Angular 6 *ngFor display different styles for first, odd, even and last










1














I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.



I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.



Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.



Here is my code for my component HTML



>



<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>

<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="'background-color':getColor(i)" style="color: white;">
<strong>Index : </strong>i <strong>ID : </strong>course.id <strong>Name</strong> : course.name
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>

<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>


Code for .TS



>



import Component from '@angular/core';

@Component(
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
)


export class AppComponent
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = id: null, name: null;
courses: Array<Courses> = ;
viewMode: string = null;

checkNumber($event)
if ($event.keyCode != 13)
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;



onAdd() !this.fields.name)
this.noValues = true;
else
this.courses.push(id: this.fields.id, name: this.fields.name);
this.fields.id = null;
this.fields.name = null;
this.noValues = false;



onRemove(i)
this.courses.splice(i, 1);


onClear()
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;


onModify(i) !this.fields.name)
this.noModifyValues = true;
else
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;




getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';

return 'red';


interface Courses
id: number;
name: string;



Image of the code in action for better understanding.










share|improve this question





















  • If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
    – Eliseo
    Nov 13 '18 at 8:15















1














I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.



I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.



Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.



Here is my code for my component HTML



>



<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>

<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="'background-color':getColor(i)" style="color: white;">
<strong>Index : </strong>i <strong>ID : </strong>course.id <strong>Name</strong> : course.name
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>

<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>


Code for .TS



>



import Component from '@angular/core';

@Component(
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
)


export class AppComponent
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = id: null, name: null;
courses: Array<Courses> = ;
viewMode: string = null;

checkNumber($event)
if ($event.keyCode != 13)
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;



onAdd() !this.fields.name)
this.noValues = true;
else
this.courses.push(id: this.fields.id, name: this.fields.name);
this.fields.id = null;
this.fields.name = null;
this.noValues = false;



onRemove(i)
this.courses.splice(i, 1);


onClear()
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;


onModify(i) !this.fields.name)
this.noModifyValues = true;
else
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;




getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';

return 'red';


interface Courses
id: number;
name: string;



Image of the code in action for better understanding.










share|improve this question





















  • If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
    – Eliseo
    Nov 13 '18 at 8:15













1












1








1







I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.



I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.



Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.



Here is my code for my component HTML



>



<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>

<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="'background-color':getColor(i)" style="color: white;">
<strong>Index : </strong>i <strong>ID : </strong>course.id <strong>Name</strong> : course.name
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>

<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>


Code for .TS



>



import Component from '@angular/core';

@Component(
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
)


export class AppComponent
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = id: null, name: null;
courses: Array<Courses> = ;
viewMode: string = null;

checkNumber($event)
if ($event.keyCode != 13)
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;



onAdd() !this.fields.name)
this.noValues = true;
else
this.courses.push(id: this.fields.id, name: this.fields.name);
this.fields.id = null;
this.fields.name = null;
this.noValues = false;



onRemove(i)
this.courses.splice(i, 1);


onClear()
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;


onModify(i) !this.fields.name)
this.noModifyValues = true;
else
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;




getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';

return 'red';


interface Courses
id: number;
name: string;



Image of the code in action for better understanding.










share|improve this question













I am learning Angular 6 and just trying to put togheter some of the stuff I have learned and I am currently running into an issue that I cannot find an answer to. I am trying to change the style of a LI using *ngFor depending if the index is First, Last, Odd or Even. So far everything works but I can't figure out how to do it for the Last because everything I add a new object to my list, it is obviously the last so it render the color for the last.



I understand how to do it but the real problem is that I am adding stuff dynamicly to my list from a form and I'm not sure how to evaluate the Last so that the others become to right color.



Keep in mind that I am still a newb and it might look messy and I also understand that some client-side validations I am doing are probably not optimal or required since HTMl5 but I made it to learn.



Here is my code for my component HTML



>



<h1>List of courses :</h1><br>
<div *ngIf="courses.length > 0; then coursesList else noCourses"></div>

<ng-template #coursesList>
<h2>List of Courses :</h2>
<ul *ngFor="let course of courses; index as i;">
<li [ngStyle]="'background-color':getColor(i)" style="color: white;">
<strong>Index : </strong>i <strong>ID : </strong>course.id <strong>Name</strong> : course.name
<button (click)="onRemove(i)">Remove</button>
<button (click)="onModify(i)">Modify</button>
</li>
</ul>
</ng-template>
<ng-template #noCourses>
<h5>There are no courses in this list. Use the form bellow to add some.</h5>
</ng-template>

<div (keyup.enter)="onAdd()">
<span>ID : <input type="number" (keypress)="checkNumber($event)" [(ngModel)]="fields.id" placeholder="Enter an ID"></span>
<span>Name : <input type="text" [(ngModel)]="fields.name" placeholder="Enter a NAME"></span>
<button (click)="onAdd()">Add</button>
<button (click)="onClear()">Clear</button>
</div>
<div *ngIf="isNotNumber" style="background-color: red; color:black"><strong>ID can only be numbers !</strong></div>
<div *ngIf="noValues" style="background-color: red; color:black"><strong>Please fill all fields !</strong></div>
<div *ngIf="noModifyValues" style="background-color: red; color:black"><strong>To modify enter all informations!</strong></div>


Code for .TS



>



import Component from '@angular/core';

@Component(
selector: 'app-root',
templateUrl: './app.component.html',
styleUrls: ['./app.component.css']
)


export class AppComponent
noValues: boolean;
noModifyValues: boolean;
isNotNumber: boolean;
fields: Courses = id: null, name: null;
courses: Array<Courses> = ;
viewMode: string = null;

checkNumber($event)
if ($event.keyCode != 13)
isFinite($event.key) ? this.isNotNumber = false : this.isNotNumber = true;



onAdd() !this.fields.name)
this.noValues = true;
else
this.courses.push(id: this.fields.id, name: this.fields.name);
this.fields.id = null;
this.fields.name = null;
this.noValues = false;



onRemove(i)
this.courses.splice(i, 1);


onClear()
this.courses = ;
this.fields.id = null;
this.fields.name = null;
this.noValues = false;


onModify(i) !this.fields.name)
this.noModifyValues = true;
else
this.courses[i].name = this.fields.name;
this.courses[i].id = this.fields.id;
this.noModifyValues = false;




getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';

return 'red';


interface Courses
id: number;
name: string;



Image of the code in action for better understanding.







arrays angular typescript angular6






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share|improve this question










asked Nov 13 '18 at 3:01









Jean-Philippe DufourJean-Philippe Dufour

297




297











  • If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
    – Eliseo
    Nov 13 '18 at 8:15
















  • If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
    – Eliseo
    Nov 13 '18 at 8:15















If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
– Eliseo
Nov 13 '18 at 8:15




If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html, see my answer
– Eliseo
Nov 13 '18 at 8:15












4 Answers
4






active

oldest

votes


















1














Try something like this



getColor(i)
if (i % 2 === 0 && i != 0)i = 'odd';
if (this.courses && (this.courses.length - 1 === i)) i = 'last'
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';

return 'red';



Hope it works - Happy coding !!






share|improve this answer




















  • You can use it as else if in case to avoid another condition :)
    – Rahul
    Nov 13 '18 at 3:45


















1














If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html



<ul *ngFor="let course of courses; let index=i;
let odd=odd;
let last=last;
let first=first">
<li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
...
</li>
</ul>





share|improve this answer




















  • That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
    – Jean-Philippe Dufour
    Nov 13 '18 at 14:13











  • If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
    – Eliseo
    Nov 16 '18 at 13:14










  • thanks for your input. I will defenitly look this up.
    – Jean-Philippe Dufour
    Nov 17 '18 at 6:06


















0














Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :







getColor(i)
if (this.courses && i != 0 && (this.courses.length - 1 === i)) i = 'last'
if (i % 2 === 0 && i != 0 && i != 'last')i = 'odd';
switch (i)
case i = 0 : return 'orange';
case i = 'odd' : return 'blue';
case i = 'last' : return 'purple';

return 'red';



Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?






share|improve this answer




























    0














    You could use if else ladder instead of mixing up if else and switch and assignments like given below



    getColor(i)

    if(this.courses)

    if(i==0)
    return "orange";
    else if(i==this.courses.length-1)
    return "purple";
    else if (i%2==0)
    return "red";
    else
    return "blue";







    share|improve this answer
















    • 1




      Would def make a cleaner and easier to understand code. Thanks for your input.
      – Jean-Philippe Dufour
      Nov 13 '18 at 5:38










    • When you have simpler alternatives, don't mix up and always welcome :)
      – Mithil Mohan
      Nov 13 '18 at 5:39










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    4 Answers
    4






    active

    oldest

    votes








    4 Answers
    4






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    Try something like this



    getColor(i)
    if (i % 2 === 0 && i != 0)i = 'odd';
    if (this.courses && (this.courses.length - 1 === i)) i = 'last'
    switch (i)
    case i = 0 : return 'orange';
    case i = 'odd' : return 'blue';

    return 'red';



    Hope it works - Happy coding !!






    share|improve this answer




















    • You can use it as else if in case to avoid another condition :)
      – Rahul
      Nov 13 '18 at 3:45















    1














    Try something like this



    getColor(i)
    if (i % 2 === 0 && i != 0)i = 'odd';
    if (this.courses && (this.courses.length - 1 === i)) i = 'last'
    switch (i)
    case i = 0 : return 'orange';
    case i = 'odd' : return 'blue';

    return 'red';



    Hope it works - Happy coding !!






    share|improve this answer




















    • You can use it as else if in case to avoid another condition :)
      – Rahul
      Nov 13 '18 at 3:45













    1












    1








    1






    Try something like this



    getColor(i)
    if (i % 2 === 0 && i != 0)i = 'odd';
    if (this.courses && (this.courses.length - 1 === i)) i = 'last'
    switch (i)
    case i = 0 : return 'orange';
    case i = 'odd' : return 'blue';

    return 'red';



    Hope it works - Happy coding !!






    share|improve this answer












    Try something like this



    getColor(i)
    if (i % 2 === 0 && i != 0)i = 'odd';
    if (this.courses && (this.courses.length - 1 === i)) i = 'last'
    switch (i)
    case i = 0 : return 'orange';
    case i = 'odd' : return 'blue';

    return 'red';



    Hope it works - Happy coding !!







    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 13 '18 at 3:31









    RahulRahul

    1,0231315




    1,0231315











    • You can use it as else if in case to avoid another condition :)
      – Rahul
      Nov 13 '18 at 3:45
















    • You can use it as else if in case to avoid another condition :)
      – Rahul
      Nov 13 '18 at 3:45















    You can use it as else if in case to avoid another condition :)
    – Rahul
    Nov 13 '18 at 3:45




    You can use it as else if in case to avoid another condition :)
    – Rahul
    Nov 13 '18 at 3:45













    1














    If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html



    <ul *ngFor="let course of courses; let index=i;
    let odd=odd;
    let last=last;
    let first=first">
    <li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
    ...
    </li>
    </ul>





    share|improve this answer




















    • That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
      – Jean-Philippe Dufour
      Nov 13 '18 at 14:13











    • If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
      – Eliseo
      Nov 16 '18 at 13:14










    • thanks for your input. I will defenitly look this up.
      – Jean-Philippe Dufour
      Nov 17 '18 at 6:06















    1














    If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html



    <ul *ngFor="let course of courses; let index=i;
    let odd=odd;
    let last=last;
    let first=first">
    <li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
    ...
    </li>
    </ul>





    share|improve this answer




















    • That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
      – Jean-Philippe Dufour
      Nov 13 '18 at 14:13











    • If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
      – Eliseo
      Nov 16 '18 at 13:14










    • thanks for your input. I will defenitly look this up.
      – Jean-Philippe Dufour
      Nov 17 '18 at 6:06













    1












    1








    1






    If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html



    <ul *ngFor="let course of courses; let index=i;
    let odd=odd;
    let last=last;
    let first=first">
    <li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
    ...
    </li>
    </ul>





    share|improve this answer












    If you only want cange the background-color you can use [style.background-color] and you can use ternary operator in the .html



    <ul *ngFor="let course of courses; let index=i;
    let odd=odd;
    let last=last;
    let first=first">
    <li [style.backgound-color]="first?'orange':last?'purple':odd?'blue':'red'">
    ...
    </li>
    </ul>






    share|improve this answer












    share|improve this answer



    share|improve this answer










    answered Nov 13 '18 at 8:13









    EliseoEliseo

    5,5491312




    5,5491312











    • That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
      – Jean-Philippe Dufour
      Nov 13 '18 at 14:13











    • If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
      – Eliseo
      Nov 16 '18 at 13:14










    • thanks for your input. I will defenitly look this up.
      – Jean-Philippe Dufour
      Nov 17 '18 at 6:06
















    • That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
      – Jean-Philippe Dufour
      Nov 13 '18 at 14:13











    • If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
      – Eliseo
      Nov 16 '18 at 13:14










    • thanks for your input. I will defenitly look this up.
      – Jean-Philippe Dufour
      Nov 17 '18 at 6:06















    That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
    – Jean-Philippe Dufour
    Nov 13 '18 at 14:13





    That's one good way to do it, I wanted to do it this way first but I didn't know you could use more than 1 condition in a short IF on a bind like that. By the way, is there a difference in performance with either ways? I understand this is just a style tho but what if we have ALOT Of values
    – Jean-Philippe Dufour
    Nov 13 '18 at 14:13













    If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
    – Eliseo
    Nov 16 '18 at 13:14




    If you has a lot of values, you can use [className]="first?'class1':... where 'class1', 'class2' are style defining in your component.css. In perfomance a ternary opertor is always faster. I prefer not make a call to a function, but I'm not sure about performance
    – Eliseo
    Nov 16 '18 at 13:14












    thanks for your input. I will defenitly look this up.
    – Jean-Philippe Dufour
    Nov 17 '18 at 6:06




    thanks for your input. I will defenitly look this up.
    – Jean-Philippe Dufour
    Nov 17 '18 at 6:06











    0














    Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :







    getColor(i)
    if (this.courses && i != 0 && (this.courses.length - 1 === i)) i = 'last'
    if (i % 2 === 0 && i != 0 && i != 'last')i = 'odd';
    switch (i)
    case i = 0 : return 'orange';
    case i = 'odd' : return 'blue';
    case i = 'last' : return 'purple';

    return 'red';



    Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?






    share|improve this answer

























      0














      Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :







      getColor(i)
      if (this.courses && i != 0 && (this.courses.length - 1 === i)) i = 'last'
      if (i % 2 === 0 && i != 0 && i != 'last')i = 'odd';
      switch (i)
      case i = 0 : return 'orange';
      case i = 'odd' : return 'blue';
      case i = 'last' : return 'purple';

      return 'red';



      Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?






      share|improve this answer























        0












        0








        0






        Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :







        getColor(i)
        if (this.courses && i != 0 && (this.courses.length - 1 === i)) i = 'last'
        if (i % 2 === 0 && i != 0 && i != 'last')i = 'odd';
        switch (i)
        case i = 0 : return 'orange';
        case i = 'odd' : return 'blue';
        case i = 'last' : return 'purple';

        return 'red';



        Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?






        share|improve this answer












        Thanks Rahul. The part I was missing is evaluating if there is something in courses. However, I had to had a few more lines to Odd and Last as follow :







        getColor(i)
        if (this.courses && i != 0 && (this.courses.length - 1 === i)) i = 'last'
        if (i % 2 === 0 && i != 0 && i != 'last')i = 'odd';
        switch (i)
        case i = 0 : return 'orange';
        case i = 'odd' : return 'blue';
        case i = 'last' : return 'purple';

        return 'red';



        Quick question. It seems like a whole lot of IF and && and checking specific things. Is that the way to do it properly?







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 13 '18 at 3:43









        Jean-Philippe DufourJean-Philippe Dufour

        297




        297





















            0














            You could use if else ladder instead of mixing up if else and switch and assignments like given below



            getColor(i)

            if(this.courses)

            if(i==0)
            return "orange";
            else if(i==this.courses.length-1)
            return "purple";
            else if (i%2==0)
            return "red";
            else
            return "blue";







            share|improve this answer
















            • 1




              Would def make a cleaner and easier to understand code. Thanks for your input.
              – Jean-Philippe Dufour
              Nov 13 '18 at 5:38










            • When you have simpler alternatives, don't mix up and always welcome :)
              – Mithil Mohan
              Nov 13 '18 at 5:39















            0














            You could use if else ladder instead of mixing up if else and switch and assignments like given below



            getColor(i)

            if(this.courses)

            if(i==0)
            return "orange";
            else if(i==this.courses.length-1)
            return "purple";
            else if (i%2==0)
            return "red";
            else
            return "blue";







            share|improve this answer
















            • 1




              Would def make a cleaner and easier to understand code. Thanks for your input.
              – Jean-Philippe Dufour
              Nov 13 '18 at 5:38










            • When you have simpler alternatives, don't mix up and always welcome :)
              – Mithil Mohan
              Nov 13 '18 at 5:39













            0












            0








            0






            You could use if else ladder instead of mixing up if else and switch and assignments like given below



            getColor(i)

            if(this.courses)

            if(i==0)
            return "orange";
            else if(i==this.courses.length-1)
            return "purple";
            else if (i%2==0)
            return "red";
            else
            return "blue";







            share|improve this answer












            You could use if else ladder instead of mixing up if else and switch and assignments like given below



            getColor(i)

            if(this.courses)

            if(i==0)
            return "orange";
            else if(i==this.courses.length-1)
            return "purple";
            else if (i%2==0)
            return "red";
            else
            return "blue";








            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered Nov 13 '18 at 5:30









            Mithil MohanMithil Mohan

            1389




            1389







            • 1




              Would def make a cleaner and easier to understand code. Thanks for your input.
              – Jean-Philippe Dufour
              Nov 13 '18 at 5:38










            • When you have simpler alternatives, don't mix up and always welcome :)
              – Mithil Mohan
              Nov 13 '18 at 5:39












            • 1




              Would def make a cleaner and easier to understand code. Thanks for your input.
              – Jean-Philippe Dufour
              Nov 13 '18 at 5:38










            • When you have simpler alternatives, don't mix up and always welcome :)
              – Mithil Mohan
              Nov 13 '18 at 5:39







            1




            1




            Would def make a cleaner and easier to understand code. Thanks for your input.
            – Jean-Philippe Dufour
            Nov 13 '18 at 5:38




            Would def make a cleaner and easier to understand code. Thanks for your input.
            – Jean-Philippe Dufour
            Nov 13 '18 at 5:38












            When you have simpler alternatives, don't mix up and always welcome :)
            – Mithil Mohan
            Nov 13 '18 at 5:39




            When you have simpler alternatives, don't mix up and always welcome :)
            – Mithil Mohan
            Nov 13 '18 at 5:39

















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