newObj =
'firstName': this.searchform.value.firstName,
'lastName': this.searchform.value.lastName,
'answer': this.searchform.value.answer.label,
;
console.log(newObj);
answered Nov 13 '18 at 22:33
amsams
2187
add a comment |
This happens because you have an array inside and you gotta access the value of the array
console.log(this.searchform.value.firstName);
console.log(this.searchform.value.lastName);
console.log(this.searchform.value.answer.label);
answered Nov 13 '18 at 22:12
Jose OJose O
141
I don't want to print them one by one. I want to print them all out in a single object like I showed in my question
– progx
Nov 13 '18 at 22:13
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Remove the optionLabel="label" property from your p-dropdown, and intialise the answers object with a value, and a label:
this.answers = [
label: 'Yes', value: 'Yes' ,
label: 'No', value: 'No' ,
];
This will now print in your expected format.
Here is a fork of the Stackblitz
answered Nov 13 '18 at 23:13
user184994user184994
11.2k11828
Thanks a lot for your input bro!
– progx
Nov 14 '18 at 15:32
add a comment |
Remove the optionLabel="label" property from your p-dropdown, and intialise the answers object with a value, and a label:
this.answers = [
label: 'Yes', value: 'Yes' ,
label: 'No', value: 'No' ,
];
This will now print in your expected format.
Here is a fork of the Stackblitz
answered Nov 13 '18 at 23:13
user184994user184994
11.2k11828
Thanks a lot for your input bro!
– progx
Nov 14 '18 at 15:32
add a comment |
Remove the optionLabel="label" property from your p-dropdown, and intialise the answers object with a value, and a label:
this.answers = [
label: 'Yes', value: 'Yes' ,
label: 'No', value: 'No' ,
];
This will now print in your expected format.
Here is a fork of the Stackblitz
answered Nov 13 '18 at 23:13
user184994user184994
11.2k11828
Remove the optionLabel="label" property from your p-dropdown, and intialise the answers object with a value, and a label:
this.answers = [
label: 'Yes', value: 'Yes' ,
label: 'No', value: 'No' ,
];
This will now print in your expected format.
Here is a fork of the Stackblitz
answered Nov 13 '18 at 23:13
user184994user184994
11.2k11828
answered Nov 13 '18 at 23:13
user184994user184994
11.2k11828
answered Nov 13 '18 at 23:13
user184994user184994
11.2k11828
answered Nov 13 '18 at 23:13
user184994user184994
11.2k11828
11.2k11828
Thanks a lot for your input bro!
– progx
Nov 14 '18 at 15:32
add a comment |
Thanks a lot for your input bro!
– progx
Nov 14 '18 at 15:32
Thanks a lot for your input bro!
– progx
Nov 14 '18 at 15:32
Thanks a lot for your input bro!
– progx
Nov 14 '18 at 15:32
add a comment |
How about this?
const newObj =
'firstName': this.searchform.value.firstName,
'lastName': this.searchform.value.lastName,
'answer': this.searchform.value.answer.label,
;
console.log(newObj);
answered Nov 13 '18 at 22:33
amsams
2187
add a comment |
How about this?
const newObj =
'firstName': this.searchform.value.firstName,
'lastName': this.searchform.value.lastName,
'answer': this.searchform.value.answer.label,
;
console.log(newObj);
answered Nov 13 '18 at 22:33
amsams
2187
add a comment |
How about this?
const newObj =
'firstName': this.searchform.value.firstName,
'lastName': this.searchform.value.lastName,
'answer': this.searchform.value.answer.label,
;
console.log(newObj);
answered Nov 13 '18 at 22:33
amsams
2187
How about this?
const newObj =
'firstName': this.searchform.value.firstName,
'lastName': this.searchform.value.lastName,
'answer': this.searchform.value.answer.label,
;
console.log(newObj);
answered Nov 13 '18 at 22:33
amsams
2187
answered Nov 13 '18 at 22:33
amsams
2187
answered Nov 13 '18 at 22:33
amsams
2187
answered Nov 13 '18 at 22:33
amsams
2187
2187
add a comment |
add a comment |
This happens because you have an array inside and you gotta access the value of the array
console.log(this.searchform.value.firstName);
console.log(this.searchform.value.lastName);
console.log(this.searchform.value.answer.label);
answered Nov 13 '18 at 22:12
Jose OJose O
141
I don't want to print them one by one. I want to print them all out in a single object like I showed in my question
– progx
Nov 13 '18 at 22:13
add a comment |
This happens because you have an array inside and you gotta access the value of the array
console.log(this.searchform.value.firstName);
console.log(this.searchform.value.lastName);
console.log(this.searchform.value.answer.label);
answered Nov 13 '18 at 22:12
Jose OJose O
141
I don't want to print them one by one. I want to print them all out in a single object like I showed in my question
– progx
Nov 13 '18 at 22:13
add a comment |
This happens because you have an array inside and you gotta access the value of the array
console.log(this.searchform.value.firstName);
console.log(this.searchform.value.lastName);
console.log(this.searchform.value.answer.label);
answered Nov 13 '18 at 22:12
Jose OJose O
141
This happens because you have an array inside and you gotta access the value of the array
console.log(this.searchform.value.firstName);
console.log(this.searchform.value.lastName);
console.log(this.searchform.value.answer.label);
answered Nov 13 '18 at 22:12
Jose OJose O
141
edited Nov 13 '18 at 22:13
answered Nov 13 '18 at 22:12
Jose OJose O
141
answered Nov 13 '18 at 22:12
Jose OJose O
141
answered Nov 13 '18 at 22:12
Jose OJose O
141
141
I don't want to print them one by one. I want to print them all out in a single object like I showed in my question
– progx
Nov 13 '18 at 22:13
add a comment |
I don't want to print them one by one. I want to print them all out in a single object like I showed in my question
– progx
Nov 13 '18 at 22:13
I don't want to print them one by one. I want to print them all out in a single object like I showed in my question
– progx
Nov 13 '18 at 22:13
I don't want to print them one by one. I want to print them all out in a single object like I showed in my question
– progx
Nov 13 '18 at 22:13
add a comment |
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2
You could always
console.logthis instead:Object.assign(, this.searchform.value, answer: this.searchform.value.answer.label )– Daniel W Strimpel
Nov 13 '18 at 22:13
You can literally copy that code in your stackblitz as is to see it... stackblitz.com/edit/angular-rvpmjk
– Daniel W Strimpel
Nov 13 '18 at 22:23
@DanielWStrimpel thanks a lot bro!
– progx
Nov 13 '18 at 22:24
JSON.stringify(this.searchform.value); try this or you can directly use Json pipe in html like json
– Nitin Walia
Nov 13 '18 at 22:24