Get row from one table, plus COUNT from a related table










1















I'm trying to build an SQL query where I grab one table's information (WHERE shops.shop_domain = X) along with the COUNT of the customers table WHERE customers.product_id = 4242451.



The shops table DOES NOT have product.id in it, but the customers table DOES HAVE the shop_domain in it, hence my attempt to do some sort of join.



I essentially want to return the following:



  • shops.id

  • shops.name

  • shops.shop_domain


  • COUNT OF CUSTOMERS WHERE customers.product_id = '4242451'

Here is my not so lovely attempt at the query.
I think I have the idea right (maybe...) but I can't wrap my head around building this query.



SELECT shops.id, shops.name, shops.shop_domain, COUNT(customers.customer_id) 
FROM shops
LEFT JOIN customers ON shops.shop_domain = customers.shop_domain
WHERE shops.shop_domain = 'myshop.com' AND
customers.product_id = '4242451'
GROUP BY shops.shop_id


Relevant database schemas:



shops:
id, name, shop_domain

customers:
id, name, product_id, shop_domain









share|improve this question




























    1















    I'm trying to build an SQL query where I grab one table's information (WHERE shops.shop_domain = X) along with the COUNT of the customers table WHERE customers.product_id = 4242451.



    The shops table DOES NOT have product.id in it, but the customers table DOES HAVE the shop_domain in it, hence my attempt to do some sort of join.



    I essentially want to return the following:



    • shops.id

    • shops.name

    • shops.shop_domain


    • COUNT OF CUSTOMERS WHERE customers.product_id = '4242451'

    Here is my not so lovely attempt at the query.
    I think I have the idea right (maybe...) but I can't wrap my head around building this query.



    SELECT shops.id, shops.name, shops.shop_domain, COUNT(customers.customer_id) 
    FROM shops
    LEFT JOIN customers ON shops.shop_domain = customers.shop_domain
    WHERE shops.shop_domain = 'myshop.com' AND
    customers.product_id = '4242451'
    GROUP BY shops.shop_id


    Relevant database schemas:



    shops:
    id, name, shop_domain

    customers:
    id, name, product_id, shop_domain









    share|improve this question


























      1












      1








      1








      I'm trying to build an SQL query where I grab one table's information (WHERE shops.shop_domain = X) along with the COUNT of the customers table WHERE customers.product_id = 4242451.



      The shops table DOES NOT have product.id in it, but the customers table DOES HAVE the shop_domain in it, hence my attempt to do some sort of join.



      I essentially want to return the following:



      • shops.id

      • shops.name

      • shops.shop_domain


      • COUNT OF CUSTOMERS WHERE customers.product_id = '4242451'

      Here is my not so lovely attempt at the query.
      I think I have the idea right (maybe...) but I can't wrap my head around building this query.



      SELECT shops.id, shops.name, shops.shop_domain, COUNT(customers.customer_id) 
      FROM shops
      LEFT JOIN customers ON shops.shop_domain = customers.shop_domain
      WHERE shops.shop_domain = 'myshop.com' AND
      customers.product_id = '4242451'
      GROUP BY shops.shop_id


      Relevant database schemas:



      shops:
      id, name, shop_domain

      customers:
      id, name, product_id, shop_domain









      share|improve this question
















      I'm trying to build an SQL query where I grab one table's information (WHERE shops.shop_domain = X) along with the COUNT of the customers table WHERE customers.product_id = 4242451.



      The shops table DOES NOT have product.id in it, but the customers table DOES HAVE the shop_domain in it, hence my attempt to do some sort of join.



      I essentially want to return the following:



      • shops.id

      • shops.name

      • shops.shop_domain


      • COUNT OF CUSTOMERS WHERE customers.product_id = '4242451'

      Here is my not so lovely attempt at the query.
      I think I have the idea right (maybe...) but I can't wrap my head around building this query.



      SELECT shops.id, shops.name, shops.shop_domain, COUNT(customers.customer_id) 
      FROM shops
      LEFT JOIN customers ON shops.shop_domain = customers.shop_domain
      WHERE shops.shop_domain = 'myshop.com' AND
      customers.product_id = '4242451'
      GROUP BY shops.shop_id


      Relevant database schemas:



      shops:
      id, name, shop_domain

      customers:
      id, name, product_id, shop_domain






      sql database postgresql






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 13 '18 at 21:55









      Erwin Brandstetter

      343k65627803




      343k65627803










      asked Nov 13 '18 at 19:26









      Patrick BollenbachPatrick Bollenbach

      6317




      6317






















          2 Answers
          2






          active

          oldest

          votes


















          1














          You are close. The condition on customers needs to go in the ON clause, because this is a LEFT JOIN and customers is the second table:



          SELECT s.id, s.name, s.shop_domain, COUNT(c.customer_id)
          FROM shops s LEFT JOIN
          customers c
          ON s.shop_domain = c.shop_domain AND c.product_id = '4242451'
          WHERE s.shop_domain = 'myshop.com'
          GROUP BY s.id, s.name, s.shop_domain;


          I am also inclined to include all three columns in the GROUP BY, although Postgres (and ANSI/ISO standards) are happy with just id if it is declared as the primary key in the table.






          share|improve this answer

























          • Wow. That was incredibly quick. I just threw this in and I believe it works perfectly.... Give me a few minutes to just run a test through this. Thanks so much Gordon.

            – Patrick Bollenbach
            Nov 13 '18 at 19:31











          • You rock. Thanks so much Gordon, really appreciate it. Have a great day.

            – Patrick Bollenbach
            Nov 13 '18 at 19:40











          • Postgres is only happy with the PK in this case. UNIQUE is not enough (short of fully implementing the standard).

            – Erwin Brandstetter
            Nov 13 '18 at 21:43











          • @ErwinBrandstetter . . . Thank you for the clarifying. I see now that the documentation not only says "functional dependency" but also gives "primary key" as the definition.

            – Gordon Linoff
            Nov 13 '18 at 21:59


















          1














          A correlated subquery should be substantially cheaper (and simpler) for the purpose:



          SELECT id, name, shop_domain
          , (SELECT count(*)
          FROM customers
          WHERE shop_domain = s.shop_domain
          AND product_id = 4242451) AS special_count
          FROM shops s
          WHERE shop_domain = 'myshop.com';


          This way you only need to aggregate in the subquery, and need not worry about undesired effects on the outer query.



          Assuming product_id is a numeric data type, so I use a numeric literal (4242451) instead of a string literal '4242451' - which might cause problems otherwise.






          share|improve this answer
























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            1














            You are close. The condition on customers needs to go in the ON clause, because this is a LEFT JOIN and customers is the second table:



            SELECT s.id, s.name, s.shop_domain, COUNT(c.customer_id)
            FROM shops s LEFT JOIN
            customers c
            ON s.shop_domain = c.shop_domain AND c.product_id = '4242451'
            WHERE s.shop_domain = 'myshop.com'
            GROUP BY s.id, s.name, s.shop_domain;


            I am also inclined to include all three columns in the GROUP BY, although Postgres (and ANSI/ISO standards) are happy with just id if it is declared as the primary key in the table.






            share|improve this answer

























            • Wow. That was incredibly quick. I just threw this in and I believe it works perfectly.... Give me a few minutes to just run a test through this. Thanks so much Gordon.

              – Patrick Bollenbach
              Nov 13 '18 at 19:31











            • You rock. Thanks so much Gordon, really appreciate it. Have a great day.

              – Patrick Bollenbach
              Nov 13 '18 at 19:40











            • Postgres is only happy with the PK in this case. UNIQUE is not enough (short of fully implementing the standard).

              – Erwin Brandstetter
              Nov 13 '18 at 21:43











            • @ErwinBrandstetter . . . Thank you for the clarifying. I see now that the documentation not only says "functional dependency" but also gives "primary key" as the definition.

              – Gordon Linoff
              Nov 13 '18 at 21:59















            1














            You are close. The condition on customers needs to go in the ON clause, because this is a LEFT JOIN and customers is the second table:



            SELECT s.id, s.name, s.shop_domain, COUNT(c.customer_id)
            FROM shops s LEFT JOIN
            customers c
            ON s.shop_domain = c.shop_domain AND c.product_id = '4242451'
            WHERE s.shop_domain = 'myshop.com'
            GROUP BY s.id, s.name, s.shop_domain;


            I am also inclined to include all three columns in the GROUP BY, although Postgres (and ANSI/ISO standards) are happy with just id if it is declared as the primary key in the table.






            share|improve this answer

























            • Wow. That was incredibly quick. I just threw this in and I believe it works perfectly.... Give me a few minutes to just run a test through this. Thanks so much Gordon.

              – Patrick Bollenbach
              Nov 13 '18 at 19:31











            • You rock. Thanks so much Gordon, really appreciate it. Have a great day.

              – Patrick Bollenbach
              Nov 13 '18 at 19:40











            • Postgres is only happy with the PK in this case. UNIQUE is not enough (short of fully implementing the standard).

              – Erwin Brandstetter
              Nov 13 '18 at 21:43











            • @ErwinBrandstetter . . . Thank you for the clarifying. I see now that the documentation not only says "functional dependency" but also gives "primary key" as the definition.

              – Gordon Linoff
              Nov 13 '18 at 21:59













            1












            1








            1







            You are close. The condition on customers needs to go in the ON clause, because this is a LEFT JOIN and customers is the second table:



            SELECT s.id, s.name, s.shop_domain, COUNT(c.customer_id)
            FROM shops s LEFT JOIN
            customers c
            ON s.shop_domain = c.shop_domain AND c.product_id = '4242451'
            WHERE s.shop_domain = 'myshop.com'
            GROUP BY s.id, s.name, s.shop_domain;


            I am also inclined to include all three columns in the GROUP BY, although Postgres (and ANSI/ISO standards) are happy with just id if it is declared as the primary key in the table.






            share|improve this answer















            You are close. The condition on customers needs to go in the ON clause, because this is a LEFT JOIN and customers is the second table:



            SELECT s.id, s.name, s.shop_domain, COUNT(c.customer_id)
            FROM shops s LEFT JOIN
            customers c
            ON s.shop_domain = c.shop_domain AND c.product_id = '4242451'
            WHERE s.shop_domain = 'myshop.com'
            GROUP BY s.id, s.name, s.shop_domain;


            I am also inclined to include all three columns in the GROUP BY, although Postgres (and ANSI/ISO standards) are happy with just id if it is declared as the primary key in the table.







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited Nov 13 '18 at 21:51

























            answered Nov 13 '18 at 19:28









            Gordon LinoffGordon Linoff

            768k35300402




            768k35300402












            • Wow. That was incredibly quick. I just threw this in and I believe it works perfectly.... Give me a few minutes to just run a test through this. Thanks so much Gordon.

              – Patrick Bollenbach
              Nov 13 '18 at 19:31











            • You rock. Thanks so much Gordon, really appreciate it. Have a great day.

              – Patrick Bollenbach
              Nov 13 '18 at 19:40











            • Postgres is only happy with the PK in this case. UNIQUE is not enough (short of fully implementing the standard).

              – Erwin Brandstetter
              Nov 13 '18 at 21:43











            • @ErwinBrandstetter . . . Thank you for the clarifying. I see now that the documentation not only says "functional dependency" but also gives "primary key" as the definition.

              – Gordon Linoff
              Nov 13 '18 at 21:59

















            • Wow. That was incredibly quick. I just threw this in and I believe it works perfectly.... Give me a few minutes to just run a test through this. Thanks so much Gordon.

              – Patrick Bollenbach
              Nov 13 '18 at 19:31











            • You rock. Thanks so much Gordon, really appreciate it. Have a great day.

              – Patrick Bollenbach
              Nov 13 '18 at 19:40











            • Postgres is only happy with the PK in this case. UNIQUE is not enough (short of fully implementing the standard).

              – Erwin Brandstetter
              Nov 13 '18 at 21:43











            • @ErwinBrandstetter . . . Thank you for the clarifying. I see now that the documentation not only says "functional dependency" but also gives "primary key" as the definition.

              – Gordon Linoff
              Nov 13 '18 at 21:59
















            Wow. That was incredibly quick. I just threw this in and I believe it works perfectly.... Give me a few minutes to just run a test through this. Thanks so much Gordon.

            – Patrick Bollenbach
            Nov 13 '18 at 19:31





            Wow. That was incredibly quick. I just threw this in and I believe it works perfectly.... Give me a few minutes to just run a test through this. Thanks so much Gordon.

            – Patrick Bollenbach
            Nov 13 '18 at 19:31













            You rock. Thanks so much Gordon, really appreciate it. Have a great day.

            – Patrick Bollenbach
            Nov 13 '18 at 19:40





            You rock. Thanks so much Gordon, really appreciate it. Have a great day.

            – Patrick Bollenbach
            Nov 13 '18 at 19:40













            Postgres is only happy with the PK in this case. UNIQUE is not enough (short of fully implementing the standard).

            – Erwin Brandstetter
            Nov 13 '18 at 21:43





            Postgres is only happy with the PK in this case. UNIQUE is not enough (short of fully implementing the standard).

            – Erwin Brandstetter
            Nov 13 '18 at 21:43













            @ErwinBrandstetter . . . Thank you for the clarifying. I see now that the documentation not only says "functional dependency" but also gives "primary key" as the definition.

            – Gordon Linoff
            Nov 13 '18 at 21:59





            @ErwinBrandstetter . . . Thank you for the clarifying. I see now that the documentation not only says "functional dependency" but also gives "primary key" as the definition.

            – Gordon Linoff
            Nov 13 '18 at 21:59













            1














            A correlated subquery should be substantially cheaper (and simpler) for the purpose:



            SELECT id, name, shop_domain
            , (SELECT count(*)
            FROM customers
            WHERE shop_domain = s.shop_domain
            AND product_id = 4242451) AS special_count
            FROM shops s
            WHERE shop_domain = 'myshop.com';


            This way you only need to aggregate in the subquery, and need not worry about undesired effects on the outer query.



            Assuming product_id is a numeric data type, so I use a numeric literal (4242451) instead of a string literal '4242451' - which might cause problems otherwise.






            share|improve this answer





























              1














              A correlated subquery should be substantially cheaper (and simpler) for the purpose:



              SELECT id, name, shop_domain
              , (SELECT count(*)
              FROM customers
              WHERE shop_domain = s.shop_domain
              AND product_id = 4242451) AS special_count
              FROM shops s
              WHERE shop_domain = 'myshop.com';


              This way you only need to aggregate in the subquery, and need not worry about undesired effects on the outer query.



              Assuming product_id is a numeric data type, so I use a numeric literal (4242451) instead of a string literal '4242451' - which might cause problems otherwise.






              share|improve this answer



























                1












                1








                1







                A correlated subquery should be substantially cheaper (and simpler) for the purpose:



                SELECT id, name, shop_domain
                , (SELECT count(*)
                FROM customers
                WHERE shop_domain = s.shop_domain
                AND product_id = 4242451) AS special_count
                FROM shops s
                WHERE shop_domain = 'myshop.com';


                This way you only need to aggregate in the subquery, and need not worry about undesired effects on the outer query.



                Assuming product_id is a numeric data type, so I use a numeric literal (4242451) instead of a string literal '4242451' - which might cause problems otherwise.






                share|improve this answer















                A correlated subquery should be substantially cheaper (and simpler) for the purpose:



                SELECT id, name, shop_domain
                , (SELECT count(*)
                FROM customers
                WHERE shop_domain = s.shop_domain
                AND product_id = 4242451) AS special_count
                FROM shops s
                WHERE shop_domain = 'myshop.com';


                This way you only need to aggregate in the subquery, and need not worry about undesired effects on the outer query.



                Assuming product_id is a numeric data type, so I use a numeric literal (4242451) instead of a string literal '4242451' - which might cause problems otherwise.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 13 '18 at 21:58

























                answered Nov 13 '18 at 21:52









                Erwin BrandstetterErwin Brandstetter

                343k65627803




                343k65627803



























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