Update input value dynamically & update another element after dynamic input change
up vote
0
down vote
favorite
Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p>
tags outside of the form. I have been able to update the first two <p>
tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p>
tag to update when the third input value has dynamically changed.
Here is a Codepen for the problem.
HTML
<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>
JS
let one = $('#one');
let two = $('#two');
let three = $('#three');
$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');
$('#'+attrName).text(target.val());
);
function sum(a,b)
return a+b;
$('.sumVari').each(function()
$(this).change(function()
if(one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val()));
);
);
jquery forms events input dynamically-generated
add a comment |
up vote
0
down vote
favorite
Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p>
tags outside of the form. I have been able to update the first two <p>
tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p>
tag to update when the third input value has dynamically changed.
Here is a Codepen for the problem.
HTML
<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>
JS
let one = $('#one');
let two = $('#two');
let three = $('#three');
$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');
$('#'+attrName).text(target.val());
);
function sum(a,b)
return a+b;
$('.sumVari').each(function()
$(this).change(function()
if(one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val()));
);
);
jquery forms events input dynamically-generated
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p>
tags outside of the form. I have been able to update the first two <p>
tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p>
tag to update when the third input value has dynamically changed.
Here is a Codepen for the problem.
HTML
<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>
JS
let one = $('#one');
let two = $('#two');
let three = $('#three');
$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');
$('#'+attrName).text(target.val());
);
function sum(a,b)
return a+b;
$('.sumVari').each(function()
$(this).change(function()
if(one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val()));
);
);
jquery forms events input dynamically-generated
Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p>
tags outside of the form. I have been able to update the first two <p>
tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p>
tag to update when the third input value has dynamically changed.
Here is a Codepen for the problem.
HTML
<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>
JS
let one = $('#one');
let two = $('#two');
let three = $('#three');
$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');
$('#'+attrName).text(target.val());
);
function sum(a,b)
return a+b;
$('.sumVari').each(function()
$(this).change(function()
if(one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val()));
);
);
jquery forms events input dynamically-generated
jquery forms events input dynamically-generated
asked Nov 12 at 0:24
prestondoris
395
395
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
up vote
1
down vote
accepted
- Call the change event manually when putting value on the sum
let one = $('#one');
let two = $('#two');
let three = $('#three');
$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');
$('#' + attrName).text(target.val());
);
function sum(a, b)
return a + b;
$('.sumVari').each(function()
$(this).change(function()
if (one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>
@prestondoris glad it works for you happy coding mate :)
– guradio
Nov 13 at 0:25
add a comment |
Your Answer
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
accepted
- Call the change event manually when putting value on the sum
let one = $('#one');
let two = $('#two');
let three = $('#three');
$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');
$('#' + attrName).text(target.val());
);
function sum(a, b)
return a + b;
$('.sumVari').each(function()
$(this).change(function()
if (one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>
@prestondoris glad it works for you happy coding mate :)
– guradio
Nov 13 at 0:25
add a comment |
up vote
1
down vote
accepted
- Call the change event manually when putting value on the sum
let one = $('#one');
let two = $('#two');
let three = $('#three');
$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');
$('#' + attrName).text(target.val());
);
function sum(a, b)
return a + b;
$('.sumVari').each(function()
$(this).change(function()
if (one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>
@prestondoris glad it works for you happy coding mate :)
– guradio
Nov 13 at 0:25
add a comment |
up vote
1
down vote
accepted
up vote
1
down vote
accepted
- Call the change event manually when putting value on the sum
let one = $('#one');
let two = $('#two');
let three = $('#three');
$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');
$('#' + attrName).text(target.val());
);
function sum(a, b)
return a + b;
$('.sumVari').each(function()
$(this).change(function()
if (one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>
- Call the change event manually when putting value on the sum
let one = $('#one');
let two = $('#two');
let three = $('#three');
$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');
$('#' + attrName).text(target.val());
);
function sum(a, b)
return a + b;
$('.sumVari').each(function()
$(this).change(function()
if (one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>
let one = $('#one');
let two = $('#two');
let three = $('#three');
$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');
$('#' + attrName).text(target.val());
);
function sum(a, b)
return a + b;
$('.sumVari').each(function()
$(this).change(function()
if (one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>
let one = $('#one');
let two = $('#two');
let three = $('#three');
$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');
$('#' + attrName).text(target.val());
);
function sum(a, b)
return a + b;
$('.sumVari').each(function()
$(this).change(function()
if (one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input
);
);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>
answered Nov 12 at 0:28
guradio
13.7k31836
13.7k31836
@prestondoris glad it works for you happy coding mate :)
– guradio
Nov 13 at 0:25
add a comment |
@prestondoris glad it works for you happy coding mate :)
– guradio
Nov 13 at 0:25
@prestondoris glad it works for you happy coding mate :)
– guradio
Nov 13 at 0:25
@prestondoris glad it works for you happy coding mate :)
– guradio
Nov 13 at 0:25
add a comment |
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