Filter selected children from data using Javascript










1















I try to write a function in JavaScript which filter an array by a selected property (an value).



But it works for 2 level only I do not understand what do I missing.



The data I want to filter:



 var data = [


name: "john_pc",
children: [

name: "sabrina_pc",
children: [

name: "sabrina_pc"
,

name: "john_pc"

]
,

name: "john_pc"

]
,


name: "sabrina_pc"

]




The childrenFilter funciton :



const childrenFilter = (childrenData, filters) => 
let filteredData = childrenData.filter(item =>
for (var property in filters)
var optionalValues = filters[property];
var value = item[property];
if (item.children)
item.children = childrenFilter(item.children, filters);

let hasValue = value == optionalValues;
if (hasValue)
return true;

return false;

return false;
, this);
return filteredData;



Calling the function:



As you can see the 'childrenFilter' get an object which the key is property in the data and the key is value I want to keep.

let result = childrenFilter(data,
"name": "a1"
);
console.log(JSON.stringify(result, null, 2))



The wanted result :





 [

"name": "john_pc",
"children": [

"name": "sabrina_pc",
"children": [

"name": "john_pc"

]
,

"name": "john_pc"

]

]











share|improve this question



















  • 2





    please add the wanted result as well. please choose unique names.

    – Nina Scholz
    Nov 13 '18 at 18:21












  • For an object to be included, does it have to match all the filters or just one of them?

    – slider
    Nov 13 '18 at 18:28











  • It is a good question.Maybe I should add third argument to do both

    – E1ad
    Nov 13 '18 at 18:32











  • can you show a more realistic example instead of a bunch of a1 and a2?

    – PA.
    Nov 13 '18 at 18:33











  • If you could post what your wanting as a result that would really help us to assist you. Also when posting a recursive function comments and specific naming really helps. It may be clear to you, but to anyone who didn't write it, this particular recursive function may be difficult to wrap their head around.

    – zfrisch
    Nov 13 '18 at 18:33
















1















I try to write a function in JavaScript which filter an array by a selected property (an value).



But it works for 2 level only I do not understand what do I missing.



The data I want to filter:



 var data = [


name: "john_pc",
children: [

name: "sabrina_pc",
children: [

name: "sabrina_pc"
,

name: "john_pc"

]
,

name: "john_pc"

]
,


name: "sabrina_pc"

]




The childrenFilter funciton :



const childrenFilter = (childrenData, filters) => 
let filteredData = childrenData.filter(item =>
for (var property in filters)
var optionalValues = filters[property];
var value = item[property];
if (item.children)
item.children = childrenFilter(item.children, filters);

let hasValue = value == optionalValues;
if (hasValue)
return true;

return false;

return false;
, this);
return filteredData;



Calling the function:



As you can see the 'childrenFilter' get an object which the key is property in the data and the key is value I want to keep.

let result = childrenFilter(data,
"name": "a1"
);
console.log(JSON.stringify(result, null, 2))



The wanted result :





 [

"name": "john_pc",
"children": [

"name": "sabrina_pc",
"children": [

"name": "john_pc"

]
,

"name": "john_pc"

]

]











share|improve this question



















  • 2





    please add the wanted result as well. please choose unique names.

    – Nina Scholz
    Nov 13 '18 at 18:21












  • For an object to be included, does it have to match all the filters or just one of them?

    – slider
    Nov 13 '18 at 18:28











  • It is a good question.Maybe I should add third argument to do both

    – E1ad
    Nov 13 '18 at 18:32











  • can you show a more realistic example instead of a bunch of a1 and a2?

    – PA.
    Nov 13 '18 at 18:33











  • If you could post what your wanting as a result that would really help us to assist you. Also when posting a recursive function comments and specific naming really helps. It may be clear to you, but to anyone who didn't write it, this particular recursive function may be difficult to wrap their head around.

    – zfrisch
    Nov 13 '18 at 18:33














1












1








1








I try to write a function in JavaScript which filter an array by a selected property (an value).



But it works for 2 level only I do not understand what do I missing.



The data I want to filter:



 var data = [


name: "john_pc",
children: [

name: "sabrina_pc",
children: [

name: "sabrina_pc"
,

name: "john_pc"

]
,

name: "john_pc"

]
,


name: "sabrina_pc"

]




The childrenFilter funciton :



const childrenFilter = (childrenData, filters) => 
let filteredData = childrenData.filter(item =>
for (var property in filters)
var optionalValues = filters[property];
var value = item[property];
if (item.children)
item.children = childrenFilter(item.children, filters);

let hasValue = value == optionalValues;
if (hasValue)
return true;

return false;

return false;
, this);
return filteredData;



Calling the function:



As you can see the 'childrenFilter' get an object which the key is property in the data and the key is value I want to keep.

let result = childrenFilter(data,
"name": "a1"
);
console.log(JSON.stringify(result, null, 2))



The wanted result :





 [

"name": "john_pc",
"children": [

"name": "sabrina_pc",
"children": [

"name": "john_pc"

]
,

"name": "john_pc"

]

]











share|improve this question
















I try to write a function in JavaScript which filter an array by a selected property (an value).



But it works for 2 level only I do not understand what do I missing.



The data I want to filter:



 var data = [


name: "john_pc",
children: [

name: "sabrina_pc",
children: [

name: "sabrina_pc"
,

name: "john_pc"

]
,

name: "john_pc"

]
,


name: "sabrina_pc"

]




The childrenFilter funciton :



const childrenFilter = (childrenData, filters) => 
let filteredData = childrenData.filter(item =>
for (var property in filters)
var optionalValues = filters[property];
var value = item[property];
if (item.children)
item.children = childrenFilter(item.children, filters);

let hasValue = value == optionalValues;
if (hasValue)
return true;

return false;

return false;
, this);
return filteredData;



Calling the function:



As you can see the 'childrenFilter' get an object which the key is property in the data and the key is value I want to keep.

let result = childrenFilter(data,
"name": "a1"
);
console.log(JSON.stringify(result, null, 2))



The wanted result :





 [

"name": "john_pc",
"children": [

"name": "sabrina_pc",
"children": [

"name": "john_pc"

]
,

"name": "john_pc"

]

]








javascript data-structures filter






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 13 '18 at 18:45







E1ad

















asked Nov 13 '18 at 18:18









E1adE1ad

325




325







  • 2





    please add the wanted result as well. please choose unique names.

    – Nina Scholz
    Nov 13 '18 at 18:21












  • For an object to be included, does it have to match all the filters or just one of them?

    – slider
    Nov 13 '18 at 18:28











  • It is a good question.Maybe I should add third argument to do both

    – E1ad
    Nov 13 '18 at 18:32











  • can you show a more realistic example instead of a bunch of a1 and a2?

    – PA.
    Nov 13 '18 at 18:33











  • If you could post what your wanting as a result that would really help us to assist you. Also when posting a recursive function comments and specific naming really helps. It may be clear to you, but to anyone who didn't write it, this particular recursive function may be difficult to wrap their head around.

    – zfrisch
    Nov 13 '18 at 18:33













  • 2





    please add the wanted result as well. please choose unique names.

    – Nina Scholz
    Nov 13 '18 at 18:21












  • For an object to be included, does it have to match all the filters or just one of them?

    – slider
    Nov 13 '18 at 18:28











  • It is a good question.Maybe I should add third argument to do both

    – E1ad
    Nov 13 '18 at 18:32











  • can you show a more realistic example instead of a bunch of a1 and a2?

    – PA.
    Nov 13 '18 at 18:33











  • If you could post what your wanting as a result that would really help us to assist you. Also when posting a recursive function comments and specific naming really helps. It may be clear to you, but to anyone who didn't write it, this particular recursive function may be difficult to wrap their head around.

    – zfrisch
    Nov 13 '18 at 18:33








2




2





please add the wanted result as well. please choose unique names.

– Nina Scholz
Nov 13 '18 at 18:21






please add the wanted result as well. please choose unique names.

– Nina Scholz
Nov 13 '18 at 18:21














For an object to be included, does it have to match all the filters or just one of them?

– slider
Nov 13 '18 at 18:28





For an object to be included, does it have to match all the filters or just one of them?

– slider
Nov 13 '18 at 18:28













It is a good question.Maybe I should add third argument to do both

– E1ad
Nov 13 '18 at 18:32





It is a good question.Maybe I should add third argument to do both

– E1ad
Nov 13 '18 at 18:32













can you show a more realistic example instead of a bunch of a1 and a2?

– PA.
Nov 13 '18 at 18:33





can you show a more realistic example instead of a bunch of a1 and a2?

– PA.
Nov 13 '18 at 18:33













If you could post what your wanting as a result that would really help us to assist you. Also when posting a recursive function comments and specific naming really helps. It may be clear to you, but to anyone who didn't write it, this particular recursive function may be difficult to wrap their head around.

– zfrisch
Nov 13 '18 at 18:33






If you could post what your wanting as a result that would really help us to assist you. Also when posting a recursive function comments and specific naming really helps. It may be clear to you, but to anyone who didn't write it, this particular recursive function may be difficult to wrap their head around.

– zfrisch
Nov 13 '18 at 18:33













2 Answers
2






active

oldest

votes


















1














Your filter function does not take into account whether or not children elements match the pattern, therefore even though some child elements of the object match the pattern, the object itself is being filtered out.



Here is the explanation:



 
name: "a2", // does not match filter name:'a1 so is removed alongside child objects
children: [ // gets removed with parent object

name: "a2"
,

name: "a1"

]



This should produce the desired output:



 const childrenFilter = (childrenData, filters) => 
let filteredData = childrenData.filter(item =>
for (var property in filters) item.children.length) // include item when children mathes the pattern
return true;

return false;

return false;
, this);
return filteredData;






share|improve this answer

























  • Right... How do you recommend to fix that?

    – E1ad
    Nov 13 '18 at 18:46



















1














You could build new array for each step of filtering, beginning from the leaves and check if this contains the wanted value.



This approach generates new objects and does not mutate the original data.






function filter(array, filters) 
return array.reduce((r, o) => , filters);
return children , undefined);


var data = [ name: "a1", children: [ name: "a2", children: [ name: "a2" , name: "a1" ] , name: "a1" ] , name: "b1" ];

console.log(filter(data, name: "a1" ));

.as-console-wrapper max-height: 100% !important; top: 0; 








share|improve this answer
























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    2 Answers
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    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    Your filter function does not take into account whether or not children elements match the pattern, therefore even though some child elements of the object match the pattern, the object itself is being filtered out.



    Here is the explanation:



     
    name: "a2", // does not match filter name:'a1 so is removed alongside child objects
    children: [ // gets removed with parent object

    name: "a2"
    ,

    name: "a1"

    ]



    This should produce the desired output:



     const childrenFilter = (childrenData, filters) => 
    let filteredData = childrenData.filter(item =>
    for (var property in filters) item.children.length) // include item when children mathes the pattern
    return true;

    return false;

    return false;
    , this);
    return filteredData;






    share|improve this answer

























    • Right... How do you recommend to fix that?

      – E1ad
      Nov 13 '18 at 18:46
















    1














    Your filter function does not take into account whether or not children elements match the pattern, therefore even though some child elements of the object match the pattern, the object itself is being filtered out.



    Here is the explanation:



     
    name: "a2", // does not match filter name:'a1 so is removed alongside child objects
    children: [ // gets removed with parent object

    name: "a2"
    ,

    name: "a1"

    ]



    This should produce the desired output:



     const childrenFilter = (childrenData, filters) => 
    let filteredData = childrenData.filter(item =>
    for (var property in filters) item.children.length) // include item when children mathes the pattern
    return true;

    return false;

    return false;
    , this);
    return filteredData;






    share|improve this answer

























    • Right... How do you recommend to fix that?

      – E1ad
      Nov 13 '18 at 18:46














    1












    1








    1







    Your filter function does not take into account whether or not children elements match the pattern, therefore even though some child elements of the object match the pattern, the object itself is being filtered out.



    Here is the explanation:



     
    name: "a2", // does not match filter name:'a1 so is removed alongside child objects
    children: [ // gets removed with parent object

    name: "a2"
    ,

    name: "a1"

    ]



    This should produce the desired output:



     const childrenFilter = (childrenData, filters) => 
    let filteredData = childrenData.filter(item =>
    for (var property in filters) item.children.length) // include item when children mathes the pattern
    return true;

    return false;

    return false;
    , this);
    return filteredData;






    share|improve this answer















    Your filter function does not take into account whether or not children elements match the pattern, therefore even though some child elements of the object match the pattern, the object itself is being filtered out.



    Here is the explanation:



     
    name: "a2", // does not match filter name:'a1 so is removed alongside child objects
    children: [ // gets removed with parent object

    name: "a2"
    ,

    name: "a1"

    ]



    This should produce the desired output:



     const childrenFilter = (childrenData, filters) => 
    let filteredData = childrenData.filter(item =>
    for (var property in filters) item.children.length) // include item when children mathes the pattern
    return true;

    return false;

    return false;
    , this);
    return filteredData;







    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 13 '18 at 18:45

























    answered Nov 13 '18 at 18:38









    MateuszMateusz

    263




    263












    • Right... How do you recommend to fix that?

      – E1ad
      Nov 13 '18 at 18:46


















    • Right... How do you recommend to fix that?

      – E1ad
      Nov 13 '18 at 18:46

















    Right... How do you recommend to fix that?

    – E1ad
    Nov 13 '18 at 18:46






    Right... How do you recommend to fix that?

    – E1ad
    Nov 13 '18 at 18:46














    1














    You could build new array for each step of filtering, beginning from the leaves and check if this contains the wanted value.



    This approach generates new objects and does not mutate the original data.






    function filter(array, filters) 
    return array.reduce((r, o) => , filters);
    return children , undefined);


    var data = [ name: "a1", children: [ name: "a2", children: [ name: "a2" , name: "a1" ] , name: "a1" ] , name: "b1" ];

    console.log(filter(data, name: "a1" ));

    .as-console-wrapper max-height: 100% !important; top: 0; 








    share|improve this answer





























      1














      You could build new array for each step of filtering, beginning from the leaves and check if this contains the wanted value.



      This approach generates new objects and does not mutate the original data.






      function filter(array, filters) 
      return array.reduce((r, o) => , filters);
      return children , undefined);


      var data = [ name: "a1", children: [ name: "a2", children: [ name: "a2" , name: "a1" ] , name: "a1" ] , name: "b1" ];

      console.log(filter(data, name: "a1" ));

      .as-console-wrapper max-height: 100% !important; top: 0; 








      share|improve this answer



























        1












        1








        1







        You could build new array for each step of filtering, beginning from the leaves and check if this contains the wanted value.



        This approach generates new objects and does not mutate the original data.






        function filter(array, filters) 
        return array.reduce((r, o) => , filters);
        return children , undefined);


        var data = [ name: "a1", children: [ name: "a2", children: [ name: "a2" , name: "a1" ] , name: "a1" ] , name: "b1" ];

        console.log(filter(data, name: "a1" ));

        .as-console-wrapper max-height: 100% !important; top: 0; 








        share|improve this answer















        You could build new array for each step of filtering, beginning from the leaves and check if this contains the wanted value.



        This approach generates new objects and does not mutate the original data.






        function filter(array, filters) 
        return array.reduce((r, o) => , filters);
        return children , undefined);


        var data = [ name: "a1", children: [ name: "a2", children: [ name: "a2" , name: "a1" ] , name: "a1" ] , name: "b1" ];

        console.log(filter(data, name: "a1" ));

        .as-console-wrapper max-height: 100% !important; top: 0; 








        function filter(array, filters) 
        return array.reduce((r, o) => , filters);
        return children , undefined);


        var data = [ name: "a1", children: [ name: "a2", children: [ name: "a2" , name: "a1" ] , name: "a1" ] , name: "b1" ];

        console.log(filter(data, name: "a1" ));

        .as-console-wrapper max-height: 100% !important; top: 0; 





        function filter(array, filters) 
        return array.reduce((r, o) => , filters);
        return children , undefined);


        var data = [ name: "a1", children: [ name: "a2", children: [ name: "a2" , name: "a1" ] , name: "a1" ] , name: "b1" ];

        console.log(filter(data, name: "a1" ));

        .as-console-wrapper max-height: 100% !important; top: 0; 






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 13 '18 at 19:06

























        answered Nov 13 '18 at 18:53









        Nina ScholzNina Scholz

        181k1494163




        181k1494163



























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