Is there any way to know the stack address of stack allocated local variable created using alloca instruction in LLVM









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1
down vote

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I have a simple add program.



int main() 

int x=10,y=10,result=0;
result=x+y;
return 0;



I created a LLVM frontend module pass which can traverse through the entire module.



So my pass iterates through the basic block and fetches me instructions.



FORE(iter, (*bb)) 
if(isa<AllocaInst>(iter))
errs()<<"The address of allocated variable is "<<&(*iter);




The output of this would be the address of alloca instruction but not the real stack address of the local variable.



Is there any way I can get the stack address of local variable using pass?










share|improve this question

























    up vote
    1
    down vote

    favorite












    I have a simple add program.



    int main() 

    int x=10,y=10,result=0;
    result=x+y;
    return 0;



    I created a LLVM frontend module pass which can traverse through the entire module.



    So my pass iterates through the basic block and fetches me instructions.



    FORE(iter, (*bb)) 
    if(isa<AllocaInst>(iter))
    errs()<<"The address of allocated variable is "<<&(*iter);




    The output of this would be the address of alloca instruction but not the real stack address of the local variable.



    Is there any way I can get the stack address of local variable using pass?










    share|improve this question























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      I have a simple add program.



      int main() 

      int x=10,y=10,result=0;
      result=x+y;
      return 0;



      I created a LLVM frontend module pass which can traverse through the entire module.



      So my pass iterates through the basic block and fetches me instructions.



      FORE(iter, (*bb)) 
      if(isa<AllocaInst>(iter))
      errs()<<"The address of allocated variable is "<<&(*iter);




      The output of this would be the address of alloca instruction but not the real stack address of the local variable.



      Is there any way I can get the stack address of local variable using pass?










      share|improve this question













      I have a simple add program.



      int main() 

      int x=10,y=10,result=0;
      result=x+y;
      return 0;



      I created a LLVM frontend module pass which can traverse through the entire module.



      So my pass iterates through the basic block and fetches me instructions.



      FORE(iter, (*bb)) 
      if(isa<AllocaInst>(iter))
      errs()<<"The address of allocated variable is "<<&(*iter);




      The output of this would be the address of alloca instruction but not the real stack address of the local variable.



      Is there any way I can get the stack address of local variable using pass?







      llvm llvm-ir






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 11 at 14:59









      Arjun

      184




      184






















          1 Answer
          1






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          up vote
          2
          down vote



          accepted










          You can't.



          It is not even guaranteed the address of the variables will be the same when you run the program multiple times (see Address Space Layout Randomization), so there's no way one could predict the address statically.



          Even if we did know that the stack always started at a fixed address, it is perfectly normal for the same variable to have a different address during different calls of the function. Take this for example:



          #include <stdio.h>

          void f()
          int x;
          printf("The address of x is: %pn", &x);


          void g()
          int y;
          f();


          int main()
          f();
          g();
          return 0;



          Assuming you compile this without optimizations (which would remove the definition of y), this will print two different addresses for x. So when looking at the definition of f, we couldn't possibly predict the address of its variables because it isn't even going to be the same within the same run of the program.



          Furthermore your phase isn't going to know which optimizations are going to run after it, which variables are going to be stored in registers or which register are going to be spilled to stack memory - all of which would affect the addresses.






          share|improve this answer




















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            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes








            up vote
            2
            down vote



            accepted










            You can't.



            It is not even guaranteed the address of the variables will be the same when you run the program multiple times (see Address Space Layout Randomization), so there's no way one could predict the address statically.



            Even if we did know that the stack always started at a fixed address, it is perfectly normal for the same variable to have a different address during different calls of the function. Take this for example:



            #include <stdio.h>

            void f()
            int x;
            printf("The address of x is: %pn", &x);


            void g()
            int y;
            f();


            int main()
            f();
            g();
            return 0;



            Assuming you compile this without optimizations (which would remove the definition of y), this will print two different addresses for x. So when looking at the definition of f, we couldn't possibly predict the address of its variables because it isn't even going to be the same within the same run of the program.



            Furthermore your phase isn't going to know which optimizations are going to run after it, which variables are going to be stored in registers or which register are going to be spilled to stack memory - all of which would affect the addresses.






            share|improve this answer
























              up vote
              2
              down vote



              accepted










              You can't.



              It is not even guaranteed the address of the variables will be the same when you run the program multiple times (see Address Space Layout Randomization), so there's no way one could predict the address statically.



              Even if we did know that the stack always started at a fixed address, it is perfectly normal for the same variable to have a different address during different calls of the function. Take this for example:



              #include <stdio.h>

              void f()
              int x;
              printf("The address of x is: %pn", &x);


              void g()
              int y;
              f();


              int main()
              f();
              g();
              return 0;



              Assuming you compile this without optimizations (which would remove the definition of y), this will print two different addresses for x. So when looking at the definition of f, we couldn't possibly predict the address of its variables because it isn't even going to be the same within the same run of the program.



              Furthermore your phase isn't going to know which optimizations are going to run after it, which variables are going to be stored in registers or which register are going to be spilled to stack memory - all of which would affect the addresses.






              share|improve this answer






















                up vote
                2
                down vote



                accepted







                up vote
                2
                down vote



                accepted






                You can't.



                It is not even guaranteed the address of the variables will be the same when you run the program multiple times (see Address Space Layout Randomization), so there's no way one could predict the address statically.



                Even if we did know that the stack always started at a fixed address, it is perfectly normal for the same variable to have a different address during different calls of the function. Take this for example:



                #include <stdio.h>

                void f()
                int x;
                printf("The address of x is: %pn", &x);


                void g()
                int y;
                f();


                int main()
                f();
                g();
                return 0;



                Assuming you compile this without optimizations (which would remove the definition of y), this will print two different addresses for x. So when looking at the definition of f, we couldn't possibly predict the address of its variables because it isn't even going to be the same within the same run of the program.



                Furthermore your phase isn't going to know which optimizations are going to run after it, which variables are going to be stored in registers or which register are going to be spilled to stack memory - all of which would affect the addresses.






                share|improve this answer












                You can't.



                It is not even guaranteed the address of the variables will be the same when you run the program multiple times (see Address Space Layout Randomization), so there's no way one could predict the address statically.



                Even if we did know that the stack always started at a fixed address, it is perfectly normal for the same variable to have a different address during different calls of the function. Take this for example:



                #include <stdio.h>

                void f()
                int x;
                printf("The address of x is: %pn", &x);


                void g()
                int y;
                f();


                int main()
                f();
                g();
                return 0;



                Assuming you compile this without optimizations (which would remove the definition of y), this will print two different addresses for x. So when looking at the definition of f, we couldn't possibly predict the address of its variables because it isn't even going to be the same within the same run of the program.



                Furthermore your phase isn't going to know which optimizations are going to run after it, which variables are going to be stored in registers or which register are going to be spilled to stack memory - all of which would affect the addresses.







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 11 at 15:28









                sepp2k

                291k37593605




                291k37593605



























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