Wrong php date('t')
I have this script
echo 'giorni mese: '.date('t', $mese_start).' - mese start: '.$mese_start;
output is:
giorni mese: 31 - mese start: 11
But november doesn't have 30 days?
What am I missing?
Update:
right, thank you.
php date
asked Nov 14 '18 at 21:24
alebalalebal
1,268248
add a comment |
I have this script
echo 'giorni mese: '.date('t', $mese_start).' - mese start: '.$mese_start;
output is:
giorni mese: 31 - mese start: 11
But november doesn't have 30 days?
What am I missing?
Update:
right, thank you.
php date
asked Nov 14 '18 at 21:24
alebalalebal
1,268248
2
$mese_startis not a timestamp in November.
– Barmar
Nov 14 '18 at 21:26
1
It all depends on what the value of$mese_startis
– Patrick Q
Nov 14 '18 at 21:26
add a comment |
I have this script
echo 'giorni mese: '.date('t', $mese_start).' - mese start: '.$mese_start;
output is:
giorni mese: 31 - mese start: 11
But november doesn't have 30 days?
What am I missing?
Update:
right, thank you.
php date
asked Nov 14 '18 at 21:24
alebalalebal
1,268248
I have this script
echo 'giorni mese: '.date('t', $mese_start).' - mese start: '.$mese_start;
output is:
giorni mese: 31 - mese start: 11
But november doesn't have 30 days?
What am I missing?
Update:
right, thank you.
php date
php date
asked Nov 14 '18 at 21:24
alebalalebal
1,268248
asked Nov 14 '18 at 21:24
alebalalebal
1,268248
edited Nov 14 '18 at 22:05
alebal
asked Nov 14 '18 at 21:24
alebalalebal
1,268248
asked Nov 14 '18 at 21:24
alebalalebal
1,268248
asked Nov 14 '18 at 21:24
alebalalebal
1,268248
1,268248
2
$mese_startis not a timestamp in November.
– Barmar
Nov 14 '18 at 21:26
1
It all depends on what the value of$mese_startis
– Patrick Q
Nov 14 '18 at 21:26
add a comment |
2
$mese_startis not a timestamp in November.
– Barmar
Nov 14 '18 at 21:26
1
It all depends on what the value of$mese_startis
– Patrick Q
Nov 14 '18 at 21:26
2
2
$mese_start is not a timestamp in November.– Barmar
Nov 14 '18 at 21:26
$mese_start is not a timestamp in November.– Barmar
Nov 14 '18 at 21:26
1
1
It all depends on what the value of
$mese_start is– Patrick Q
Nov 14 '18 at 21:26
It all depends on what the value of
$mese_start is– Patrick Q
Nov 14 '18 at 21:26
add a comment |
2 Answers
2
active
oldest
votes
The second argument to date() is a timestamp, which is the number of seconds since 1970-01-01 00:00:00 UTC. The value of $mese_start is 11. So that timestamp is 1970-01-01 00:00:11 UTC, and January has 31 days.
If you want to use $mese_start as a month number rather than a timestamp, you can use mktime() to create a timestamp from a particular date:
$ts = mktime(0, 0, 0, $mese_start);
echo 'giorni mese: '.date('t', $ts).' - mese start: '.$mese_start;
answered Nov 14 '18 at 21:29
BarmarBarmar
429k36250352
add a comment |
The second argument of date is interpreted as a Unix timestamp, not a month. You are passing "11" which equals some time on January 1st, 1970. And January has 31 days.
You could either construct a valid timestamp for November or use cal_days_in_month:
echo cal_days_in_month(CAL_GREGORIAN, 11, 2018); // 30
answered Nov 14 '18 at 21:30
MarvinMarvin
7,83323238
add a comment |
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2 Answers
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2 Answers
2
active
oldest
votes
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oldest
votes
The second argument to date() is a timestamp, which is the number of seconds since 1970-01-01 00:00:00 UTC. The value of $mese_start is 11. So that timestamp is 1970-01-01 00:00:11 UTC, and January has 31 days.
If you want to use $mese_start as a month number rather than a timestamp, you can use mktime() to create a timestamp from a particular date:
$ts = mktime(0, 0, 0, $mese_start);
echo 'giorni mese: '.date('t', $ts).' - mese start: '.$mese_start;
answered Nov 14 '18 at 21:29
BarmarBarmar
429k36250352
add a comment |
The second argument to date() is a timestamp, which is the number of seconds since 1970-01-01 00:00:00 UTC. The value of $mese_start is 11. So that timestamp is 1970-01-01 00:00:11 UTC, and January has 31 days.
If you want to use $mese_start as a month number rather than a timestamp, you can use mktime() to create a timestamp from a particular date:
$ts = mktime(0, 0, 0, $mese_start);
echo 'giorni mese: '.date('t', $ts).' - mese start: '.$mese_start;
answered Nov 14 '18 at 21:29
BarmarBarmar
429k36250352
add a comment |
The second argument to date() is a timestamp, which is the number of seconds since 1970-01-01 00:00:00 UTC. The value of $mese_start is 11. So that timestamp is 1970-01-01 00:00:11 UTC, and January has 31 days.
If you want to use $mese_start as a month number rather than a timestamp, you can use mktime() to create a timestamp from a particular date:
$ts = mktime(0, 0, 0, $mese_start);
echo 'giorni mese: '.date('t', $ts).' - mese start: '.$mese_start;
answered Nov 14 '18 at 21:29
BarmarBarmar
429k36250352
The second argument to date() is a timestamp, which is the number of seconds since 1970-01-01 00:00:00 UTC. The value of $mese_start is 11. So that timestamp is 1970-01-01 00:00:11 UTC, and January has 31 days.
If you want to use $mese_start as a month number rather than a timestamp, you can use mktime() to create a timestamp from a particular date:
$ts = mktime(0, 0, 0, $mese_start);
echo 'giorni mese: '.date('t', $ts).' - mese start: '.$mese_start;
answered Nov 14 '18 at 21:29
BarmarBarmar
429k36250352
answered Nov 14 '18 at 21:29
BarmarBarmar
429k36250352
answered Nov 14 '18 at 21:29
BarmarBarmar
429k36250352
answered Nov 14 '18 at 21:29
BarmarBarmar
429k36250352
429k36250352
add a comment |
add a comment |
The second argument of date is interpreted as a Unix timestamp, not a month. You are passing "11" which equals some time on January 1st, 1970. And January has 31 days.
You could either construct a valid timestamp for November or use cal_days_in_month:
echo cal_days_in_month(CAL_GREGORIAN, 11, 2018); // 30
answered Nov 14 '18 at 21:30
MarvinMarvin
7,83323238
add a comment |
The second argument of date is interpreted as a Unix timestamp, not a month. You are passing "11" which equals some time on January 1st, 1970. And January has 31 days.
You could either construct a valid timestamp for November or use cal_days_in_month:
echo cal_days_in_month(CAL_GREGORIAN, 11, 2018); // 30
answered Nov 14 '18 at 21:30
MarvinMarvin
7,83323238
add a comment |
The second argument of date is interpreted as a Unix timestamp, not a month. You are passing "11" which equals some time on January 1st, 1970. And January has 31 days.
You could either construct a valid timestamp for November or use cal_days_in_month:
echo cal_days_in_month(CAL_GREGORIAN, 11, 2018); // 30
answered Nov 14 '18 at 21:30
MarvinMarvin
7,83323238
The second argument of date is interpreted as a Unix timestamp, not a month. You are passing "11" which equals some time on January 1st, 1970. And January has 31 days.
You could either construct a valid timestamp for November or use cal_days_in_month:
echo cal_days_in_month(CAL_GREGORIAN, 11, 2018); // 30
answered Nov 14 '18 at 21:30
MarvinMarvin
7,83323238
answered Nov 14 '18 at 21:30
MarvinMarvin
7,83323238
answered Nov 14 '18 at 21:30
MarvinMarvin
7,83323238
answered Nov 14 '18 at 21:30
MarvinMarvin
7,83323238
7,83323238
add a comment |
add a comment |
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2
$mese_startis not a timestamp in November.– Barmar
Nov 14 '18 at 21:26
1
It all depends on what the value of
$mese_startis– Patrick Q
Nov 14 '18 at 21:26