Plotting when time series is in rows not columns- using R










-1















Excel allows you to switch rows and columns in its Chart functionality.



I am trying to replicate this in R. My data (shown) below, is showing production for each company in rows. I am unable to figure out how to show the Month-1, Month-2 etc in x-axis, and the series for each company in the same graph. Any help appreciated.



Data:



sample table



tibble::tribble( ~Company.Name, ~Month-1, ~Month-2, ~Month-3, ~Month-4, "Comp-1", 945.5438986, 1081.417009, 976.7388701, 864.309703, "Comp-2", 16448.87, 13913.19, 12005.28, 10605.32, "Comp-3", 346.9689321, 398.2297592, 549.1282647, 550.4207169, "Comp-4", 748.8806367, 949.463941, 1018.877481, 932.3773791 )










share|improve this question



















  • 1





    as.data.frame(t(data))

    – G5W
    Nov 14 '18 at 21:14











  • Welcome to SO! Could you make your problem reproducible by sharing a sample of your data and the code you're working on so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?

    – Tung
    Nov 15 '18 at 0:34











  • Hi, sorry new to this site and R. Coming from the world of Excel. The data i have is a table that has up to 100 months of production data for over 7,000 companies. As such, I did not think transpose was efficient. The sample data is shown in my original post next to data with a hyper link. Sorry, this comment is not allowing me to paste it again. I need to show the production for each company in one graph. The x-axis is Month-1, Month-2, etc. The Y-axis will be a time series of production for multiple companies.

    – Ajit
    Nov 15 '18 at 15:23












  • tibble::tribble( ~Company.Name, ~Month-1, ~Month-2, ~Month-3, ~Month-4, "Comp-1", 945.5438986, 1081.417009, 976.7388701, 864.309703, "Comp-2", 16448.87, 13913.19, 12005.28, 10605.32, "Comp-3", 346.9689321, 398.2297592, 549.1282647, 550.4207169, "Comp-4", 748.8806367, 949.463941, 1018.877481, 932.3773791 )

    – Ajit
    Nov 15 '18 at 15:48











  • It's much easier to work with code that's in the question, not comments. You can edit the question to put your data & code there

    – camille
    Nov 16 '18 at 0:03















-1















Excel allows you to switch rows and columns in its Chart functionality.



I am trying to replicate this in R. My data (shown) below, is showing production for each company in rows. I am unable to figure out how to show the Month-1, Month-2 etc in x-axis, and the series for each company in the same graph. Any help appreciated.



Data:



sample table



tibble::tribble( ~Company.Name, ~Month-1, ~Month-2, ~Month-3, ~Month-4, "Comp-1", 945.5438986, 1081.417009, 976.7388701, 864.309703, "Comp-2", 16448.87, 13913.19, 12005.28, 10605.32, "Comp-3", 346.9689321, 398.2297592, 549.1282647, 550.4207169, "Comp-4", 748.8806367, 949.463941, 1018.877481, 932.3773791 )










share|improve this question



















  • 1





    as.data.frame(t(data))

    – G5W
    Nov 14 '18 at 21:14











  • Welcome to SO! Could you make your problem reproducible by sharing a sample of your data and the code you're working on so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?

    – Tung
    Nov 15 '18 at 0:34











  • Hi, sorry new to this site and R. Coming from the world of Excel. The data i have is a table that has up to 100 months of production data for over 7,000 companies. As such, I did not think transpose was efficient. The sample data is shown in my original post next to data with a hyper link. Sorry, this comment is not allowing me to paste it again. I need to show the production for each company in one graph. The x-axis is Month-1, Month-2, etc. The Y-axis will be a time series of production for multiple companies.

    – Ajit
    Nov 15 '18 at 15:23












  • tibble::tribble( ~Company.Name, ~Month-1, ~Month-2, ~Month-3, ~Month-4, "Comp-1", 945.5438986, 1081.417009, 976.7388701, 864.309703, "Comp-2", 16448.87, 13913.19, 12005.28, 10605.32, "Comp-3", 346.9689321, 398.2297592, 549.1282647, 550.4207169, "Comp-4", 748.8806367, 949.463941, 1018.877481, 932.3773791 )

    – Ajit
    Nov 15 '18 at 15:48











  • It's much easier to work with code that's in the question, not comments. You can edit the question to put your data & code there

    – camille
    Nov 16 '18 at 0:03













-1












-1








-1








Excel allows you to switch rows and columns in its Chart functionality.



I am trying to replicate this in R. My data (shown) below, is showing production for each company in rows. I am unable to figure out how to show the Month-1, Month-2 etc in x-axis, and the series for each company in the same graph. Any help appreciated.



Data:



sample table



tibble::tribble( ~Company.Name, ~Month-1, ~Month-2, ~Month-3, ~Month-4, "Comp-1", 945.5438986, 1081.417009, 976.7388701, 864.309703, "Comp-2", 16448.87, 13913.19, 12005.28, 10605.32, "Comp-3", 346.9689321, 398.2297592, 549.1282647, 550.4207169, "Comp-4", 748.8806367, 949.463941, 1018.877481, 932.3773791 )










share|improve this question
















Excel allows you to switch rows and columns in its Chart functionality.



I am trying to replicate this in R. My data (shown) below, is showing production for each company in rows. I am unable to figure out how to show the Month-1, Month-2 etc in x-axis, and the series for each company in the same graph. Any help appreciated.



Data:



sample table



tibble::tribble( ~Company.Name, ~Month-1, ~Month-2, ~Month-3, ~Month-4, "Comp-1", 945.5438986, 1081.417009, 976.7388701, 864.309703, "Comp-2", 16448.87, 13913.19, 12005.28, 10605.32, "Comp-3", 346.9689321, 398.2297592, 549.1282647, 550.4207169, "Comp-4", 748.8806367, 949.463941, 1018.877481, 932.3773791 )







r plot






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 16 '18 at 23:04









r2evans

27.5k33158




27.5k33158










asked Nov 14 '18 at 21:08









AjitAjit

22




22







  • 1





    as.data.frame(t(data))

    – G5W
    Nov 14 '18 at 21:14











  • Welcome to SO! Could you make your problem reproducible by sharing a sample of your data and the code you're working on so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?

    – Tung
    Nov 15 '18 at 0:34











  • Hi, sorry new to this site and R. Coming from the world of Excel. The data i have is a table that has up to 100 months of production data for over 7,000 companies. As such, I did not think transpose was efficient. The sample data is shown in my original post next to data with a hyper link. Sorry, this comment is not allowing me to paste it again. I need to show the production for each company in one graph. The x-axis is Month-1, Month-2, etc. The Y-axis will be a time series of production for multiple companies.

    – Ajit
    Nov 15 '18 at 15:23












  • tibble::tribble( ~Company.Name, ~Month-1, ~Month-2, ~Month-3, ~Month-4, "Comp-1", 945.5438986, 1081.417009, 976.7388701, 864.309703, "Comp-2", 16448.87, 13913.19, 12005.28, 10605.32, "Comp-3", 346.9689321, 398.2297592, 549.1282647, 550.4207169, "Comp-4", 748.8806367, 949.463941, 1018.877481, 932.3773791 )

    – Ajit
    Nov 15 '18 at 15:48











  • It's much easier to work with code that's in the question, not comments. You can edit the question to put your data & code there

    – camille
    Nov 16 '18 at 0:03












  • 1





    as.data.frame(t(data))

    – G5W
    Nov 14 '18 at 21:14











  • Welcome to SO! Could you make your problem reproducible by sharing a sample of your data and the code you're working on so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?

    – Tung
    Nov 15 '18 at 0:34











  • Hi, sorry new to this site and R. Coming from the world of Excel. The data i have is a table that has up to 100 months of production data for over 7,000 companies. As such, I did not think transpose was efficient. The sample data is shown in my original post next to data with a hyper link. Sorry, this comment is not allowing me to paste it again. I need to show the production for each company in one graph. The x-axis is Month-1, Month-2, etc. The Y-axis will be a time series of production for multiple companies.

    – Ajit
    Nov 15 '18 at 15:23












  • tibble::tribble( ~Company.Name, ~Month-1, ~Month-2, ~Month-3, ~Month-4, "Comp-1", 945.5438986, 1081.417009, 976.7388701, 864.309703, "Comp-2", 16448.87, 13913.19, 12005.28, 10605.32, "Comp-3", 346.9689321, 398.2297592, 549.1282647, 550.4207169, "Comp-4", 748.8806367, 949.463941, 1018.877481, 932.3773791 )

    – Ajit
    Nov 15 '18 at 15:48











  • It's much easier to work with code that's in the question, not comments. You can edit the question to put your data & code there

    – camille
    Nov 16 '18 at 0:03







1




1





as.data.frame(t(data))

– G5W
Nov 14 '18 at 21:14





as.data.frame(t(data))

– G5W
Nov 14 '18 at 21:14













Welcome to SO! Could you make your problem reproducible by sharing a sample of your data and the code you're working on so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?

– Tung
Nov 15 '18 at 0:34





Welcome to SO! Could you make your problem reproducible by sharing a sample of your data and the code you're working on so others can help (please do not use str(), head() or screenshot)? You can use the reprex and datapasta packages to assist you with that. See also Help me Help you & How to make a great R reproducible example?

– Tung
Nov 15 '18 at 0:34













Hi, sorry new to this site and R. Coming from the world of Excel. The data i have is a table that has up to 100 months of production data for over 7,000 companies. As such, I did not think transpose was efficient. The sample data is shown in my original post next to data with a hyper link. Sorry, this comment is not allowing me to paste it again. I need to show the production for each company in one graph. The x-axis is Month-1, Month-2, etc. The Y-axis will be a time series of production for multiple companies.

– Ajit
Nov 15 '18 at 15:23






Hi, sorry new to this site and R. Coming from the world of Excel. The data i have is a table that has up to 100 months of production data for over 7,000 companies. As such, I did not think transpose was efficient. The sample data is shown in my original post next to data with a hyper link. Sorry, this comment is not allowing me to paste it again. I need to show the production for each company in one graph. The x-axis is Month-1, Month-2, etc. The Y-axis will be a time series of production for multiple companies.

– Ajit
Nov 15 '18 at 15:23














tibble::tribble( ~Company.Name, ~Month-1, ~Month-2, ~Month-3, ~Month-4, "Comp-1", 945.5438986, 1081.417009, 976.7388701, 864.309703, "Comp-2", 16448.87, 13913.19, 12005.28, 10605.32, "Comp-3", 346.9689321, 398.2297592, 549.1282647, 550.4207169, "Comp-4", 748.8806367, 949.463941, 1018.877481, 932.3773791 )

– Ajit
Nov 15 '18 at 15:48





tibble::tribble( ~Company.Name, ~Month-1, ~Month-2, ~Month-3, ~Month-4, "Comp-1", 945.5438986, 1081.417009, 976.7388701, 864.309703, "Comp-2", 16448.87, 13913.19, 12005.28, 10605.32, "Comp-3", 346.9689321, 398.2297592, 549.1282647, 550.4207169, "Comp-4", 748.8806367, 949.463941, 1018.877481, 932.3773791 )

– Ajit
Nov 15 '18 at 15:48













It's much easier to work with code that's in the question, not comments. You can edit the question to put your data & code there

– camille
Nov 16 '18 at 0:03





It's much easier to work with code that's in the question, not comments. You can edit the question to put your data & code there

– camille
Nov 16 '18 at 0:03












1 Answer
1






active

oldest

votes


















0














I'm going to skip the part where you want to transpose, and infer that your purpose for that was solely to help with plotting. The part I'm focusing on here is "show the Month-1, Month-2 etc in x-axis, and the series for each company in the same graph".



This is doable in base graphics, but I highly recommend using ggplot2 (or plotly or similar), due to its ease of dealing with dimensional plots like this. The "grammar of graphics" (which both tend to implement) really prefers data like this be in a "long" format, so part of what I'll do is convert to this format.



First, some data:



set.seed(2)
months <- paste0("Month", 1:30)
companies <- paste0("Comp", 1:5)
m <- matrix(abs(rnorm(length(months)*length(companies), sd=1e3)),
nrow = length(companies))
d <- cbind.data.frame(
Company = companies,
m,
stringsAsFactors = FALSE
)
colnames(d)[-1] <- months
str(d)
# 'data.frame': 5 obs. of 31 variables:
# $ Company: chr "Comp1" "Comp2" "Comp3" "Comp4" ...
# $ Month1 : num 896.9 184.8 1587.8 1130.4 80.3
# $ Month2 : num 132 708 240 1984 139
# $ Month3 : num 418 982 393 1040 1782
# $ Month4 : num 2311.1 878.6 35.8 1012.8 432.3
# (truncated)


Reshaping can be done with multiple libraries, including base R, here are two techniques:



library(data.table)
d2 <- melt(as.data.table(d), id = 1, variable.name = "Month", value.name = "Cost")
d2[,Month := as.integer(gsub("[^0-9]", "", Month)),]
d2
# Company Month Cost
# 1: Comp1 1 896.91455
# 2: Comp2 1 184.84918
# 3: Comp3 1 1587.84533
# 4: Comp4 1 1130.37567
# 5: Comp5 1 80.25176
# ---
# 146: Comp1 30 653.67306
# 147: Comp2 30 657.10598
# 148: Comp3 30 549.90924
# 149: Comp4 30 806.72936
# 150: Comp5 30 997.37972

library(dplyr)
# library(tidyr)
d2 <- tbl_df(d) %>%
tidyr::gather(Month, Cost, -Company) %>%
mutate(Month = as.integer(gsub("[^0-9]", "", Month)))


I also integerized the Month, since it made sense with an ordinal variable. This isn't strictly necessary, the plot would just treat them as discretes.



The plot is anti-climactically simple:



library(ggplot2)
ggplot(d2, aes(Month, Cost, group=Company)) +
geom_line(aes(color = Company))


sample ggplot2 plot



Bottom line: I don't think you need to worry about transposing your data: doing so has many complications that can just confuse things. Reshaping is a good thing (in my opinion), but with this kind of data is fast enough that if your data is stored in the wide format, you can re-transform it without too much difficulty. (If you are thinking about putting this in a database, however, I'd strongly recommend you re-think "wide", your db schema will be challenging if you keep it.)






share|improve this answer























  • Ajit, did this answer your question? If so, please accept it; doing so not only provides a little perk to the answerer with some points, but also provides some closure for readers with similar questions. (If there are still issues, you will likely need to edit your question with further details.)

    – r2evans
    Dec 6 '18 at 21:12










Your Answer






StackExchange.ifUsing("editor", function ()
StackExchange.using("externalEditor", function ()
StackExchange.using("snippets", function ()
StackExchange.snippets.init();
);
);
, "code-snippets");

StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "1"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);

else
createEditor();

);

function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);



);













draft saved

draft discarded


















StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53308740%2fplotting-when-time-series-is-in-rows-not-columns-using-r%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














I'm going to skip the part where you want to transpose, and infer that your purpose for that was solely to help with plotting. The part I'm focusing on here is "show the Month-1, Month-2 etc in x-axis, and the series for each company in the same graph".



This is doable in base graphics, but I highly recommend using ggplot2 (or plotly or similar), due to its ease of dealing with dimensional plots like this. The "grammar of graphics" (which both tend to implement) really prefers data like this be in a "long" format, so part of what I'll do is convert to this format.



First, some data:



set.seed(2)
months <- paste0("Month", 1:30)
companies <- paste0("Comp", 1:5)
m <- matrix(abs(rnorm(length(months)*length(companies), sd=1e3)),
nrow = length(companies))
d <- cbind.data.frame(
Company = companies,
m,
stringsAsFactors = FALSE
)
colnames(d)[-1] <- months
str(d)
# 'data.frame': 5 obs. of 31 variables:
# $ Company: chr "Comp1" "Comp2" "Comp3" "Comp4" ...
# $ Month1 : num 896.9 184.8 1587.8 1130.4 80.3
# $ Month2 : num 132 708 240 1984 139
# $ Month3 : num 418 982 393 1040 1782
# $ Month4 : num 2311.1 878.6 35.8 1012.8 432.3
# (truncated)


Reshaping can be done with multiple libraries, including base R, here are two techniques:



library(data.table)
d2 <- melt(as.data.table(d), id = 1, variable.name = "Month", value.name = "Cost")
d2[,Month := as.integer(gsub("[^0-9]", "", Month)),]
d2
# Company Month Cost
# 1: Comp1 1 896.91455
# 2: Comp2 1 184.84918
# 3: Comp3 1 1587.84533
# 4: Comp4 1 1130.37567
# 5: Comp5 1 80.25176
# ---
# 146: Comp1 30 653.67306
# 147: Comp2 30 657.10598
# 148: Comp3 30 549.90924
# 149: Comp4 30 806.72936
# 150: Comp5 30 997.37972

library(dplyr)
# library(tidyr)
d2 <- tbl_df(d) %>%
tidyr::gather(Month, Cost, -Company) %>%
mutate(Month = as.integer(gsub("[^0-9]", "", Month)))


I also integerized the Month, since it made sense with an ordinal variable. This isn't strictly necessary, the plot would just treat them as discretes.



The plot is anti-climactically simple:



library(ggplot2)
ggplot(d2, aes(Month, Cost, group=Company)) +
geom_line(aes(color = Company))


sample ggplot2 plot



Bottom line: I don't think you need to worry about transposing your data: doing so has many complications that can just confuse things. Reshaping is a good thing (in my opinion), but with this kind of data is fast enough that if your data is stored in the wide format, you can re-transform it without too much difficulty. (If you are thinking about putting this in a database, however, I'd strongly recommend you re-think "wide", your db schema will be challenging if you keep it.)






share|improve this answer























  • Ajit, did this answer your question? If so, please accept it; doing so not only provides a little perk to the answerer with some points, but also provides some closure for readers with similar questions. (If there are still issues, you will likely need to edit your question with further details.)

    – r2evans
    Dec 6 '18 at 21:12















0














I'm going to skip the part where you want to transpose, and infer that your purpose for that was solely to help with plotting. The part I'm focusing on here is "show the Month-1, Month-2 etc in x-axis, and the series for each company in the same graph".



This is doable in base graphics, but I highly recommend using ggplot2 (or plotly or similar), due to its ease of dealing with dimensional plots like this. The "grammar of graphics" (which both tend to implement) really prefers data like this be in a "long" format, so part of what I'll do is convert to this format.



First, some data:



set.seed(2)
months <- paste0("Month", 1:30)
companies <- paste0("Comp", 1:5)
m <- matrix(abs(rnorm(length(months)*length(companies), sd=1e3)),
nrow = length(companies))
d <- cbind.data.frame(
Company = companies,
m,
stringsAsFactors = FALSE
)
colnames(d)[-1] <- months
str(d)
# 'data.frame': 5 obs. of 31 variables:
# $ Company: chr "Comp1" "Comp2" "Comp3" "Comp4" ...
# $ Month1 : num 896.9 184.8 1587.8 1130.4 80.3
# $ Month2 : num 132 708 240 1984 139
# $ Month3 : num 418 982 393 1040 1782
# $ Month4 : num 2311.1 878.6 35.8 1012.8 432.3
# (truncated)


Reshaping can be done with multiple libraries, including base R, here are two techniques:



library(data.table)
d2 <- melt(as.data.table(d), id = 1, variable.name = "Month", value.name = "Cost")
d2[,Month := as.integer(gsub("[^0-9]", "", Month)),]
d2
# Company Month Cost
# 1: Comp1 1 896.91455
# 2: Comp2 1 184.84918
# 3: Comp3 1 1587.84533
# 4: Comp4 1 1130.37567
# 5: Comp5 1 80.25176
# ---
# 146: Comp1 30 653.67306
# 147: Comp2 30 657.10598
# 148: Comp3 30 549.90924
# 149: Comp4 30 806.72936
# 150: Comp5 30 997.37972

library(dplyr)
# library(tidyr)
d2 <- tbl_df(d) %>%
tidyr::gather(Month, Cost, -Company) %>%
mutate(Month = as.integer(gsub("[^0-9]", "", Month)))


I also integerized the Month, since it made sense with an ordinal variable. This isn't strictly necessary, the plot would just treat them as discretes.



The plot is anti-climactically simple:



library(ggplot2)
ggplot(d2, aes(Month, Cost, group=Company)) +
geom_line(aes(color = Company))


sample ggplot2 plot



Bottom line: I don't think you need to worry about transposing your data: doing so has many complications that can just confuse things. Reshaping is a good thing (in my opinion), but with this kind of data is fast enough that if your data is stored in the wide format, you can re-transform it without too much difficulty. (If you are thinking about putting this in a database, however, I'd strongly recommend you re-think "wide", your db schema will be challenging if you keep it.)






share|improve this answer























  • Ajit, did this answer your question? If so, please accept it; doing so not only provides a little perk to the answerer with some points, but also provides some closure for readers with similar questions. (If there are still issues, you will likely need to edit your question with further details.)

    – r2evans
    Dec 6 '18 at 21:12













0












0








0







I'm going to skip the part where you want to transpose, and infer that your purpose for that was solely to help with plotting. The part I'm focusing on here is "show the Month-1, Month-2 etc in x-axis, and the series for each company in the same graph".



This is doable in base graphics, but I highly recommend using ggplot2 (or plotly or similar), due to its ease of dealing with dimensional plots like this. The "grammar of graphics" (which both tend to implement) really prefers data like this be in a "long" format, so part of what I'll do is convert to this format.



First, some data:



set.seed(2)
months <- paste0("Month", 1:30)
companies <- paste0("Comp", 1:5)
m <- matrix(abs(rnorm(length(months)*length(companies), sd=1e3)),
nrow = length(companies))
d <- cbind.data.frame(
Company = companies,
m,
stringsAsFactors = FALSE
)
colnames(d)[-1] <- months
str(d)
# 'data.frame': 5 obs. of 31 variables:
# $ Company: chr "Comp1" "Comp2" "Comp3" "Comp4" ...
# $ Month1 : num 896.9 184.8 1587.8 1130.4 80.3
# $ Month2 : num 132 708 240 1984 139
# $ Month3 : num 418 982 393 1040 1782
# $ Month4 : num 2311.1 878.6 35.8 1012.8 432.3
# (truncated)


Reshaping can be done with multiple libraries, including base R, here are two techniques:



library(data.table)
d2 <- melt(as.data.table(d), id = 1, variable.name = "Month", value.name = "Cost")
d2[,Month := as.integer(gsub("[^0-9]", "", Month)),]
d2
# Company Month Cost
# 1: Comp1 1 896.91455
# 2: Comp2 1 184.84918
# 3: Comp3 1 1587.84533
# 4: Comp4 1 1130.37567
# 5: Comp5 1 80.25176
# ---
# 146: Comp1 30 653.67306
# 147: Comp2 30 657.10598
# 148: Comp3 30 549.90924
# 149: Comp4 30 806.72936
# 150: Comp5 30 997.37972

library(dplyr)
# library(tidyr)
d2 <- tbl_df(d) %>%
tidyr::gather(Month, Cost, -Company) %>%
mutate(Month = as.integer(gsub("[^0-9]", "", Month)))


I also integerized the Month, since it made sense with an ordinal variable. This isn't strictly necessary, the plot would just treat them as discretes.



The plot is anti-climactically simple:



library(ggplot2)
ggplot(d2, aes(Month, Cost, group=Company)) +
geom_line(aes(color = Company))


sample ggplot2 plot



Bottom line: I don't think you need to worry about transposing your data: doing so has many complications that can just confuse things. Reshaping is a good thing (in my opinion), but with this kind of data is fast enough that if your data is stored in the wide format, you can re-transform it without too much difficulty. (If you are thinking about putting this in a database, however, I'd strongly recommend you re-think "wide", your db schema will be challenging if you keep it.)






share|improve this answer













I'm going to skip the part where you want to transpose, and infer that your purpose for that was solely to help with plotting. The part I'm focusing on here is "show the Month-1, Month-2 etc in x-axis, and the series for each company in the same graph".



This is doable in base graphics, but I highly recommend using ggplot2 (or plotly or similar), due to its ease of dealing with dimensional plots like this. The "grammar of graphics" (which both tend to implement) really prefers data like this be in a "long" format, so part of what I'll do is convert to this format.



First, some data:



set.seed(2)
months <- paste0("Month", 1:30)
companies <- paste0("Comp", 1:5)
m <- matrix(abs(rnorm(length(months)*length(companies), sd=1e3)),
nrow = length(companies))
d <- cbind.data.frame(
Company = companies,
m,
stringsAsFactors = FALSE
)
colnames(d)[-1] <- months
str(d)
# 'data.frame': 5 obs. of 31 variables:
# $ Company: chr "Comp1" "Comp2" "Comp3" "Comp4" ...
# $ Month1 : num 896.9 184.8 1587.8 1130.4 80.3
# $ Month2 : num 132 708 240 1984 139
# $ Month3 : num 418 982 393 1040 1782
# $ Month4 : num 2311.1 878.6 35.8 1012.8 432.3
# (truncated)


Reshaping can be done with multiple libraries, including base R, here are two techniques:



library(data.table)
d2 <- melt(as.data.table(d), id = 1, variable.name = "Month", value.name = "Cost")
d2[,Month := as.integer(gsub("[^0-9]", "", Month)),]
d2
# Company Month Cost
# 1: Comp1 1 896.91455
# 2: Comp2 1 184.84918
# 3: Comp3 1 1587.84533
# 4: Comp4 1 1130.37567
# 5: Comp5 1 80.25176
# ---
# 146: Comp1 30 653.67306
# 147: Comp2 30 657.10598
# 148: Comp3 30 549.90924
# 149: Comp4 30 806.72936
# 150: Comp5 30 997.37972

library(dplyr)
# library(tidyr)
d2 <- tbl_df(d) %>%
tidyr::gather(Month, Cost, -Company) %>%
mutate(Month = as.integer(gsub("[^0-9]", "", Month)))


I also integerized the Month, since it made sense with an ordinal variable. This isn't strictly necessary, the plot would just treat them as discretes.



The plot is anti-climactically simple:



library(ggplot2)
ggplot(d2, aes(Month, Cost, group=Company)) +
geom_line(aes(color = Company))


sample ggplot2 plot



Bottom line: I don't think you need to worry about transposing your data: doing so has many complications that can just confuse things. Reshaping is a good thing (in my opinion), but with this kind of data is fast enough that if your data is stored in the wide format, you can re-transform it without too much difficulty. (If you are thinking about putting this in a database, however, I'd strongly recommend you re-think "wide", your db schema will be challenging if you keep it.)







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 16 '18 at 23:40









r2evansr2evans

27.5k33158




27.5k33158












  • Ajit, did this answer your question? If so, please accept it; doing so not only provides a little perk to the answerer with some points, but also provides some closure for readers with similar questions. (If there are still issues, you will likely need to edit your question with further details.)

    – r2evans
    Dec 6 '18 at 21:12

















  • Ajit, did this answer your question? If so, please accept it; doing so not only provides a little perk to the answerer with some points, but also provides some closure for readers with similar questions. (If there are still issues, you will likely need to edit your question with further details.)

    – r2evans
    Dec 6 '18 at 21:12
















Ajit, did this answer your question? If so, please accept it; doing so not only provides a little perk to the answerer with some points, but also provides some closure for readers with similar questions. (If there are still issues, you will likely need to edit your question with further details.)

– r2evans
Dec 6 '18 at 21:12





Ajit, did this answer your question? If so, please accept it; doing so not only provides a little perk to the answerer with some points, but also provides some closure for readers with similar questions. (If there are still issues, you will likely need to edit your question with further details.)

– r2evans
Dec 6 '18 at 21:12



















draft saved

draft discarded
















































Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid


  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.

To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53308740%2fplotting-when-time-series-is-in-rows-not-columns-using-r%23new-answer', 'question_page');

);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







這個網誌中的熱門文章

How to read a connectionString WITH PROVIDER in .NET Core?

In R, how to develop a multiplot heatmap.2 figure showing key labels successfully

Museum of Modern and Contemporary Art of Trento and Rovereto