The difference between the two dates in PostgreSQL
0
Is there an equivalent to this T-SQL command in PostgreSQL?
SELECT COUNT(*)
FROM [dbo].[LayerTable]
where layerType=3
and created >= Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp))),0)
I have found date_part() and extract function() but not working.
sql postgresql date-arithmetic
asked Nov 12 at 7:09
Onur Ek.
206
add a comment |
0
Is there an equivalent to this T-SQL command in PostgreSQL?
SELECT COUNT(*)
FROM [dbo].[LayerTable]
where layerType=3
and created >= Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp))),0)
I have found date_part() and extract function() but not working.
sql postgresql date-arithmetic
asked Nov 12 at 7:09
Onur Ek.
206
1
No everybody that knows Postgres will know what that T-SQL query is doing. Can you explain in words what thedateadd()function is doing? Does it add six months tocurrent_timestamp?
– a_horse_with_no_name
Nov 12 at 7:11
DATEADD (datepart , number , date ) : Returns a new datetime value by adding an interval to the specified datepart of the specified date. DATEDIFF ( datepart , startdate , enddate ) : Returns the number of date or time datepart boundaries, crossed between two specified dates.
– Onur Ek.
Nov 12 at 7:14
Your SQL seems to be invalid: When I runselect Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp))))I get an error "The dateadd function requires 3 argument(s).": dbfiddle.uk/…
– a_horse_with_no_name
Nov 12 at 7:14
Im so so Sorry. select Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp)),0)
– Onur Ek.
Nov 12 at 7:17
add a comment |
0
0
0
Is there an equivalent to this T-SQL command in PostgreSQL?
SELECT COUNT(*)
FROM [dbo].[LayerTable]
where layerType=3
and created >= Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp))),0)
I have found date_part() and extract function() but not working.
sql postgresql date-arithmetic
asked Nov 12 at 7:09
Onur Ek.
206
Is there an equivalent to this T-SQL command in PostgreSQL?
SELECT COUNT(*)
FROM [dbo].[LayerTable]
where layerType=3
and created >= Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp))),0)
I have found date_part() and extract function() but not working.
sql postgresql date-arithmetic
sql postgresql date-arithmetic
asked Nov 12 at 7:09
Onur Ek.
206
asked Nov 12 at 7:09
Onur Ek.
206
edited Nov 12 at 7:18
asked Nov 12 at 7:09
Onur Ek.
206
asked Nov 12 at 7:09
Onur Ek.
206
asked Nov 12 at 7:09
Onur Ek.
206
206
1
No everybody that knows Postgres will know what that T-SQL query is doing. Can you explain in words what thedateadd()function is doing? Does it add six months tocurrent_timestamp?
– a_horse_with_no_name
Nov 12 at 7:11
DATEADD (datepart , number , date ) : Returns a new datetime value by adding an interval to the specified datepart of the specified date. DATEDIFF ( datepart , startdate , enddate ) : Returns the number of date or time datepart boundaries, crossed between two specified dates.
– Onur Ek.
Nov 12 at 7:14
Your SQL seems to be invalid: When I runselect Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp))))I get an error "The dateadd function requires 3 argument(s).": dbfiddle.uk/…
– a_horse_with_no_name
Nov 12 at 7:14
Im so so Sorry. select Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp)),0)
– Onur Ek.
Nov 12 at 7:17
add a comment |
1
No everybody that knows Postgres will know what that T-SQL query is doing. Can you explain in words what thedateadd()function is doing? Does it add six months tocurrent_timestamp?
– a_horse_with_no_name
Nov 12 at 7:11
DATEADD (datepart , number , date ) : Returns a new datetime value by adding an interval to the specified datepart of the specified date. DATEDIFF ( datepart , startdate , enddate ) : Returns the number of date or time datepart boundaries, crossed between two specified dates.
– Onur Ek.
Nov 12 at 7:14
Your SQL seems to be invalid: When I runselect Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp))))I get an error "The dateadd function requires 3 argument(s).": dbfiddle.uk/…
– a_horse_with_no_name
Nov 12 at 7:14
Im so so Sorry. select Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp)),0)
– Onur Ek.
Nov 12 at 7:17
1
1
No everybody that knows Postgres will know what that T-SQL query is doing. Can you explain in words what the
dateadd() function is doing? Does it add six months to current_timestamp?– a_horse_with_no_name
Nov 12 at 7:11
No everybody that knows Postgres will know what that T-SQL query is doing. Can you explain in words what the
dateadd() function is doing? Does it add six months to current_timestamp?– a_horse_with_no_name
Nov 12 at 7:11
DATEADD (datepart , number , date ) : Returns a new datetime value by adding an interval to the specified datepart of the specified date. DATEDIFF ( datepart , startdate , enddate ) : Returns the number of date or time datepart boundaries, crossed between two specified dates.
– Onur Ek.
Nov 12 at 7:14
DATEADD (datepart , number , date ) : Returns a new datetime value by adding an interval to the specified datepart of the specified date. DATEDIFF ( datepart , startdate , enddate ) : Returns the number of date or time datepart boundaries, crossed between two specified dates.
– Onur Ek.
Nov 12 at 7:14
Your SQL seems to be invalid: When I run
select Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp)))) I get an error "The dateadd function requires 3 argument(s).": dbfiddle.uk/…– a_horse_with_no_name
Nov 12 at 7:14
Your SQL seems to be invalid: When I run
select Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp)))) I get an error "The dateadd function requires 3 argument(s).": dbfiddle.uk/…– a_horse_with_no_name
Nov 12 at 7:14
Im so so Sorry. select Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp)),0)
– Onur Ek.
Nov 12 at 7:17
Im so so Sorry. select Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp)),0)
– Onur Ek.
Nov 12 at 7:17
add a comment |
1 Answer
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1
Looks like this is simply subtracting 6 months from current_timestamp, so the equivalent would be:
SELECT COUNT(*)
FROM dbo.layer_table
where layer_type=3
and created >= current_timestamp - interval '6 months';
If you want the start of the month (rather than the "same" day as "today") as the result use:
created >= date_trunc('month', current_timestamp - interval '6 months')
answered Nov 12 at 7:16
a_horse_with_no_name
291k46444537
add a comment |
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1
Looks like this is simply subtracting 6 months from current_timestamp, so the equivalent would be:
SELECT COUNT(*)
FROM dbo.layer_table
where layer_type=3
and created >= current_timestamp - interval '6 months';
If you want the start of the month (rather than the "same" day as "today") as the result use:
created >= date_trunc('month', current_timestamp - interval '6 months')
answered Nov 12 at 7:16
a_horse_with_no_name
291k46444537
add a comment |
1
Looks like this is simply subtracting 6 months from current_timestamp, so the equivalent would be:
SELECT COUNT(*)
FROM dbo.layer_table
where layer_type=3
and created >= current_timestamp - interval '6 months';
If you want the start of the month (rather than the "same" day as "today") as the result use:
created >= date_trunc('month', current_timestamp - interval '6 months')
answered Nov 12 at 7:16
a_horse_with_no_name
291k46444537
add a comment |
1
1
1
Looks like this is simply subtracting 6 months from current_timestamp, so the equivalent would be:
SELECT COUNT(*)
FROM dbo.layer_table
where layer_type=3
and created >= current_timestamp - interval '6 months';
If you want the start of the month (rather than the "same" day as "today") as the result use:
created >= date_trunc('month', current_timestamp - interval '6 months')
answered Nov 12 at 7:16
a_horse_with_no_name
291k46444537
Looks like this is simply subtracting 6 months from current_timestamp, so the equivalent would be:
SELECT COUNT(*)
FROM dbo.layer_table
where layer_type=3
and created >= current_timestamp - interval '6 months';
If you want the start of the month (rather than the "same" day as "today") as the result use:
created >= date_trunc('month', current_timestamp - interval '6 months')
answered Nov 12 at 7:16
a_horse_with_no_name
291k46444537
answered Nov 12 at 7:16
a_horse_with_no_name
291k46444537
answered Nov 12 at 7:16
a_horse_with_no_name
291k46444537
answered Nov 12 at 7:16
a_horse_with_no_name
291k46444537
291k46444537
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1
No everybody that knows Postgres will know what that T-SQL query is doing. Can you explain in words what the
dateadd()function is doing? Does it add six months tocurrent_timestamp?– a_horse_with_no_name
Nov 12 at 7:11
DATEADD (datepart , number , date ) : Returns a new datetime value by adding an interval to the specified datepart of the specified date. DATEDIFF ( datepart , startdate , enddate ) : Returns the number of date or time datepart boundaries, crossed between two specified dates.
– Onur Ek.
Nov 12 at 7:14
Your SQL seems to be invalid: When I run
select Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp))))I get an error "The dateadd function requires 3 argument(s).": dbfiddle.uk/…– a_horse_with_no_name
Nov 12 at 7:14
Im so so Sorry. select Dateadd(Month, Datediff(Month, 0, DATEADD(m, -6, current_timestamp)),0)
– Onur Ek.
Nov 12 at 7:17