Sort column in pandas dataframe after rarity of values within groups
I have a pandas dataframe of scraped websites with a website identifier, a text and a label of the websites. A small number of websites have two labels, but since I want to train first a single label classifier, I would like to create a version of the data with only one label for every website (I'm aware that this is slightly problematic). The labels in my dataset are unbalanced (with some labels occurring very often and some being very rare). If I delete duplicate website IDs, I would like to delete labels that are very common first. This is how my dataset with several labels looks like:
ID Label Text
1 a some text
1 b other text
1 a data
2 a words
2 c more words
3 a text
3 b short text
My idea was to sort the label column within every website identifier by rarity of the label. For that I would first do value_counts(ascending = True)
on the label column, to get a list of all labels sorted by rarity.
to_sort = [c, b, a]
I then would like to use that list to sort within every website ID by rarity. I'm not sure how to do that, though. The result should look like this:
ID Label Text
1 b other text
1 a some text
1 a data
2 c more words
2 a words
3 b short text
3 a text
I then would use df.drop_duplicates(subset = 'ID', keep = 'first')
, to keep the label that is the most rare. How can I do the sorting?
python pandas
add a comment |
I have a pandas dataframe of scraped websites with a website identifier, a text and a label of the websites. A small number of websites have two labels, but since I want to train first a single label classifier, I would like to create a version of the data with only one label for every website (I'm aware that this is slightly problematic). The labels in my dataset are unbalanced (with some labels occurring very often and some being very rare). If I delete duplicate website IDs, I would like to delete labels that are very common first. This is how my dataset with several labels looks like:
ID Label Text
1 a some text
1 b other text
1 a data
2 a words
2 c more words
3 a text
3 b short text
My idea was to sort the label column within every website identifier by rarity of the label. For that I would first do value_counts(ascending = True)
on the label column, to get a list of all labels sorted by rarity.
to_sort = [c, b, a]
I then would like to use that list to sort within every website ID by rarity. I'm not sure how to do that, though. The result should look like this:
ID Label Text
1 b other text
1 a some text
1 a data
2 c more words
2 a words
3 b short text
3 a text
I then would use df.drop_duplicates(subset = 'ID', keep = 'first')
, to keep the label that is the most rare. How can I do the sorting?
python pandas
add a comment |
I have a pandas dataframe of scraped websites with a website identifier, a text and a label of the websites. A small number of websites have two labels, but since I want to train first a single label classifier, I would like to create a version of the data with only one label for every website (I'm aware that this is slightly problematic). The labels in my dataset are unbalanced (with some labels occurring very often and some being very rare). If I delete duplicate website IDs, I would like to delete labels that are very common first. This is how my dataset with several labels looks like:
ID Label Text
1 a some text
1 b other text
1 a data
2 a words
2 c more words
3 a text
3 b short text
My idea was to sort the label column within every website identifier by rarity of the label. For that I would first do value_counts(ascending = True)
on the label column, to get a list of all labels sorted by rarity.
to_sort = [c, b, a]
I then would like to use that list to sort within every website ID by rarity. I'm not sure how to do that, though. The result should look like this:
ID Label Text
1 b other text
1 a some text
1 a data
2 c more words
2 a words
3 b short text
3 a text
I then would use df.drop_duplicates(subset = 'ID', keep = 'first')
, to keep the label that is the most rare. How can I do the sorting?
python pandas
I have a pandas dataframe of scraped websites with a website identifier, a text and a label of the websites. A small number of websites have two labels, but since I want to train first a single label classifier, I would like to create a version of the data with only one label for every website (I'm aware that this is slightly problematic). The labels in my dataset are unbalanced (with some labels occurring very often and some being very rare). If I delete duplicate website IDs, I would like to delete labels that are very common first. This is how my dataset with several labels looks like:
ID Label Text
1 a some text
1 b other text
1 a data
2 a words
2 c more words
3 a text
3 b short text
My idea was to sort the label column within every website identifier by rarity of the label. For that I would first do value_counts(ascending = True)
on the label column, to get a list of all labels sorted by rarity.
to_sort = [c, b, a]
I then would like to use that list to sort within every website ID by rarity. I'm not sure how to do that, though. The result should look like this:
ID Label Text
1 b other text
1 a some text
1 a data
2 c more words
2 a words
3 b short text
3 a text
I then would use df.drop_duplicates(subset = 'ID', keep = 'first')
, to keep the label that is the most rare. How can I do the sorting?
python pandas
python pandas
asked Nov 12 at 15:17
Amelia Bones
285
285
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
Use ordered categorical
, so possible use sort_values
:
to_sort = list('cba')
df['Label'] = pd.Categorical(df['Label'], ordered=True, categories=to_sort)
df = df.sort_values(['ID','Label'])
print (df)
ID Label Text
1 1 b other text
0 1 a some text
2 1 a data
4 2 c more words
3 2 a words
6 3 b short text
5 3 a text
1
Thanks a lot! Very helpful
– Amelia Bones
Nov 12 at 15:32
add a comment |
You can achieve your goal by making the Label Column Categorical, then sort by ID and Label . Let's see it in practice.
import pandas as pd
df = pd.DataFrame( 'ID': [1,1,1,2,2,3,3], "Label": ["a", "b", "a", "a", "c", "a", "b"],
'Text': ["some text", "other text","data", "words", "more words", "text", "short text"] )
df
ID Label Text
0 1 a some text
1 1 b other text
2 1 a data
3 2 a words
4 2 c more words
5 3 a text
6 3 b short text
Define your labels' order by doing :
to_sort = df.Label.value_counts(ascending = True).index
to_sort
Index(['c', 'b', 'a'], dtype='object')
Then make the Label column Categorical like this :
df.Label = pd.Categorical(df.Label,categories = to_sort, ordered = True)
Finally, sort by ID and Label :
df.sort_values(["ID", "Label"]).reset_index(drop = True)
ID Label Text
0 1 b other text
1 1 a some text
2 1 a data
3 2 c more words
4 2 a words
5 3 b short text
6 3 a text
So why you post your answer? OP knowdf.Label.value_counts(ascending = True).index
and.reset_index(drop = True)
is only small difference with my answer :(
– jezrael
Nov 12 at 15:55
I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
– Neroksi
Nov 12 at 16:40
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use ordered categorical
, so possible use sort_values
:
to_sort = list('cba')
df['Label'] = pd.Categorical(df['Label'], ordered=True, categories=to_sort)
df = df.sort_values(['ID','Label'])
print (df)
ID Label Text
1 1 b other text
0 1 a some text
2 1 a data
4 2 c more words
3 2 a words
6 3 b short text
5 3 a text
1
Thanks a lot! Very helpful
– Amelia Bones
Nov 12 at 15:32
add a comment |
Use ordered categorical
, so possible use sort_values
:
to_sort = list('cba')
df['Label'] = pd.Categorical(df['Label'], ordered=True, categories=to_sort)
df = df.sort_values(['ID','Label'])
print (df)
ID Label Text
1 1 b other text
0 1 a some text
2 1 a data
4 2 c more words
3 2 a words
6 3 b short text
5 3 a text
1
Thanks a lot! Very helpful
– Amelia Bones
Nov 12 at 15:32
add a comment |
Use ordered categorical
, so possible use sort_values
:
to_sort = list('cba')
df['Label'] = pd.Categorical(df['Label'], ordered=True, categories=to_sort)
df = df.sort_values(['ID','Label'])
print (df)
ID Label Text
1 1 b other text
0 1 a some text
2 1 a data
4 2 c more words
3 2 a words
6 3 b short text
5 3 a text
Use ordered categorical
, so possible use sort_values
:
to_sort = list('cba')
df['Label'] = pd.Categorical(df['Label'], ordered=True, categories=to_sort)
df = df.sort_values(['ID','Label'])
print (df)
ID Label Text
1 1 b other text
0 1 a some text
2 1 a data
4 2 c more words
3 2 a words
6 3 b short text
5 3 a text
answered Nov 12 at 15:19
jezrael
320k22259338
320k22259338
1
Thanks a lot! Very helpful
– Amelia Bones
Nov 12 at 15:32
add a comment |
1
Thanks a lot! Very helpful
– Amelia Bones
Nov 12 at 15:32
1
1
Thanks a lot! Very helpful
– Amelia Bones
Nov 12 at 15:32
Thanks a lot! Very helpful
– Amelia Bones
Nov 12 at 15:32
add a comment |
You can achieve your goal by making the Label Column Categorical, then sort by ID and Label . Let's see it in practice.
import pandas as pd
df = pd.DataFrame( 'ID': [1,1,1,2,2,3,3], "Label": ["a", "b", "a", "a", "c", "a", "b"],
'Text': ["some text", "other text","data", "words", "more words", "text", "short text"] )
df
ID Label Text
0 1 a some text
1 1 b other text
2 1 a data
3 2 a words
4 2 c more words
5 3 a text
6 3 b short text
Define your labels' order by doing :
to_sort = df.Label.value_counts(ascending = True).index
to_sort
Index(['c', 'b', 'a'], dtype='object')
Then make the Label column Categorical like this :
df.Label = pd.Categorical(df.Label,categories = to_sort, ordered = True)
Finally, sort by ID and Label :
df.sort_values(["ID", "Label"]).reset_index(drop = True)
ID Label Text
0 1 b other text
1 1 a some text
2 1 a data
3 2 c more words
4 2 a words
5 3 b short text
6 3 a text
So why you post your answer? OP knowdf.Label.value_counts(ascending = True).index
and.reset_index(drop = True)
is only small difference with my answer :(
– jezrael
Nov 12 at 15:55
I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
– Neroksi
Nov 12 at 16:40
add a comment |
You can achieve your goal by making the Label Column Categorical, then sort by ID and Label . Let's see it in practice.
import pandas as pd
df = pd.DataFrame( 'ID': [1,1,1,2,2,3,3], "Label": ["a", "b", "a", "a", "c", "a", "b"],
'Text': ["some text", "other text","data", "words", "more words", "text", "short text"] )
df
ID Label Text
0 1 a some text
1 1 b other text
2 1 a data
3 2 a words
4 2 c more words
5 3 a text
6 3 b short text
Define your labels' order by doing :
to_sort = df.Label.value_counts(ascending = True).index
to_sort
Index(['c', 'b', 'a'], dtype='object')
Then make the Label column Categorical like this :
df.Label = pd.Categorical(df.Label,categories = to_sort, ordered = True)
Finally, sort by ID and Label :
df.sort_values(["ID", "Label"]).reset_index(drop = True)
ID Label Text
0 1 b other text
1 1 a some text
2 1 a data
3 2 c more words
4 2 a words
5 3 b short text
6 3 a text
So why you post your answer? OP knowdf.Label.value_counts(ascending = True).index
and.reset_index(drop = True)
is only small difference with my answer :(
– jezrael
Nov 12 at 15:55
I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
– Neroksi
Nov 12 at 16:40
add a comment |
You can achieve your goal by making the Label Column Categorical, then sort by ID and Label . Let's see it in practice.
import pandas as pd
df = pd.DataFrame( 'ID': [1,1,1,2,2,3,3], "Label": ["a", "b", "a", "a", "c", "a", "b"],
'Text': ["some text", "other text","data", "words", "more words", "text", "short text"] )
df
ID Label Text
0 1 a some text
1 1 b other text
2 1 a data
3 2 a words
4 2 c more words
5 3 a text
6 3 b short text
Define your labels' order by doing :
to_sort = df.Label.value_counts(ascending = True).index
to_sort
Index(['c', 'b', 'a'], dtype='object')
Then make the Label column Categorical like this :
df.Label = pd.Categorical(df.Label,categories = to_sort, ordered = True)
Finally, sort by ID and Label :
df.sort_values(["ID", "Label"]).reset_index(drop = True)
ID Label Text
0 1 b other text
1 1 a some text
2 1 a data
3 2 c more words
4 2 a words
5 3 b short text
6 3 a text
You can achieve your goal by making the Label Column Categorical, then sort by ID and Label . Let's see it in practice.
import pandas as pd
df = pd.DataFrame( 'ID': [1,1,1,2,2,3,3], "Label": ["a", "b", "a", "a", "c", "a", "b"],
'Text': ["some text", "other text","data", "words", "more words", "text", "short text"] )
df
ID Label Text
0 1 a some text
1 1 b other text
2 1 a data
3 2 a words
4 2 c more words
5 3 a text
6 3 b short text
Define your labels' order by doing :
to_sort = df.Label.value_counts(ascending = True).index
to_sort
Index(['c', 'b', 'a'], dtype='object')
Then make the Label column Categorical like this :
df.Label = pd.Categorical(df.Label,categories = to_sort, ordered = True)
Finally, sort by ID and Label :
df.sort_values(["ID", "Label"]).reset_index(drop = True)
ID Label Text
0 1 b other text
1 1 a some text
2 1 a data
3 2 c more words
4 2 a words
5 3 b short text
6 3 a text
answered Nov 12 at 15:53
Neroksi
382111
382111
So why you post your answer? OP knowdf.Label.value_counts(ascending = True).index
and.reset_index(drop = True)
is only small difference with my answer :(
– jezrael
Nov 12 at 15:55
I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
– Neroksi
Nov 12 at 16:40
add a comment |
So why you post your answer? OP knowdf.Label.value_counts(ascending = True).index
and.reset_index(drop = True)
is only small difference with my answer :(
– jezrael
Nov 12 at 15:55
I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
– Neroksi
Nov 12 at 16:40
So why you post your answer? OP know
df.Label.value_counts(ascending = True).index
and .reset_index(drop = True)
is only small difference with my answer :(– jezrael
Nov 12 at 15:55
So why you post your answer? OP know
df.Label.value_counts(ascending = True).index
and .reset_index(drop = True)
is only small difference with my answer :(– jezrael
Nov 12 at 15:55
I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
– Neroksi
Nov 12 at 16:40
I wrote mine independently and only saw yours after posting mine. I avoid, however, to delete it because it is more detailed.
– Neroksi
Nov 12 at 16:40
add a comment |
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