Remove certain characters from write-host output in Powershell (Get-ADuser)
I'm comparing users between two domains to make sure users that are disabled in one, are disabled in the other, using these two steps:
Domain 1:
Get-ADUser -SearchBase "OU=ou2,OU=ou1,DC=pre,DC=domain1,DC=com" -Filter * -Properties * | Select-Object Name | Export-Csv -encoding "utf8" Users.csv
Domain 2:
$input = import-csv -path "Users.csv"
ForEach ($User in $input)
$result = get-aduser -SearchBase "OU=ou2,OU=ou1,DC=pre,DC=domain2,DC=com" -Filter "name -eq '$($User.Name)'"
This works, but gives me the following output:
Name Enabled
---- -------
Firstname1 Lastname1 True
@Name=Firstname2 Lastname2 - Name not found. Please do a manual check
How do I remove "@Name=" and ""?
I have tried adding -ExtendProperity to $result, and Replace with no luck. I'm probably doing it wrong..
powershell compare
add a comment |
I'm comparing users between two domains to make sure users that are disabled in one, are disabled in the other, using these two steps:
Domain 1:
Get-ADUser -SearchBase "OU=ou2,OU=ou1,DC=pre,DC=domain1,DC=com" -Filter * -Properties * | Select-Object Name | Export-Csv -encoding "utf8" Users.csv
Domain 2:
$input = import-csv -path "Users.csv"
ForEach ($User in $input)
$result = get-aduser -SearchBase "OU=ou2,OU=ou1,DC=pre,DC=domain2,DC=com" -Filter "name -eq '$($User.Name)'"
This works, but gives me the following output:
Name Enabled
---- -------
Firstname1 Lastname1 True
@Name=Firstname2 Lastname2 - Name not found. Please do a manual check
How do I remove "@Name=" and ""?
I have tried adding -ExtendProperity to $result, and Replace with no luck. I'm probably doing it wrong..
powershell compare
@Name=Firstname2 Lastname2 is an array and not a string value.
– TobyU
Nov 12 at 14:24
1
@TobyU: It is the string representation of a custom object, not of an array.
– mklement0
Nov 12 at 14:32
1
Also, don't do-Properties *
if all you are after are theName
andEnabled
properties. These two properties are returned by default, as areDistinguishedName, GivenName, ObjectClass, ObjectGUID, SamAccountName, SID, Surname, UserPrincipalName
, so you can skip the-Properties *
alltogether.
– Theo
Nov 12 at 14:35
add a comment |
I'm comparing users between two domains to make sure users that are disabled in one, are disabled in the other, using these two steps:
Domain 1:
Get-ADUser -SearchBase "OU=ou2,OU=ou1,DC=pre,DC=domain1,DC=com" -Filter * -Properties * | Select-Object Name | Export-Csv -encoding "utf8" Users.csv
Domain 2:
$input = import-csv -path "Users.csv"
ForEach ($User in $input)
$result = get-aduser -SearchBase "OU=ou2,OU=ou1,DC=pre,DC=domain2,DC=com" -Filter "name -eq '$($User.Name)'"
This works, but gives me the following output:
Name Enabled
---- -------
Firstname1 Lastname1 True
@Name=Firstname2 Lastname2 - Name not found. Please do a manual check
How do I remove "@Name=" and ""?
I have tried adding -ExtendProperity to $result, and Replace with no luck. I'm probably doing it wrong..
powershell compare
I'm comparing users between two domains to make sure users that are disabled in one, are disabled in the other, using these two steps:
Domain 1:
Get-ADUser -SearchBase "OU=ou2,OU=ou1,DC=pre,DC=domain1,DC=com" -Filter * -Properties * | Select-Object Name | Export-Csv -encoding "utf8" Users.csv
Domain 2:
$input = import-csv -path "Users.csv"
ForEach ($User in $input)
$result = get-aduser -SearchBase "OU=ou2,OU=ou1,DC=pre,DC=domain2,DC=com" -Filter "name -eq '$($User.Name)'"
This works, but gives me the following output:
Name Enabled
---- -------
Firstname1 Lastname1 True
@Name=Firstname2 Lastname2 - Name not found. Please do a manual check
How do I remove "@Name=" and ""?
I have tried adding -ExtendProperity to $result, and Replace with no luck. I'm probably doing it wrong..
powershell compare
powershell compare
asked Nov 12 at 14:20
Erik M.
365
365
@Name=Firstname2 Lastname2 is an array and not a string value.
– TobyU
Nov 12 at 14:24
1
@TobyU: It is the string representation of a custom object, not of an array.
– mklement0
Nov 12 at 14:32
1
Also, don't do-Properties *
if all you are after are theName
andEnabled
properties. These two properties are returned by default, as areDistinguishedName, GivenName, ObjectClass, ObjectGUID, SamAccountName, SID, Surname, UserPrincipalName
, so you can skip the-Properties *
alltogether.
– Theo
Nov 12 at 14:35
add a comment |
@Name=Firstname2 Lastname2 is an array and not a string value.
– TobyU
Nov 12 at 14:24
1
@TobyU: It is the string representation of a custom object, not of an array.
– mklement0
Nov 12 at 14:32
1
Also, don't do-Properties *
if all you are after are theName
andEnabled
properties. These two properties are returned by default, as areDistinguishedName, GivenName, ObjectClass, ObjectGUID, SamAccountName, SID, Surname, UserPrincipalName
, so you can skip the-Properties *
alltogether.
– Theo
Nov 12 at 14:35
@Name=Firstname2 Lastname2 is an array and not a string value.
– TobyU
Nov 12 at 14:24
@Name=Firstname2 Lastname2 is an array and not a string value.
– TobyU
Nov 12 at 14:24
1
1
@TobyU: It is the string representation of a custom object, not of an array.
– mklement0
Nov 12 at 14:32
@TobyU: It is the string representation of a custom object, not of an array.
– mklement0
Nov 12 at 14:32
1
1
Also, don't do
-Properties *
if all you are after are the Name
and Enabled
properties. These two properties are returned by default, as are DistinguishedName, GivenName, ObjectClass, ObjectGUID, SamAccountName, SID, Surname, UserPrincipalName
, so you can skip the -Properties *
alltogether.– Theo
Nov 12 at 14:35
Also, don't do
-Properties *
if all you are after are the Name
and Enabled
properties. These two properties are returned by default, as are DistinguishedName, GivenName, ObjectClass, ObjectGUID, SamAccountName, SID, Surname, UserPrincipalName
, so you can skip the -Properties *
alltogether.– Theo
Nov 12 at 14:35
add a comment |
1 Answer
1
active
oldest
votes
$User
is a custom object (type [pscustomobject]
, as output by Import-Csv
), and @Name=Firstname2 Lastname2
is its stringified representation[1], because Write-Host
stringifies its arguments for display.
Access the .Name
property instead to get just the name:
Write-host -ForegroundColor Yellow $User.Name "- Name not found. Please do a manual check"
More idiomatically, using a single expandable string (string interpolation inside "..."
):
Write-host -ForegroundColor Yellow "$($User.Name) - Name not found. Please do a manual check"
If you want to include the full object representation as it would appear if you printed it directly to the console, you need Out-String
, but note that you'll end up with multi-line output:
Write-host -ForegroundColor Yellow "$($User | Out-String) - Name not found. Please do a manual check"
[1] You can verify this as follows: $user = [pscustomobject] @ Name = 'Firstname1 LastName1' ; "$user"
. The output is string @Name=Firstname1 LastName1
.
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$User
is a custom object (type [pscustomobject]
, as output by Import-Csv
), and @Name=Firstname2 Lastname2
is its stringified representation[1], because Write-Host
stringifies its arguments for display.
Access the .Name
property instead to get just the name:
Write-host -ForegroundColor Yellow $User.Name "- Name not found. Please do a manual check"
More idiomatically, using a single expandable string (string interpolation inside "..."
):
Write-host -ForegroundColor Yellow "$($User.Name) - Name not found. Please do a manual check"
If you want to include the full object representation as it would appear if you printed it directly to the console, you need Out-String
, but note that you'll end up with multi-line output:
Write-host -ForegroundColor Yellow "$($User | Out-String) - Name not found. Please do a manual check"
[1] You can verify this as follows: $user = [pscustomobject] @ Name = 'Firstname1 LastName1' ; "$user"
. The output is string @Name=Firstname1 LastName1
.
add a comment |
$User
is a custom object (type [pscustomobject]
, as output by Import-Csv
), and @Name=Firstname2 Lastname2
is its stringified representation[1], because Write-Host
stringifies its arguments for display.
Access the .Name
property instead to get just the name:
Write-host -ForegroundColor Yellow $User.Name "- Name not found. Please do a manual check"
More idiomatically, using a single expandable string (string interpolation inside "..."
):
Write-host -ForegroundColor Yellow "$($User.Name) - Name not found. Please do a manual check"
If you want to include the full object representation as it would appear if you printed it directly to the console, you need Out-String
, but note that you'll end up with multi-line output:
Write-host -ForegroundColor Yellow "$($User | Out-String) - Name not found. Please do a manual check"
[1] You can verify this as follows: $user = [pscustomobject] @ Name = 'Firstname1 LastName1' ; "$user"
. The output is string @Name=Firstname1 LastName1
.
add a comment |
$User
is a custom object (type [pscustomobject]
, as output by Import-Csv
), and @Name=Firstname2 Lastname2
is its stringified representation[1], because Write-Host
stringifies its arguments for display.
Access the .Name
property instead to get just the name:
Write-host -ForegroundColor Yellow $User.Name "- Name not found. Please do a manual check"
More idiomatically, using a single expandable string (string interpolation inside "..."
):
Write-host -ForegroundColor Yellow "$($User.Name) - Name not found. Please do a manual check"
If you want to include the full object representation as it would appear if you printed it directly to the console, you need Out-String
, but note that you'll end up with multi-line output:
Write-host -ForegroundColor Yellow "$($User | Out-String) - Name not found. Please do a manual check"
[1] You can verify this as follows: $user = [pscustomobject] @ Name = 'Firstname1 LastName1' ; "$user"
. The output is string @Name=Firstname1 LastName1
.
$User
is a custom object (type [pscustomobject]
, as output by Import-Csv
), and @Name=Firstname2 Lastname2
is its stringified representation[1], because Write-Host
stringifies its arguments for display.
Access the .Name
property instead to get just the name:
Write-host -ForegroundColor Yellow $User.Name "- Name not found. Please do a manual check"
More idiomatically, using a single expandable string (string interpolation inside "..."
):
Write-host -ForegroundColor Yellow "$($User.Name) - Name not found. Please do a manual check"
If you want to include the full object representation as it would appear if you printed it directly to the console, you need Out-String
, but note that you'll end up with multi-line output:
Write-host -ForegroundColor Yellow "$($User | Out-String) - Name not found. Please do a manual check"
[1] You can verify this as follows: $user = [pscustomobject] @ Name = 'Firstname1 LastName1' ; "$user"
. The output is string @Name=Firstname1 LastName1
.
edited Nov 12 at 14:35
answered Nov 12 at 14:27
mklement0
126k20239267
126k20239267
add a comment |
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@Name=Firstname2 Lastname2 is an array and not a string value.
– TobyU
Nov 12 at 14:24
1
@TobyU: It is the string representation of a custom object, not of an array.
– mklement0
Nov 12 at 14:32
1
Also, don't do
-Properties *
if all you are after are theName
andEnabled
properties. These two properties are returned by default, as areDistinguishedName, GivenName, ObjectClass, ObjectGUID, SamAccountName, SID, Surname, UserPrincipalName
, so you can skip the-Properties *
alltogether.– Theo
Nov 12 at 14:35