Check for an empty variable when using split() in python3
If I have for example a line of string like this:
line = alfa,bravo,zeta,cookie,dragonball
I can create them into a list like this:
parts = line.split(",")
However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:
,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,
How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:
print("ERROR in line: ".format(line))
I thought about using a try/except, but I don't really know how it should be formatted in this case.
python-3.x list error-handling split try-except
asked Nov 14 '18 at 15:04
AstudentAstudent
608
add a comment |
If I have for example a line of string like this:
line = alfa,bravo,zeta,cookie,dragonball
I can create them into a list like this:
parts = line.split(",")
However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:
,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,
How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:
print("ERROR in line: ".format(line))
I thought about using a try/except, but I don't really know how it should be formatted in this case.
python-3.x list error-handling split try-except
asked Nov 14 '18 at 15:04
AstudentAstudent
608
1
What about checking for"" in line.split(",")?
– DocDriven
Nov 14 '18 at 15:08
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09
add a comment |
If I have for example a line of string like this:
line = alfa,bravo,zeta,cookie,dragonball
I can create them into a list like this:
parts = line.split(",")
However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:
,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,
How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:
print("ERROR in line: ".format(line))
I thought about using a try/except, but I don't really know how it should be formatted in this case.
python-3.x list error-handling split try-except
asked Nov 14 '18 at 15:04
AstudentAstudent
608
If I have for example a line of string like this:
line = alfa,bravo,zeta,cookie,dragonball
I can create them into a list like this:
parts = line.split(",")
However, I should be able to deal with an error if the line has "empty" objects, like in the following situations:
,coookie,dragonball,alfa
alfa,,dragonball,cookie
alfa,dragonball,cookie,
How can I do this? in case of an error, the line would not be included in a list, and the program would give an error message:
print("ERROR in line: ".format(line))
I thought about using a try/except, but I don't really know how it should be formatted in this case.
python-3.x list error-handling split try-except
python-3.x list error-handling split try-except
asked Nov 14 '18 at 15:04
AstudentAstudent
608
asked Nov 14 '18 at 15:04
AstudentAstudent
608
edited Nov 14 '18 at 15:08
Astudent
asked Nov 14 '18 at 15:04
AstudentAstudent
608
asked Nov 14 '18 at 15:04
AstudentAstudent
608
asked Nov 14 '18 at 15:04
AstudentAstudent
608
608
1
What about checking for"" in line.split(",")?
– DocDriven
Nov 14 '18 at 15:08
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09
add a comment |
1
What about checking for"" in line.split(",")?
– DocDriven
Nov 14 '18 at 15:08
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09
1
1
What about checking for
"" in line.split(",")?– DocDriven
Nov 14 '18 at 15:08
What about checking for
"" in line.split(",")?– DocDriven
Nov 14 '18 at 15:08
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09
add a comment |
1 Answer
1
active
oldest
votes
Try this:
line = "alfa,bravo,zeta,cookie,dragonball"
if "" in line.split(","):
print("ERROR in line: ".format(line))
## further error handling...
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,2022620
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
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active
oldest
votes
Try this:
line = "alfa,bravo,zeta,cookie,dragonball"
if "" in line.split(","):
print("ERROR in line: ".format(line))
## further error handling...
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,2022620
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
add a comment |
Try this:
line = "alfa,bravo,zeta,cookie,dragonball"
if "" in line.split(","):
print("ERROR in line: ".format(line))
## further error handling...
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,2022620
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
add a comment |
Try this:
line = "alfa,bravo,zeta,cookie,dragonball"
if "" in line.split(","):
print("ERROR in line: ".format(line))
## further error handling...
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,2022620
Try this:
line = "alfa,bravo,zeta,cookie,dragonball"
if "" in line.split(","):
print("ERROR in line: ".format(line))
## further error handling...
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,2022620
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,2022620
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,2022620
answered Nov 14 '18 at 15:13
DocDrivenDocDriven
1,2022620
1,2022620
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
add a comment |
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
1
1
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
Excellent answer. Thanks a lot!
– Astudent
Nov 14 '18 at 15:16
add a comment |
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What about checking for
"" in line.split(",")?– DocDriven
Nov 14 '18 at 15:08
You mean like this? if line.split(",") == "": #report error
– Astudent
Nov 14 '18 at 15:09