I am trying to calculate this continued fraction but i cant seem to work, the program however can be compiled properly but crashes while it works










0















Im trying to get this program working as it requires to calculate continued fraction inputed in a linked list. the programme doesn't show any error however it always crashes in the middle. Can someone help me?



The task is simply to store the programme on a linked list and then calculate it by taking the parameter from the link. It is a continued fraction.



#include <iostream>
#include <cmath>
using namespace std;
struct node

int data;
node *next;
*h=nullptr, *t=nullptr;

float calculation (int co)

float a,c;
node *b,*f;
b->next = f;

while(co != 0)

f = t;
a = (float)f->data;
a = 1/a;
c = (float)b->data;
a = c + a;
t = b;
co--;



return a;


void storedata (int& c)

node *n = new node;
n->data = c;
n->next = nullptr;
cout<<n->data<<endl;
if(h==nullptr)

h=n;
t=n;
n=nullptr;

else

t->next=n;
t=n;



void formula (int a, int b, int co)

int c;
int z;
while (co!=0)

c = a/b;
storedata(c);
z = b*c;
z = a-z;
a = b;
b = z;
co--;



int main ()

int a,b,c,z,co,d;
float e;

a = 123;
b = 100;
co = 5;
formula (a,b,co);
e = calculation(co);
cout<<"cf1 = 123/100 ="<<e;










share|improve this question
























  • Nobody wants to read code with one-letter variable names. Least of all your instructor.

    – stark
    Nov 15 '18 at 14:26











  • I don't know if it can help, but in a recent question I posted a code that calculates continued fraction: stackoverflow.com/questions/53267626/…. I don't feel at ease with ads. I will suppress this comment if people disagree.

    – Damien
    Nov 15 '18 at 16:13
















0















Im trying to get this program working as it requires to calculate continued fraction inputed in a linked list. the programme doesn't show any error however it always crashes in the middle. Can someone help me?



The task is simply to store the programme on a linked list and then calculate it by taking the parameter from the link. It is a continued fraction.



#include <iostream>
#include <cmath>
using namespace std;
struct node

int data;
node *next;
*h=nullptr, *t=nullptr;

float calculation (int co)

float a,c;
node *b,*f;
b->next = f;

while(co != 0)

f = t;
a = (float)f->data;
a = 1/a;
c = (float)b->data;
a = c + a;
t = b;
co--;



return a;


void storedata (int& c)

node *n = new node;
n->data = c;
n->next = nullptr;
cout<<n->data<<endl;
if(h==nullptr)

h=n;
t=n;
n=nullptr;

else

t->next=n;
t=n;



void formula (int a, int b, int co)

int c;
int z;
while (co!=0)

c = a/b;
storedata(c);
z = b*c;
z = a-z;
a = b;
b = z;
co--;



int main ()

int a,b,c,z,co,d;
float e;

a = 123;
b = 100;
co = 5;
formula (a,b,co);
e = calculation(co);
cout<<"cf1 = 123/100 ="<<e;










share|improve this question
























  • Nobody wants to read code with one-letter variable names. Least of all your instructor.

    – stark
    Nov 15 '18 at 14:26











  • I don't know if it can help, but in a recent question I posted a code that calculates continued fraction: stackoverflow.com/questions/53267626/…. I don't feel at ease with ads. I will suppress this comment if people disagree.

    – Damien
    Nov 15 '18 at 16:13














0












0








0








Im trying to get this program working as it requires to calculate continued fraction inputed in a linked list. the programme doesn't show any error however it always crashes in the middle. Can someone help me?



The task is simply to store the programme on a linked list and then calculate it by taking the parameter from the link. It is a continued fraction.



#include <iostream>
#include <cmath>
using namespace std;
struct node

int data;
node *next;
*h=nullptr, *t=nullptr;

float calculation (int co)

float a,c;
node *b,*f;
b->next = f;

while(co != 0)

f = t;
a = (float)f->data;
a = 1/a;
c = (float)b->data;
a = c + a;
t = b;
co--;



return a;


void storedata (int& c)

node *n = new node;
n->data = c;
n->next = nullptr;
cout<<n->data<<endl;
if(h==nullptr)

h=n;
t=n;
n=nullptr;

else

t->next=n;
t=n;



void formula (int a, int b, int co)

int c;
int z;
while (co!=0)

c = a/b;
storedata(c);
z = b*c;
z = a-z;
a = b;
b = z;
co--;



int main ()

int a,b,c,z,co,d;
float e;

a = 123;
b = 100;
co = 5;
formula (a,b,co);
e = calculation(co);
cout<<"cf1 = 123/100 ="<<e;










share|improve this question
















Im trying to get this program working as it requires to calculate continued fraction inputed in a linked list. the programme doesn't show any error however it always crashes in the middle. Can someone help me?



The task is simply to store the programme on a linked list and then calculate it by taking the parameter from the link. It is a continued fraction.



#include <iostream>
#include <cmath>
using namespace std;
struct node

int data;
node *next;
*h=nullptr, *t=nullptr;

float calculation (int co)

float a,c;
node *b,*f;
b->next = f;

while(co != 0)

f = t;
a = (float)f->data;
a = 1/a;
c = (float)b->data;
a = c + a;
t = b;
co--;



return a;


void storedata (int& c)

node *n = new node;
n->data = c;
n->next = nullptr;
cout<<n->data<<endl;
if(h==nullptr)

h=n;
t=n;
n=nullptr;

else

t->next=n;
t=n;



void formula (int a, int b, int co)

int c;
int z;
while (co!=0)

c = a/b;
storedata(c);
z = b*c;
z = a-z;
a = b;
b = z;
co--;



int main ()

int a,b,c,z,co,d;
float e;

a = 123;
b = 100;
co = 5;
formula (a,b,co);
e = calculation(co);
cout<<"cf1 = 123/100 ="<<e;







c++ linked-list floating-point singly-linked-list continued-fractions






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edited Nov 16 '18 at 9:23









Rudy Velthuis

25.1k43775




25.1k43775










asked Nov 15 '18 at 13:10









navesaurusnavesaurus

41




41












  • Nobody wants to read code with one-letter variable names. Least of all your instructor.

    – stark
    Nov 15 '18 at 14:26











  • I don't know if it can help, but in a recent question I posted a code that calculates continued fraction: stackoverflow.com/questions/53267626/…. I don't feel at ease with ads. I will suppress this comment if people disagree.

    – Damien
    Nov 15 '18 at 16:13


















  • Nobody wants to read code with one-letter variable names. Least of all your instructor.

    – stark
    Nov 15 '18 at 14:26











  • I don't know if it can help, but in a recent question I posted a code that calculates continued fraction: stackoverflow.com/questions/53267626/…. I don't feel at ease with ads. I will suppress this comment if people disagree.

    – Damien
    Nov 15 '18 at 16:13

















Nobody wants to read code with one-letter variable names. Least of all your instructor.

– stark
Nov 15 '18 at 14:26





Nobody wants to read code with one-letter variable names. Least of all your instructor.

– stark
Nov 15 '18 at 14:26













I don't know if it can help, but in a recent question I posted a code that calculates continued fraction: stackoverflow.com/questions/53267626/…. I don't feel at ease with ads. I will suppress this comment if people disagree.

– Damien
Nov 15 '18 at 16:13






I don't know if it can help, but in a recent question I posted a code that calculates continued fraction: stackoverflow.com/questions/53267626/…. I don't feel at ease with ads. I will suppress this comment if people disagree.

– Damien
Nov 15 '18 at 16:13













1 Answer
1






active

oldest

votes


















1














At least the following problems (some of which would be caught with warnings enabled, e.g. -Wall):



  1. Using uninitialized pointers, e.g. node *b,*f; b->next = f;. This causes undefined behavior.


  2. new but no delete anywhere, therefore memory leaks will be present.






share|improve this answer























  • What is the connection between formula and calculation. Dynamic memory variables not connected between each other. You can`t get access from one memory block to other if variables are temporary. If after working of function you exit from function all variables are destroyed and dynamic will be memory leaks. You need to connect them.

    – Timur Kukharskiy
    Nov 15 '18 at 13:30











  • @TimurKukharskiy They are actually connected. It is kind of difficult to spot, but formula modifies the global t through storedata and calculation accesses t as well. I agree though, that this is bad design. h and t should be local and passed around as function arguments. The naming is also bad, they should probably be head and tail.

    – user10605163
    Nov 15 '18 at 13:33











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









1














At least the following problems (some of which would be caught with warnings enabled, e.g. -Wall):



  1. Using uninitialized pointers, e.g. node *b,*f; b->next = f;. This causes undefined behavior.


  2. new but no delete anywhere, therefore memory leaks will be present.






share|improve this answer























  • What is the connection between formula and calculation. Dynamic memory variables not connected between each other. You can`t get access from one memory block to other if variables are temporary. If after working of function you exit from function all variables are destroyed and dynamic will be memory leaks. You need to connect them.

    – Timur Kukharskiy
    Nov 15 '18 at 13:30











  • @TimurKukharskiy They are actually connected. It is kind of difficult to spot, but formula modifies the global t through storedata and calculation accesses t as well. I agree though, that this is bad design. h and t should be local and passed around as function arguments. The naming is also bad, they should probably be head and tail.

    – user10605163
    Nov 15 '18 at 13:33
















1














At least the following problems (some of which would be caught with warnings enabled, e.g. -Wall):



  1. Using uninitialized pointers, e.g. node *b,*f; b->next = f;. This causes undefined behavior.


  2. new but no delete anywhere, therefore memory leaks will be present.






share|improve this answer























  • What is the connection between formula and calculation. Dynamic memory variables not connected between each other. You can`t get access from one memory block to other if variables are temporary. If after working of function you exit from function all variables are destroyed and dynamic will be memory leaks. You need to connect them.

    – Timur Kukharskiy
    Nov 15 '18 at 13:30











  • @TimurKukharskiy They are actually connected. It is kind of difficult to spot, but formula modifies the global t through storedata and calculation accesses t as well. I agree though, that this is bad design. h and t should be local and passed around as function arguments. The naming is also bad, they should probably be head and tail.

    – user10605163
    Nov 15 '18 at 13:33














1












1








1







At least the following problems (some of which would be caught with warnings enabled, e.g. -Wall):



  1. Using uninitialized pointers, e.g. node *b,*f; b->next = f;. This causes undefined behavior.


  2. new but no delete anywhere, therefore memory leaks will be present.






share|improve this answer













At least the following problems (some of which would be caught with warnings enabled, e.g. -Wall):



  1. Using uninitialized pointers, e.g. node *b,*f; b->next = f;. This causes undefined behavior.


  2. new but no delete anywhere, therefore memory leaks will be present.







share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 15 '18 at 13:19









user10605163user10605163

2,868624




2,868624












  • What is the connection between formula and calculation. Dynamic memory variables not connected between each other. You can`t get access from one memory block to other if variables are temporary. If after working of function you exit from function all variables are destroyed and dynamic will be memory leaks. You need to connect them.

    – Timur Kukharskiy
    Nov 15 '18 at 13:30











  • @TimurKukharskiy They are actually connected. It is kind of difficult to spot, but formula modifies the global t through storedata and calculation accesses t as well. I agree though, that this is bad design. h and t should be local and passed around as function arguments. The naming is also bad, they should probably be head and tail.

    – user10605163
    Nov 15 '18 at 13:33


















  • What is the connection between formula and calculation. Dynamic memory variables not connected between each other. You can`t get access from one memory block to other if variables are temporary. If after working of function you exit from function all variables are destroyed and dynamic will be memory leaks. You need to connect them.

    – Timur Kukharskiy
    Nov 15 '18 at 13:30











  • @TimurKukharskiy They are actually connected. It is kind of difficult to spot, but formula modifies the global t through storedata and calculation accesses t as well. I agree though, that this is bad design. h and t should be local and passed around as function arguments. The naming is also bad, they should probably be head and tail.

    – user10605163
    Nov 15 '18 at 13:33

















What is the connection between formula and calculation. Dynamic memory variables not connected between each other. You can`t get access from one memory block to other if variables are temporary. If after working of function you exit from function all variables are destroyed and dynamic will be memory leaks. You need to connect them.

– Timur Kukharskiy
Nov 15 '18 at 13:30





What is the connection between formula and calculation. Dynamic memory variables not connected between each other. You can`t get access from one memory block to other if variables are temporary. If after working of function you exit from function all variables are destroyed and dynamic will be memory leaks. You need to connect them.

– Timur Kukharskiy
Nov 15 '18 at 13:30













@TimurKukharskiy They are actually connected. It is kind of difficult to spot, but formula modifies the global t through storedata and calculation accesses t as well. I agree though, that this is bad design. h and t should be local and passed around as function arguments. The naming is also bad, they should probably be head and tail.

– user10605163
Nov 15 '18 at 13:33






@TimurKukharskiy They are actually connected. It is kind of difficult to spot, but formula modifies the global t through storedata and calculation accesses t as well. I agree though, that this is bad design. h and t should be local and passed around as function arguments. The naming is also bad, they should probably be head and tail.

– user10605163
Nov 15 '18 at 13:33




















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