Sort column in pandas dataframe after rarity of values within groups










1














I have a pandas dataframe of scraped websites with a website identifier, a text and a label of the websites. A small number of websites have two labels, but since I want to train first a single label classifier, I would like to create a version of the data with only one label for every website (I'm aware that this is slightly problematic). The labels in my dataset are unbalanced (with some labels occurring very often and some being very rare). If I delete duplicate website IDs, I would like to delete labels that are very common first. This is how my dataset with several labels looks like:



ID Label Text
1 a some text
1 b other text
1 a data
2 a words
2 c more words
3 a text
3 b short text


My idea was to sort the label column within every website identifier by rarity of the label. For that I would first do value_counts(ascending = True) on the label column, to get a list of all labels sorted by rarity.



to_sort = [c, b, a]


I then would like to use that list to sort within every website ID by rarity. I'm not sure how to do that, though. The result should look like this:



ID Label Text
1 b other text
1 a some text
1 a data
2 c more words
2 a words
3 b short text
3 a text


I then would use df.drop_duplicates(subset = 'ID', keep = 'first'), to keep the label that is the most rare. How can I do the sorting?










share|improve this question


























    1














    I have a pandas dataframe of scraped websites with a website identifier, a text and a label of the websites. A small number of websites have two labels, but since I want to train first a single label classifier, I would like to create a version of the data with only one label for every website (I'm aware that this is slightly problematic). The labels in my dataset are unbalanced (with some labels occurring very often and some being very rare). If I delete duplicate website IDs, I would like to delete labels that are very common first. This is how my dataset with several labels looks like:



    ID Label Text
    1 a some text
    1 b other text
    1 a data
    2 a words
    2 c more words
    3 a text
    3 b short text


    My idea was to sort the label column within every website identifier by rarity of the label. For that I would first do value_counts(ascending = True) on the label column, to get a list of all labels sorted by rarity.



    to_sort = [c, b, a]


    I then would like to use that list to sort within every website ID by rarity. I'm not sure how to do that, though. The result should look like this:



    ID Label Text
    1 b other text
    1 a some text
    1 a data
    2 c more words
    2 a words
    3 b short text
    3 a text


    I then would use df.drop_duplicates(subset = 'ID', keep = 'first'), to keep the label that is the most rare. How can I do the sorting?










    share|improve this question
























      1












      1








      1







      I have a pandas dataframe of scraped websites with a website identifier, a text and a label of the websites. A small number of websites have two labels, but since I want to train first a single label classifier, I would like to create a version of the data with only one label for every website (I'm aware that this is slightly problematic). The labels in my dataset are unbalanced (with some labels occurring very often and some being very rare). If I delete duplicate website IDs, I would like to delete labels that are very common first. This is how my dataset with several labels looks like:



      ID Label Text
      1 a some text
      1 b other text
      1 a data
      2 a words
      2 c more words
      3 a text
      3 b short text


      My idea was to sort the label column within every website identifier by rarity of the label. For that I would first do value_counts(ascending = True) on the label column, to get a list of all labels sorted by rarity.



      to_sort = [c, b, a]


      I then would like to use that list to sort within every website ID by rarity. I'm not sure how to do that, though. The result should look like this:



      ID Label Text
      1 b other text
      1 a some text
      1 a data
      2 c more words
      2 a words
      3 b short text
      3 a text


      I then would use df.drop_duplicates(subset = 'ID', keep = 'first'), to keep the label that is the most rare. How can I do the sorting?










      share|improve this question













      I have a pandas dataframe of scraped websites with a website identifier, a text and a label of the websites. A small number of websites have two labels, but since I want to train first a single label classifier, I would like to create a version of the data with only one label for every website (I'm aware that this is slightly problematic). The labels in my dataset are unbalanced (with some labels occurring very often and some being very rare). If I delete duplicate website IDs, I would like to delete labels that are very common first. This is how my dataset with several labels looks like:



      ID Label Text
      1 a some text
      1 b other text
      1 a data
      2 a words
      2 c more words
      3 a text
      3 b short text


      My idea was to sort the label column within every website identifier by rarity of the label. For that I would first do value_counts(ascending = True) on the label column, to get a list of all labels sorted by rarity.



      to_sort = [c, b, a]


      I then would like to use that list to sort within every website ID by rarity. I'm not sure how to do that, though. The result should look like this:



      ID Label Text
      1 b other text
      1 a some text
      1 a data
      2 c more words
      2 a words
      3 b short text
      3 a text


      I then would use df.drop_duplicates(subset = 'ID', keep = 'first'), to keep the label that is the most rare. How can I do the sorting?







      python pandas






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Nov 12 at 15:17









      Amelia Bones

      285




      285






















          2 Answers
          2






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          0














          Use ordered categorical, so possible use sort_values:



          to_sort = list('cba')

          df['Label'] = pd.Categorical(df['Label'], ordered=True, categories=to_sort)

          df = df.sort_values(['ID','Label'])
          print (df)
          ID Label Text
          1 1 b other text
          0 1 a some text
          2 1 a data
          4 2 c more words
          3 2 a words
          6 3 b short text
          5 3 a text





          share|improve this answer
















          • 1




            Thanks a lot! Very helpful
            – Amelia Bones
            Nov 12 at 15:32


















          0














          You can achieve your goal by making the Label Column Categorical, then sort by ID and Label . Let's see it in practice.



          import pandas as pd
          df = pd.DataFrame( 'ID': [1,1,1,2,2,3,3], "Label": ["a", "b", "a", "a", "c", "a", "b"],
          'Text': ["some text", "other text","data", "words", "more words", "text", "short text"] )
          df
          ID Label Text
          0 1 a some text
          1 1 b other text
          2 1 a data
          3 2 a words
          4 2 c more words
          5 3 a text
          6 3 b short text


          Define your labels' order by doing :



          to_sort = df.Label.value_counts(ascending = True).index
          to_sort
          Index(['c', 'b', 'a'], dtype='object')


          Then make the Label column Categorical like this :



          df.Label = pd.Categorical(df.Label,categories = to_sort, ordered = True)


          Finally, sort by ID and Label :



          df.sort_values(["ID", "Label"]).reset_index(drop = True)

          ID Label Text
          0 1 b other text
          1 1 a some text
          2 1 a data
          3 2 c more words
          4 2 a words
          5 3 b short text
          6 3 a text





          share|improve this answer




















          • So why you post your answer? OP know df.Label.value_counts(ascending = True).index and .reset_index(drop = True) is only small difference with my answer :(
            – jezrael
            Nov 12 at 15:55










          • I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
            – Neroksi
            Nov 12 at 16:40










          Your Answer






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          2 Answers
          2






          active

          oldest

          votes








          2 Answers
          2






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          0














          Use ordered categorical, so possible use sort_values:



          to_sort = list('cba')

          df['Label'] = pd.Categorical(df['Label'], ordered=True, categories=to_sort)

          df = df.sort_values(['ID','Label'])
          print (df)
          ID Label Text
          1 1 b other text
          0 1 a some text
          2 1 a data
          4 2 c more words
          3 2 a words
          6 3 b short text
          5 3 a text





          share|improve this answer
















          • 1




            Thanks a lot! Very helpful
            – Amelia Bones
            Nov 12 at 15:32















          0














          Use ordered categorical, so possible use sort_values:



          to_sort = list('cba')

          df['Label'] = pd.Categorical(df['Label'], ordered=True, categories=to_sort)

          df = df.sort_values(['ID','Label'])
          print (df)
          ID Label Text
          1 1 b other text
          0 1 a some text
          2 1 a data
          4 2 c more words
          3 2 a words
          6 3 b short text
          5 3 a text





          share|improve this answer
















          • 1




            Thanks a lot! Very helpful
            – Amelia Bones
            Nov 12 at 15:32













          0












          0








          0






          Use ordered categorical, so possible use sort_values:



          to_sort = list('cba')

          df['Label'] = pd.Categorical(df['Label'], ordered=True, categories=to_sort)

          df = df.sort_values(['ID','Label'])
          print (df)
          ID Label Text
          1 1 b other text
          0 1 a some text
          2 1 a data
          4 2 c more words
          3 2 a words
          6 3 b short text
          5 3 a text





          share|improve this answer












          Use ordered categorical, so possible use sort_values:



          to_sort = list('cba')

          df['Label'] = pd.Categorical(df['Label'], ordered=True, categories=to_sort)

          df = df.sort_values(['ID','Label'])
          print (df)
          ID Label Text
          1 1 b other text
          0 1 a some text
          2 1 a data
          4 2 c more words
          3 2 a words
          6 3 b short text
          5 3 a text






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 12 at 15:19









          jezrael

          320k22259338




          320k22259338







          • 1




            Thanks a lot! Very helpful
            – Amelia Bones
            Nov 12 at 15:32












          • 1




            Thanks a lot! Very helpful
            – Amelia Bones
            Nov 12 at 15:32







          1




          1




          Thanks a lot! Very helpful
          – Amelia Bones
          Nov 12 at 15:32




          Thanks a lot! Very helpful
          – Amelia Bones
          Nov 12 at 15:32













          0














          You can achieve your goal by making the Label Column Categorical, then sort by ID and Label . Let's see it in practice.



          import pandas as pd
          df = pd.DataFrame( 'ID': [1,1,1,2,2,3,3], "Label": ["a", "b", "a", "a", "c", "a", "b"],
          'Text': ["some text", "other text","data", "words", "more words", "text", "short text"] )
          df
          ID Label Text
          0 1 a some text
          1 1 b other text
          2 1 a data
          3 2 a words
          4 2 c more words
          5 3 a text
          6 3 b short text


          Define your labels' order by doing :



          to_sort = df.Label.value_counts(ascending = True).index
          to_sort
          Index(['c', 'b', 'a'], dtype='object')


          Then make the Label column Categorical like this :



          df.Label = pd.Categorical(df.Label,categories = to_sort, ordered = True)


          Finally, sort by ID and Label :



          df.sort_values(["ID", "Label"]).reset_index(drop = True)

          ID Label Text
          0 1 b other text
          1 1 a some text
          2 1 a data
          3 2 c more words
          4 2 a words
          5 3 b short text
          6 3 a text





          share|improve this answer




















          • So why you post your answer? OP know df.Label.value_counts(ascending = True).index and .reset_index(drop = True) is only small difference with my answer :(
            – jezrael
            Nov 12 at 15:55










          • I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
            – Neroksi
            Nov 12 at 16:40















          0














          You can achieve your goal by making the Label Column Categorical, then sort by ID and Label . Let's see it in practice.



          import pandas as pd
          df = pd.DataFrame( 'ID': [1,1,1,2,2,3,3], "Label": ["a", "b", "a", "a", "c", "a", "b"],
          'Text': ["some text", "other text","data", "words", "more words", "text", "short text"] )
          df
          ID Label Text
          0 1 a some text
          1 1 b other text
          2 1 a data
          3 2 a words
          4 2 c more words
          5 3 a text
          6 3 b short text


          Define your labels' order by doing :



          to_sort = df.Label.value_counts(ascending = True).index
          to_sort
          Index(['c', 'b', 'a'], dtype='object')


          Then make the Label column Categorical like this :



          df.Label = pd.Categorical(df.Label,categories = to_sort, ordered = True)


          Finally, sort by ID and Label :



          df.sort_values(["ID", "Label"]).reset_index(drop = True)

          ID Label Text
          0 1 b other text
          1 1 a some text
          2 1 a data
          3 2 c more words
          4 2 a words
          5 3 b short text
          6 3 a text





          share|improve this answer




















          • So why you post your answer? OP know df.Label.value_counts(ascending = True).index and .reset_index(drop = True) is only small difference with my answer :(
            – jezrael
            Nov 12 at 15:55










          • I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
            – Neroksi
            Nov 12 at 16:40













          0












          0








          0






          You can achieve your goal by making the Label Column Categorical, then sort by ID and Label . Let's see it in practice.



          import pandas as pd
          df = pd.DataFrame( 'ID': [1,1,1,2,2,3,3], "Label": ["a", "b", "a", "a", "c", "a", "b"],
          'Text': ["some text", "other text","data", "words", "more words", "text", "short text"] )
          df
          ID Label Text
          0 1 a some text
          1 1 b other text
          2 1 a data
          3 2 a words
          4 2 c more words
          5 3 a text
          6 3 b short text


          Define your labels' order by doing :



          to_sort = df.Label.value_counts(ascending = True).index
          to_sort
          Index(['c', 'b', 'a'], dtype='object')


          Then make the Label column Categorical like this :



          df.Label = pd.Categorical(df.Label,categories = to_sort, ordered = True)


          Finally, sort by ID and Label :



          df.sort_values(["ID", "Label"]).reset_index(drop = True)

          ID Label Text
          0 1 b other text
          1 1 a some text
          2 1 a data
          3 2 c more words
          4 2 a words
          5 3 b short text
          6 3 a text





          share|improve this answer












          You can achieve your goal by making the Label Column Categorical, then sort by ID and Label . Let's see it in practice.



          import pandas as pd
          df = pd.DataFrame( 'ID': [1,1,1,2,2,3,3], "Label": ["a", "b", "a", "a", "c", "a", "b"],
          'Text': ["some text", "other text","data", "words", "more words", "text", "short text"] )
          df
          ID Label Text
          0 1 a some text
          1 1 b other text
          2 1 a data
          3 2 a words
          4 2 c more words
          5 3 a text
          6 3 b short text


          Define your labels' order by doing :



          to_sort = df.Label.value_counts(ascending = True).index
          to_sort
          Index(['c', 'b', 'a'], dtype='object')


          Then make the Label column Categorical like this :



          df.Label = pd.Categorical(df.Label,categories = to_sort, ordered = True)


          Finally, sort by ID and Label :



          df.sort_values(["ID", "Label"]).reset_index(drop = True)

          ID Label Text
          0 1 b other text
          1 1 a some text
          2 1 a data
          3 2 c more words
          4 2 a words
          5 3 b short text
          6 3 a text






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 12 at 15:53









          Neroksi

          382111




          382111











          • So why you post your answer? OP know df.Label.value_counts(ascending = True).index and .reset_index(drop = True) is only small difference with my answer :(
            – jezrael
            Nov 12 at 15:55










          • I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
            – Neroksi
            Nov 12 at 16:40
















          • So why you post your answer? OP know df.Label.value_counts(ascending = True).index and .reset_index(drop = True) is only small difference with my answer :(
            – jezrael
            Nov 12 at 15:55










          • I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
            – Neroksi
            Nov 12 at 16:40















          So why you post your answer? OP know df.Label.value_counts(ascending = True).index and .reset_index(drop = True) is only small difference with my answer :(
          – jezrael
          Nov 12 at 15:55




          So why you post your answer? OP know df.Label.value_counts(ascending = True).index and .reset_index(drop = True) is only small difference with my answer :(
          – jezrael
          Nov 12 at 15:55












          I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
          – Neroksi
          Nov 12 at 16:40




          I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
          – Neroksi
          Nov 12 at 16:40

















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