unable to show dynamic value in the dropdown list available in the table column
I have a simple html table with multiple rows and one of the column has the dropdown list which should populate the values dynamically.
My code has some issue to show the value in the dropdown list in the table, i want to show same value in all the dropdown list shown under 'Select Product' column.
Demo link : http://plnkr.co/edit/roklRKCLjjVeOPe1df4m?p=preview
Sample code below:
// Populate the dropdown with the value
function populateSelect(ids)
var productDropdown = $("#product");
console.log("productDropdown value : " +productDropdown);
$.each(ids, function()
$("<option />").appendTo(productDropdown);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<body onload="populateSelect('TestProduct')">
<table id="productTable" border="1">
<thead>
<tr>
<th>PID</th>
<th>Select Product</th>
</tr>
</thead>
<tbody>
<tr>
<td>100</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>200</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>300</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>400</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
</tbody>
</table>
</body></html>Note : In the above code i'm trying to show the value 'TestProduct' in all the dropdown's shown in the 'Select Product' column.
javascript jquery html
asked Nov 14 '18 at 18:22
user3684675user3684675
1231517
add a comment |
I have a simple html table with multiple rows and one of the column has the dropdown list which should populate the values dynamically.
My code has some issue to show the value in the dropdown list in the table, i want to show same value in all the dropdown list shown under 'Select Product' column.
Demo link : http://plnkr.co/edit/roklRKCLjjVeOPe1df4m?p=preview
Sample code below:
// Populate the dropdown with the value
function populateSelect(ids)
var productDropdown = $("#product");
console.log("productDropdown value : " +productDropdown);
$.each(ids, function()
$("<option />").appendTo(productDropdown);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<body onload="populateSelect('TestProduct')">
<table id="productTable" border="1">
<thead>
<tr>
<th>PID</th>
<th>Select Product</th>
</tr>
</thead>
<tbody>
<tr>
<td>100</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>200</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>300</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>400</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
</tbody>
</table>
</body></html>Note : In the above code i'm trying to show the value 'TestProduct' in all the dropdown's shown in the 'Select Product' column.
javascript jquery html
asked Nov 14 '18 at 18:22
user3684675user3684675
1231517
$.each takes in an array/object, 'TestProduct' is a string
– Toxnyc
Nov 14 '18 at 18:39
add a comment |
I have a simple html table with multiple rows and one of the column has the dropdown list which should populate the values dynamically.
My code has some issue to show the value in the dropdown list in the table, i want to show same value in all the dropdown list shown under 'Select Product' column.
Demo link : http://plnkr.co/edit/roklRKCLjjVeOPe1df4m?p=preview
Sample code below:
// Populate the dropdown with the value
function populateSelect(ids)
var productDropdown = $("#product");
console.log("productDropdown value : " +productDropdown);
$.each(ids, function()
$("<option />").appendTo(productDropdown);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<body onload="populateSelect('TestProduct')">
<table id="productTable" border="1">
<thead>
<tr>
<th>PID</th>
<th>Select Product</th>
</tr>
</thead>
<tbody>
<tr>
<td>100</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>200</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>300</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>400</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
</tbody>
</table>
</body></html>Note : In the above code i'm trying to show the value 'TestProduct' in all the dropdown's shown in the 'Select Product' column.
javascript jquery html
asked Nov 14 '18 at 18:22
user3684675user3684675
1231517
I have a simple html table with multiple rows and one of the column has the dropdown list which should populate the values dynamically.
My code has some issue to show the value in the dropdown list in the table, i want to show same value in all the dropdown list shown under 'Select Product' column.
Demo link : http://plnkr.co/edit/roklRKCLjjVeOPe1df4m?p=preview
Sample code below:
// Populate the dropdown with the value
function populateSelect(ids)
var productDropdown = $("#product");
console.log("productDropdown value : " +productDropdown);
$.each(ids, function()
$("<option />").appendTo(productDropdown);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<body onload="populateSelect('TestProduct')">
<table id="productTable" border="1">
<thead>
<tr>
<th>PID</th>
<th>Select Product</th>
</tr>
</thead>
<tbody>
<tr>
<td>100</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>200</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>300</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>400</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
</tbody>
</table>
</body></html>Note : In the above code i'm trying to show the value 'TestProduct' in all the dropdown's shown in the 'Select Product' column.
// Populate the dropdown with the value
function populateSelect(ids)
var productDropdown = $("#product");
console.log("productDropdown value : " +productDropdown);
$.each(ids, function()
$("<option />").appendTo(productDropdown);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<body onload="populateSelect('TestProduct')">
<table id="productTable" border="1">
<thead>
<tr>
<th>PID</th>
<th>Select Product</th>
</tr>
</thead>
<tbody>
<tr>
<td>100</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>200</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>300</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>400</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
</tbody>
</table>
</body></html>// Populate the dropdown with the value
function populateSelect(ids)
var productDropdown = $("#product");
console.log("productDropdown value : " +productDropdown);
$.each(ids, function()
$("<option />").appendTo(productDropdown);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<body onload="populateSelect('TestProduct')">
<table id="productTable" border="1">
<thead>
<tr>
<th>PID</th>
<th>Select Product</th>
</tr>
</thead>
<tbody>
<tr>
<td>100</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>200</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>300</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>400</td>
<td class="dropdown">
<select name="filter_for" id="product">
<option value=""> </option>
</select>
</td>
</tr>
</tbody>
</table>
</body></html>javascript jquery html
javascript jquery html
asked Nov 14 '18 at 18:22
user3684675user3684675
1231517
asked Nov 14 '18 at 18:22
user3684675user3684675
1231517
asked Nov 14 '18 at 18:22
user3684675user3684675
1231517
asked Nov 14 '18 at 18:22
user3684675user3684675
1231517
asked Nov 14 '18 at 18:22
user3684675user3684675
1231517
1231517
$.each takes in an array/object, 'TestProduct' is a string
– Toxnyc
Nov 14 '18 at 18:39
add a comment |
$.each takes in an array/object, 'TestProduct' is a string
– Toxnyc
Nov 14 '18 at 18:39
$.each takes in an array/object, 'TestProduct' is a string
– Toxnyc
Nov 14 '18 at 18:39
$.each takes in an array/object, 'TestProduct' is a string
– Toxnyc
Nov 14 '18 at 18:39
add a comment |
2 Answers
2
active
oldest
votes
To have all the dropdowns with the value 'Test Product', use the following code, you don't need a loop for this.
function populateSelect(ids)
var productDropdown = $(".dropdown select");
console.log("productDropdown va " + productDropdown);
$(`<option>$ids</option>`).appendTo(productDropdown);
answered Nov 14 '18 at 18:49
ToxnycToxnyc
1876
add a comment |
I think the issue you're running into is with the way you're initializing the data body onload="populateSelect('TestProduct'); First of all, in order to successfully $.each() through the ids, you'll need to pass them as an array rather than a string.
Since you have jQuery, I'd recommend using $(document).ready(function()); like so:
EDIT: forgot to mention that when you call your $.each() function the first time, the callback function needs the parameters of index and value, so you can iterate through them as key => value pairs if that's what you're choosing to do. Otherwise, you could just use the value parameter in your option-build like:
var option = '<option value="'+value+'">'+value+'</option>';
function populateSelect(ids)
console.log(ids);
var productDropdown = $(".product");
//console.log("productDropdown va " + productDropdown);
$.each(ids, function(index, value)
var option = '<option value="'+index+'">' + value + '</option>';
$.each(productDropdown, function()
$(this).append(option);
);
);
$(document).ready(function()
populateSelect(['TestProduct', 'TestProduct2']);
);
Also, you're using a non-unique ID #product for each of your dropdowns. IDs should be unique, so I've written the code using .product as a class instead. The new HTML:
<table id="productTable" border="1">
<thead>
<tr>
<th>PID</th>
<th>Select Product</th>
</tr>
</thead>
<tbody>
<tr>
<td>100</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>200</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>300</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>400</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
</tbody>
</table>
answered Nov 14 '18 at 18:34
RyanRyan
3169
Please find the updated code demo plnkr.co/edit/3J4mJqznsIY7rEVtvvqG?p=preview . The value is shown in the quotations in the drop down list in the table. Any inputs to not to show the quotations in the dropdown list.
– user3684675
Nov 14 '18 at 21:37
I think this post stackoverflow.com/questions/16598477/… will help with that problem for you!
– Ryan
Nov 14 '18 at 21:43
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
To have all the dropdowns with the value 'Test Product', use the following code, you don't need a loop for this.
function populateSelect(ids)
var productDropdown = $(".dropdown select");
console.log("productDropdown va " + productDropdown);
$(`<option>$ids</option>`).appendTo(productDropdown);
answered Nov 14 '18 at 18:49
ToxnycToxnyc
1876
add a comment |
To have all the dropdowns with the value 'Test Product', use the following code, you don't need a loop for this.
function populateSelect(ids)
var productDropdown = $(".dropdown select");
console.log("productDropdown va " + productDropdown);
$(`<option>$ids</option>`).appendTo(productDropdown);
answered Nov 14 '18 at 18:49
ToxnycToxnyc
1876
add a comment |
To have all the dropdowns with the value 'Test Product', use the following code, you don't need a loop for this.
function populateSelect(ids)
var productDropdown = $(".dropdown select");
console.log("productDropdown va " + productDropdown);
$(`<option>$ids</option>`).appendTo(productDropdown);
answered Nov 14 '18 at 18:49
ToxnycToxnyc
1876
To have all the dropdowns with the value 'Test Product', use the following code, you don't need a loop for this.
function populateSelect(ids)
var productDropdown = $(".dropdown select");
console.log("productDropdown va " + productDropdown);
$(`<option>$ids</option>`).appendTo(productDropdown);
answered Nov 14 '18 at 18:49
ToxnycToxnyc
1876
answered Nov 14 '18 at 18:49
ToxnycToxnyc
1876
answered Nov 14 '18 at 18:49
ToxnycToxnyc
1876
answered Nov 14 '18 at 18:49
ToxnycToxnyc
1876
1876
add a comment |
add a comment |
I think the issue you're running into is with the way you're initializing the data body onload="populateSelect('TestProduct'); First of all, in order to successfully $.each() through the ids, you'll need to pass them as an array rather than a string.
Since you have jQuery, I'd recommend using $(document).ready(function()); like so:
EDIT: forgot to mention that when you call your $.each() function the first time, the callback function needs the parameters of index and value, so you can iterate through them as key => value pairs if that's what you're choosing to do. Otherwise, you could just use the value parameter in your option-build like:
var option = '<option value="'+value+'">'+value+'</option>';
function populateSelect(ids)
console.log(ids);
var productDropdown = $(".product");
//console.log("productDropdown va " + productDropdown);
$.each(ids, function(index, value)
var option = '<option value="'+index+'">' + value + '</option>';
$.each(productDropdown, function()
$(this).append(option);
);
);
$(document).ready(function()
populateSelect(['TestProduct', 'TestProduct2']);
);
Also, you're using a non-unique ID #product for each of your dropdowns. IDs should be unique, so I've written the code using .product as a class instead. The new HTML:
<table id="productTable" border="1">
<thead>
<tr>
<th>PID</th>
<th>Select Product</th>
</tr>
</thead>
<tbody>
<tr>
<td>100</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>200</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>300</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>400</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
</tbody>
</table>
answered Nov 14 '18 at 18:34
RyanRyan
3169
Please find the updated code demo plnkr.co/edit/3J4mJqznsIY7rEVtvvqG?p=preview . The value is shown in the quotations in the drop down list in the table. Any inputs to not to show the quotations in the dropdown list.
– user3684675
Nov 14 '18 at 21:37
I think this post stackoverflow.com/questions/16598477/… will help with that problem for you!
– Ryan
Nov 14 '18 at 21:43
add a comment |
I think the issue you're running into is with the way you're initializing the data body onload="populateSelect('TestProduct'); First of all, in order to successfully $.each() through the ids, you'll need to pass them as an array rather than a string.
Since you have jQuery, I'd recommend using $(document).ready(function()); like so:
EDIT: forgot to mention that when you call your $.each() function the first time, the callback function needs the parameters of index and value, so you can iterate through them as key => value pairs if that's what you're choosing to do. Otherwise, you could just use the value parameter in your option-build like:
var option = '<option value="'+value+'">'+value+'</option>';
function populateSelect(ids)
console.log(ids);
var productDropdown = $(".product");
//console.log("productDropdown va " + productDropdown);
$.each(ids, function(index, value)
var option = '<option value="'+index+'">' + value + '</option>';
$.each(productDropdown, function()
$(this).append(option);
);
);
$(document).ready(function()
populateSelect(['TestProduct', 'TestProduct2']);
);
Also, you're using a non-unique ID #product for each of your dropdowns. IDs should be unique, so I've written the code using .product as a class instead. The new HTML:
<table id="productTable" border="1">
<thead>
<tr>
<th>PID</th>
<th>Select Product</th>
</tr>
</thead>
<tbody>
<tr>
<td>100</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>200</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>300</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>400</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
</tbody>
</table>
answered Nov 14 '18 at 18:34
RyanRyan
3169
Please find the updated code demo plnkr.co/edit/3J4mJqznsIY7rEVtvvqG?p=preview . The value is shown in the quotations in the drop down list in the table. Any inputs to not to show the quotations in the dropdown list.
– user3684675
Nov 14 '18 at 21:37
I think this post stackoverflow.com/questions/16598477/… will help with that problem for you!
– Ryan
Nov 14 '18 at 21:43
add a comment |
I think the issue you're running into is with the way you're initializing the data body onload="populateSelect('TestProduct'); First of all, in order to successfully $.each() through the ids, you'll need to pass them as an array rather than a string.
Since you have jQuery, I'd recommend using $(document).ready(function()); like so:
EDIT: forgot to mention that when you call your $.each() function the first time, the callback function needs the parameters of index and value, so you can iterate through them as key => value pairs if that's what you're choosing to do. Otherwise, you could just use the value parameter in your option-build like:
var option = '<option value="'+value+'">'+value+'</option>';
function populateSelect(ids)
console.log(ids);
var productDropdown = $(".product");
//console.log("productDropdown va " + productDropdown);
$.each(ids, function(index, value)
var option = '<option value="'+index+'">' + value + '</option>';
$.each(productDropdown, function()
$(this).append(option);
);
);
$(document).ready(function()
populateSelect(['TestProduct', 'TestProduct2']);
);
Also, you're using a non-unique ID #product for each of your dropdowns. IDs should be unique, so I've written the code using .product as a class instead. The new HTML:
<table id="productTable" border="1">
<thead>
<tr>
<th>PID</th>
<th>Select Product</th>
</tr>
</thead>
<tbody>
<tr>
<td>100</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>200</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>300</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>400</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
</tbody>
</table>
answered Nov 14 '18 at 18:34
RyanRyan
3169
I think the issue you're running into is with the way you're initializing the data body onload="populateSelect('TestProduct'); First of all, in order to successfully $.each() through the ids, you'll need to pass them as an array rather than a string.
Since you have jQuery, I'd recommend using $(document).ready(function()); like so:
EDIT: forgot to mention that when you call your $.each() function the first time, the callback function needs the parameters of index and value, so you can iterate through them as key => value pairs if that's what you're choosing to do. Otherwise, you could just use the value parameter in your option-build like:
var option = '<option value="'+value+'">'+value+'</option>';
function populateSelect(ids)
console.log(ids);
var productDropdown = $(".product");
//console.log("productDropdown va " + productDropdown);
$.each(ids, function(index, value)
var option = '<option value="'+index+'">' + value + '</option>';
$.each(productDropdown, function()
$(this).append(option);
);
);
$(document).ready(function()
populateSelect(['TestProduct', 'TestProduct2']);
);
Also, you're using a non-unique ID #product for each of your dropdowns. IDs should be unique, so I've written the code using .product as a class instead. The new HTML:
<table id="productTable" border="1">
<thead>
<tr>
<th>PID</th>
<th>Select Product</th>
</tr>
</thead>
<tbody>
<tr>
<td>100</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>200</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>300</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
<tr>
<td>400</td>
<td class="dropdown">
<select name="filter_for" class="product">
<option value=""> </option>
</select>
</td>
</tr>
</tbody>
</table>
answered Nov 14 '18 at 18:34
RyanRyan
3169
edited Nov 14 '18 at 18:45
answered Nov 14 '18 at 18:34
RyanRyan
3169
answered Nov 14 '18 at 18:34
RyanRyan
3169
answered Nov 14 '18 at 18:34
RyanRyan
3169
3169
Please find the updated code demo plnkr.co/edit/3J4mJqznsIY7rEVtvvqG?p=preview . The value is shown in the quotations in the drop down list in the table. Any inputs to not to show the quotations in the dropdown list.
– user3684675
Nov 14 '18 at 21:37
I think this post stackoverflow.com/questions/16598477/… will help with that problem for you!
– Ryan
Nov 14 '18 at 21:43
add a comment |
Please find the updated code demo plnkr.co/edit/3J4mJqznsIY7rEVtvvqG?p=preview . The value is shown in the quotations in the drop down list in the table. Any inputs to not to show the quotations in the dropdown list.
– user3684675
Nov 14 '18 at 21:37
I think this post stackoverflow.com/questions/16598477/… will help with that problem for you!
– Ryan
Nov 14 '18 at 21:43
Please find the updated code demo plnkr.co/edit/3J4mJqznsIY7rEVtvvqG?p=preview . The value is shown in the quotations in the drop down list in the table. Any inputs to not to show the quotations in the dropdown list.
– user3684675
Nov 14 '18 at 21:37
Please find the updated code demo plnkr.co/edit/3J4mJqznsIY7rEVtvvqG?p=preview . The value is shown in the quotations in the drop down list in the table. Any inputs to not to show the quotations in the dropdown list.
– user3684675
Nov 14 '18 at 21:37
I think this post stackoverflow.com/questions/16598477/… will help with that problem for you!
– Ryan
Nov 14 '18 at 21:43
I think this post stackoverflow.com/questions/16598477/… will help with that problem for you!
– Ryan
Nov 14 '18 at 21:43
add a comment |
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$.each takes in an array/object, 'TestProduct' is a string
– Toxnyc
Nov 14 '18 at 18:39