JQuery Datepicker is not working when appending new row - JQuery UI
I have a datepicker
in a table. the <tr>
appends when button
clicked.
It's work fine when populate 1st <tr>
but when 2nd <tr>
created on button
click, datepicker
is not working.
Check My Fiddle
jquery jquery-ui jquery-ui-datepicker
add a comment |
I have a datepicker
in a table. the <tr>
appends when button
clicked.
It's work fine when populate 1st <tr>
but when 2nd <tr>
created on button
click, datepicker
is not working.
Check My Fiddle
jquery jquery-ui jquery-ui-datepicker
add a comment |
I have a datepicker
in a table. the <tr>
appends when button
clicked.
It's work fine when populate 1st <tr>
but when 2nd <tr>
created on button
click, datepicker
is not working.
Check My Fiddle
jquery jquery-ui jquery-ui-datepicker
I have a datepicker
in a table. the <tr>
appends when button
clicked.
It's work fine when populate 1st <tr>
but when 2nd <tr>
created on button
click, datepicker
is not working.
Check My Fiddle
jquery jquery-ui jquery-ui-datepicker
jquery jquery-ui jquery-ui-datepicker
asked Nov 15 '18 at 12:13
HuzaifaHuzaifa
347
347
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
This code should do the trick. You need to remove the id
from the date input. Since, datepicker
uses the id internally and this must be unique. Also, in case you still need ids on each field. I added a counter, so that you could create unique ids for each row.
// Variable that we will be using to create unique ids.
var counter = 0;
$('#addnew').click(function ()
//Creating <tr> for cheque details
var tr = $("<tr><td class='banks'><input type="text" class="form-control Product" name="Product"+ counter +"" id="Product"+ counter +"" placeholder="Product"></td>"
+ "<td><div>"
+ "<div class="input-group date">"
+ "<div class="input-group-addon"><i class="fa fa-calendar"></i>"
+ "</div>"
+ "<input type="text" class="form-control Date" name="ChqDate" id="Datet"+ counter +"" placeholder="Date">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type="text" name="Price" class="form-control" id="Pricet"+ counter +"" placeholder="Price" /></td>"
+ "<td><button data-itemId="0" type="button" class="btn btn-danger removeRow">remove</button></td></tr>");
//append <tr> into table <tbody>
$('#example1 tbody').append(tr);
$(tr).find('.Date').datepicker(
autoclose: true
);
counter++;
);
Hope it works.
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
This code should do the trick. You need to remove the id
from the date input. Since, datepicker
uses the id internally and this must be unique. Also, in case you still need ids on each field. I added a counter, so that you could create unique ids for each row.
// Variable that we will be using to create unique ids.
var counter = 0;
$('#addnew').click(function ()
//Creating <tr> for cheque details
var tr = $("<tr><td class='banks'><input type="text" class="form-control Product" name="Product"+ counter +"" id="Product"+ counter +"" placeholder="Product"></td>"
+ "<td><div>"
+ "<div class="input-group date">"
+ "<div class="input-group-addon"><i class="fa fa-calendar"></i>"
+ "</div>"
+ "<input type="text" class="form-control Date" name="ChqDate" id="Datet"+ counter +"" placeholder="Date">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type="text" name="Price" class="form-control" id="Pricet"+ counter +"" placeholder="Price" /></td>"
+ "<td><button data-itemId="0" type="button" class="btn btn-danger removeRow">remove</button></td></tr>");
//append <tr> into table <tbody>
$('#example1 tbody').append(tr);
$(tr).find('.Date').datepicker(
autoclose: true
);
counter++;
);
Hope it works.
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
add a comment |
This code should do the trick. You need to remove the id
from the date input. Since, datepicker
uses the id internally and this must be unique. Also, in case you still need ids on each field. I added a counter, so that you could create unique ids for each row.
// Variable that we will be using to create unique ids.
var counter = 0;
$('#addnew').click(function ()
//Creating <tr> for cheque details
var tr = $("<tr><td class='banks'><input type="text" class="form-control Product" name="Product"+ counter +"" id="Product"+ counter +"" placeholder="Product"></td>"
+ "<td><div>"
+ "<div class="input-group date">"
+ "<div class="input-group-addon"><i class="fa fa-calendar"></i>"
+ "</div>"
+ "<input type="text" class="form-control Date" name="ChqDate" id="Datet"+ counter +"" placeholder="Date">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type="text" name="Price" class="form-control" id="Pricet"+ counter +"" placeholder="Price" /></td>"
+ "<td><button data-itemId="0" type="button" class="btn btn-danger removeRow">remove</button></td></tr>");
//append <tr> into table <tbody>
$('#example1 tbody').append(tr);
$(tr).find('.Date').datepicker(
autoclose: true
);
counter++;
);
Hope it works.
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
add a comment |
This code should do the trick. You need to remove the id
from the date input. Since, datepicker
uses the id internally and this must be unique. Also, in case you still need ids on each field. I added a counter, so that you could create unique ids for each row.
// Variable that we will be using to create unique ids.
var counter = 0;
$('#addnew').click(function ()
//Creating <tr> for cheque details
var tr = $("<tr><td class='banks'><input type="text" class="form-control Product" name="Product"+ counter +"" id="Product"+ counter +"" placeholder="Product"></td>"
+ "<td><div>"
+ "<div class="input-group date">"
+ "<div class="input-group-addon"><i class="fa fa-calendar"></i>"
+ "</div>"
+ "<input type="text" class="form-control Date" name="ChqDate" id="Datet"+ counter +"" placeholder="Date">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type="text" name="Price" class="form-control" id="Pricet"+ counter +"" placeholder="Price" /></td>"
+ "<td><button data-itemId="0" type="button" class="btn btn-danger removeRow">remove</button></td></tr>");
//append <tr> into table <tbody>
$('#example1 tbody').append(tr);
$(tr).find('.Date').datepicker(
autoclose: true
);
counter++;
);
Hope it works.
This code should do the trick. You need to remove the id
from the date input. Since, datepicker
uses the id internally and this must be unique. Also, in case you still need ids on each field. I added a counter, so that you could create unique ids for each row.
// Variable that we will be using to create unique ids.
var counter = 0;
$('#addnew').click(function ()
//Creating <tr> for cheque details
var tr = $("<tr><td class='banks'><input type="text" class="form-control Product" name="Product"+ counter +"" id="Product"+ counter +"" placeholder="Product"></td>"
+ "<td><div>"
+ "<div class="input-group date">"
+ "<div class="input-group-addon"><i class="fa fa-calendar"></i>"
+ "</div>"
+ "<input type="text" class="form-control Date" name="ChqDate" id="Datet"+ counter +"" placeholder="Date">"
+ "</div><!-- /.input group -->"
+ "</div></td>"
+ "<td><input type="text" name="Price" class="form-control" id="Pricet"+ counter +"" placeholder="Price" /></td>"
+ "<td><button data-itemId="0" type="button" class="btn btn-danger removeRow">remove</button></td></tr>");
//append <tr> into table <tbody>
$('#example1 tbody').append(tr);
$(tr).find('.Date').datepicker(
autoclose: true
);
counter++;
);
Hope it works.
edited Nov 15 '18 at 12:33
answered Nov 15 '18 at 12:22
Alain CruzAlain Cruz
2,1003920
2,1003920
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
add a comment |
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
Thanks brother it works fine. :-)
– Huzaifa
Nov 15 '18 at 13:01
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
I am glad I was of help! :)
– Alain Cruz
Nov 15 '18 at 13:02
add a comment |
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