Update a user entity field in JPQL with IN clause
I have a class user where I need to update the loginCount and lastLogin.
Some users have already logged in and updated data, so I want to update there loginCount to 1.
I tried to use JPQL.
I created a query, where I am sending loginCount variable = 1, lastLogin as currentDate and ids as a combination of all ids as CommaSeparatedString.
@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") String ids);
I want to use 'IN' clause but here I got a problem that by to use IN clause I have to have a comma-delimited-string but my id which I am finding is of type Long.
ERROR:
Parameter value [1,2] did not match expected type [java.lang.Long(n/a)]
Is there a way to resolve this?
java hibernate jpql
add a comment |
I have a class user where I need to update the loginCount and lastLogin.
Some users have already logged in and updated data, so I want to update there loginCount to 1.
I tried to use JPQL.
I created a query, where I am sending loginCount variable = 1, lastLogin as currentDate and ids as a combination of all ids as CommaSeparatedString.
@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") String ids);
I want to use 'IN' clause but here I got a problem that by to use IN clause I have to have a comma-delimited-string but my id which I am finding is of type Long.
ERROR:
Parameter value [1,2] did not match expected type [java.lang.Long(n/a)]
Is there a way to resolve this?
java hibernate jpql
You need to passids
as aList<Long> ids
and change the param type ofids
in the method param as well.
– Erfan Ahmed
Nov 15 '18 at 7:16
Thanks Erfan Ahmed Emon
– Sudhanshu Gupta
Nov 15 '18 at 7:41
add a comment |
I have a class user where I need to update the loginCount and lastLogin.
Some users have already logged in and updated data, so I want to update there loginCount to 1.
I tried to use JPQL.
I created a query, where I am sending loginCount variable = 1, lastLogin as currentDate and ids as a combination of all ids as CommaSeparatedString.
@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") String ids);
I want to use 'IN' clause but here I got a problem that by to use IN clause I have to have a comma-delimited-string but my id which I am finding is of type Long.
ERROR:
Parameter value [1,2] did not match expected type [java.lang.Long(n/a)]
Is there a way to resolve this?
java hibernate jpql
I have a class user where I need to update the loginCount and lastLogin.
Some users have already logged in and updated data, so I want to update there loginCount to 1.
I tried to use JPQL.
I created a query, where I am sending loginCount variable = 1, lastLogin as currentDate and ids as a combination of all ids as CommaSeparatedString.
@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") String ids);
I want to use 'IN' clause but here I got a problem that by to use IN clause I have to have a comma-delimited-string but my id which I am finding is of type Long.
ERROR:
Parameter value [1,2] did not match expected type [java.lang.Long(n/a)]
Is there a way to resolve this?
java hibernate jpql
java hibernate jpql
asked Nov 15 '18 at 7:10
Sudhanshu GuptaSudhanshu Gupta
75931753
75931753
You need to passids
as aList<Long> ids
and change the param type ofids
in the method param as well.
– Erfan Ahmed
Nov 15 '18 at 7:16
Thanks Erfan Ahmed Emon
– Sudhanshu Gupta
Nov 15 '18 at 7:41
add a comment |
You need to passids
as aList<Long> ids
and change the param type ofids
in the method param as well.
– Erfan Ahmed
Nov 15 '18 at 7:16
Thanks Erfan Ahmed Emon
– Sudhanshu Gupta
Nov 15 '18 at 7:41
You need to pass
ids
as a List<Long> ids
and change the param type of ids
in the method param as well.– Erfan Ahmed
Nov 15 '18 at 7:16
You need to pass
ids
as a List<Long> ids
and change the param type of ids
in the method param as well.– Erfan Ahmed
Nov 15 '18 at 7:16
Thanks Erfan Ahmed Emon
– Sudhanshu Gupta
Nov 15 '18 at 7:41
Thanks Erfan Ahmed Emon
– Sudhanshu Gupta
Nov 15 '18 at 7:41
add a comment |
1 Answer
1
active
oldest
votes
You need to pass list of long as Param for ids instead of String.
@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") List<Long> ids);
And when you call this method create an array list of Long and add the ids in it and pass as parameter.
Thanks, Pooja, I should have known that. TCH
– Sudhanshu Gupta
Nov 15 '18 at 7:32
add a comment |
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You need to pass list of long as Param for ids instead of String.
@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") List<Long> ids);
And when you call this method create an array list of Long and add the ids in it and pass as parameter.
Thanks, Pooja, I should have known that. TCH
– Sudhanshu Gupta
Nov 15 '18 at 7:32
add a comment |
You need to pass list of long as Param for ids instead of String.
@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") List<Long> ids);
And when you call this method create an array list of Long and add the ids in it and pass as parameter.
Thanks, Pooja, I should have known that. TCH
– Sudhanshu Gupta
Nov 15 '18 at 7:32
add a comment |
You need to pass list of long as Param for ids instead of String.
@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") List<Long> ids);
And when you call this method create an array list of Long and add the ids in it and pass as parameter.
You need to pass list of long as Param for ids instead of String.
@Query("update User u set u.loginCount = :loginCount, u.lastLogin = :lastLogin where u.id IN (:ids)")
void updateUserInitialLoginCount(@Param("loginCount") Long loginCount, @Param("lastLogin") Date lastLogin, @Param("ids") List<Long> ids);
And when you call this method create an array list of Long and add the ids in it and pass as parameter.
answered Nov 15 '18 at 7:14
Pooja AggarwalPooja Aggarwal
870211
870211
Thanks, Pooja, I should have known that. TCH
– Sudhanshu Gupta
Nov 15 '18 at 7:32
add a comment |
Thanks, Pooja, I should have known that. TCH
– Sudhanshu Gupta
Nov 15 '18 at 7:32
Thanks, Pooja, I should have known that. TCH
– Sudhanshu Gupta
Nov 15 '18 at 7:32
Thanks, Pooja, I should have known that. TCH
– Sudhanshu Gupta
Nov 15 '18 at 7:32
add a comment |
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You need to pass
ids
as aList<Long> ids
and change the param type ofids
in the method param as well.– Erfan Ahmed
Nov 15 '18 at 7:16
Thanks Erfan Ahmed Emon
– Sudhanshu Gupta
Nov 15 '18 at 7:41