Alias for variables in pattern matching









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I often have something similar to the following (standard type definition for trees):



match tree with
| Branch(v, Branch(vl, tll, tlr), _) = f Branch(vl, tll, tlr)


In other languages there is the ability to do something like:



match tree with
| Branch(v, tl@Branch(_, _, _), _) = f tl


Does OCaml have something similar?










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    up vote
    0
    down vote

    favorite












    I often have something similar to the following (standard type definition for trees):



    match tree with
    | Branch(v, Branch(vl, tll, tlr), _) = f Branch(vl, tll, tlr)


    In other languages there is the ability to do something like:



    match tree with
    | Branch(v, tl@Branch(_, _, _), _) = f tl


    Does OCaml have something similar?










    share|improve this question

























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I often have something similar to the following (standard type definition for trees):



      match tree with
      | Branch(v, Branch(vl, tll, tlr), _) = f Branch(vl, tll, tlr)


      In other languages there is the ability to do something like:



      match tree with
      | Branch(v, tl@Branch(_, _, _), _) = f tl


      Does OCaml have something similar?










      share|improve this question















      I often have something similar to the following (standard type definition for trees):



      match tree with
      | Branch(v, Branch(vl, tll, tlr), _) = f Branch(vl, tll, tlr)


      In other languages there is the ability to do something like:



      match tree with
      | Branch(v, tl@Branch(_, _, _), _) = f tl


      Does OCaml have something similar?







      ocaml






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 11 at 18:13

























      asked Nov 11 at 18:03









      Cjen1

      8581731




      8581731






















          1 Answer
          1






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          up vote
          1
          down vote



          accepted










          This is done using the as keyword in OCaml:



          match tree with
          | Branch(v, (Branch(_, _, _) as tl), _) = f tl





          share|improve this answer






















          • This is failing to compile for me, although it works if I surround the Branch(_,_,_) as tl in parenthesis
            – Cjen1
            Nov 11 at 18:23






          • 1




            @Cjen1 Right, my mistake. Without the parentheses it take v, Branch(_,_,_) to be the left operand of as.
            – sepp2k
            Nov 11 at 18:31










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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          1
          down vote



          accepted










          This is done using the as keyword in OCaml:



          match tree with
          | Branch(v, (Branch(_, _, _) as tl), _) = f tl





          share|improve this answer






















          • This is failing to compile for me, although it works if I surround the Branch(_,_,_) as tl in parenthesis
            – Cjen1
            Nov 11 at 18:23






          • 1




            @Cjen1 Right, my mistake. Without the parentheses it take v, Branch(_,_,_) to be the left operand of as.
            – sepp2k
            Nov 11 at 18:31














          up vote
          1
          down vote



          accepted










          This is done using the as keyword in OCaml:



          match tree with
          | Branch(v, (Branch(_, _, _) as tl), _) = f tl





          share|improve this answer






















          • This is failing to compile for me, although it works if I surround the Branch(_,_,_) as tl in parenthesis
            – Cjen1
            Nov 11 at 18:23






          • 1




            @Cjen1 Right, my mistake. Without the parentheses it take v, Branch(_,_,_) to be the left operand of as.
            – sepp2k
            Nov 11 at 18:31












          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          This is done using the as keyword in OCaml:



          match tree with
          | Branch(v, (Branch(_, _, _) as tl), _) = f tl





          share|improve this answer














          This is done using the as keyword in OCaml:



          match tree with
          | Branch(v, (Branch(_, _, _) as tl), _) = f tl






          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Nov 11 at 18:31

























          answered Nov 11 at 18:16









          sepp2k

          291k38593605




          291k38593605











          • This is failing to compile for me, although it works if I surround the Branch(_,_,_) as tl in parenthesis
            – Cjen1
            Nov 11 at 18:23






          • 1




            @Cjen1 Right, my mistake. Without the parentheses it take v, Branch(_,_,_) to be the left operand of as.
            – sepp2k
            Nov 11 at 18:31
















          • This is failing to compile for me, although it works if I surround the Branch(_,_,_) as tl in parenthesis
            – Cjen1
            Nov 11 at 18:23






          • 1




            @Cjen1 Right, my mistake. Without the parentheses it take v, Branch(_,_,_) to be the left operand of as.
            – sepp2k
            Nov 11 at 18:31















          This is failing to compile for me, although it works if I surround the Branch(_,_,_) as tl in parenthesis
          – Cjen1
          Nov 11 at 18:23




          This is failing to compile for me, although it works if I surround the Branch(_,_,_) as tl in parenthesis
          – Cjen1
          Nov 11 at 18:23




          1




          1




          @Cjen1 Right, my mistake. Without the parentheses it take v, Branch(_,_,_) to be the left operand of as.
          – sepp2k
          Nov 11 at 18:31




          @Cjen1 Right, my mistake. Without the parentheses it take v, Branch(_,_,_) to be the left operand of as.
          – sepp2k
          Nov 11 at 18:31

















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