Routh stability calculator algorithm in javascript

up vote
1
down vote

favorite

Im trying to write algorithm for routh stability criterion, I load inputs into array then I try to calculate other values with algorithm. But Im struggling with that algorithm

this is what I have right now:

function parse() 
 var str = document.getElementById("input").value;

 var n = str.split(/[-+]/).length;
 console.log(n);

 var x = ;
 x = str.split(/[-+]/);

 var a = ;
 for (var i = 0; i <= n - 1; i++) 
 if (x[i].charAt(0) == "s") 
 a[i] = 1;
 else 
 a[i] = Number(x[i].charAt(0));
 
 

 i = 0;

 console.log(a[0]);
 console.log(a[1]);
 console.log(a[2]);
 console.log(a[3]);

 var k = ;

 k[0] = a[0] / a[1];

 var b = ;

 for (i; i < n - 2; i++) 

 b[i] = a[i + 2] - (k[i] * a[i + 3]); // a[i+3] is undefined 
 k[i + 1] = a[i + 1] / b[i];

 console.log(b[0]);
 console.log(b[1]);
 console.log(k[0]);
 console.log(k[1]);

<input type="text" name="input" id="input">
<button onclick="parse()">calculate</button>

Values in blue I have and values in red I need, I dont know how to define when there is no more values in array to calculate next line.

routh criterion

edited Nov 11 at 15:22

Ele

22.5k42044

asked Nov 11 at 15:21

Thomas231

my input looks like this: s^3+4s^2+4s+8
– Thomas231
Nov 11 at 15:23

add a comment |

up vote
1
down vote

favorite

Im trying to write algorithm for routh stability criterion, I load inputs into array then I try to calculate other values with algorithm. But Im struggling with that algorithm

this is what I have right now:

function parse() 
 var str = document.getElementById("input").value;

 var n = str.split(/[-+]/).length;
 console.log(n);

 var x = ;
 x = str.split(/[-+]/);

 var a = ;
 for (var i = 0; i <= n - 1; i++) 
 if (x[i].charAt(0) == "s") 
 a[i] = 1;
 else 
 a[i] = Number(x[i].charAt(0));
 
 

 i = 0;

 console.log(a[0]);
 console.log(a[1]);
 console.log(a[2]);
 console.log(a[3]);

 var k = ;

 k[0] = a[0] / a[1];

 var b = ;

 for (i; i < n - 2; i++) 

 b[i] = a[i + 2] - (k[i] * a[i + 3]); // a[i+3] is undefined 
 k[i + 1] = a[i + 1] / b[i];

 console.log(b[0]);
 console.log(b[1]);
 console.log(k[0]);
 console.log(k[1]);

<input type="text" name="input" id="input">
<button onclick="parse()">calculate</button>

Values in blue I have and values in red I need, I dont know how to define when there is no more values in array to calculate next line.

routh criterion

edited Nov 11 at 15:22

Ele

22.5k42044

asked Nov 11 at 15:21

Thomas231

my input looks like this: s^3+4s^2+4s+8
– Thomas231
Nov 11 at 15:23

add a comment |

up vote
1
down vote

favorite

Im trying to write algorithm for routh stability criterion, I load inputs into array then I try to calculate other values with algorithm. But Im struggling with that algorithm

this is what I have right now:

function parse() 
 var str = document.getElementById("input").value;

 var n = str.split(/[-+]/).length;
 console.log(n);

 var x = ;
 x = str.split(/[-+]/);

 var a = ;
 for (var i = 0; i <= n - 1; i++) 
 if (x[i].charAt(0) == "s") 
 a[i] = 1;
 else 
 a[i] = Number(x[i].charAt(0));
 
 

 i = 0;

 console.log(a[0]);
 console.log(a[1]);
 console.log(a[2]);
 console.log(a[3]);

 var k = ;

 k[0] = a[0] / a[1];

 var b = ;

 for (i; i < n - 2; i++) 

 b[i] = a[i + 2] - (k[i] * a[i + 3]); // a[i+3] is undefined 
 k[i + 1] = a[i + 1] / b[i];

 console.log(b[0]);
 console.log(b[1]);
 console.log(k[0]);
 console.log(k[1]);

<input type="text" name="input" id="input">
<button onclick="parse()">calculate</button>

Values in blue I have and values in red I need, I dont know how to define when there is no more values in array to calculate next line.

routh criterion

edited Nov 11 at 15:22

Ele

22.5k42044

asked Nov 11 at 15:21

Thomas231

Im trying to write algorithm for routh stability criterion, I load inputs into array then I try to calculate other values with algorithm. But Im struggling with that algorithm

this is what I have right now:

function parse() 
 var str = document.getElementById("input").value;

 var n = str.split(/[-+]/).length;
 console.log(n);

 var x = ;
 x = str.split(/[-+]/);

 var a = ;
 for (var i = 0; i <= n - 1; i++) 
 if (x[i].charAt(0) == "s") 
 a[i] = 1;
 else 
 a[i] = Number(x[i].charAt(0));
 
 

 i = 0;

 console.log(a[0]);
 console.log(a[1]);
 console.log(a[2]);
 console.log(a[3]);

 var k = ;

 k[0] = a[0] / a[1];

 var b = ;

 for (i; i < n - 2; i++) 

 b[i] = a[i + 2] - (k[i] * a[i + 3]); // a[i+3] is undefined 
 k[i + 1] = a[i + 1] / b[i];

 console.log(b[0]);
 console.log(b[1]);
 console.log(k[0]);
 console.log(k[1]);

<input type="text" name="input" id="input">
<button onclick="parse()">calculate</button>

Values in blue I have and values in red I need, I dont know how to define when there is no more values in array to calculate next line.

routh criterion

function parse() 
 var str = document.getElementById("input").value;

 var n = str.split(/[-+]/).length;
 console.log(n);

 var x = ;
 x = str.split(/[-+]/);

 var a = ;
 for (var i = 0; i <= n - 1; i++) 
 if (x[i].charAt(0) == "s") 
 a[i] = 1;
 else 
 a[i] = Number(x[i].charAt(0));
 
 

 i = 0;

 console.log(a[0]);
 console.log(a[1]);
 console.log(a[2]);
 console.log(a[3]);

 var k = ;

 k[0] = a[0] / a[1];

 var b = ;

 for (i; i < n - 2; i++) 

 b[i] = a[i + 2] - (k[i] * a[i + 3]); // a[i+3] is undefined 
 k[i + 1] = a[i + 1] / b[i];

 console.log(b[0]);
 console.log(b[1]);
 console.log(k[0]);
 console.log(k[1]);

<input type="text" name="input" id="input">
<button onclick="parse()">calculate</button>

function parse() 
 var str = document.getElementById("input").value;

 var n = str.split(/[-+]/).length;
 console.log(n);

 var x = ;
 x = str.split(/[-+]/);

 var a = ;
 for (var i = 0; i <= n - 1; i++) 
 if (x[i].charAt(0) == "s") 
 a[i] = 1;
 else 
 a[i] = Number(x[i].charAt(0));
 
 

 i = 0;

 console.log(a[0]);
 console.log(a[1]);
 console.log(a[2]);
 console.log(a[3]);

 var k = ;

 k[0] = a[0] / a[1];

 var b = ;

 for (i; i < n - 2; i++) 

 b[i] = a[i + 2] - (k[i] * a[i + 3]); // a[i+3] is undefined 
 k[i + 1] = a[i + 1] / b[i];

 console.log(b[0]);
 console.log(b[1]);
 console.log(k[0]);
 console.log(k[1]);

<input type="text" name="input" id="input">
<button onclick="parse()">calculate</button>

javascript arrays math

edited Nov 11 at 15:22

Ele

22.5k42044

asked Nov 11 at 15:21

Thomas231

edited Nov 11 at 15:22

Ele

22.5k42044

asked Nov 11 at 15:21

Thomas231

edited Nov 11 at 15:22

Ele

22.5k42044

edited Nov 11 at 15:22

Ele

22.5k42044

edited Nov 11 at 15:22

Ele

22.5k42044

asked Nov 11 at 15:21

Thomas231

asked Nov 11 at 15:21

Thomas231

asked Nov 11 at 15:21

Thomas231

my input looks like this: s^3+4s^2+4s+8
– Thomas231
Nov 11 at 15:23

add a comment |

my input looks like this: s^3+4s^2+4s+8
– Thomas231
Nov 11 at 15:23

my input looks like this: s^3+4s^2+4s+8
– Thomas231
Nov 11 at 15:23

add a comment |

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