Call python instance method, given the instance and function objects of the instance method?
0
In Python, given an instance of a class, and the class method objects, is it possible to call the corresponding instance method? E.g.
class MyClass:
def doA(self):
print("A")
def doB(self):
print("B")
methodA = MyClass.doA
methodB = MyClass.doB
instance = MyClass()
Am I somehow able to invoke instance.doA(), but given the methodA object? e.g.
instance.__invoke__(methodA)
python python-3.x
asked Nov 15 '18 at 4:08
NathanNathan
67111126
add a comment |
0
In Python, given an instance of a class, and the class method objects, is it possible to call the corresponding instance method? E.g.
class MyClass:
def doA(self):
print("A")
def doB(self):
print("B")
methodA = MyClass.doA
methodB = MyClass.doB
instance = MyClass()
Am I somehow able to invoke instance.doA(), but given the methodA object? e.g.
instance.__invoke__(methodA)
python python-3.x
asked Nov 15 '18 at 4:08
NathanNathan
67111126
1
Yes, you would instead callmethodA(instance).
– metatoaster
Nov 15 '18 at 4:09
Ah, perfect. I fumbled around with the search terms for a bit but came out empty-handed. What are some keywords that I should've googled for this?
– Nathan
Nov 15 '18 at 4:13
1
The reason for that call signature is thatselfis theinstancewhen called as a method
– Brad Solomon
Nov 15 '18 at 4:28
add a comment |
0
0
0
In Python, given an instance of a class, and the class method objects, is it possible to call the corresponding instance method? E.g.
class MyClass:
def doA(self):
print("A")
def doB(self):
print("B")
methodA = MyClass.doA
methodB = MyClass.doB
instance = MyClass()
Am I somehow able to invoke instance.doA(), but given the methodA object? e.g.
instance.__invoke__(methodA)
python python-3.x
asked Nov 15 '18 at 4:08
NathanNathan
67111126
In Python, given an instance of a class, and the class method objects, is it possible to call the corresponding instance method? E.g.
class MyClass:
def doA(self):
print("A")
def doB(self):
print("B")
methodA = MyClass.doA
methodB = MyClass.doB
instance = MyClass()
Am I somehow able to invoke instance.doA(), but given the methodA object? e.g.
instance.__invoke__(methodA)
python python-3.x
python python-3.x
asked Nov 15 '18 at 4:08
NathanNathan
67111126
asked Nov 15 '18 at 4:08
NathanNathan
67111126
asked Nov 15 '18 at 4:08
NathanNathan
67111126
asked Nov 15 '18 at 4:08
NathanNathan
67111126
asked Nov 15 '18 at 4:08
NathanNathan
67111126
67111126
1
Yes, you would instead callmethodA(instance).
– metatoaster
Nov 15 '18 at 4:09
Ah, perfect. I fumbled around with the search terms for a bit but came out empty-handed. What are some keywords that I should've googled for this?
– Nathan
Nov 15 '18 at 4:13
1
The reason for that call signature is thatselfis theinstancewhen called as a method
– Brad Solomon
Nov 15 '18 at 4:28
add a comment |
1
Yes, you would instead callmethodA(instance).
– metatoaster
Nov 15 '18 at 4:09
Ah, perfect. I fumbled around with the search terms for a bit but came out empty-handed. What are some keywords that I should've googled for this?
– Nathan
Nov 15 '18 at 4:13
1
The reason for that call signature is thatselfis theinstancewhen called as a method
– Brad Solomon
Nov 15 '18 at 4:28
1
1
Yes, you would instead call
methodA(instance).– metatoaster
Nov 15 '18 at 4:09
Yes, you would instead call
methodA(instance).– metatoaster
Nov 15 '18 at 4:09
Ah, perfect. I fumbled around with the search terms for a bit but came out empty-handed. What are some keywords that I should've googled for this?
– Nathan
Nov 15 '18 at 4:13
Ah, perfect. I fumbled around with the search terms for a bit but came out empty-handed. What are some keywords that I should've googled for this?
– Nathan
Nov 15 '18 at 4:13
1
1
The reason for that call signature is that
self is the instance when called as a method– Brad Solomon
Nov 15 '18 at 4:28
The reason for that call signature is that
self is the instance when called as a method– Brad Solomon
Nov 15 '18 at 4:28
add a comment |
0
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1
Yes, you would instead call
methodA(instance).– metatoaster
Nov 15 '18 at 4:09
Ah, perfect. I fumbled around with the search terms for a bit but came out empty-handed. What are some keywords that I should've googled for this?
– Nathan
Nov 15 '18 at 4:13
1
The reason for that call signature is that
selfis theinstancewhen called as a method– Brad Solomon
Nov 15 '18 at 4:28