Logstash - Join two Dicts










1















i wrote a small working example to explain my question:



input 
stdin
codec => "json"


filter
mutate
rename => "[DictA]" => "[ZielDict]"
rename => "[DictB]" => "[ZielDict]"


output
stdout



Input




"DictA":
"valueA": 123
,
"DictB":
"valueB": 456




Output




"@version" => "1",
"host" => "78f85c66a671",
"@timestamp" => 2018-11-15T12:11:01.193Z,
"ZielDict" =>
"valueB" => 456




Wanted Output (i dont want to override DictA!)




"@version" => "1",
"host" => "78f85c66a671",
"@timestamp" => 2018-11-15T12:11:01.193Z,
"ZielDict" =>
"valueA" => 123
"valueB" => 456




So as you can see i want to append to the ZielDict instead of overriding it with DictB. How can i handle this?
Thanks in advance!










share|improve this question




























    1















    i wrote a small working example to explain my question:



    input 
    stdin
    codec => "json"


    filter
    mutate
    rename => "[DictA]" => "[ZielDict]"
    rename => "[DictB]" => "[ZielDict]"


    output
    stdout



    Input




    "DictA":
    "valueA": 123
    ,
    "DictB":
    "valueB": 456




    Output




    "@version" => "1",
    "host" => "78f85c66a671",
    "@timestamp" => 2018-11-15T12:11:01.193Z,
    "ZielDict" =>
    "valueB" => 456




    Wanted Output (i dont want to override DictA!)




    "@version" => "1",
    "host" => "78f85c66a671",
    "@timestamp" => 2018-11-15T12:11:01.193Z,
    "ZielDict" =>
    "valueA" => 123
    "valueB" => 456




    So as you can see i want to append to the ZielDict instead of overriding it with DictB. How can i handle this?
    Thanks in advance!










    share|improve this question


























      1












      1








      1








      i wrote a small working example to explain my question:



      input 
      stdin
      codec => "json"


      filter
      mutate
      rename => "[DictA]" => "[ZielDict]"
      rename => "[DictB]" => "[ZielDict]"


      output
      stdout



      Input




      "DictA":
      "valueA": 123
      ,
      "DictB":
      "valueB": 456




      Output




      "@version" => "1",
      "host" => "78f85c66a671",
      "@timestamp" => 2018-11-15T12:11:01.193Z,
      "ZielDict" =>
      "valueB" => 456




      Wanted Output (i dont want to override DictA!)




      "@version" => "1",
      "host" => "78f85c66a671",
      "@timestamp" => 2018-11-15T12:11:01.193Z,
      "ZielDict" =>
      "valueA" => 123
      "valueB" => 456




      So as you can see i want to append to the ZielDict instead of overriding it with DictB. How can i handle this?
      Thanks in advance!










      share|improve this question
















      i wrote a small working example to explain my question:



      input 
      stdin
      codec => "json"


      filter
      mutate
      rename => "[DictA]" => "[ZielDict]"
      rename => "[DictB]" => "[ZielDict]"


      output
      stdout



      Input




      "DictA":
      "valueA": 123
      ,
      "DictB":
      "valueB": 456




      Output




      "@version" => "1",
      "host" => "78f85c66a671",
      "@timestamp" => 2018-11-15T12:11:01.193Z,
      "ZielDict" =>
      "valueB" => 456




      Wanted Output (i dont want to override DictA!)




      "@version" => "1",
      "host" => "78f85c66a671",
      "@timestamp" => 2018-11-15T12:11:01.193Z,
      "ZielDict" =>
      "valueA" => 123
      "valueB" => 456




      So as you can see i want to append to the ZielDict instead of overriding it with DictB. How can i handle this?
      Thanks in advance!







      logstash






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 15 '18 at 12:21







      Che Veyo

















      asked Nov 15 '18 at 12:14









      Che VeyoChe Veyo

      10511




      10511






















          1 Answer
          1






          active

          oldest

          votes


















          1














          Use the mutate.merge option:



          input 
          stdin
          codec => "json"


          filter
          mutate
          merge => "DictA" => "DictB"


          output
          stdout



          With this configuration, you get:




          "host" => "frsred-0077",
          "@timestamp" => 2018-11-15T13:54:19.923Z,
          "DictA" =>
          "valueB" => 456,
          "valueA" => 123
          ,
          "DictB" =>
          "valueB" => 456
          ,
          "@version" => "1"



          You'll have to remove the DictB field and rename the DictA to get your wanted output.






          share|improve this answer























          • Thanks it works :)

            – Che Veyo
            Nov 16 '18 at 18:05










          Your Answer






          StackExchange.ifUsing("editor", function ()
          StackExchange.using("externalEditor", function ()
          StackExchange.using("snippets", function ()
          StackExchange.snippets.init();
          );
          );
          , "code-snippets");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "1"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader:
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          ,
          onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );













          draft saved

          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53319282%2flogstash-join-two-dicts%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          1














          Use the mutate.merge option:



          input 
          stdin
          codec => "json"


          filter
          mutate
          merge => "DictA" => "DictB"


          output
          stdout



          With this configuration, you get:




          "host" => "frsred-0077",
          "@timestamp" => 2018-11-15T13:54:19.923Z,
          "DictA" =>
          "valueB" => 456,
          "valueA" => 123
          ,
          "DictB" =>
          "valueB" => 456
          ,
          "@version" => "1"



          You'll have to remove the DictB field and rename the DictA to get your wanted output.






          share|improve this answer























          • Thanks it works :)

            – Che Veyo
            Nov 16 '18 at 18:05















          1














          Use the mutate.merge option:



          input 
          stdin
          codec => "json"


          filter
          mutate
          merge => "DictA" => "DictB"


          output
          stdout



          With this configuration, you get:




          "host" => "frsred-0077",
          "@timestamp" => 2018-11-15T13:54:19.923Z,
          "DictA" =>
          "valueB" => 456,
          "valueA" => 123
          ,
          "DictB" =>
          "valueB" => 456
          ,
          "@version" => "1"



          You'll have to remove the DictB field and rename the DictA to get your wanted output.






          share|improve this answer























          • Thanks it works :)

            – Che Veyo
            Nov 16 '18 at 18:05













          1












          1








          1







          Use the mutate.merge option:



          input 
          stdin
          codec => "json"


          filter
          mutate
          merge => "DictA" => "DictB"


          output
          stdout



          With this configuration, you get:




          "host" => "frsred-0077",
          "@timestamp" => 2018-11-15T13:54:19.923Z,
          "DictA" =>
          "valueB" => 456,
          "valueA" => 123
          ,
          "DictB" =>
          "valueB" => 456
          ,
          "@version" => "1"



          You'll have to remove the DictB field and rename the DictA to get your wanted output.






          share|improve this answer













          Use the mutate.merge option:



          input 
          stdin
          codec => "json"


          filter
          mutate
          merge => "DictA" => "DictB"


          output
          stdout



          With this configuration, you get:




          "host" => "frsred-0077",
          "@timestamp" => 2018-11-15T13:54:19.923Z,
          "DictA" =>
          "valueB" => 456,
          "valueA" => 123
          ,
          "DictB" =>
          "valueB" => 456
          ,
          "@version" => "1"



          You'll have to remove the DictB field and rename the DictA to get your wanted output.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 15 '18 at 13:57









          baudspbaudsp

          3,12011228




          3,12011228












          • Thanks it works :)

            – Che Veyo
            Nov 16 '18 at 18:05

















          • Thanks it works :)

            – Che Veyo
            Nov 16 '18 at 18:05
















          Thanks it works :)

          – Che Veyo
          Nov 16 '18 at 18:05





          Thanks it works :)

          – Che Veyo
          Nov 16 '18 at 18:05



















          draft saved

          draft discarded
















































          Thanks for contributing an answer to Stack Overflow!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid


          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.

          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53319282%2flogstash-join-two-dicts%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          這個網誌中的熱門文章

          Barbados

          How to read a connectionString WITH PROVIDER in .NET Core?

          Node.js Script on GitHub Pages or Amazon S3