printing directories code on UNIX makes error
1
I've been studying UNIX and there's a example code on the book,
but this code seems not working. When I compile the code, returns segmentation error.
#include<dirent.h>
#include<stdlib.h>
#include<stdio.h>
#include<unistd.h>
#include<sys/types.h>
int my_double_ls(const char *name)
struct dirent *d;
DIR *dp;
if ((dp=opendir(name)) == NULL)
return (-1);
while (d=readdir(dp))
if (d->d_ino != 0)
printf("%sn", d->d_name);
rewinddir(dp);
while (d = readdir(dp))
if (d->d_ino != 0)
printf("%sn", d->d_name);
closedir(dp);
return(0);
int main(int argc, char **argv)
my_double_ls(argv[1]);
return(0);
c unix posix command-line-arguments ls
asked Nov 12 at 14:11
JLee
82
add a comment |
1
I've been studying UNIX and there's a example code on the book,
but this code seems not working. When I compile the code, returns segmentation error.
#include<dirent.h>
#include<stdlib.h>
#include<stdio.h>
#include<unistd.h>
#include<sys/types.h>
int my_double_ls(const char *name)
struct dirent *d;
DIR *dp;
if ((dp=opendir(name)) == NULL)
return (-1);
while (d=readdir(dp))
if (d->d_ino != 0)
printf("%sn", d->d_name);
rewinddir(dp);
while (d = readdir(dp))
if (d->d_ino != 0)
printf("%sn", d->d_name);
closedir(dp);
return(0);
int main(int argc, char **argv)
my_double_ls(argv[1]);
return(0);
c unix posix command-line-arguments ls
asked Nov 12 at 14:11
JLee
82
1
Cannot reproduce. Are you sure you told us everything? How do you compile? What is your platform? How do you run the program? Did you try to debug this? Did you run the program from an IDE without specifying and command line?
– Jabberwocky
Nov 12 at 14:23
BTW: unrelated, but don't writereturn(0), just writereturn 0.return(0)is not actually wrong, but is just looks like a function call (which it isn't) and it's unusual.
– Jabberwocky
Nov 12 at 14:28
add a comment |
1
1
1
I've been studying UNIX and there's a example code on the book,
but this code seems not working. When I compile the code, returns segmentation error.
#include<dirent.h>
#include<stdlib.h>
#include<stdio.h>
#include<unistd.h>
#include<sys/types.h>
int my_double_ls(const char *name)
struct dirent *d;
DIR *dp;
if ((dp=opendir(name)) == NULL)
return (-1);
while (d=readdir(dp))
if (d->d_ino != 0)
printf("%sn", d->d_name);
rewinddir(dp);
while (d = readdir(dp))
if (d->d_ino != 0)
printf("%sn", d->d_name);
closedir(dp);
return(0);
int main(int argc, char **argv)
my_double_ls(argv[1]);
return(0);
c unix posix command-line-arguments ls
asked Nov 12 at 14:11
JLee
82
I've been studying UNIX and there's a example code on the book,
but this code seems not working. When I compile the code, returns segmentation error.
#include<dirent.h>
#include<stdlib.h>
#include<stdio.h>
#include<unistd.h>
#include<sys/types.h>
int my_double_ls(const char *name)
struct dirent *d;
DIR *dp;
if ((dp=opendir(name)) == NULL)
return (-1);
while (d=readdir(dp))
if (d->d_ino != 0)
printf("%sn", d->d_name);
rewinddir(dp);
while (d = readdir(dp))
if (d->d_ino != 0)
printf("%sn", d->d_name);
closedir(dp);
return(0);
int main(int argc, char **argv)
my_double_ls(argv[1]);
return(0);
c unix posix command-line-arguments ls
c unix posix command-line-arguments ls
asked Nov 12 at 14:11
JLee
82
asked Nov 12 at 14:11
JLee
82
asked Nov 12 at 14:11
JLee
82
asked Nov 12 at 14:11
JLee
82
asked Nov 12 at 14:11
JLee
82
82
1
Cannot reproduce. Are you sure you told us everything? How do you compile? What is your platform? How do you run the program? Did you try to debug this? Did you run the program from an IDE without specifying and command line?
– Jabberwocky
Nov 12 at 14:23
BTW: unrelated, but don't writereturn(0), just writereturn 0.return(0)is not actually wrong, but is just looks like a function call (which it isn't) and it's unusual.
– Jabberwocky
Nov 12 at 14:28
add a comment |
1
Cannot reproduce. Are you sure you told us everything? How do you compile? What is your platform? How do you run the program? Did you try to debug this? Did you run the program from an IDE without specifying and command line?
– Jabberwocky
Nov 12 at 14:23
BTW: unrelated, but don't writereturn(0), just writereturn 0.return(0)is not actually wrong, but is just looks like a function call (which it isn't) and it's unusual.
– Jabberwocky
Nov 12 at 14:28
1
1
Cannot reproduce. Are you sure you told us everything? How do you compile? What is your platform? How do you run the program? Did you try to debug this? Did you run the program from an IDE without specifying and command line?
– Jabberwocky
Nov 12 at 14:23
Cannot reproduce. Are you sure you told us everything? How do you compile? What is your platform? How do you run the program? Did you try to debug this? Did you run the program from an IDE without specifying and command line?
– Jabberwocky
Nov 12 at 14:23
BTW: unrelated, but don't write
return(0), just write return 0. return(0) is not actually wrong, but is just looks like a function call (which it isn't) and it's unusual.– Jabberwocky
Nov 12 at 14:28
BTW: unrelated, but don't write
return(0), just write return 0. return(0) is not actually wrong, but is just looks like a function call (which it isn't) and it's unusual.– Jabberwocky
Nov 12 at 14:28
add a comment |
1 Answer
1
active
oldest
votes
1
You probably invoked the program without command line arguments:
Try this:
...
int main(int argc, char **argv)
if (argc < 2)
printf("You need to specify the directory.n");
exit(1);
my_double_ls(argv[1]);
return 0;
The my_double_ls function looks more or less correct to me.
answered Nov 12 at 14:25
Jabberwocky
26.5k93769
my bad. I forgot to write directory command line arguments. Thanks anyway :)
– JLee
Nov 12 at 14:30
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You probably invoked the program without command line arguments:
Try this:
...
int main(int argc, char **argv)
if (argc < 2)
printf("You need to specify the directory.n");
exit(1);
my_double_ls(argv[1]);
return 0;
The my_double_ls function looks more or less correct to me.
answered Nov 12 at 14:25
Jabberwocky
26.5k93769
my bad. I forgot to write directory command line arguments. Thanks anyway :)
– JLee
Nov 12 at 14:30
add a comment |
1
You probably invoked the program without command line arguments:
Try this:
...
int main(int argc, char **argv)
if (argc < 2)
printf("You need to specify the directory.n");
exit(1);
my_double_ls(argv[1]);
return 0;
The my_double_ls function looks more or less correct to me.
answered Nov 12 at 14:25
Jabberwocky
26.5k93769
my bad. I forgot to write directory command line arguments. Thanks anyway :)
– JLee
Nov 12 at 14:30
add a comment |
1
1
1
You probably invoked the program without command line arguments:
Try this:
...
int main(int argc, char **argv)
if (argc < 2)
printf("You need to specify the directory.n");
exit(1);
my_double_ls(argv[1]);
return 0;
The my_double_ls function looks more or less correct to me.
answered Nov 12 at 14:25
Jabberwocky
26.5k93769
You probably invoked the program without command line arguments:
Try this:
...
int main(int argc, char **argv)
if (argc < 2)
printf("You need to specify the directory.n");
exit(1);
my_double_ls(argv[1]);
return 0;
The my_double_ls function looks more or less correct to me.
answered Nov 12 at 14:25
Jabberwocky
26.5k93769
edited Nov 12 at 14:34
answered Nov 12 at 14:25
Jabberwocky
26.5k93769
answered Nov 12 at 14:25
Jabberwocky
26.5k93769
answered Nov 12 at 14:25
Jabberwocky
26.5k93769
26.5k93769
my bad. I forgot to write directory command line arguments. Thanks anyway :)
– JLee
Nov 12 at 14:30
add a comment |
my bad. I forgot to write directory command line arguments. Thanks anyway :)
– JLee
Nov 12 at 14:30
my bad. I forgot to write directory command line arguments. Thanks anyway :)
– JLee
Nov 12 at 14:30
my bad. I forgot to write directory command line arguments. Thanks anyway :)
– JLee
Nov 12 at 14:30
add a comment |
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1
Cannot reproduce. Are you sure you told us everything? How do you compile? What is your platform? How do you run the program? Did you try to debug this? Did you run the program from an IDE without specifying and command line?
– Jabberwocky
Nov 12 at 14:23
BTW: unrelated, but don't write
return(0), just writereturn 0.return(0)is not actually wrong, but is just looks like a function call (which it isn't) and it's unusual.– Jabberwocky
Nov 12 at 14:28