How to find shortest path in prolog with weighted graph









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I have this code :



link(a,b,4). 
link(a,c,2).
link(b,g,5).
link(c,g,6).
link(c,d,5).
link(d,g,3).

path(S,D,TDist):-
link(S,D,TDist).
path(S,D,TDist):-
link(S,X,TD1), path(X,D,TD2), TDist=TD1+TD2.


This will follow a depth first search strategy, but the result is that it will give me all the paths, and it won't show which is the shortest. Is it possible to still use that strategy and find the shortest path? if not, what search strategy to use? and how can I implement it.










share|improve this question



























    up vote
    0
    down vote

    favorite












    I have this code :



    link(a,b,4). 
    link(a,c,2).
    link(b,g,5).
    link(c,g,6).
    link(c,d,5).
    link(d,g,3).

    path(S,D,TDist):-
    link(S,D,TDist).
    path(S,D,TDist):-
    link(S,X,TD1), path(X,D,TD2), TDist=TD1+TD2.


    This will follow a depth first search strategy, but the result is that it will give me all the paths, and it won't show which is the shortest. Is it possible to still use that strategy and find the shortest path? if not, what search strategy to use? and how can I implement it.










    share|improve this question

























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      I have this code :



      link(a,b,4). 
      link(a,c,2).
      link(b,g,5).
      link(c,g,6).
      link(c,d,5).
      link(d,g,3).

      path(S,D,TDist):-
      link(S,D,TDist).
      path(S,D,TDist):-
      link(S,X,TD1), path(X,D,TD2), TDist=TD1+TD2.


      This will follow a depth first search strategy, but the result is that it will give me all the paths, and it won't show which is the shortest. Is it possible to still use that strategy and find the shortest path? if not, what search strategy to use? and how can I implement it.










      share|improve this question















      I have this code :



      link(a,b,4). 
      link(a,c,2).
      link(b,g,5).
      link(c,g,6).
      link(c,d,5).
      link(d,g,3).

      path(S,D,TDist):-
      link(S,D,TDist).
      path(S,D,TDist):-
      link(S,X,TD1), path(X,D,TD2), TDist=TD1+TD2.


      This will follow a depth first search strategy, but the result is that it will give me all the paths, and it won't show which is the shortest. Is it possible to still use that strategy and find the shortest path? if not, what search strategy to use? and how can I implement it.







      prolog depth-first-search shortest-path uniform-cost-search






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 13 at 0:22









      false

      10.9k769141




      10.9k769141










      asked Nov 10 at 19:08









      sosscs

      363




      363






















          1 Answer
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          up vote
          0
          down vote













          I think there are problems with your code:



          • TDist=TD1+TD2 doesn't compute the sum, use is/2 instead, at least when a path is returned.


          • It will loop if the graph contains cycles, but assuming the data actually is a DAG, we can ignore by now.


          • We can't say what the actual path will be, just its value.


          Anyway, library(aggregate) can be used to find the shortest path. For instance



          ?- aggregate(min(D), path(a,g,D), D).
          D = 8.


          Or, since gnu-prolog doesn't have library(aggregate), take the first element computed by setof/3:



          ?- setof(D, path(a,g,D), [Min|Rest]).
          Min = 8,
          Rest = [9, 10].





          share|improve this answer




















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            up vote
            0
            down vote













            I think there are problems with your code:



            • TDist=TD1+TD2 doesn't compute the sum, use is/2 instead, at least when a path is returned.


            • It will loop if the graph contains cycles, but assuming the data actually is a DAG, we can ignore by now.


            • We can't say what the actual path will be, just its value.


            Anyway, library(aggregate) can be used to find the shortest path. For instance



            ?- aggregate(min(D), path(a,g,D), D).
            D = 8.


            Or, since gnu-prolog doesn't have library(aggregate), take the first element computed by setof/3:



            ?- setof(D, path(a,g,D), [Min|Rest]).
            Min = 8,
            Rest = [9, 10].





            share|improve this answer
























              up vote
              0
              down vote













              I think there are problems with your code:



              • TDist=TD1+TD2 doesn't compute the sum, use is/2 instead, at least when a path is returned.


              • It will loop if the graph contains cycles, but assuming the data actually is a DAG, we can ignore by now.


              • We can't say what the actual path will be, just its value.


              Anyway, library(aggregate) can be used to find the shortest path. For instance



              ?- aggregate(min(D), path(a,g,D), D).
              D = 8.


              Or, since gnu-prolog doesn't have library(aggregate), take the first element computed by setof/3:



              ?- setof(D, path(a,g,D), [Min|Rest]).
              Min = 8,
              Rest = [9, 10].





              share|improve this answer






















                up vote
                0
                down vote










                up vote
                0
                down vote









                I think there are problems with your code:



                • TDist=TD1+TD2 doesn't compute the sum, use is/2 instead, at least when a path is returned.


                • It will loop if the graph contains cycles, but assuming the data actually is a DAG, we can ignore by now.


                • We can't say what the actual path will be, just its value.


                Anyway, library(aggregate) can be used to find the shortest path. For instance



                ?- aggregate(min(D), path(a,g,D), D).
                D = 8.


                Or, since gnu-prolog doesn't have library(aggregate), take the first element computed by setof/3:



                ?- setof(D, path(a,g,D), [Min|Rest]).
                Min = 8,
                Rest = [9, 10].





                share|improve this answer












                I think there are problems with your code:



                • TDist=TD1+TD2 doesn't compute the sum, use is/2 instead, at least when a path is returned.


                • It will loop if the graph contains cycles, but assuming the data actually is a DAG, we can ignore by now.


                • We can't say what the actual path will be, just its value.


                Anyway, library(aggregate) can be used to find the shortest path. For instance



                ?- aggregate(min(D), path(a,g,D), D).
                D = 8.


                Or, since gnu-prolog doesn't have library(aggregate), take the first element computed by setof/3:



                ?- setof(D, path(a,g,D), [Min|Rest]).
                Min = 8,
                Rest = [9, 10].






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 10 at 19:35









                CapelliC

                50.8k43262




                50.8k43262



























                     

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