Odtnhj

I need to process with IsOpen property in a code Behind.

XAML:

DataContext="Binding RelativeSource=RelativeSource Self"
IsOpen="Binding ChildWindow_IsOpen"

Code Behind:

public bool ChildWindow_IsOpen

 

 get return (bool)GetValue(WindowProperty); 
 set SetValue(WindowProperty, value); 

 

 public static readonly DependencyProperty WindowProperty = DependencyProperty.Register("ChildWindow_IsOpen", typeof(bool), typeof(MainWindow));

MainWindow:

 ChildWindow childWindow = new ChildWindow();

 private async void button3_OnClick(object sender, RoutedEventArgs e)

 

 if (childWindow.ChildWindow_IsOpen == false)
 
 await this.ShowChildWindowAsync(new ChildWindow() IsModal = false, AllowMove = true, , RootGrid);

 childWindow.ChildWindow_IsOpen = true;
 

 else if (childWindow.ChildWindow_IsOpen == true)

 
 childWindow.Close();

 childWindow.ChildWindow_IsOpen = false;
 

 else
 
 return;
 


 

So my question is how to do that in a professional way?
My code doesn't affect to ChildWindow at all.

Thanks in advance!

Update: ChildWindow's XAML is situated in MainWindow XAML. This works like a charm!

 private void button1_Click(object sender, RoutedEventArgs e)
 {
 if (ChildWindow.IsOpen == false)

 
 ChildWindow.IsOpen = true;

 

 else if (ChildWindow.IsOpen == true)

 

 ChildWindow.Close();

 

 else 

 

 return;