Update a user entity field in JPQL with IN clause










0















I have a class user where I need to update the loginCount and lastLogin.
Some users have already logged in and updated data, so I want to update there loginCount to 1.



I tried to use JPQL.



I created a query, where I am sending loginCount variable = 1, lastLogin as currentDate and ids as a combination of all ids as CommaSeparatedString.



@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") String ids);


I want to use 'IN' clause but here I got a problem that by to use IN clause I have to have a comma-delimited-string but my id which I am finding is of type Long.




ERROR:
Parameter value [1,2] did not match expected type [java.lang.Long(n/a)]



Is there a way to resolve this?










share|improve this question






















  • You need to pass ids as a List<Long> ids and change the param type of ids in the method param as well.

    – Erfan Ahmed
    Nov 15 '18 at 7:16












  • Thanks Erfan Ahmed Emon

    – Sudhanshu Gupta
    Nov 15 '18 at 7:41















0















I have a class user where I need to update the loginCount and lastLogin.
Some users have already logged in and updated data, so I want to update there loginCount to 1.



I tried to use JPQL.



I created a query, where I am sending loginCount variable = 1, lastLogin as currentDate and ids as a combination of all ids as CommaSeparatedString.



@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") String ids);


I want to use 'IN' clause but here I got a problem that by to use IN clause I have to have a comma-delimited-string but my id which I am finding is of type Long.




ERROR:
Parameter value [1,2] did not match expected type [java.lang.Long(n/a)]



Is there a way to resolve this?










share|improve this question






















  • You need to pass ids as a List<Long> ids and change the param type of ids in the method param as well.

    – Erfan Ahmed
    Nov 15 '18 at 7:16












  • Thanks Erfan Ahmed Emon

    – Sudhanshu Gupta
    Nov 15 '18 at 7:41













0












0








0








I have a class user where I need to update the loginCount and lastLogin.
Some users have already logged in and updated data, so I want to update there loginCount to 1.



I tried to use JPQL.



I created a query, where I am sending loginCount variable = 1, lastLogin as currentDate and ids as a combination of all ids as CommaSeparatedString.



@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") String ids);


I want to use 'IN' clause but here I got a problem that by to use IN clause I have to have a comma-delimited-string but my id which I am finding is of type Long.




ERROR:
Parameter value [1,2] did not match expected type [java.lang.Long(n/a)]



Is there a way to resolve this?










share|improve this question














I have a class user where I need to update the loginCount and lastLogin.
Some users have already logged in and updated data, so I want to update there loginCount to 1.



I tried to use JPQL.



I created a query, where I am sending loginCount variable = 1, lastLogin as currentDate and ids as a combination of all ids as CommaSeparatedString.



@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") String ids);


I want to use 'IN' clause but here I got a problem that by to use IN clause I have to have a comma-delimited-string but my id which I am finding is of type Long.




ERROR:
Parameter value [1,2] did not match expected type [java.lang.Long(n/a)]



Is there a way to resolve this?







java hibernate jpql






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asked Nov 15 '18 at 7:10









Sudhanshu GuptaSudhanshu Gupta

75931753




75931753












  • You need to pass ids as a List<Long> ids and change the param type of ids in the method param as well.

    – Erfan Ahmed
    Nov 15 '18 at 7:16












  • Thanks Erfan Ahmed Emon

    – Sudhanshu Gupta
    Nov 15 '18 at 7:41

















  • You need to pass ids as a List<Long> ids and change the param type of ids in the method param as well.

    – Erfan Ahmed
    Nov 15 '18 at 7:16












  • Thanks Erfan Ahmed Emon

    – Sudhanshu Gupta
    Nov 15 '18 at 7:41
















You need to pass ids as a List<Long> ids and change the param type of ids in the method param as well.

– Erfan Ahmed
Nov 15 '18 at 7:16






You need to pass ids as a List<Long> ids and change the param type of ids in the method param as well.

– Erfan Ahmed
Nov 15 '18 at 7:16














Thanks Erfan Ahmed Emon

– Sudhanshu Gupta
Nov 15 '18 at 7:41





Thanks Erfan Ahmed Emon

– Sudhanshu Gupta
Nov 15 '18 at 7:41












1 Answer
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oldest

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1














You need to pass list of long as Param for ids instead of String.



@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") List<Long> ids);


And when you call this method create an array list of Long and add the ids in it and pass as parameter.






share|improve this answer























  • Thanks, Pooja, I should have known that. TCH

    – Sudhanshu Gupta
    Nov 15 '18 at 7:32










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1 Answer
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1 Answer
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active

oldest

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oldest

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oldest

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1














You need to pass list of long as Param for ids instead of String.



@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") List<Long> ids);


And when you call this method create an array list of Long and add the ids in it and pass as parameter.






share|improve this answer























  • Thanks, Pooja, I should have known that. TCH

    – Sudhanshu Gupta
    Nov 15 '18 at 7:32















1














You need to pass list of long as Param for ids instead of String.



@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") List<Long> ids);


And when you call this method create an array list of Long and add the ids in it and pass as parameter.






share|improve this answer























  • Thanks, Pooja, I should have known that. TCH

    – Sudhanshu Gupta
    Nov 15 '18 at 7:32













1












1








1







You need to pass list of long as Param for ids instead of String.



@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") List<Long> ids);


And when you call this method create an array list of Long and add the ids in it and pass as parameter.






share|improve this answer













You need to pass list of long as Param for ids instead of String.



@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") List<Long> ids);


And when you call this method create an array list of Long and add the ids in it and pass as parameter.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 '18 at 7:14









Pooja AggarwalPooja Aggarwal

870211




870211












  • Thanks, Pooja, I should have known that. TCH

    – Sudhanshu Gupta
    Nov 15 '18 at 7:32

















  • Thanks, Pooja, I should have known that. TCH

    – Sudhanshu Gupta
    Nov 15 '18 at 7:32
















Thanks, Pooja, I should have known that. TCH

– Sudhanshu Gupta
Nov 15 '18 at 7:32





Thanks, Pooja, I should have known that. TCH

– Sudhanshu Gupta
Nov 15 '18 at 7:32



















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