Print all the instances of a matching pattern in a file










0















I've been trying to print all the instances of a matching pattern from file.



Input file:



"id":"prod123","a":1.3,"c":"xyz","q":2, 
"id":"prod456","a":1.3,"c":"xyz","q":1]}
"id":"prod789","a":1.3,"currency":"xyz","q":2,
"id":"prod101112","a":1.3,"c":"xyz","q":1]}


I'd want to print everything between "id":" and ",.



Expected output:



prod123
prod456
prod789
prod101112


I'm using the command



grep -Eo 'id":"[^"]+"",*' | grep -Eo '^[^"]+'


Am I missing anything here?










share|improve this question



















  • 2





    Do you have jq installed?

    – anubhava
    Nov 14 '18 at 17:18






  • 2





    Your output seems to be a grep or whatever on a JSON file. You might be interested in using jq on your full file. But for this, we should need to see how this thing looks like.

    – kvantour
    Nov 14 '18 at 17:27






  • 1





    Use some JSON parser, whether it be jq or a module in your language of choice. Don't use line-oriented tools like grep or awk to try to parse JSON.

    – chepner
    Nov 14 '18 at 17:27















0















I've been trying to print all the instances of a matching pattern from file.



Input file:



"id":"prod123","a":1.3,"c":"xyz","q":2, 
"id":"prod456","a":1.3,"c":"xyz","q":1]}
"id":"prod789","a":1.3,"currency":"xyz","q":2,
"id":"prod101112","a":1.3,"c":"xyz","q":1]}


I'd want to print everything between "id":" and ",.



Expected output:



prod123
prod456
prod789
prod101112


I'm using the command



grep -Eo 'id":"[^"]+"",*' | grep -Eo '^[^"]+'


Am I missing anything here?










share|improve this question



















  • 2





    Do you have jq installed?

    – anubhava
    Nov 14 '18 at 17:18






  • 2





    Your output seems to be a grep or whatever on a JSON file. You might be interested in using jq on your full file. But for this, we should need to see how this thing looks like.

    – kvantour
    Nov 14 '18 at 17:27






  • 1





    Use some JSON parser, whether it be jq or a module in your language of choice. Don't use line-oriented tools like grep or awk to try to parse JSON.

    – chepner
    Nov 14 '18 at 17:27













0












0








0








I've been trying to print all the instances of a matching pattern from file.



Input file:



"id":"prod123","a":1.3,"c":"xyz","q":2, 
"id":"prod456","a":1.3,"c":"xyz","q":1]}
"id":"prod789","a":1.3,"currency":"xyz","q":2,
"id":"prod101112","a":1.3,"c":"xyz","q":1]}


I'd want to print everything between "id":" and ",.



Expected output:



prod123
prod456
prod789
prod101112


I'm using the command



grep -Eo 'id":"[^"]+"",*' | grep -Eo '^[^"]+'


Am I missing anything here?










share|improve this question
















I've been trying to print all the instances of a matching pattern from file.



Input file:



"id":"prod123","a":1.3,"c":"xyz","q":2, 
"id":"prod456","a":1.3,"c":"xyz","q":1]}
"id":"prod789","a":1.3,"currency":"xyz","q":2,
"id":"prod101112","a":1.3,"c":"xyz","q":1]}


I'd want to print everything between "id":" and ",.



Expected output:



prod123
prod456
prod789
prod101112


I'm using the command



grep -Eo 'id":"[^"]+"",*' | grep -Eo '^[^"]+'


Am I missing anything here?







bash awk sed grep






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 14 '18 at 17:15









oguzismail

3,72031125




3,72031125










asked Nov 14 '18 at 17:09









VenkatVenkat

63




63







  • 2





    Do you have jq installed?

    – anubhava
    Nov 14 '18 at 17:18






  • 2





    Your output seems to be a grep or whatever on a JSON file. You might be interested in using jq on your full file. But for this, we should need to see how this thing looks like.

    – kvantour
    Nov 14 '18 at 17:27






  • 1





    Use some JSON parser, whether it be jq or a module in your language of choice. Don't use line-oriented tools like grep or awk to try to parse JSON.

    – chepner
    Nov 14 '18 at 17:27












  • 2





    Do you have jq installed?

    – anubhava
    Nov 14 '18 at 17:18






  • 2





    Your output seems to be a grep or whatever on a JSON file. You might be interested in using jq on your full file. But for this, we should need to see how this thing looks like.

    – kvantour
    Nov 14 '18 at 17:27






  • 1





    Use some JSON parser, whether it be jq or a module in your language of choice. Don't use line-oriented tools like grep or awk to try to parse JSON.

    – chepner
    Nov 14 '18 at 17:27







2




2





Do you have jq installed?

– anubhava
Nov 14 '18 at 17:18





Do you have jq installed?

– anubhava
Nov 14 '18 at 17:18




2




2





Your output seems to be a grep or whatever on a JSON file. You might be interested in using jq on your full file. But for this, we should need to see how this thing looks like.

– kvantour
Nov 14 '18 at 17:27





Your output seems to be a grep or whatever on a JSON file. You might be interested in using jq on your full file. But for this, we should need to see how this thing looks like.

– kvantour
Nov 14 '18 at 17:27




1




1





Use some JSON parser, whether it be jq or a module in your language of choice. Don't use line-oriented tools like grep or awk to try to parse JSON.

– chepner
Nov 14 '18 at 17:27





Use some JSON parser, whether it be jq or a module in your language of choice. Don't use line-oriented tools like grep or awk to try to parse JSON.

– chepner
Nov 14 '18 at 17:27












1 Answer
1






active

oldest

votes


















0














What went wrong is the place of the comma in the first grep:



grep -Eo 'id.:.[^"]+","' inputfile


You need to do something extra for getting the desired substring.



grep -Eo 'id.:.[^"]+","' inputfile | cut -d: -f2 | grep -Eo '[^",]+'


I used cut, that would be easy for your example input.



cut -d'"' -f4 < inputfile


You have alternatives, like using jq, or



sed -r 's/{"id":"([^"]*).*/1/' inputfile


or using awk (solution now like cut but can be changed easy)



awk -F'"' 'print $4' inputfile





share|improve this answer























  • Thank you very much, this has helped and I got the desired result.

    – Venkat
    Nov 15 '18 at 5:41











  • In that case you can accept it: stackoverflow.com/help/someone-answers

    – Walter A
    Nov 15 '18 at 8:57










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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














What went wrong is the place of the comma in the first grep:



grep -Eo 'id.:.[^"]+","' inputfile


You need to do something extra for getting the desired substring.



grep -Eo 'id.:.[^"]+","' inputfile | cut -d: -f2 | grep -Eo '[^",]+'


I used cut, that would be easy for your example input.



cut -d'"' -f4 < inputfile


You have alternatives, like using jq, or



sed -r 's/{"id":"([^"]*).*/1/' inputfile


or using awk (solution now like cut but can be changed easy)



awk -F'"' 'print $4' inputfile





share|improve this answer























  • Thank you very much, this has helped and I got the desired result.

    – Venkat
    Nov 15 '18 at 5:41











  • In that case you can accept it: stackoverflow.com/help/someone-answers

    – Walter A
    Nov 15 '18 at 8:57















0














What went wrong is the place of the comma in the first grep:



grep -Eo 'id.:.[^"]+","' inputfile


You need to do something extra for getting the desired substring.



grep -Eo 'id.:.[^"]+","' inputfile | cut -d: -f2 | grep -Eo '[^",]+'


I used cut, that would be easy for your example input.



cut -d'"' -f4 < inputfile


You have alternatives, like using jq, or



sed -r 's/{"id":"([^"]*).*/1/' inputfile


or using awk (solution now like cut but can be changed easy)



awk -F'"' 'print $4' inputfile





share|improve this answer























  • Thank you very much, this has helped and I got the desired result.

    – Venkat
    Nov 15 '18 at 5:41











  • In that case you can accept it: stackoverflow.com/help/someone-answers

    – Walter A
    Nov 15 '18 at 8:57













0












0








0







What went wrong is the place of the comma in the first grep:



grep -Eo 'id.:.[^"]+","' inputfile


You need to do something extra for getting the desired substring.



grep -Eo 'id.:.[^"]+","' inputfile | cut -d: -f2 | grep -Eo '[^",]+'


I used cut, that would be easy for your example input.



cut -d'"' -f4 < inputfile


You have alternatives, like using jq, or



sed -r 's/{"id":"([^"]*).*/1/' inputfile


or using awk (solution now like cut but can be changed easy)



awk -F'"' 'print $4' inputfile





share|improve this answer













What went wrong is the place of the comma in the first grep:



grep -Eo 'id.:.[^"]+","' inputfile


You need to do something extra for getting the desired substring.



grep -Eo 'id.:.[^"]+","' inputfile | cut -d: -f2 | grep -Eo '[^",]+'


I used cut, that would be easy for your example input.



cut -d'"' -f4 < inputfile


You have alternatives, like using jq, or



sed -r 's/{"id":"([^"]*).*/1/' inputfile


or using awk (solution now like cut but can be changed easy)



awk -F'"' 'print $4' inputfile






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 14 '18 at 20:33









Walter AWalter A

10.9k21031




10.9k21031












  • Thank you very much, this has helped and I got the desired result.

    – Venkat
    Nov 15 '18 at 5:41











  • In that case you can accept it: stackoverflow.com/help/someone-answers

    – Walter A
    Nov 15 '18 at 8:57

















  • Thank you very much, this has helped and I got the desired result.

    – Venkat
    Nov 15 '18 at 5:41











  • In that case you can accept it: stackoverflow.com/help/someone-answers

    – Walter A
    Nov 15 '18 at 8:57
















Thank you very much, this has helped and I got the desired result.

– Venkat
Nov 15 '18 at 5:41





Thank you very much, this has helped and I got the desired result.

– Venkat
Nov 15 '18 at 5:41













In that case you can accept it: stackoverflow.com/help/someone-answers

– Walter A
Nov 15 '18 at 8:57





In that case you can accept it: stackoverflow.com/help/someone-answers

– Walter A
Nov 15 '18 at 8:57



















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