Odtnhj

Can you guys, please, explain to me what does count[word.charAt(i)]++, exactly do in this code and overall--?

public static void main(String args) 
 String S = "Some random text to test.";
 int count = new int[124];
 for (int i=0; i< S.length(); i++) 
 count[S.charAt(i)]++;
 System.out.print(count[S.charAt(i)] + " ");
 
 int max = 1;
 char result = ' ';

 for (int i = 0; i < S.length(); i++) 
 if (max < count[S.charAt(i)] && S.charAt(i) != ' ') 
 max = count[S.charAt(i)];
 result = S.charAt(i);
 
 
 System.out.println(result);

The printing of count[S.charAt(i)] was just me trying to figure it out.

S.charAt(i) returns the character in the i-th position of that string S.

Then count[S.charAt(i)] will execute like this. Lets say you get 'S' as the character. Then the character value for 'S' will be 83. So, it will take the element of the 83 index in count array and increment it by one.

word.charAt(i) returns the character at the i-th index in the String word.

count is an int array with all zeros automatically : int count = new int[124];

count[i]++ increments the value that is in count at index i by 1.

Here, you're passing word.charAt(i) as an index i.e count[word.charAt(i)]++, and what it does is:

-Evaluate word.charAt(i) first, but
note that index i must be an integer!

so automatically gets the ASCII value of the character. For example ('a' = 97, 'b' = 98..)

-then, count[ASCII number returned]++, for example count[97]++, will be incremented and now count[97] = 1

But note that if your String has '}', there will be Index out of bound exception, since its ASCII value is 125; and 125 > 124 the size of count!