execute Thread.interrupt() Object.notify() at the same time, why does has two results?
up vote
2
down vote
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public class WaitNotifyAll
private static volatile Object resourceA = new Object();
public static void main(String args) throws Exception
Thread threadA = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
try
System.out.println("threadA begin wait");
resourceA.wait();
System.out.println("threadA end wait");
catch (InterruptedException e)
e.printStackTrace();
);
Thread threaB = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
System.out.println("threadC begin notify");
threadA.interrupt();
resourceA.notify();
);
threadA.start();
Thread.sleep(1000);
threaB.start();
System.out.println("main over");
There are two possible result here:
throws InterruptedException
normal termination
why?
I don't understand. when threadA is interruptted ,result should throws InterruptedException. but sometimes execute this program, it can normal finish.
environment: java8, mac
java concurrency interrupt notify
add a comment |
up vote
2
down vote
favorite
public class WaitNotifyAll
private static volatile Object resourceA = new Object();
public static void main(String args) throws Exception
Thread threadA = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
try
System.out.println("threadA begin wait");
resourceA.wait();
System.out.println("threadA end wait");
catch (InterruptedException e)
e.printStackTrace();
);
Thread threaB = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
System.out.println("threadC begin notify");
threadA.interrupt();
resourceA.notify();
);
threadA.start();
Thread.sleep(1000);
threaB.start();
System.out.println("main over");
There are two possible result here:
throws InterruptedException
normal termination
why?
I don't understand. when threadA is interruptted ,result should throws InterruptedException. but sometimes execute this program, it can normal finish.
environment: java8, mac
java concurrency interrupt notify
add a comment |
up vote
2
down vote
favorite
up vote
2
down vote
favorite
public class WaitNotifyAll
private static volatile Object resourceA = new Object();
public static void main(String args) throws Exception
Thread threadA = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
try
System.out.println("threadA begin wait");
resourceA.wait();
System.out.println("threadA end wait");
catch (InterruptedException e)
e.printStackTrace();
);
Thread threaB = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
System.out.println("threadC begin notify");
threadA.interrupt();
resourceA.notify();
);
threadA.start();
Thread.sleep(1000);
threaB.start();
System.out.println("main over");
There are two possible result here:
throws InterruptedException
normal termination
why?
I don't understand. when threadA is interruptted ,result should throws InterruptedException. but sometimes execute this program, it can normal finish.
environment: java8, mac
java concurrency interrupt notify
public class WaitNotifyAll
private static volatile Object resourceA = new Object();
public static void main(String args) throws Exception
Thread threadA = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
try
System.out.println("threadA begin wait");
resourceA.wait();
System.out.println("threadA end wait");
catch (InterruptedException e)
e.printStackTrace();
);
Thread threaB = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
System.out.println("threadC begin notify");
threadA.interrupt();
resourceA.notify();
);
threadA.start();
Thread.sleep(1000);
threaB.start();
System.out.println("main over");
There are two possible result here:
throws InterruptedException
normal termination
why?
I don't understand. when threadA is interruptted ,result should throws InterruptedException. but sometimes execute this program, it can normal finish.
environment: java8, mac
java concurrency interrupt notify
java concurrency interrupt notify
edited Nov 11 at 15:23
JB Nizet
531k51855990
531k51855990
asked Nov 11 at 15:22
zhenyu wu
212
212
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
up vote
0
down vote
Because of reordering. In normal termination compiler reordered instruction interrupt and notify, interruption invokes on working thread and no interrupted exception throws.
Try to forbid reordering with reading volatile variable and you always get interrupted exception.
public class WaitNotifyAll
private static volatile Object resourceA = new Object();
public static void main(String args) throws Exception
Thread threadA = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
try
System.out.println("threadA begin wait");
resourceA.wait();
System.out.println("threadA end wait");
catch (InterruptedException e)
e.printStackTrace();
);
Thread threaB = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
System.out.println("threadC begin notify");
threadA.interrupt();
System.out.print(resourceA);
resourceA.notify();
);
threadA.start();
Thread.sleep(1000);
threaB.start();
System.out.println("main over");
New contributor
add a comment |
up vote
0
down vote
When a thread receives both an interrupt and a notify, the behaviour may vary.
Please refer to https://docs.oracle.com/javase/specs/jls/se7/html/jls-17.html#jls-17.2.3
Credit - Alex Otenko on the Concurrency Interest mailing list
add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Because of reordering. In normal termination compiler reordered instruction interrupt and notify, interruption invokes on working thread and no interrupted exception throws.
Try to forbid reordering with reading volatile variable and you always get interrupted exception.
public class WaitNotifyAll
private static volatile Object resourceA = new Object();
public static void main(String args) throws Exception
Thread threadA = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
try
System.out.println("threadA begin wait");
resourceA.wait();
System.out.println("threadA end wait");
catch (InterruptedException e)
e.printStackTrace();
);
Thread threaB = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
System.out.println("threadC begin notify");
threadA.interrupt();
System.out.print(resourceA);
resourceA.notify();
);
threadA.start();
Thread.sleep(1000);
threaB.start();
System.out.println("main over");
New contributor
add a comment |
up vote
0
down vote
Because of reordering. In normal termination compiler reordered instruction interrupt and notify, interruption invokes on working thread and no interrupted exception throws.
Try to forbid reordering with reading volatile variable and you always get interrupted exception.
public class WaitNotifyAll
private static volatile Object resourceA = new Object();
public static void main(String args) throws Exception
Thread threadA = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
try
System.out.println("threadA begin wait");
resourceA.wait();
System.out.println("threadA end wait");
catch (InterruptedException e)
e.printStackTrace();
);
Thread threaB = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
System.out.println("threadC begin notify");
threadA.interrupt();
System.out.print(resourceA);
resourceA.notify();
);
threadA.start();
Thread.sleep(1000);
threaB.start();
System.out.println("main over");
New contributor
add a comment |
up vote
0
down vote
up vote
0
down vote
Because of reordering. In normal termination compiler reordered instruction interrupt and notify, interruption invokes on working thread and no interrupted exception throws.
Try to forbid reordering with reading volatile variable and you always get interrupted exception.
public class WaitNotifyAll
private static volatile Object resourceA = new Object();
public static void main(String args) throws Exception
Thread threadA = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
try
System.out.println("threadA begin wait");
resourceA.wait();
System.out.println("threadA end wait");
catch (InterruptedException e)
e.printStackTrace();
);
Thread threaB = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
System.out.println("threadC begin notify");
threadA.interrupt();
System.out.print(resourceA);
resourceA.notify();
);
threadA.start();
Thread.sleep(1000);
threaB.start();
System.out.println("main over");
New contributor
Because of reordering. In normal termination compiler reordered instruction interrupt and notify, interruption invokes on working thread and no interrupted exception throws.
Try to forbid reordering with reading volatile variable and you always get interrupted exception.
public class WaitNotifyAll
private static volatile Object resourceA = new Object();
public static void main(String args) throws Exception
Thread threadA = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
try
System.out.println("threadA begin wait");
resourceA.wait();
System.out.println("threadA end wait");
catch (InterruptedException e)
e.printStackTrace();
);
Thread threaB = new Thread(new Runnable()
@Override
public void run()
synchronized (resourceA)
System.out.println("threadC begin notify");
threadA.interrupt();
System.out.print(resourceA);
resourceA.notify();
);
threadA.start();
Thread.sleep(1000);
threaB.start();
System.out.println("main over");
New contributor
edited Dec 3 at 12:27
New contributor
answered Dec 3 at 11:22
eSerpentine
11
11
New contributor
New contributor
add a comment |
add a comment |
up vote
0
down vote
When a thread receives both an interrupt and a notify, the behaviour may vary.
Please refer to https://docs.oracle.com/javase/specs/jls/se7/html/jls-17.html#jls-17.2.3
Credit - Alex Otenko on the Concurrency Interest mailing list
add a comment |
up vote
0
down vote
When a thread receives both an interrupt and a notify, the behaviour may vary.
Please refer to https://docs.oracle.com/javase/specs/jls/se7/html/jls-17.html#jls-17.2.3
Credit - Alex Otenko on the Concurrency Interest mailing list
add a comment |
up vote
0
down vote
up vote
0
down vote
When a thread receives both an interrupt and a notify, the behaviour may vary.
Please refer to https://docs.oracle.com/javase/specs/jls/se7/html/jls-17.html#jls-17.2.3
Credit - Alex Otenko on the Concurrency Interest mailing list
When a thread receives both an interrupt and a notify, the behaviour may vary.
Please refer to https://docs.oracle.com/javase/specs/jls/se7/html/jls-17.html#jls-17.2.3
Credit - Alex Otenko on the Concurrency Interest mailing list
answered Dec 4 at 4:11
Ashutosh A
63137
63137
add a comment |
add a comment |
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