Es6: Create an array of objects from a json










0














I have a json in the below format.



 [
"id": 1,
"name": "peter" ,
"id": 2,
"name": "john" ,
"id": 3,
"name": "justin"
.
.
"id": 500,
"name": "david" ,
]


I am trying to create an array in batches of 10 in the below format



[

"id": 1,
"name": "peter" ,
.
.
"id": 10,
"name": "nixon" ,
,


"id": 11,
"name": "nancy" ,
.
.
"id": 20,
"name": "underwood" ,

.
.
]


I tried using reduce and tried for loop to loop through it, but was unsuccessful










share|improve this question

















  • 1




    Possible duplicate of Splitting a JS array into N arrays
    – k0pernikus
    Nov 12 at 14:21










  • stackoverflow.com/q/8495687/457268
    – k0pernikus
    Nov 12 at 14:23










  • Objects should have key value pairs. You cannot put another object inside without a key.
    – Dinesh Pandiyan
    Nov 13 at 13:59















0














I have a json in the below format.



 [
"id": 1,
"name": "peter" ,
"id": 2,
"name": "john" ,
"id": 3,
"name": "justin"
.
.
"id": 500,
"name": "david" ,
]


I am trying to create an array in batches of 10 in the below format



[

"id": 1,
"name": "peter" ,
.
.
"id": 10,
"name": "nixon" ,
,


"id": 11,
"name": "nancy" ,
.
.
"id": 20,
"name": "underwood" ,

.
.
]


I tried using reduce and tried for loop to loop through it, but was unsuccessful










share|improve this question

















  • 1




    Possible duplicate of Splitting a JS array into N arrays
    – k0pernikus
    Nov 12 at 14:21










  • stackoverflow.com/q/8495687/457268
    – k0pernikus
    Nov 12 at 14:23










  • Objects should have key value pairs. You cannot put another object inside without a key.
    – Dinesh Pandiyan
    Nov 13 at 13:59













0












0








0







I have a json in the below format.



 [
"id": 1,
"name": "peter" ,
"id": 2,
"name": "john" ,
"id": 3,
"name": "justin"
.
.
"id": 500,
"name": "david" ,
]


I am trying to create an array in batches of 10 in the below format



[

"id": 1,
"name": "peter" ,
.
.
"id": 10,
"name": "nixon" ,
,


"id": 11,
"name": "nancy" ,
.
.
"id": 20,
"name": "underwood" ,

.
.
]


I tried using reduce and tried for loop to loop through it, but was unsuccessful










share|improve this question













I have a json in the below format.



 [
"id": 1,
"name": "peter" ,
"id": 2,
"name": "john" ,
"id": 3,
"name": "justin"
.
.
"id": 500,
"name": "david" ,
]


I am trying to create an array in batches of 10 in the below format



[

"id": 1,
"name": "peter" ,
.
.
"id": 10,
"name": "nixon" ,
,


"id": 11,
"name": "nancy" ,
.
.
"id": 20,
"name": "underwood" ,

.
.
]


I tried using reduce and tried for loop to loop through it, but was unsuccessful







ecmascript-6






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 12 at 14:13









indra257

150428




150428







  • 1




    Possible duplicate of Splitting a JS array into N arrays
    – k0pernikus
    Nov 12 at 14:21










  • stackoverflow.com/q/8495687/457268
    – k0pernikus
    Nov 12 at 14:23










  • Objects should have key value pairs. You cannot put another object inside without a key.
    – Dinesh Pandiyan
    Nov 13 at 13:59












  • 1




    Possible duplicate of Splitting a JS array into N arrays
    – k0pernikus
    Nov 12 at 14:21










  • stackoverflow.com/q/8495687/457268
    – k0pernikus
    Nov 12 at 14:23










  • Objects should have key value pairs. You cannot put another object inside without a key.
    – Dinesh Pandiyan
    Nov 13 at 13:59







1




1




Possible duplicate of Splitting a JS array into N arrays
– k0pernikus
Nov 12 at 14:21




Possible duplicate of Splitting a JS array into N arrays
– k0pernikus
Nov 12 at 14:21












stackoverflow.com/q/8495687/457268
– k0pernikus
Nov 12 at 14:23




stackoverflow.com/q/8495687/457268
– k0pernikus
Nov 12 at 14:23












Objects should have key value pairs. You cannot put another object inside without a key.
– Dinesh Pandiyan
Nov 13 at 13:59




Objects should have key value pairs. You cannot put another object inside without a key.
– Dinesh Pandiyan
Nov 13 at 13:59












1 Answer
1






active

oldest

votes


















0














Here's a demo.






const str = "abcdefghigklmnopqrstuvwxyz";
let data = ;
for(let i = 0; i < 26; i++)
data.push(id : i, name: str.charAt(i));


let res = data.reduce((acc, d) =>
let groupId = Math.floor(d.id / 10);
acc[groupId] = acc[groupId] , );
console.log(Object.values(res));







If you can ensure that id is the same sequence as their position in array, i think simply slice will better.






share|improve this answer




















    Your Answer






    StackExchange.ifUsing("editor", function ()
    StackExchange.using("externalEditor", function ()
    StackExchange.using("snippets", function ()
    StackExchange.snippets.init();
    );
    );
    , "code-snippets");

    StackExchange.ready(function()
    var channelOptions =
    tags: "".split(" "),
    id: "1"
    ;
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function()
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled)
    StackExchange.using("snippets", function()
    createEditor();
    );

    else
    createEditor();

    );

    function createEditor()
    StackExchange.prepareEditor(
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader:
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    ,
    onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    );



    );













    draft saved

    draft discarded


















    StackExchange.ready(
    function ()
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53263983%2fes6-create-an-array-of-objects-from-a-json%23new-answer', 'question_page');

    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    Here's a demo.






    const str = "abcdefghigklmnopqrstuvwxyz";
    let data = ;
    for(let i = 0; i < 26; i++)
    data.push(id : i, name: str.charAt(i));


    let res = data.reduce((acc, d) =>
    let groupId = Math.floor(d.id / 10);
    acc[groupId] = acc[groupId] , );
    console.log(Object.values(res));







    If you can ensure that id is the same sequence as their position in array, i think simply slice will better.






    share|improve this answer

























      0














      Here's a demo.






      const str = "abcdefghigklmnopqrstuvwxyz";
      let data = ;
      for(let i = 0; i < 26; i++)
      data.push(id : i, name: str.charAt(i));


      let res = data.reduce((acc, d) =>
      let groupId = Math.floor(d.id / 10);
      acc[groupId] = acc[groupId] , );
      console.log(Object.values(res));







      If you can ensure that id is the same sequence as their position in array, i think simply slice will better.






      share|improve this answer























        0












        0








        0






        Here's a demo.






        const str = "abcdefghigklmnopqrstuvwxyz";
        let data = ;
        for(let i = 0; i < 26; i++)
        data.push(id : i, name: str.charAt(i));


        let res = data.reduce((acc, d) =>
        let groupId = Math.floor(d.id / 10);
        acc[groupId] = acc[groupId] , );
        console.log(Object.values(res));







        If you can ensure that id is the same sequence as their position in array, i think simply slice will better.






        share|improve this answer












        Here's a demo.






        const str = "abcdefghigklmnopqrstuvwxyz";
        let data = ;
        for(let i = 0; i < 26; i++)
        data.push(id : i, name: str.charAt(i));


        let res = data.reduce((acc, d) =>
        let groupId = Math.floor(d.id / 10);
        acc[groupId] = acc[groupId] , );
        console.log(Object.values(res));







        If you can ensure that id is the same sequence as their position in array, i think simply slice will better.






        const str = "abcdefghigklmnopqrstuvwxyz";
        let data = ;
        for(let i = 0; i < 26; i++)
        data.push(id : i, name: str.charAt(i));


        let res = data.reduce((acc, d) =>
        let groupId = Math.floor(d.id / 10);
        acc[groupId] = acc[groupId] , );
        console.log(Object.values(res));





        const str = "abcdefghigklmnopqrstuvwxyz";
        let data = ;
        for(let i = 0; i < 26; i++)
        data.push(id : i, name: str.charAt(i));


        let res = data.reduce((acc, d) =>
        let groupId = Math.floor(d.id / 10);
        acc[groupId] = acc[groupId] , );
        console.log(Object.values(res));






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 13 at 13:51









        user8510613

        938




        938



























            draft saved

            draft discarded
















































            Thanks for contributing an answer to Stack Overflow!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.





            Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


            Please pay close attention to the following guidance:


            • Please be sure to answer the question. Provide details and share your research!

            But avoid


            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.

            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function ()
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53263983%2fes6-create-an-array-of-objects-from-a-json%23new-answer', 'question_page');

            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            這個網誌中的熱門文章

            How to read a connectionString WITH PROVIDER in .NET Core?

            Museum of Modern and Contemporary Art of Trento and Rovereto

            In R, how to develop a multiplot heatmap.2 figure showing key labels successfully