Can a Descriptor change type in Typescript?









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I'm trying to make descriptor which can change return type in typescript but I don't know how to do this.



Here is the code and what I tried:



function changeReturnType()

return <T extends unknown>(
target: ,
key: string

class Foo
@changeReturnType()
square ()

return 1;



let val = new Foo().square(); // I hope ts know here is string

console.dir(
val,
type: typeof val,
);









share|improve this question



























    up vote
    1
    down vote

    favorite
    1












    I'm trying to make descriptor which can change return type in typescript but I don't know how to do this.



    Here is the code and what I tried:



    function changeReturnType()

    return <T extends unknown>(
    target: ,
    key: string

    class Foo
    @changeReturnType()
    square ()

    return 1;



    let val = new Foo().square(); // I hope ts know here is string

    console.dir(
    val,
    type: typeof val,
    );









    share|improve this question

























      up vote
      1
      down vote

      favorite
      1









      up vote
      1
      down vote

      favorite
      1






      1





      I'm trying to make descriptor which can change return type in typescript but I don't know how to do this.



      Here is the code and what I tried:



      function changeReturnType()

      return <T extends unknown>(
      target: ,
      key: string

      class Foo
      @changeReturnType()
      square ()

      return 1;



      let val = new Foo().square(); // I hope ts know here is string

      console.dir(
      val,
      type: typeof val,
      );









      share|improve this question















      I'm trying to make descriptor which can change return type in typescript but I don't know how to do this.



      Here is the code and what I tried:



      function changeReturnType()

      return <T extends unknown>(
      target: ,
      key: string

      class Foo
      @changeReturnType()
      square ()

      return 1;



      let val = new Foo().square(); // I hope ts know here is string

      console.dir(
      val,
      type: typeof val,
      );






      javascript node.js typescript types descriptor






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      share|improve this question













      share|improve this question




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      edited Nov 11 at 7:15









      Roy Scheffers

      2,12281625




      2,12281625










      asked Nov 11 at 6:06









      bluelovers

      1388




      1388






















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          0
          down vote













          This is currently not possible in TypeScript but you may look at this comment and modify hack described there to your needs (i.e. for method decorator usage).






          share|improve this answer




















          • The situation is different in linked comment. Returned type is ignored in class decorator, while in method decorator it's taken into account, so decorated method type is incompatible with original method.
            – estus
            Nov 11 at 15:32










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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          0
          down vote













          This is currently not possible in TypeScript but you may look at this comment and modify hack described there to your needs (i.e. for method decorator usage).






          share|improve this answer




















          • The situation is different in linked comment. Returned type is ignored in class decorator, while in method decorator it's taken into account, so decorated method type is incompatible with original method.
            – estus
            Nov 11 at 15:32














          up vote
          0
          down vote













          This is currently not possible in TypeScript but you may look at this comment and modify hack described there to your needs (i.e. for method decorator usage).






          share|improve this answer




















          • The situation is different in linked comment. Returned type is ignored in class decorator, while in method decorator it's taken into account, so decorated method type is incompatible with original method.
            – estus
            Nov 11 at 15:32












          up vote
          0
          down vote










          up vote
          0
          down vote









          This is currently not possible in TypeScript but you may look at this comment and modify hack described there to your needs (i.e. for method decorator usage).






          share|improve this answer












          This is currently not possible in TypeScript but you may look at this comment and modify hack described there to your needs (i.e. for method decorator usage).







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 11 at 10:10









          syntagma

          12.4k1248103




          12.4k1248103











          • The situation is different in linked comment. Returned type is ignored in class decorator, while in method decorator it's taken into account, so decorated method type is incompatible with original method.
            – estus
            Nov 11 at 15:32
















          • The situation is different in linked comment. Returned type is ignored in class decorator, while in method decorator it's taken into account, so decorated method type is incompatible with original method.
            – estus
            Nov 11 at 15:32















          The situation is different in linked comment. Returned type is ignored in class decorator, while in method decorator it's taken into account, so decorated method type is incompatible with original method.
          – estus
          Nov 11 at 15:32




          The situation is different in linked comment. Returned type is ignored in class decorator, while in method decorator it's taken into account, so decorated method type is incompatible with original method.
          – estus
          Nov 11 at 15:32

















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