Update input value dynamically & update another element after dynamic input change









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Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p> tags outside of the form. I have been able to update the first two <p> tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p> tag to update when the third input value has dynamically changed.



Here is a Codepen for the problem.



HTML



<form>
<input id="one" type="number" class="sumVari" name="a">
<input id="two" type="number" class="sumVari" name="b">
<input id="three" type="number" name="sum" placeholder="sum of a & b">
</form>
<div id="displayValues">
<p>The value of a is: <span id="a"></span> </p>
<p>The value of a is: <span id="b"></span></p>
<p>The value of the sum is: <span id="sum"></span></p>
</div>


JS



let one = $('#one');
let two = $('#two');
let three = $('#three');

$('form').on('change', 'input', function()
let target = $(this);
let attrName = target.attr('name');

$('#'+attrName).text(target.val());
);

function sum(a,b)
return a+b;


$('.sumVari').each(function()
$(this).change(function()
if(one.val() != '' && two.val() != '')
three.val(sum(one.val(), two.val()));

);
);









share|improve this question

























    up vote
    0
    down vote

    favorite












    Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p> tags outside of the form. I have been able to update the first two <p> tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p> tag to update when the third input value has dynamically changed.



    Here is a Codepen for the problem.



    HTML



    <form>
    <input id="one" type="number" class="sumVari" name="a">
    <input id="two" type="number" class="sumVari" name="b">
    <input id="three" type="number" name="sum" placeholder="sum of a & b">
    </form>
    <div id="displayValues">
    <p>The value of a is: <span id="a"></span> </p>
    <p>The value of a is: <span id="b"></span></p>
    <p>The value of the sum is: <span id="sum"></span></p>
    </div>


    JS



    let one = $('#one');
    let two = $('#two');
    let three = $('#three');

    $('form').on('change', 'input', function()
    let target = $(this);
    let attrName = target.attr('name');

    $('#'+attrName).text(target.val());
    );

    function sum(a,b)
    return a+b;


    $('.sumVari').each(function()
    $(this).change(function()
    if(one.val() != '' && two.val() != '')
    three.val(sum(one.val(), two.val()));

    );
    );









    share|improve this question























      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











      Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p> tags outside of the form. I have been able to update the first two <p> tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p> tag to update when the third input value has dynamically changed.



      Here is a Codepen for the problem.



      HTML



      <form>
      <input id="one" type="number" class="sumVari" name="a">
      <input id="two" type="number" class="sumVari" name="b">
      <input id="three" type="number" name="sum" placeholder="sum of a & b">
      </form>
      <div id="displayValues">
      <p>The value of a is: <span id="a"></span> </p>
      <p>The value of a is: <span id="b"></span></p>
      <p>The value of the sum is: <span id="sum"></span></p>
      </div>


      JS



      let one = $('#one');
      let two = $('#two');
      let three = $('#three');

      $('form').on('change', 'input', function()
      let target = $(this);
      let attrName = target.attr('name');

      $('#'+attrName).text(target.val());
      );

      function sum(a,b)
      return a+b;


      $('.sumVari').each(function()
      $(this).change(function()
      if(one.val() != '' && two.val() != '')
      three.val(sum(one.val(), two.val()));

      );
      );









      share|improve this question













      Below is the sample HTML and JS that I created for the problem that I am having. I have a form that has three inputs. The value from the first two inputs will dictate the value of the third. I also want the values of all three inputs to display in <p> tags outside of the form. I have been able to update the first two <p> tags outside the form correctly, and I have been able to update the third input value correctly. However, I cannot get the third <p> tag to update when the third input value has dynamically changed.



      Here is a Codepen for the problem.



      HTML



      <form>
      <input id="one" type="number" class="sumVari" name="a">
      <input id="two" type="number" class="sumVari" name="b">
      <input id="three" type="number" name="sum" placeholder="sum of a & b">
      </form>
      <div id="displayValues">
      <p>The value of a is: <span id="a"></span> </p>
      <p>The value of a is: <span id="b"></span></p>
      <p>The value of the sum is: <span id="sum"></span></p>
      </div>


      JS



      let one = $('#one');
      let two = $('#two');
      let three = $('#three');

      $('form').on('change', 'input', function()
      let target = $(this);
      let attrName = target.attr('name');

      $('#'+attrName).text(target.val());
      );

      function sum(a,b)
      return a+b;


      $('.sumVari').each(function()
      $(this).change(function()
      if(one.val() != '' && two.val() != '')
      three.val(sum(one.val(), two.val()));

      );
      );






      jquery forms events input dynamically-generated






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      asked Nov 12 at 0:24









      prestondoris

      395




      395






















          1 Answer
          1






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          oldest

          votes

















          up vote
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          down vote



          accepted










          1. Call the change event manually when putting value on the sum




          let one = $('#one');
          let two = $('#two');
          let three = $('#three');

          $('form').on('change', 'input', function()
          let target = $(this);
          let attrName = target.attr('name');

          $('#' + attrName).text(target.val());
          );

          function sum(a, b)
          return a + b;


          $('.sumVari').each(function()
          $(this).change(function()
          if (one.val() != '' && two.val() != '')
          three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input

          );
          );

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <form>
          <input id="one" type="number" class="sumVari" name="a">
          <input id="two" type="number" class="sumVari" name="b">
          <input id="three" type="number" name="sum" placeholder="sum of a & b">
          </form>
          <div id="displayValues">
          <p>The value of a is: <span id="a"></span> </p>
          <p>The value of a is: <span id="b"></span></p>
          <p>The value of the sum is: <span id="sum"></span></p>
          </div>








          share|improve this answer




















          • @prestondoris glad it works for you happy coding mate :)
            – guradio
            Nov 13 at 0:25










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          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes








          up vote
          1
          down vote



          accepted










          1. Call the change event manually when putting value on the sum




          let one = $('#one');
          let two = $('#two');
          let three = $('#three');

          $('form').on('change', 'input', function()
          let target = $(this);
          let attrName = target.attr('name');

          $('#' + attrName).text(target.val());
          );

          function sum(a, b)
          return a + b;


          $('.sumVari').each(function()
          $(this).change(function()
          if (one.val() != '' && two.val() != '')
          three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input

          );
          );

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <form>
          <input id="one" type="number" class="sumVari" name="a">
          <input id="two" type="number" class="sumVari" name="b">
          <input id="three" type="number" name="sum" placeholder="sum of a & b">
          </form>
          <div id="displayValues">
          <p>The value of a is: <span id="a"></span> </p>
          <p>The value of a is: <span id="b"></span></p>
          <p>The value of the sum is: <span id="sum"></span></p>
          </div>








          share|improve this answer




















          • @prestondoris glad it works for you happy coding mate :)
            – guradio
            Nov 13 at 0:25














          up vote
          1
          down vote



          accepted










          1. Call the change event manually when putting value on the sum




          let one = $('#one');
          let two = $('#two');
          let three = $('#three');

          $('form').on('change', 'input', function()
          let target = $(this);
          let attrName = target.attr('name');

          $('#' + attrName).text(target.val());
          );

          function sum(a, b)
          return a + b;


          $('.sumVari').each(function()
          $(this).change(function()
          if (one.val() != '' && two.val() != '')
          three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input

          );
          );

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <form>
          <input id="one" type="number" class="sumVari" name="a">
          <input id="two" type="number" class="sumVari" name="b">
          <input id="three" type="number" name="sum" placeholder="sum of a & b">
          </form>
          <div id="displayValues">
          <p>The value of a is: <span id="a"></span> </p>
          <p>The value of a is: <span id="b"></span></p>
          <p>The value of the sum is: <span id="sum"></span></p>
          </div>








          share|improve this answer




















          • @prestondoris glad it works for you happy coding mate :)
            – guradio
            Nov 13 at 0:25












          up vote
          1
          down vote



          accepted







          up vote
          1
          down vote



          accepted






          1. Call the change event manually when putting value on the sum




          let one = $('#one');
          let two = $('#two');
          let three = $('#three');

          $('form').on('change', 'input', function()
          let target = $(this);
          let attrName = target.attr('name');

          $('#' + attrName).text(target.val());
          );

          function sum(a, b)
          return a + b;


          $('.sumVari').each(function()
          $(this).change(function()
          if (one.val() != '' && two.val() != '')
          three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input

          );
          );

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <form>
          <input id="one" type="number" class="sumVari" name="a">
          <input id="two" type="number" class="sumVari" name="b">
          <input id="three" type="number" name="sum" placeholder="sum of a & b">
          </form>
          <div id="displayValues">
          <p>The value of a is: <span id="a"></span> </p>
          <p>The value of a is: <span id="b"></span></p>
          <p>The value of the sum is: <span id="sum"></span></p>
          </div>








          share|improve this answer












          1. Call the change event manually when putting value on the sum




          let one = $('#one');
          let two = $('#two');
          let three = $('#three');

          $('form').on('change', 'input', function()
          let target = $(this);
          let attrName = target.attr('name');

          $('#' + attrName).text(target.val());
          );

          function sum(a, b)
          return a + b;


          $('.sumVari').each(function()
          $(this).change(function()
          if (one.val() != '' && two.val() != '')
          three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input

          );
          );

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <form>
          <input id="one" type="number" class="sumVari" name="a">
          <input id="two" type="number" class="sumVari" name="b">
          <input id="three" type="number" name="sum" placeholder="sum of a & b">
          </form>
          <div id="displayValues">
          <p>The value of a is: <span id="a"></span> </p>
          <p>The value of a is: <span id="b"></span></p>
          <p>The value of the sum is: <span id="sum"></span></p>
          </div>








          let one = $('#one');
          let two = $('#two');
          let three = $('#three');

          $('form').on('change', 'input', function()
          let target = $(this);
          let attrName = target.attr('name');

          $('#' + attrName).text(target.val());
          );

          function sum(a, b)
          return a + b;


          $('.sumVari').each(function()
          $(this).change(function()
          if (one.val() != '' && two.val() != '')
          three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input

          );
          );

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <form>
          <input id="one" type="number" class="sumVari" name="a">
          <input id="two" type="number" class="sumVari" name="b">
          <input id="three" type="number" name="sum" placeholder="sum of a & b">
          </form>
          <div id="displayValues">
          <p>The value of a is: <span id="a"></span> </p>
          <p>The value of a is: <span id="b"></span></p>
          <p>The value of the sum is: <span id="sum"></span></p>
          </div>





          let one = $('#one');
          let two = $('#two');
          let three = $('#three');

          $('form').on('change', 'input', function()
          let target = $(this);
          let attrName = target.attr('name');

          $('#' + attrName).text(target.val());
          );

          function sum(a, b)
          return a + b;


          $('.sumVari').each(function()
          $(this).change(function()
          if (one.val() != '' && two.val() != '')
          three.val(sum(one.val(), two.val())).change();//call the change event manually here on the sum input so that the change function will run on the sum input

          );
          );

          <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
          <form>
          <input id="one" type="number" class="sumVari" name="a">
          <input id="two" type="number" class="sumVari" name="b">
          <input id="three" type="number" name="sum" placeholder="sum of a & b">
          </form>
          <div id="displayValues">
          <p>The value of a is: <span id="a"></span> </p>
          <p>The value of a is: <span id="b"></span></p>
          <p>The value of the sum is: <span id="sum"></span></p>
          </div>






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 12 at 0:28









          guradio

          13.7k31836




          13.7k31836











          • @prestondoris glad it works for you happy coding mate :)
            – guradio
            Nov 13 at 0:25
















          • @prestondoris glad it works for you happy coding mate :)
            – guradio
            Nov 13 at 0:25















          @prestondoris glad it works for you happy coding mate :)
          – guradio
          Nov 13 at 0:25




          @prestondoris glad it works for you happy coding mate :)
          – guradio
          Nov 13 at 0:25

















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