How would one read space separated input in Eiffel?
up vote
1
down vote
favorite
I can't really use Io.read_integer as that just ignores everything except
the first number.
I can use Io.read_line to get something like 15 14 59 86.
How would I split these into integers now?
Javascript has split(), C++ has stringstream, something similar would be ideal.
input stream eiffel
asked Nov 11 at 10:01
Legolas
255
add a comment |
up vote
1
down vote
favorite
I can't really use Io.read_integer as that just ignores everything except
the first number.
I can use Io.read_line to get something like 15 14 59 86.
How would I split these into integers now?
Javascript has split(), C++ has stringstream, something similar would be ideal.
input stream eiffel
asked Nov 11 at 10:01
Legolas
255
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
I can't really use Io.read_integer as that just ignores everything except
the first number.
I can use Io.read_line to get something like 15 14 59 86.
How would I split these into integers now?
Javascript has split(), C++ has stringstream, something similar would be ideal.
input stream eiffel
asked Nov 11 at 10:01
Legolas
255
I can't really use Io.read_integer as that just ignores everything except
the first number.
I can use Io.read_line to get something like 15 14 59 86.
How would I split these into integers now?
Javascript has split(), C++ has stringstream, something similar would be ideal.
input stream eiffel
input stream eiffel
asked Nov 11 at 10:01
Legolas
255
asked Nov 11 at 10:01
Legolas
255
asked Nov 11 at 10:01
Legolas
255
asked Nov 11 at 10:01
Legolas
255
asked Nov 11 at 10:01
Legolas
255
255
add a comment |
add a comment |
2 Answers
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If you use only one space, there is a split method in the STRING class. The argument of the split method is a CHARACTER instead of a STRING. So, you have to use ' ' instead of " ". Here is a little function that do what I think you want.
split_to_integer_list(a_string:STRING):ARRAYED_LIST[INTEGER]
-- Convert `a_string', a space separated list of integer
-- into a LIST of INTEGER
local
l_split:LIST[STRING]
do
l_split := a_string.split (' ')
create Result.make (a_string.count)
across l_split as la_split loop
if la_split.item.is_integer then
Result.extend(la_split.item.to_integer)
end
end
end
answered Nov 12 at 0:55
Louis M
49124
add a comment |
up vote
2
down vote
In case you want to allow several spaces, tabs, etc. between the integers, you can use the class ST_SPLITTER from the Gobo library. Here is an example:
local
l_line: STRING
l_splitter: ST_SPLITTER
l_list: DS_LINKED_LIST [INTEGER]
do
io.read_line
l_line := io.last_string
create l_list.make
create l_splitter.make_with_separators (" %T")
across l_splitter.split (l_line) as l_split loop
if l_split.item.is_integer then
l_list.put_last (l_split.item.to_integer)
end
end
answered Nov 12 at 8:46
Eric Bezault
414
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
If you use only one space, there is a split method in the STRING class. The argument of the split method is a CHARACTER instead of a STRING. So, you have to use ' ' instead of " ". Here is a little function that do what I think you want.
split_to_integer_list(a_string:STRING):ARRAYED_LIST[INTEGER]
-- Convert `a_string', a space separated list of integer
-- into a LIST of INTEGER
local
l_split:LIST[STRING]
do
l_split := a_string.split (' ')
create Result.make (a_string.count)
across l_split as la_split loop
if la_split.item.is_integer then
Result.extend(la_split.item.to_integer)
end
end
end
answered Nov 12 at 0:55
Louis M
49124
add a comment |
up vote
3
down vote
accepted
If you use only one space, there is a split method in the STRING class. The argument of the split method is a CHARACTER instead of a STRING. So, you have to use ' ' instead of " ". Here is a little function that do what I think you want.
split_to_integer_list(a_string:STRING):ARRAYED_LIST[INTEGER]
-- Convert `a_string', a space separated list of integer
-- into a LIST of INTEGER
local
l_split:LIST[STRING]
do
l_split := a_string.split (' ')
create Result.make (a_string.count)
across l_split as la_split loop
if la_split.item.is_integer then
Result.extend(la_split.item.to_integer)
end
end
end
answered Nov 12 at 0:55
Louis M
49124
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
If you use only one space, there is a split method in the STRING class. The argument of the split method is a CHARACTER instead of a STRING. So, you have to use ' ' instead of " ". Here is a little function that do what I think you want.
split_to_integer_list(a_string:STRING):ARRAYED_LIST[INTEGER]
-- Convert `a_string', a space separated list of integer
-- into a LIST of INTEGER
local
l_split:LIST[STRING]
do
l_split := a_string.split (' ')
create Result.make (a_string.count)
across l_split as la_split loop
if la_split.item.is_integer then
Result.extend(la_split.item.to_integer)
end
end
end
answered Nov 12 at 0:55
Louis M
49124
If you use only one space, there is a split method in the STRING class. The argument of the split method is a CHARACTER instead of a STRING. So, you have to use ' ' instead of " ". Here is a little function that do what I think you want.
split_to_integer_list(a_string:STRING):ARRAYED_LIST[INTEGER]
-- Convert `a_string', a space separated list of integer
-- into a LIST of INTEGER
local
l_split:LIST[STRING]
do
l_split := a_string.split (' ')
create Result.make (a_string.count)
across l_split as la_split loop
if la_split.item.is_integer then
Result.extend(la_split.item.to_integer)
end
end
end
answered Nov 12 at 0:55
Louis M
49124
answered Nov 12 at 0:55
Louis M
49124
answered Nov 12 at 0:55
Louis M
49124
answered Nov 12 at 0:55
Louis M
49124
49124
add a comment |
add a comment |
up vote
2
down vote
In case you want to allow several spaces, tabs, etc. between the integers, you can use the class ST_SPLITTER from the Gobo library. Here is an example:
local
l_line: STRING
l_splitter: ST_SPLITTER
l_list: DS_LINKED_LIST [INTEGER]
do
io.read_line
l_line := io.last_string
create l_list.make
create l_splitter.make_with_separators (" %T")
across l_splitter.split (l_line) as l_split loop
if l_split.item.is_integer then
l_list.put_last (l_split.item.to_integer)
end
end
answered Nov 12 at 8:46
Eric Bezault
414
add a comment |
up vote
2
down vote
In case you want to allow several spaces, tabs, etc. between the integers, you can use the class ST_SPLITTER from the Gobo library. Here is an example:
local
l_line: STRING
l_splitter: ST_SPLITTER
l_list: DS_LINKED_LIST [INTEGER]
do
io.read_line
l_line := io.last_string
create l_list.make
create l_splitter.make_with_separators (" %T")
across l_splitter.split (l_line) as l_split loop
if l_split.item.is_integer then
l_list.put_last (l_split.item.to_integer)
end
end
answered Nov 12 at 8:46
Eric Bezault
414
add a comment |
up vote
2
down vote
up vote
2
down vote
In case you want to allow several spaces, tabs, etc. between the integers, you can use the class ST_SPLITTER from the Gobo library. Here is an example:
local
l_line: STRING
l_splitter: ST_SPLITTER
l_list: DS_LINKED_LIST [INTEGER]
do
io.read_line
l_line := io.last_string
create l_list.make
create l_splitter.make_with_separators (" %T")
across l_splitter.split (l_line) as l_split loop
if l_split.item.is_integer then
l_list.put_last (l_split.item.to_integer)
end
end
answered Nov 12 at 8:46
Eric Bezault
414
In case you want to allow several spaces, tabs, etc. between the integers, you can use the class ST_SPLITTER from the Gobo library. Here is an example:
local
l_line: STRING
l_splitter: ST_SPLITTER
l_list: DS_LINKED_LIST [INTEGER]
do
io.read_line
l_line := io.last_string
create l_list.make
create l_splitter.make_with_separators (" %T")
across l_splitter.split (l_line) as l_split loop
if l_split.item.is_integer then
l_list.put_last (l_split.item.to_integer)
end
end
answered Nov 12 at 8:46
Eric Bezault
414
answered Nov 12 at 8:46
Eric Bezault
414
answered Nov 12 at 8:46
Eric Bezault
414
answered Nov 12 at 8:46
Eric Bezault
414
414
add a comment |
add a comment |
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