Accumulator for outer nested loop Python










0















I'm learning python on my own from a book and solving problems. In one problem, the user inputs amount of rain for each month in one year across a period of years. I need to find the average of rain in each year (sum(monthly rain)/numb_months, and also the average of rain in that period, e.g. in two years. In the following code, I can get the average for each year (I used 3 months only instead of 12 months to avoid tedious input now), but I don't know where I need to put an accumulator for total rain in that period and then average it. I appreciate your help.



number_of_months = 3
years_in_period = int(input("Please enter the number of years in the period. n"))

for year in range(years_in_period):
yearly_rain = 0
print('Year', year+1)
print('−−−−−−−−−−−−−−−−−')
for month in range(number_of_months):
print('Month', month+1, end='')
monthly_rain = float(input("Please enter rainfall for this month: n"))
yearly_rain += monthly_rain
average_yearly_rainfall = yearly_rain / number_of_months
print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
print("Year total rain is", yearly_rain)
print()









share|improve this question


























    0















    I'm learning python on my own from a book and solving problems. In one problem, the user inputs amount of rain for each month in one year across a period of years. I need to find the average of rain in each year (sum(monthly rain)/numb_months, and also the average of rain in that period, e.g. in two years. In the following code, I can get the average for each year (I used 3 months only instead of 12 months to avoid tedious input now), but I don't know where I need to put an accumulator for total rain in that period and then average it. I appreciate your help.



    number_of_months = 3
    years_in_period = int(input("Please enter the number of years in the period. n"))

    for year in range(years_in_period):
    yearly_rain = 0
    print('Year', year+1)
    print('−−−−−−−−−−−−−−−−−')
    for month in range(number_of_months):
    print('Month', month+1, end='')
    monthly_rain = float(input("Please enter rainfall for this month: n"))
    yearly_rain += monthly_rain
    average_yearly_rainfall = yearly_rain / number_of_months
    print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
    print("Year total rain is", yearly_rain)
    print()









    share|improve this question
























      0












      0








      0








      I'm learning python on my own from a book and solving problems. In one problem, the user inputs amount of rain for each month in one year across a period of years. I need to find the average of rain in each year (sum(monthly rain)/numb_months, and also the average of rain in that period, e.g. in two years. In the following code, I can get the average for each year (I used 3 months only instead of 12 months to avoid tedious input now), but I don't know where I need to put an accumulator for total rain in that period and then average it. I appreciate your help.



      number_of_months = 3
      years_in_period = int(input("Please enter the number of years in the period. n"))

      for year in range(years_in_period):
      yearly_rain = 0
      print('Year', year+1)
      print('−−−−−−−−−−−−−−−−−')
      for month in range(number_of_months):
      print('Month', month+1, end='')
      monthly_rain = float(input("Please enter rainfall for this month: n"))
      yearly_rain += monthly_rain
      average_yearly_rainfall = yearly_rain / number_of_months
      print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
      print("Year total rain is", yearly_rain)
      print()









      share|improve this question














      I'm learning python on my own from a book and solving problems. In one problem, the user inputs amount of rain for each month in one year across a period of years. I need to find the average of rain in each year (sum(monthly rain)/numb_months, and also the average of rain in that period, e.g. in two years. In the following code, I can get the average for each year (I used 3 months only instead of 12 months to avoid tedious input now), but I don't know where I need to put an accumulator for total rain in that period and then average it. I appreciate your help.



      number_of_months = 3
      years_in_period = int(input("Please enter the number of years in the period. n"))

      for year in range(years_in_period):
      yearly_rain = 0
      print('Year', year+1)
      print('−−−−−−−−−−−−−−−−−')
      for month in range(number_of_months):
      print('Month', month+1, end='')
      monthly_rain = float(input("Please enter rainfall for this month: n"))
      yearly_rain += monthly_rain
      average_yearly_rainfall = yearly_rain / number_of_months
      print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
      print("Year total rain is", yearly_rain)
      print()






      python loops nested accumulator






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      asked Nov 14 '18 at 18:15









      abenolabenol

      173




      173






















          1 Answer
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          0














          If I understood what you want (to calculate the absolute average of the rain amount during the period), this should do the trick:



          number_of_months = 3
          years_in_period = int(input("Please enter the number of years in the period. n"))

          total_rain = 0

          for year in range(years_in_period):
          yearly_rain = 0
          print('Year', year+1)
          print('−−−−−−−−−−−−−−−−−')

          for month in range(number_of_months):
          print('Month', month+1, end='')
          monthly_rain = float(input("Please enter rainfall for this month: n"))

          yearly_rain += monthly_rain

          total_rain += monthly_rain

          average_yearly_rainfall = yearly_rain / number_of_months

          print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
          print("Year total rain is", yearly_rain)
          print()


          total_months = years_in_period * number_of_months
          print("Absolute average of rain/month was", total_rain/total_months)
          print("Absolute average of rain/year was", total_rain/years_in_period)





          share|improve this answer























          • That's what I was looking for! Thank you so much, Pedro Martins for quick help!

            – abenol
            Nov 14 '18 at 18:50











          • No problem! Just let me know if you need something else ;)

            – Helena Martins
            Nov 14 '18 at 19:02










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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

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          active

          oldest

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          0














          If I understood what you want (to calculate the absolute average of the rain amount during the period), this should do the trick:



          number_of_months = 3
          years_in_period = int(input("Please enter the number of years in the period. n"))

          total_rain = 0

          for year in range(years_in_period):
          yearly_rain = 0
          print('Year', year+1)
          print('−−−−−−−−−−−−−−−−−')

          for month in range(number_of_months):
          print('Month', month+1, end='')
          monthly_rain = float(input("Please enter rainfall for this month: n"))

          yearly_rain += monthly_rain

          total_rain += monthly_rain

          average_yearly_rainfall = yearly_rain / number_of_months

          print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
          print("Year total rain is", yearly_rain)
          print()


          total_months = years_in_period * number_of_months
          print("Absolute average of rain/month was", total_rain/total_months)
          print("Absolute average of rain/year was", total_rain/years_in_period)





          share|improve this answer























          • That's what I was looking for! Thank you so much, Pedro Martins for quick help!

            – abenol
            Nov 14 '18 at 18:50











          • No problem! Just let me know if you need something else ;)

            – Helena Martins
            Nov 14 '18 at 19:02















          0














          If I understood what you want (to calculate the absolute average of the rain amount during the period), this should do the trick:



          number_of_months = 3
          years_in_period = int(input("Please enter the number of years in the period. n"))

          total_rain = 0

          for year in range(years_in_period):
          yearly_rain = 0
          print('Year', year+1)
          print('−−−−−−−−−−−−−−−−−')

          for month in range(number_of_months):
          print('Month', month+1, end='')
          monthly_rain = float(input("Please enter rainfall for this month: n"))

          yearly_rain += monthly_rain

          total_rain += monthly_rain

          average_yearly_rainfall = yearly_rain / number_of_months

          print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
          print("Year total rain is", yearly_rain)
          print()


          total_months = years_in_period * number_of_months
          print("Absolute average of rain/month was", total_rain/total_months)
          print("Absolute average of rain/year was", total_rain/years_in_period)





          share|improve this answer























          • That's what I was looking for! Thank you so much, Pedro Martins for quick help!

            – abenol
            Nov 14 '18 at 18:50











          • No problem! Just let me know if you need something else ;)

            – Helena Martins
            Nov 14 '18 at 19:02













          0












          0








          0







          If I understood what you want (to calculate the absolute average of the rain amount during the period), this should do the trick:



          number_of_months = 3
          years_in_period = int(input("Please enter the number of years in the period. n"))

          total_rain = 0

          for year in range(years_in_period):
          yearly_rain = 0
          print('Year', year+1)
          print('−−−−−−−−−−−−−−−−−')

          for month in range(number_of_months):
          print('Month', month+1, end='')
          monthly_rain = float(input("Please enter rainfall for this month: n"))

          yearly_rain += monthly_rain

          total_rain += monthly_rain

          average_yearly_rainfall = yearly_rain / number_of_months

          print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
          print("Year total rain is", yearly_rain)
          print()


          total_months = years_in_period * number_of_months
          print("Absolute average of rain/month was", total_rain/total_months)
          print("Absolute average of rain/year was", total_rain/years_in_period)





          share|improve this answer













          If I understood what you want (to calculate the absolute average of the rain amount during the period), this should do the trick:



          number_of_months = 3
          years_in_period = int(input("Please enter the number of years in the period. n"))

          total_rain = 0

          for year in range(years_in_period):
          yearly_rain = 0
          print('Year', year+1)
          print('−−−−−−−−−−−−−−−−−')

          for month in range(number_of_months):
          print('Month', month+1, end='')
          monthly_rain = float(input("Please enter rainfall for this month: n"))

          yearly_rain += monthly_rain

          total_rain += monthly_rain

          average_yearly_rainfall = yearly_rain / number_of_months

          print("Average yearly rainfall of year ", year+1, " is ", average_yearly_rainfall)
          print("Year total rain is", yearly_rain)
          print()


          total_months = years_in_period * number_of_months
          print("Absolute average of rain/month was", total_rain/total_months)
          print("Absolute average of rain/year was", total_rain/years_in_period)






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 14 '18 at 18:28









          Helena MartinsHelena Martins

          923118




          923118












          • That's what I was looking for! Thank you so much, Pedro Martins for quick help!

            – abenol
            Nov 14 '18 at 18:50











          • No problem! Just let me know if you need something else ;)

            – Helena Martins
            Nov 14 '18 at 19:02

















          • That's what I was looking for! Thank you so much, Pedro Martins for quick help!

            – abenol
            Nov 14 '18 at 18:50











          • No problem! Just let me know if you need something else ;)

            – Helena Martins
            Nov 14 '18 at 19:02
















          That's what I was looking for! Thank you so much, Pedro Martins for quick help!

          – abenol
          Nov 14 '18 at 18:50





          That's what I was looking for! Thank you so much, Pedro Martins for quick help!

          – abenol
          Nov 14 '18 at 18:50













          No problem! Just let me know if you need something else ;)

          – Helena Martins
          Nov 14 '18 at 19:02





          No problem! Just let me know if you need something else ;)

          – Helena Martins
          Nov 14 '18 at 19:02



















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