How to create an instanceof AST node using typescript compiler API










1















I would like to represent the typescript code "MyObj instanceOf MyClass" with the typescript compiler API.



I try to use the createBinary API as follow:



ts.createBinary(leftExpression,ts.SyntaxKind.InstanceOfKeyword, rightExpression);


How do I create the rightExpression?










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    1















    I would like to represent the typescript code "MyObj instanceOf MyClass" with the typescript compiler API.



    I try to use the createBinary API as follow:



    ts.createBinary(leftExpression,ts.SyntaxKind.InstanceOfKeyword, rightExpression);


    How do I create the rightExpression?










    share|improve this question


























      1












      1








      1








      I would like to represent the typescript code "MyObj instanceOf MyClass" with the typescript compiler API.



      I try to use the createBinary API as follow:



      ts.createBinary(leftExpression,ts.SyntaxKind.InstanceOfKeyword, rightExpression);


      How do I create the rightExpression?










      share|improve this question
















      I would like to represent the typescript code "MyObj instanceOf MyClass" with the typescript compiler API.



      I try to use the createBinary API as follow:



      ts.createBinary(leftExpression,ts.SyntaxKind.InstanceOfKeyword, rightExpression);


      How do I create the rightExpression?







      typescript typescript-compiler-api






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 14 '18 at 18:22









      Mr Shunz

      79112127




      79112127










      asked Nov 14 '18 at 16:45









      stef2nicestef2nice

      61




      61






















          1 Answer
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          The left and right expressions are identifiers, so the createIdentifier method could be used:



          const binaryExpression = ts.createBinary(ts.createIdentifier("MyObj"),
          ts.SyntaxKind.InstanceOfKeyword,
          ts.createIdentifier("MyClass"));





          share|improve this answer






















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            1 Answer
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            1 Answer
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            active

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            active

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            1














            The left and right expressions are identifiers, so the createIdentifier method could be used:



            const binaryExpression = ts.createBinary(ts.createIdentifier("MyObj"),
            ts.SyntaxKind.InstanceOfKeyword,
            ts.createIdentifier("MyClass"));





            share|improve this answer



























              1














              The left and right expressions are identifiers, so the createIdentifier method could be used:



              const binaryExpression = ts.createBinary(ts.createIdentifier("MyObj"),
              ts.SyntaxKind.InstanceOfKeyword,
              ts.createIdentifier("MyClass"));





              share|improve this answer

























                1












                1








                1







                The left and right expressions are identifiers, so the createIdentifier method could be used:



                const binaryExpression = ts.createBinary(ts.createIdentifier("MyObj"),
                ts.SyntaxKind.InstanceOfKeyword,
                ts.createIdentifier("MyClass"));





                share|improve this answer













                The left and right expressions are identifiers, so the createIdentifier method could be used:



                const binaryExpression = ts.createBinary(ts.createIdentifier("MyObj"),
                ts.SyntaxKind.InstanceOfKeyword,
                ts.createIdentifier("MyClass"));






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 14 '18 at 16:55









                David SherretDavid Sherret

                52.6k16122123




                52.6k16122123





























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