Calculating Overlapping Time Intervals in SQL between several users
after quite some time spent online to try to find an answer to my problem I decided to post it here.
I have a table which contains intervals of time during which some resources are not available. I would like to extract all time interval in which all resources are not available.
With the example below, I would have: start: 2018-11-16 12:30:00, end: 2018-11-16 12:45:00
Start End Resource
------------------- ------------------- ----------
2018-11-15 12:00:00 2018-11-15 13:00:00 resource A
2018-11-15 12:00:00 2018-11-15 13:00:00 resource B
2018-11-15 12:30:00 2018-11-15 14:00:00 resource C
2018-11-15 12:00:00 2018-11-15 12:45:00 resource D
2018-11-18 12:00:00 2018-11-18 13:00:00 resource A
2018-11-19 11:40:00 2018-11-19 12:20:00 resource B
2018-11-15 16:00:00 2018-11-15 17:00:00 resource D
Would someone have any idea?
Thanks in advance.
sql postgresql postgresql-9.5
|
show 2 more comments
after quite some time spent online to try to find an answer to my problem I decided to post it here.
I have a table which contains intervals of time during which some resources are not available. I would like to extract all time interval in which all resources are not available.
With the example below, I would have: start: 2018-11-16 12:30:00, end: 2018-11-16 12:45:00
Start End Resource
------------------- ------------------- ----------
2018-11-15 12:00:00 2018-11-15 13:00:00 resource A
2018-11-15 12:00:00 2018-11-15 13:00:00 resource B
2018-11-15 12:30:00 2018-11-15 14:00:00 resource C
2018-11-15 12:00:00 2018-11-15 12:45:00 resource D
2018-11-18 12:00:00 2018-11-18 13:00:00 resource A
2018-11-19 11:40:00 2018-11-19 12:20:00 resource B
2018-11-15 16:00:00 2018-11-15 17:00:00 resource D
Would someone have any idea?
Thanks in advance.
sql postgresql postgresql-9.5
What version of MySQL are you using? This is so cumbersome prior to 8.0 that it may not be worth attempting.
– Gordon Linoff
Nov 14 '18 at 20:41
Well, actually I use postgresql, the version 9.5.
– T. Balzer
Nov 14 '18 at 20:45
There is no time interval in your sample data when no resources are available. During 2018-11-16 12:30:00 to 2018-11-16 14:00:00 only resource C is unavailable
– Joakim Danielson
Nov 14 '18 at 20:53
Made a mistake with my sample. I just corrected it.
– T. Balzer
Nov 14 '18 at 21:18
2
I forgot to ask but how do we now how many "all resources" are or is that dynamic and something that is part of the query and if so do we know all resources will be represented in the table?
– Joakim Danielson
Nov 14 '18 at 21:24
|
show 2 more comments
after quite some time spent online to try to find an answer to my problem I decided to post it here.
I have a table which contains intervals of time during which some resources are not available. I would like to extract all time interval in which all resources are not available.
With the example below, I would have: start: 2018-11-16 12:30:00, end: 2018-11-16 12:45:00
Start End Resource
------------------- ------------------- ----------
2018-11-15 12:00:00 2018-11-15 13:00:00 resource A
2018-11-15 12:00:00 2018-11-15 13:00:00 resource B
2018-11-15 12:30:00 2018-11-15 14:00:00 resource C
2018-11-15 12:00:00 2018-11-15 12:45:00 resource D
2018-11-18 12:00:00 2018-11-18 13:00:00 resource A
2018-11-19 11:40:00 2018-11-19 12:20:00 resource B
2018-11-15 16:00:00 2018-11-15 17:00:00 resource D
Would someone have any idea?
Thanks in advance.
sql postgresql postgresql-9.5
after quite some time spent online to try to find an answer to my problem I decided to post it here.
I have a table which contains intervals of time during which some resources are not available. I would like to extract all time interval in which all resources are not available.
With the example below, I would have: start: 2018-11-16 12:30:00, end: 2018-11-16 12:45:00
Start End Resource
------------------- ------------------- ----------
2018-11-15 12:00:00 2018-11-15 13:00:00 resource A
2018-11-15 12:00:00 2018-11-15 13:00:00 resource B
2018-11-15 12:30:00 2018-11-15 14:00:00 resource C
2018-11-15 12:00:00 2018-11-15 12:45:00 resource D
2018-11-18 12:00:00 2018-11-18 13:00:00 resource A
2018-11-19 11:40:00 2018-11-19 12:20:00 resource B
2018-11-15 16:00:00 2018-11-15 17:00:00 resource D
Would someone have any idea?
Thanks in advance.
sql postgresql postgresql-9.5
sql postgresql postgresql-9.5
edited Nov 14 '18 at 21:18
T. Balzer
asked Nov 14 '18 at 20:40
T. BalzerT. Balzer
162
162
What version of MySQL are you using? This is so cumbersome prior to 8.0 that it may not be worth attempting.
– Gordon Linoff
Nov 14 '18 at 20:41
Well, actually I use postgresql, the version 9.5.
– T. Balzer
Nov 14 '18 at 20:45
There is no time interval in your sample data when no resources are available. During 2018-11-16 12:30:00 to 2018-11-16 14:00:00 only resource C is unavailable
– Joakim Danielson
Nov 14 '18 at 20:53
Made a mistake with my sample. I just corrected it.
– T. Balzer
Nov 14 '18 at 21:18
2
I forgot to ask but how do we now how many "all resources" are or is that dynamic and something that is part of the query and if so do we know all resources will be represented in the table?
– Joakim Danielson
Nov 14 '18 at 21:24
|
show 2 more comments
What version of MySQL are you using? This is so cumbersome prior to 8.0 that it may not be worth attempting.
– Gordon Linoff
Nov 14 '18 at 20:41
Well, actually I use postgresql, the version 9.5.
– T. Balzer
Nov 14 '18 at 20:45
There is no time interval in your sample data when no resources are available. During 2018-11-16 12:30:00 to 2018-11-16 14:00:00 only resource C is unavailable
– Joakim Danielson
Nov 14 '18 at 20:53
Made a mistake with my sample. I just corrected it.
– T. Balzer
Nov 14 '18 at 21:18
2
I forgot to ask but how do we now how many "all resources" are or is that dynamic and something that is part of the query and if so do we know all resources will be represented in the table?
– Joakim Danielson
Nov 14 '18 at 21:24
What version of MySQL are you using? This is so cumbersome prior to 8.0 that it may not be worth attempting.
– Gordon Linoff
Nov 14 '18 at 20:41
What version of MySQL are you using? This is so cumbersome prior to 8.0 that it may not be worth attempting.
– Gordon Linoff
Nov 14 '18 at 20:41
Well, actually I use postgresql, the version 9.5.
– T. Balzer
Nov 14 '18 at 20:45
Well, actually I use postgresql, the version 9.5.
– T. Balzer
Nov 14 '18 at 20:45
There is no time interval in your sample data when no resources are available. During 2018-11-16 12:30:00 to 2018-11-16 14:00:00 only resource C is unavailable
– Joakim Danielson
Nov 14 '18 at 20:53
There is no time interval in your sample data when no resources are available. During 2018-11-16 12:30:00 to 2018-11-16 14:00:00 only resource C is unavailable
– Joakim Danielson
Nov 14 '18 at 20:53
Made a mistake with my sample. I just corrected it.
– T. Balzer
Nov 14 '18 at 21:18
Made a mistake with my sample. I just corrected it.
– T. Balzer
Nov 14 '18 at 21:18
2
2
I forgot to ask but how do we now how many "all resources" are or is that dynamic and something that is part of the query and if so do we know all resources will be represented in the table?
– Joakim Danielson
Nov 14 '18 at 21:24
I forgot to ask but how do we now how many "all resources" are or is that dynamic and something that is part of the query and if so do we know all resources will be represented in the table?
– Joakim Danielson
Nov 14 '18 at 21:24
|
show 2 more comments
1 Answer
1
active
oldest
votes
If you know the number of resources (or it can be calculated) and there's no overlapping Start/End range for a resource (i.e. you got clean data):
select Start, "End"
from
( -- calculate a Cumulative Sum to get the count of resources unavailable at any point in time
select Start,
lead(Start) over (order by Start, x) as "End",
sum(x) over (order by Start, x rows unbounded preceding) as cnt
from
( -- combine starts & ends into a single table and assigne +/-1 to each row
select Start, 1 as x
from tab
union all
select "End", -1 as x
from tab
) as dt
) as dt
where cnt = 4 -- find the row where all resources are unavailable
-- where cnt = (select count(*) from resources)
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1 Answer
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1 Answer
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active
oldest
votes
active
oldest
votes
active
oldest
votes
If you know the number of resources (or it can be calculated) and there's no overlapping Start/End range for a resource (i.e. you got clean data):
select Start, "End"
from
( -- calculate a Cumulative Sum to get the count of resources unavailable at any point in time
select Start,
lead(Start) over (order by Start, x) as "End",
sum(x) over (order by Start, x rows unbounded preceding) as cnt
from
( -- combine starts & ends into a single table and assigne +/-1 to each row
select Start, 1 as x
from tab
union all
select "End", -1 as x
from tab
) as dt
) as dt
where cnt = 4 -- find the row where all resources are unavailable
-- where cnt = (select count(*) from resources)
add a comment |
If you know the number of resources (or it can be calculated) and there's no overlapping Start/End range for a resource (i.e. you got clean data):
select Start, "End"
from
( -- calculate a Cumulative Sum to get the count of resources unavailable at any point in time
select Start,
lead(Start) over (order by Start, x) as "End",
sum(x) over (order by Start, x rows unbounded preceding) as cnt
from
( -- combine starts & ends into a single table and assigne +/-1 to each row
select Start, 1 as x
from tab
union all
select "End", -1 as x
from tab
) as dt
) as dt
where cnt = 4 -- find the row where all resources are unavailable
-- where cnt = (select count(*) from resources)
add a comment |
If you know the number of resources (or it can be calculated) and there's no overlapping Start/End range for a resource (i.e. you got clean data):
select Start, "End"
from
( -- calculate a Cumulative Sum to get the count of resources unavailable at any point in time
select Start,
lead(Start) over (order by Start, x) as "End",
sum(x) over (order by Start, x rows unbounded preceding) as cnt
from
( -- combine starts & ends into a single table and assigne +/-1 to each row
select Start, 1 as x
from tab
union all
select "End", -1 as x
from tab
) as dt
) as dt
where cnt = 4 -- find the row where all resources are unavailable
-- where cnt = (select count(*) from resources)
If you know the number of resources (or it can be calculated) and there's no overlapping Start/End range for a resource (i.e. you got clean data):
select Start, "End"
from
( -- calculate a Cumulative Sum to get the count of resources unavailable at any point in time
select Start,
lead(Start) over (order by Start, x) as "End",
sum(x) over (order by Start, x rows unbounded preceding) as cnt
from
( -- combine starts & ends into a single table and assigne +/-1 to each row
select Start, 1 as x
from tab
union all
select "End", -1 as x
from tab
) as dt
) as dt
where cnt = 4 -- find the row where all resources are unavailable
-- where cnt = (select count(*) from resources)
answered Nov 14 '18 at 22:19
dnoethdnoeth
45.6k31839
45.6k31839
add a comment |
add a comment |
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What version of MySQL are you using? This is so cumbersome prior to 8.0 that it may not be worth attempting.
– Gordon Linoff
Nov 14 '18 at 20:41
Well, actually I use postgresql, the version 9.5.
– T. Balzer
Nov 14 '18 at 20:45
There is no time interval in your sample data when no resources are available. During 2018-11-16 12:30:00 to 2018-11-16 14:00:00 only resource C is unavailable
– Joakim Danielson
Nov 14 '18 at 20:53
Made a mistake with my sample. I just corrected it.
– T. Balzer
Nov 14 '18 at 21:18
2
I forgot to ask but how do we now how many "all resources" are or is that dynamic and something that is part of the query and if so do we know all resources will be represented in the table?
– Joakim Danielson
Nov 14 '18 at 21:24