Finding MST with a given path (C++)
I have a code for finding MST which would include a given path to MST, which gives me correct weight of MST (I know what the output is supposed to be). I tried to rewrite one part of the code to use std::map
instead of std::vector
for more efficient look-up (will become clear from the code below), but now it gives wrong answer, and despite looking into it for few hours, I am unable to understand where did I make a mistake. Any help with locating a bug will be appreciated.
Old version that uses vector<Edge>
. Goes through the vector of all edges (m_all_edges
). If an edge e
is in vector<Edge> path
, adds it to MST (m_mst
). Otherwise, adds it to candidate edges for MST (m_edges
).
void MSTPath::m_add_shortest_path_old(vector<Edge> path)
for (auto e : path)
m_graph->union_vu(e.get_node(),e.get_opposite_node(-1));
for (auto e : m_all_edges)
if (tempfunc(e,path)) m_mst.push_back(e);
else m_edges.push_back(e);
bool MSTPath::tempfunc(Edge e, vector<Edge> path)
for (auto edge : path)
if((edge.get_node()==e.get_node())&&(edge.get_opposite_node(-1)==e.get_opposite_node(-1))) return true;
return false;
Version with std::map
.
void MSTPath::m_add_shortest_path(map<Edge,int> path_map)
for (auto const& x : path_map)
Edge e = x.first;
m_graph->union_vu(e.get_node(),e.get_opposite_node(-1));
for (auto const& x : m_all_edges_map)(path_map.count(x.first.reversed())>0)) m_mst.push_back(x.first);
else m_edges.push_back(x.first);
Function for finding MST (called after calling m_add_shortest_path
/ m_add_shortest_path_old
).
int MSTPath::m_compute_mst()
sort(m_edges.begin(),m_edges.end(),(Edge e1, Edge e2) return e1.weight < e2.weight; );
int i = 0;
int mst_size = m_mst.size();
int mst_weight = 0;
int v,u;
for (Edge e : m_mst) mst_weight += e.weight;
while (mst_size<m_N-1)
Edge edge = m_edges[i++];
v = m_graph->find(edge.get_node());
u = m_graph->find(edge.get_opposite_node(-1));
if (u!=v)
mst_size++;
mst_weight += edge.weight;
if (mst_weight>=min_mst_weight) return numeric_limits<int>::max();
m_mst.push_back(edge);
m_graph->union_vu(v,u);
return mst_weight;
From what I see, both function get exactly the same m_mst
(and starting mst_weight
) and the same m_edges
(but in different order). But ordering should not be a problem for the algorithm (except for ordering by weight, but this is handles in m_compute_mst
), right?
Edge
class:
class Edge
public:
Edge(int v_e, int u_e, int w)
v = v_e;
u = u_e;
weight = w;
int get_node() const return v;
int get_opposite_node(int k) const
Edge reversed() const
return Edge(u,v,weight);
bool operator<(const Edge& e) const
if (this->get_node()<e.get_node()) return true;
else if (this->get_node()==e.get_node()) return this->get_opposite_node(-1)<e.get_opposite_node(-1);
else return false;
int v, u, weight;
;
Yes, I know that passing by value makes additional copies. This is a temporary version.
c++ graph-theory minimum-spanning-tree
add a comment |
I have a code for finding MST which would include a given path to MST, which gives me correct weight of MST (I know what the output is supposed to be). I tried to rewrite one part of the code to use std::map
instead of std::vector
for more efficient look-up (will become clear from the code below), but now it gives wrong answer, and despite looking into it for few hours, I am unable to understand where did I make a mistake. Any help with locating a bug will be appreciated.
Old version that uses vector<Edge>
. Goes through the vector of all edges (m_all_edges
). If an edge e
is in vector<Edge> path
, adds it to MST (m_mst
). Otherwise, adds it to candidate edges for MST (m_edges
).
void MSTPath::m_add_shortest_path_old(vector<Edge> path)
for (auto e : path)
m_graph->union_vu(e.get_node(),e.get_opposite_node(-1));
for (auto e : m_all_edges)
if (tempfunc(e,path)) m_mst.push_back(e);
else m_edges.push_back(e);
bool MSTPath::tempfunc(Edge e, vector<Edge> path)
for (auto edge : path)
if((edge.get_node()==e.get_node())&&(edge.get_opposite_node(-1)==e.get_opposite_node(-1))) return true;
return false;
Version with std::map
.
void MSTPath::m_add_shortest_path(map<Edge,int> path_map)
for (auto const& x : path_map)
Edge e = x.first;
m_graph->union_vu(e.get_node(),e.get_opposite_node(-1));
for (auto const& x : m_all_edges_map)(path_map.count(x.first.reversed())>0)) m_mst.push_back(x.first);
else m_edges.push_back(x.first);
Function for finding MST (called after calling m_add_shortest_path
/ m_add_shortest_path_old
).
int MSTPath::m_compute_mst()
sort(m_edges.begin(),m_edges.end(),(Edge e1, Edge e2) return e1.weight < e2.weight; );
int i = 0;
int mst_size = m_mst.size();
int mst_weight = 0;
int v,u;
for (Edge e : m_mst) mst_weight += e.weight;
while (mst_size<m_N-1)
Edge edge = m_edges[i++];
v = m_graph->find(edge.get_node());
u = m_graph->find(edge.get_opposite_node(-1));
if (u!=v)
mst_size++;
mst_weight += edge.weight;
if (mst_weight>=min_mst_weight) return numeric_limits<int>::max();
m_mst.push_back(edge);
m_graph->union_vu(v,u);
return mst_weight;
From what I see, both function get exactly the same m_mst
(and starting mst_weight
) and the same m_edges
(but in different order). But ordering should not be a problem for the algorithm (except for ordering by weight, but this is handles in m_compute_mst
), right?
Edge
class:
class Edge
public:
Edge(int v_e, int u_e, int w)
v = v_e;
u = u_e;
weight = w;
int get_node() const return v;
int get_opposite_node(int k) const
Edge reversed() const
return Edge(u,v,weight);
bool operator<(const Edge& e) const
if (this->get_node()<e.get_node()) return true;
else if (this->get_node()==e.get_node()) return this->get_opposite_node(-1)<e.get_opposite_node(-1);
else return false;
int v, u, weight;
;
Yes, I know that passing by value makes additional copies. This is a temporary version.
c++ graph-theory minimum-spanning-tree
map<Edge,int>
, what are you mapping Edges to ?
– Piotr Skotnicki
Nov 15 '18 at 18:46
To nothing (for now, at least; just to 0). I just use map to check if map contains the given key (Edge) in O(logN).
– Valeria
Nov 15 '18 at 21:11
add a comment |
I have a code for finding MST which would include a given path to MST, which gives me correct weight of MST (I know what the output is supposed to be). I tried to rewrite one part of the code to use std::map
instead of std::vector
for more efficient look-up (will become clear from the code below), but now it gives wrong answer, and despite looking into it for few hours, I am unable to understand where did I make a mistake. Any help with locating a bug will be appreciated.
Old version that uses vector<Edge>
. Goes through the vector of all edges (m_all_edges
). If an edge e
is in vector<Edge> path
, adds it to MST (m_mst
). Otherwise, adds it to candidate edges for MST (m_edges
).
void MSTPath::m_add_shortest_path_old(vector<Edge> path)
for (auto e : path)
m_graph->union_vu(e.get_node(),e.get_opposite_node(-1));
for (auto e : m_all_edges)
if (tempfunc(e,path)) m_mst.push_back(e);
else m_edges.push_back(e);
bool MSTPath::tempfunc(Edge e, vector<Edge> path)
for (auto edge : path)
if((edge.get_node()==e.get_node())&&(edge.get_opposite_node(-1)==e.get_opposite_node(-1))) return true;
return false;
Version with std::map
.
void MSTPath::m_add_shortest_path(map<Edge,int> path_map)
for (auto const& x : path_map)
Edge e = x.first;
m_graph->union_vu(e.get_node(),e.get_opposite_node(-1));
for (auto const& x : m_all_edges_map)(path_map.count(x.first.reversed())>0)) m_mst.push_back(x.first);
else m_edges.push_back(x.first);
Function for finding MST (called after calling m_add_shortest_path
/ m_add_shortest_path_old
).
int MSTPath::m_compute_mst()
sort(m_edges.begin(),m_edges.end(),(Edge e1, Edge e2) return e1.weight < e2.weight; );
int i = 0;
int mst_size = m_mst.size();
int mst_weight = 0;
int v,u;
for (Edge e : m_mst) mst_weight += e.weight;
while (mst_size<m_N-1)
Edge edge = m_edges[i++];
v = m_graph->find(edge.get_node());
u = m_graph->find(edge.get_opposite_node(-1));
if (u!=v)
mst_size++;
mst_weight += edge.weight;
if (mst_weight>=min_mst_weight) return numeric_limits<int>::max();
m_mst.push_back(edge);
m_graph->union_vu(v,u);
return mst_weight;
From what I see, both function get exactly the same m_mst
(and starting mst_weight
) and the same m_edges
(but in different order). But ordering should not be a problem for the algorithm (except for ordering by weight, but this is handles in m_compute_mst
), right?
Edge
class:
class Edge
public:
Edge(int v_e, int u_e, int w)
v = v_e;
u = u_e;
weight = w;
int get_node() const return v;
int get_opposite_node(int k) const
Edge reversed() const
return Edge(u,v,weight);
bool operator<(const Edge& e) const
if (this->get_node()<e.get_node()) return true;
else if (this->get_node()==e.get_node()) return this->get_opposite_node(-1)<e.get_opposite_node(-1);
else return false;
int v, u, weight;
;
Yes, I know that passing by value makes additional copies. This is a temporary version.
c++ graph-theory minimum-spanning-tree
I have a code for finding MST which would include a given path to MST, which gives me correct weight of MST (I know what the output is supposed to be). I tried to rewrite one part of the code to use std::map
instead of std::vector
for more efficient look-up (will become clear from the code below), but now it gives wrong answer, and despite looking into it for few hours, I am unable to understand where did I make a mistake. Any help with locating a bug will be appreciated.
Old version that uses vector<Edge>
. Goes through the vector of all edges (m_all_edges
). If an edge e
is in vector<Edge> path
, adds it to MST (m_mst
). Otherwise, adds it to candidate edges for MST (m_edges
).
void MSTPath::m_add_shortest_path_old(vector<Edge> path)
for (auto e : path)
m_graph->union_vu(e.get_node(),e.get_opposite_node(-1));
for (auto e : m_all_edges)
if (tempfunc(e,path)) m_mst.push_back(e);
else m_edges.push_back(e);
bool MSTPath::tempfunc(Edge e, vector<Edge> path)
for (auto edge : path)
if((edge.get_node()==e.get_node())&&(edge.get_opposite_node(-1)==e.get_opposite_node(-1))) return true;
return false;
Version with std::map
.
void MSTPath::m_add_shortest_path(map<Edge,int> path_map)
for (auto const& x : path_map)
Edge e = x.first;
m_graph->union_vu(e.get_node(),e.get_opposite_node(-1));
for (auto const& x : m_all_edges_map)(path_map.count(x.first.reversed())>0)) m_mst.push_back(x.first);
else m_edges.push_back(x.first);
Function for finding MST (called after calling m_add_shortest_path
/ m_add_shortest_path_old
).
int MSTPath::m_compute_mst()
sort(m_edges.begin(),m_edges.end(),(Edge e1, Edge e2) return e1.weight < e2.weight; );
int i = 0;
int mst_size = m_mst.size();
int mst_weight = 0;
int v,u;
for (Edge e : m_mst) mst_weight += e.weight;
while (mst_size<m_N-1)
Edge edge = m_edges[i++];
v = m_graph->find(edge.get_node());
u = m_graph->find(edge.get_opposite_node(-1));
if (u!=v)
mst_size++;
mst_weight += edge.weight;
if (mst_weight>=min_mst_weight) return numeric_limits<int>::max();
m_mst.push_back(edge);
m_graph->union_vu(v,u);
return mst_weight;
From what I see, both function get exactly the same m_mst
(and starting mst_weight
) and the same m_edges
(but in different order). But ordering should not be a problem for the algorithm (except for ordering by weight, but this is handles in m_compute_mst
), right?
Edge
class:
class Edge
public:
Edge(int v_e, int u_e, int w)
v = v_e;
u = u_e;
weight = w;
int get_node() const return v;
int get_opposite_node(int k) const
Edge reversed() const
return Edge(u,v,weight);
bool operator<(const Edge& e) const
if (this->get_node()<e.get_node()) return true;
else if (this->get_node()==e.get_node()) return this->get_opposite_node(-1)<e.get_opposite_node(-1);
else return false;
int v, u, weight;
;
Yes, I know that passing by value makes additional copies. This is a temporary version.
c++ graph-theory minimum-spanning-tree
c++ graph-theory minimum-spanning-tree
asked Nov 15 '18 at 18:24
ValeriaValeria
10911
10911
map<Edge,int>
, what are you mapping Edges to ?
– Piotr Skotnicki
Nov 15 '18 at 18:46
To nothing (for now, at least; just to 0). I just use map to check if map contains the given key (Edge) in O(logN).
– Valeria
Nov 15 '18 at 21:11
add a comment |
map<Edge,int>
, what are you mapping Edges to ?
– Piotr Skotnicki
Nov 15 '18 at 18:46
To nothing (for now, at least; just to 0). I just use map to check if map contains the given key (Edge) in O(logN).
– Valeria
Nov 15 '18 at 21:11
map<Edge,int>
, what are you mapping Edges to ?– Piotr Skotnicki
Nov 15 '18 at 18:46
map<Edge,int>
, what are you mapping Edges to ?– Piotr Skotnicki
Nov 15 '18 at 18:46
To nothing (for now, at least; just to 0). I just use map to check if map contains the given key (Edge) in O(logN).
– Valeria
Nov 15 '18 at 21:11
To nothing (for now, at least; just to 0). I just use map to check if map contains the given key (Edge) in O(logN).
– Valeria
Nov 15 '18 at 21:11
add a comment |
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map<Edge,int>
, what are you mapping Edges to ?– Piotr Skotnicki
Nov 15 '18 at 18:46
To nothing (for now, at least; just to 0). I just use map to check if map contains the given key (Edge) in O(logN).
– Valeria
Nov 15 '18 at 21:11