Angular 6 *ngFor display different styles for first, odd, even and last
I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.
I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.
Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.
Here is my code for my component HTML
>
<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>
<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="'background-color':getColor(i)" style="color: white;">
<strong>Index : </strong>i <strong>ID : </strong>course.id <strong>Name</strong> : course.name
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>
<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>
Code for .TS
>
import Component from '@angular/core';
@Component(
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
)
export class AppComponent
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = id: null, name: null;
courses: Array<Courses> = ;
viewMode: string = null;
checkNumber($event)
if ($event.keyCode != 13)
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;
onAdd() !this.fields.name)
this.noValues = true;
else
this.courses.push(id: this.fields.id, name: this.fields.name);
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
onRemove(i)
this.courses.splice(i, 1);
onClear()
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
onModify(i) !this.fields.name)
this.noModifyValues = true;
else
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;
getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
return 'red';
interface Courses
id: number;
name: string;
Image of the code in action for better understanding.
arrays angular typescript angular6
add a comment |
I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.
I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.
Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.
Here is my code for my component HTML
>
<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>
<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="'background-color':getColor(i)" style="color: white;">
<strong>Index : </strong>i <strong>ID : </strong>course.id <strong>Name</strong> : course.name
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>
<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>
Code for .TS
>
import Component from '@angular/core';
@Component(
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
)
export class AppComponent
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = id: null, name: null;
courses: Array<Courses> = ;
viewMode: string = null;
checkNumber($event)
if ($event.keyCode != 13)
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;
onAdd() !this.fields.name)
this.noValues = true;
else
this.courses.push(id: this.fields.id, name: this.fields.name);
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
onRemove(i)
this.courses.splice(i, 1);
onClear()
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
onModify(i) !this.fields.name)
this.noModifyValues = true;
else
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;
getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
return 'red';
interface Courses
id: number;
name: string;
Image of the code in action for better understanding.
arrays angular typescript angular6
If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
– Eliseo
Nov 13 '18 at 8:15
add a comment |
I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.
I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.
Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.
Here is my code for my component HTML
>
<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>
<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="'background-color':getColor(i)" style="color: white;">
<strong>Index : </strong>i <strong>ID : </strong>course.id <strong>Name</strong> : course.name
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>
<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>
Code for .TS
>
import Component from '@angular/core';
@Component(
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
)
export class AppComponent
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = id: null, name: null;
courses: Array<Courses> = ;
viewMode: string = null;
checkNumber($event)
if ($event.keyCode != 13)
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;
onAdd() !this.fields.name)
this.noValues = true;
else
this.courses.push(id: this.fields.id, name: this.fields.name);
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
onRemove(i)
this.courses.splice(i, 1);
onClear()
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
onModify(i) !this.fields.name)
this.noModifyValues = true;
else
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;
getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
return 'red';
interface Courses
id: number;
name: string;
Image of the code in action for better understanding.
arrays angular typescript angular6
I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.
I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.
Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.
Here is my code for my component HTML
>
<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>
<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="'background-color':getColor(i)" style="color: white;">
<strong>Index : </strong>i <strong>ID : </strong>course.id <strong>Name</strong> : course.name
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>
<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>
Code for .TS
>
import Component from '@angular/core';
@Component(
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
)
export class AppComponent
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = id: null, name: null;
courses: Array<Courses> = ;
viewMode: string = null;
checkNumber($event)
if ($event.keyCode != 13)
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;
onAdd() !this.fields.name)
this.noValues = true;
else
this.courses.push(id: this.fields.id, name: this.fields.name);
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
onRemove(i)
this.courses.splice(i, 1);
onClear()
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;
onModify(i) !this.fields.name)
this.noModifyValues = true;
else
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;
getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
return 'red';
interface Courses
id: number;
name: string;
Image of the code in action for better understanding.
arrays angular typescript angular6
arrays angular typescript angular6
asked Nov 13 '18 at 3:01
Jean-Philippe DufourJean-Philippe Dufour
297
297
If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
– Eliseo
Nov 13 '18 at 8:15
add a comment |
If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
– Eliseo
Nov 13 '18 at 8:15
If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
– Eliseo
Nov 13 '18 at 8:15
If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
– Eliseo
Nov 13 '18 at 8:15
add a comment |
4 Answers
4
active
oldest
votes
Try something like this
getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
if (this.courses && (this.courses.length - 1 === i)) i = 'last'
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
return 'red';
Hope it works - Happy coding !!
You can use it aselse if
in case to avoid another condition :)
– Rahul
Nov 13 '18 at 3:45
add a comment |
If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html
<ul *ngFor="let course of courses; let index=i;
let odd=odd;
let last=last;
let first=first">
<li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
...
</li>
</ul>
That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
– Jean-Philippe Dufour
Nov 13 '18 at 14:13
If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
– Eliseo
Nov 16 '18 at 13:14
thanks for your input. I will defenitly look this up.
– Jean-Philippe Dufour
Nov 17 '18 at 6:06
add a comment |
Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :
getColor(i)
if (this.courses && i != 0 && (this.courses.length - 1 === i)) i = 'last'
if (i % 2 === 0 && i != 0 && i != 'last')i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
case i = 'last' : return 'purple';
return 'red';
Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?
add a comment |
You could use if else ladder instead of mixing up if else and switch and assignments like given below
getColor(i)
if(this.courses)
if(i==0)
return "orange";
else if(i==this.courses.length-1)
return "purple";
else if (i%2==0)
return "red";
else
return "blue";
1
Would def make a cleaner and easier to understand code. Thanks for your input.
– Jean-Philippe Dufour
Nov 13 '18 at 5:38
When you have simpler alternatives, don't mix up and always welcome :)
– Mithil Mohan
Nov 13 '18 at 5:39
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try something like this
getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
if (this.courses && (this.courses.length - 1 === i)) i = 'last'
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
return 'red';
Hope it works - Happy coding !!
You can use it aselse if
in case to avoid another condition :)
– Rahul
Nov 13 '18 at 3:45
add a comment |
Try something like this
getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
if (this.courses && (this.courses.length - 1 === i)) i = 'last'
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
return 'red';
Hope it works - Happy coding !!
You can use it aselse if
in case to avoid another condition :)
– Rahul
Nov 13 '18 at 3:45
add a comment |
Try something like this
getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
if (this.courses && (this.courses.length - 1 === i)) i = 'last'
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
return 'red';
Hope it works - Happy coding !!
Try something like this
getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
if (this.courses && (this.courses.length - 1 === i)) i = 'last'
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
return 'red';
Hope it works - Happy coding !!
answered Nov 13 '18 at 3:31
RahulRahul
1,0231315
1,0231315
You can use it aselse if
in case to avoid another condition :)
– Rahul
Nov 13 '18 at 3:45
add a comment |
You can use it aselse if
in case to avoid another condition :)
– Rahul
Nov 13 '18 at 3:45
You can use it as
else if
in case to avoid another condition :)– Rahul
Nov 13 '18 at 3:45
You can use it as
else if
in case to avoid another condition :)– Rahul
Nov 13 '18 at 3:45
add a comment |
If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html
<ul *ngFor="let course of courses; let index=i;
let odd=odd;
let last=last;
let first=first">
<li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
...
</li>
</ul>
That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
– Jean-Philippe Dufour
Nov 13 '18 at 14:13
If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
– Eliseo
Nov 16 '18 at 13:14
thanks for your input. I will defenitly look this up.
– Jean-Philippe Dufour
Nov 17 '18 at 6:06
add a comment |
If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html
<ul *ngFor="let course of courses; let index=i;
let odd=odd;
let last=last;
let first=first">
<li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
...
</li>
</ul>
That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
– Jean-Philippe Dufour
Nov 13 '18 at 14:13
If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
– Eliseo
Nov 16 '18 at 13:14
thanks for your input. I will defenitly look this up.
– Jean-Philippe Dufour
Nov 17 '18 at 6:06
add a comment |
If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html
<ul *ngFor="let course of courses; let index=i;
let odd=odd;
let last=last;
let first=first">
<li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
...
</li>
</ul>
If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html
<ul *ngFor="let course of courses; let index=i;
let odd=odd;
let last=last;
let first=first">
<li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
...
</li>
</ul>
answered Nov 13 '18 at 8:13
EliseoEliseo
5,5491312
5,5491312
That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
– Jean-Philippe Dufour
Nov 13 '18 at 14:13
If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
– Eliseo
Nov 16 '18 at 13:14
thanks for your input. I will defenitly look this up.
– Jean-Philippe Dufour
Nov 17 '18 at 6:06
add a comment |
That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
– Jean-Philippe Dufour
Nov 13 '18 at 14:13
If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
– Eliseo
Nov 16 '18 at 13:14
thanks for your input. I will defenitly look this up.
– Jean-Philippe Dufour
Nov 17 '18 at 6:06
That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
– Jean-Philippe Dufour
Nov 13 '18 at 14:13
That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
– Jean-Philippe Dufour
Nov 13 '18 at 14:13
If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
– Eliseo
Nov 16 '18 at 13:14
If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
– Eliseo
Nov 16 '18 at 13:14
thanks for your input. I will defenitly look this up.
– Jean-Philippe Dufour
Nov 17 '18 at 6:06
thanks for your input. I will defenitly look this up.
– Jean-Philippe Dufour
Nov 17 '18 at 6:06
add a comment |
Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :
getColor(i)
if (this.courses && i != 0 && (this.courses.length - 1 === i)) i = 'last'
if (i % 2 === 0 && i != 0 && i != 'last')i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
case i = 'last' : return 'purple';
return 'red';
Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?
add a comment |
Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :
getColor(i)
if (this.courses && i != 0 && (this.courses.length - 1 === i)) i = 'last'
if (i % 2 === 0 && i != 0 && i != 'last')i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
case i = 'last' : return 'purple';
return 'red';
Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?
add a comment |
Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :
getColor(i)
if (this.courses && i != 0 && (this.courses.length - 1 === i)) i = 'last'
if (i % 2 === 0 && i != 0 && i != 'last')i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
case i = 'last' : return 'purple';
return 'red';
Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?
Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :
getColor(i)
if (this.courses && i != 0 && (this.courses.length - 1 === i)) i = 'last'
if (i % 2 === 0 && i != 0 && i != 'last')i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
case i = 'last' : return 'purple';
return 'red';
Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?
answered Nov 13 '18 at 3:43
Jean-Philippe DufourJean-Philippe Dufour
297
297
add a comment |
add a comment |
You could use if else ladder instead of mixing up if else and switch and assignments like given below
getColor(i)
if(this.courses)
if(i==0)
return "orange";
else if(i==this.courses.length-1)
return "purple";
else if (i%2==0)
return "red";
else
return "blue";
1
Would def make a cleaner and easier to understand code. Thanks for your input.
– Jean-Philippe Dufour
Nov 13 '18 at 5:38
When you have simpler alternatives, don't mix up and always welcome :)
– Mithil Mohan
Nov 13 '18 at 5:39
add a comment |
You could use if else ladder instead of mixing up if else and switch and assignments like given below
getColor(i)
if(this.courses)
if(i==0)
return "orange";
else if(i==this.courses.length-1)
return "purple";
else if (i%2==0)
return "red";
else
return "blue";
1
Would def make a cleaner and easier to understand code. Thanks for your input.
– Jean-Philippe Dufour
Nov 13 '18 at 5:38
When you have simpler alternatives, don't mix up and always welcome :)
– Mithil Mohan
Nov 13 '18 at 5:39
add a comment |
You could use if else ladder instead of mixing up if else and switch and assignments like given below
getColor(i)
if(this.courses)
if(i==0)
return "orange";
else if(i==this.courses.length-1)
return "purple";
else if (i%2==0)
return "red";
else
return "blue";
You could use if else ladder instead of mixing up if else and switch and assignments like given below
getColor(i)
if(this.courses)
if(i==0)
return "orange";
else if(i==this.courses.length-1)
return "purple";
else if (i%2==0)
return "red";
else
return "blue";
answered Nov 13 '18 at 5:30
Mithil MohanMithil Mohan
1389
1389
1
Would def make a cleaner and easier to understand code. Thanks for your input.
– Jean-Philippe Dufour
Nov 13 '18 at 5:38
When you have simpler alternatives, don't mix up and always welcome :)
– Mithil Mohan
Nov 13 '18 at 5:39
add a comment |
1
Would def make a cleaner and easier to understand code. Thanks for your input.
– Jean-Philippe Dufour
Nov 13 '18 at 5:38
When you have simpler alternatives, don't mix up and always welcome :)
– Mithil Mohan
Nov 13 '18 at 5:39
1
1
Would def make a cleaner and easier to understand code. Thanks for your input.
– Jean-Philippe Dufour
Nov 13 '18 at 5:38
Would def make a cleaner and easier to understand code. Thanks for your input.
– Jean-Philippe Dufour
Nov 13 '18 at 5:38
When you have simpler alternatives, don't mix up and always welcome :)
– Mithil Mohan
Nov 13 '18 at 5:39
When you have simpler alternatives, don't mix up and always welcome :)
– Mithil Mohan
Nov 13 '18 at 5:39
add a comment |
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If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
– Eliseo
Nov 13 '18 at 8:15