Iterate until matching text is found

I am writing a test which should iterate until a partial matching text is found . Once found , it should do some thing. Here is my code.

let getName = await $$('.button').getText();
if (getName === 'New name') 
 // do something here

My test doesn't iterate even though there exists a matching name. It should also consider partials tests, for instance New name 1.

Appreciate your suggestions.

edited Nov 14 '18 at 9:36

asked Nov 14 '18 at 9:30

Ninja

406

Why do you have 2 closing parenthesis ?

– executable
Nov 14 '18 at 9:34

Thanks for finding. I corrected it @executable

– Ninja
Nov 14 '18 at 9:45

add a comment |

I am writing a test which should iterate until a partial matching text is found . Once found , it should do some thing. Here is my code.

let getName = await $$('.button').getText();
if (getName === 'New name') 
 // do something here

My test doesn't iterate even though there exists a matching name. It should also consider partials tests, for instance New name 1.

Appreciate your suggestions.

edited Nov 14 '18 at 9:36

asked Nov 14 '18 at 9:30

Ninja

406

Why do you have 2 closing parenthesis ?

– executable
Nov 14 '18 at 9:34

Thanks for finding. I corrected it @executable

– Ninja
Nov 14 '18 at 9:45

add a comment |

I am writing a test which should iterate until a partial matching text is found . Once found , it should do some thing. Here is my code.

let getName = await $$('.button').getText();
if (getName === 'New name') 
 // do something here

My test doesn't iterate even though there exists a matching name. It should also consider partials tests, for instance New name 1.

Appreciate your suggestions.

edited Nov 14 '18 at 9:36

asked Nov 14 '18 at 9:30

Ninja

406

I am writing a test which should iterate until a partial matching text is found . Once found , it should do some thing. Here is my code.

let getName = await $$('.button').getText();
if (getName === 'New name') 
 // do something here

My test doesn't iterate even though there exists a matching name. It should also consider partials tests, for instance New name 1.

Appreciate your suggestions.

protractor

edited Nov 14 '18 at 9:36

asked Nov 14 '18 at 9:30

Ninja

406

edited Nov 14 '18 at 9:36

asked Nov 14 '18 at 9:30

Ninja

406

edited Nov 14 '18 at 9:36

asked Nov 14 '18 at 9:30

Ninja

406

asked Nov 14 '18 at 9:30

Ninja

406

asked Nov 14 '18 at 9:30

Ninja

406

Why do you have 2 closing parenthesis ?

– executable
Nov 14 '18 at 9:34

Thanks for finding. I corrected it @executable

– Ninja
Nov 14 '18 at 9:45

add a comment |

Why do you have 2 closing parenthesis ?

– executable
Nov 14 '18 at 9:34

Thanks for finding. I corrected it @executable

– Ninja
Nov 14 '18 at 9:45

Why do you have 2 closing parenthesis ?

– executable
Nov 14 '18 at 9:34

Thanks for finding. I corrected it @executable

– Ninja
Nov 14 '18 at 9:45

add a comment |

1 Answer
1

active

oldest

votes

My answer is a shot in a dark due to lack of details in your question, but I'll try to guess your problem.

$$().getText() returns array of strings, thus your code must be

let names = await $$('.button').getText();

for (let i=0; i<names.length; i++) 
 if (names[i].includes('New name')) 
 // do something here

But when you await $$().getText(), and there are more than ~10 elements, be ready to face this error Random occurrences of Failed: ECONNREFUSED connect ECONNREFUSED 127.0.0.1 when running protractor tests

Actually, I must include another guess here based on an assumption you'll need to interact with the first element that matches condition

let $newNameElement = await $$('.button').filter( $elem =>
 (await $elem.getText()).toLowerCase().includes('new name');
).get(0);

// do whatever you want with your $newNameElement

edited Nov 14 '18 at 18:29

answered Nov 14 '18 at 18:23

Sergey Pleshakov

210113

lmk if any problems

– Sergey Pleshakov
Nov 14 '18 at 18:29

Thanks for this. But the if statement still doesn't execute if use includes. But If i write if (name[i] === 'New name') it works. This way I can only validate one string. I want to match against multiple values

– Ninja
Nov 15 '18 at 15:12

when you find those elements, what exactly do you want to do with them? In a nut shell, let $$newNameElement = await $$('.button').filter( $elem => (await $elem.getText()).toLowerCase().includes('new name'); ) should return you all elements that you're looking for. so you can interact with each of them through forEach()

– Sergey Pleshakov
Nov 15 '18 at 16:45

add a comment |

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1 Answer
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My answer is a shot in a dark due to lack of details in your question, but I'll try to guess your problem.

$$().getText() returns array of strings, thus your code must be

let names = await $$('.button').getText();

for (let i=0; i<names.length; i++) 
 if (names[i].includes('New name')) 
 // do something here

Actually, I must include another guess here based on an assumption you'll need to interact with the first element that matches condition

let $newNameElement = await $$('.button').filter( $elem =>
 (await $elem.getText()).toLowerCase().includes('new name');
).get(0);

// do whatever you want with your $newNameElement

edited Nov 14 '18 at 18:29

answered Nov 14 '18 at 18:23

Sergey Pleshakov

210113

lmk if any problems

– Sergey Pleshakov
Nov 14 '18 at 18:29

Thanks for this. But the if statement still doesn't execute if use includes. But If i write if (name[i] === 'New name') it works. This way I can only validate one string. I want to match against multiple values

– Ninja
Nov 15 '18 at 15:12

when you find those elements, what exactly do you want to do with them? In a nut shell, let $$newNameElement = await $$('.button').filter( $elem => (await $elem.getText()).toLowerCase().includes('new name'); ) should return you all elements that you're looking for. so you can interact with each of them through forEach()

– Sergey Pleshakov
Nov 15 '18 at 16:45

add a comment |

My answer is a shot in a dark due to lack of details in your question, but I'll try to guess your problem.

$$().getText() returns array of strings, thus your code must be

let names = await $$('.button').getText();

for (let i=0; i<names.length; i++) 
 if (names[i].includes('New name')) 
 // do something here

Actually, I must include another guess here based on an assumption you'll need to interact with the first element that matches condition

let $newNameElement = await $$('.button').filter( $elem =>
 (await $elem.getText()).toLowerCase().includes('new name');
).get(0);

// do whatever you want with your $newNameElement

edited Nov 14 '18 at 18:29

answered Nov 14 '18 at 18:23

Sergey Pleshakov

210113

lmk if any problems

– Sergey Pleshakov
Nov 14 '18 at 18:29

Thanks for this. But the if statement still doesn't execute if use includes. But If i write if (name[i] === 'New name') it works. This way I can only validate one string. I want to match against multiple values

– Ninja
Nov 15 '18 at 15:12

when you find those elements, what exactly do you want to do with them? In a nut shell, let $$newNameElement = await $$('.button').filter( $elem => (await $elem.getText()).toLowerCase().includes('new name'); ) should return you all elements that you're looking for. so you can interact with each of them through forEach()

– Sergey Pleshakov
Nov 15 '18 at 16:45

add a comment |

My answer is a shot in a dark due to lack of details in your question, but I'll try to guess your problem.

$$().getText() returns array of strings, thus your code must be

let names = await $$('.button').getText();

for (let i=0; i<names.length; i++) 
 if (names[i].includes('New name')) 
 // do something here

Actually, I must include another guess here based on an assumption you'll need to interact with the first element that matches condition

let $newNameElement = await $$('.button').filter( $elem =>
 (await $elem.getText()).toLowerCase().includes('new name');
).get(0);

// do whatever you want with your $newNameElement

edited Nov 14 '18 at 18:29

answered Nov 14 '18 at 18:23

Sergey Pleshakov

210113

My answer is a shot in a dark due to lack of details in your question, but I'll try to guess your problem.

$$().getText() returns array of strings, thus your code must be

let names = await $$('.button').getText();

for (let i=0; i<names.length; i++) 
 if (names[i].includes('New name')) 
 // do something here

Actually, I must include another guess here based on an assumption you'll need to interact with the first element that matches condition

let $newNameElement = await $$('.button').filter( $elem =>
 (await $elem.getText()).toLowerCase().includes('new name');
).get(0);

// do whatever you want with your $newNameElement

edited Nov 14 '18 at 18:29

answered Nov 14 '18 at 18:23

Sergey Pleshakov

210113

edited Nov 14 '18 at 18:29

answered Nov 14 '18 at 18:23

Sergey Pleshakov

210113

answered Nov 14 '18 at 18:23

Sergey Pleshakov

210113

answered Nov 14 '18 at 18:23

Sergey Pleshakov

210113

lmk if any problems

– Sergey Pleshakov
Nov 14 '18 at 18:29

Thanks for this. But the if statement still doesn't execute if use includes. But If i write if (name[i] === 'New name') it works. This way I can only validate one string. I want to match against multiple values

– Ninja
Nov 15 '18 at 15:12

when you find those elements, what exactly do you want to do with them? In a nut shell, let $$newNameElement = await $$('.button').filter( $elem => (await $elem.getText()).toLowerCase().includes('new name'); ) should return you all elements that you're looking for. so you can interact with each of them through forEach()

– Sergey Pleshakov
Nov 15 '18 at 16:45

add a comment |

lmk if any problems

– Sergey Pleshakov
Nov 14 '18 at 18:29

Thanks for this. But the if statement still doesn't execute if use includes. But If i write if (name[i] === 'New name') it works. This way I can only validate one string. I want to match against multiple values

– Ninja
Nov 15 '18 at 15:12

when you find those elements, what exactly do you want to do with them? In a nut shell, let $$newNameElement = await $$('.button').filter( $elem => (await $elem.getText()).toLowerCase().includes('new name'); ) should return you all elements that you're looking for. so you can interact with each of them through forEach()

– Sergey Pleshakov
Nov 15 '18 at 16:45

lmk if any problems

– Sergey Pleshakov
Nov 14 '18 at 18:29

Thanks for this. But the if statement still doesn't execute if use includes. But If i write if (name[i] === 'New name') it works. This way I can only validate one string. I want to match against multiple values

– Ninja
Nov 15 '18 at 15:12

when you find those elements, what exactly do you want to do with them? In a nut shell, let $$newNameElement = await $$('.button').filter( $elem => (await $elem.getText()).toLowerCase().includes('new name'); ) should return you all elements that you're looking for. so you can interact with each of them through forEach()

– Sergey Pleshakov
Nov 15 '18 at 16:45

add a comment |

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